Answer:
Tan x= 3/4 Cos x= 4/5 Sin x=3/5
Step-by-step explanation:
"soh-cah-toa"
Just an easy way to remember how Sine, Cosine and Tangent work:
Soh...
Sine = Opposite / Hypotenuse
...cah...
Cosine = Adjacent / Hypotenuse
...toa
Tangent = Opposite / Adjacent
Answer:
tan(x)=0.75 sin(x)=0.6 Cos(x)=0.8
Step-by-step explanation:
[tex]tan(x)=\frac{opposite}{adjacent}=\frac{3}{4}=0.75[/tex]
[tex]cos(x)=\frac{adjacent}{hypotenuse}= \frac{4}{5} =0.8[/tex]
[tex]sin(x)=\frac{opposite}{hypotenuse}=\frac{3}{5}=0.6[/tex]
opposite=3
adjacent=4
hypotenuse=5
try remembering it as SOH CAH TOA
identify the terms of each expression 7 + 5 p + 4r + 6 s
I need Helpppp quick!!!!
Answer:
G
Step-by-step explanation:
let his fixed price be x and his hourly fee be y;
270 = 4y + x
420 = 7y + x
x is common in both equations
equate the two;
x = 270-4y and x = 420-7y
270-4y = 420-7y
3y = 150
y = 50
x = 270-4*50
x = 70
Express as a trinomial.
(3x+5)(2x+9)
Answer:
[tex]6x^{2} +37x+45[/tex]
Step-by-step explanation:
Hello!
A trinomial is a algebraic expression containing 3 terms
To turn this into a trinomial we have to multiply everything by each other
3x
3x * 2x = 6x^2
3x * 9 = 27x
5
5 * 2x = 10x
5 * 9 = 45
Now we put it all together
6x^2 + 27x + 10x + 45
Combine like terms
6x^2 + 37x + 45
The answer is [tex]6x^{2} +37x+45[/tex]
Hope this helps!
which graph represents (x,y)(x,y)left parenthesis, x, comma, y, right parenthesis-pairs that make the equation y = 0.5x+5y=0.5x+5y, equals, 0, point, 5, x, plus, 5 true?
The graph of [tex]\mathbf{y = 0.5x + 5}[/tex] has a slope of 0.5, and a y-intercept of 5
The equation is given as:
[tex]\mathbf{y = 0.5x + 5}[/tex]
A linear equation is represented as:
[tex]\mathbf{y = mx + c}[/tex]
Where m represents the slope, and c represents the y-intercept
So, by comparison:
m = 0.5
c = 5
This means that:
The slope is 0.5, and the y-intercept is 5
Hence, the graph of [tex]\mathbf{y = 0.5x + 5}[/tex] has a slope of 0.5, and a y-intercept of 5
See attachment for the graph of [tex]\mathbf{y = 0.5x + 5}[/tex]
Read more about linear equations at:
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3rd one i just did it on edge :P
A business has $25,000 to spend on training sessions for its employees. It wants 45 of its employees to attend. The business wants to send as many employees as it can to a technology training. The technology training costs $1,000 per person. The customer service training costs $500 per person. Create a system of equations that models how many of each type of training the business should purchase. 1,000x + 500y = 45 x + y = 25,000 1,000x + 500y = 25,000 x + y = 45 1,000x + y = 45 x + 500y = 25,000 x + 500y = 45 1,000x + y = 25,000
Answer: [tex]x+y=45\\\\1000 x + 500y = $2500[/tex]
Step-by-step explanation:
Let x = Number of employees taking technology training
y= Number of employees taking customer service training
Given, The technology training costs $1,000 per person. The customer service training costs $500 per person.
Total cost = 1000 x + 500y
Since, Total cost = $25,000 and total employee to attend training= 45 .
That means , the required equations are:
[tex]x+y=45\\\\1000 x + 500y = $2500[/tex]
Answer:
1,000x + 500y = 45
x + y =45
Step-by-step explanation:
So that means answer b is the correct answer, also I took the test.
The house Trevor's family lives in has 6 people (including Trevor) and 3 bathrooms. In the past month, each person showered for an average of 480 minutes and used an average 72 liters of shower water (over the entire month). Water costs 0.20 dollars per liter.
Answer:
$86.40
Step-by-step explanation:
The house Trevor's family lives in has 6 people (including Trevor) and 3 bathrooms. In the past month, each person showered for an average of 480 minutes and used an average 72 liters of shower water (over the
entire month). Water costs 0.20 dollars per liter.
How much did Trevor's family pay per minute on shower water
Average person=72 liters of water
6 people=72*6= 432 liters
Each person = 480 minutes
6 people=480*6= 2,880 minutes
Water=$0.20 per liter
Total cost of water= 432 * 0.20
= $86.40
Answer:
o.o3
Step-by-step explanation:
Yazmin is investigating the growth of plants under different conditions for her science class. Once the little sprouts were 1 inch tall, she found that they were growing at a steady rate of about 1/2 inch per day. Write a function that helps Yazmin to see how many days it takes for the plants to reach a given height. Let h = height of the plant (inches), and let d = number of days (days)
Answer:
0.5+d=h
Step-by-step explanation:
If a plant is growing at a steady rate of 0.5 inches (h) in 1 day (d) then after one day your equation should look like: 0.5+1 which would give you the height of the plant in inches. If this is true, then you would keep the height per day the same (0.5) substitute the 1 for d (one day); then your equation would look like this: 0.5+d which would give you the height of the plant in inches (h).
0.5+d=h
The function that helps Yazmin to see how many days it takes is h = 1 + 0.5d.
What is a function?Functions were originally the idealization of how a varying quantity depends on another quantity.
Now it is given that,
Height of sprout = 1 inch
Growth per day = 1/2 inch
Let h = height of the plant (inches), and let d = number of days (days)
∵ Growth per day = 1/2 inch
So, Growth of plant in d days = d * 1/2 = d/2 = 0.5d
Thus, height of the plant, h = 1 + Growth of plant in d days
⇒ h = 1 + 0.5d
Thus, the function that helps Yazmin to see how many days it takes is h = 1 + 0.5d.
To learn more about the function :
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solve 4w–3w+2w=24
Please
We need to simplify the left side first.
On the left side, all the terms can be combined.
So 4w - 3w + 2w is 3w.
So we have 3w = 24.
Next, dividing both sides by 3, we have w = 8.
So our solution is w = 8.
Answer
[tex] \boxed{ \huge{ \bold{ \sf{ \boxed{w = 8}}}}}[/tex]
Step by step explanation
[tex] \sf{4w - 3w + 2w = 24}[/tex]
Collect like terms
⇒[tex] \sf{w + 2w = 24}[/tex]
⇒[tex] \sf{3w = 24}[/tex]
Divide both sides of the equation by 3
⇒[tex] \sf{ \frac{3w}{3} = \frac{24}{3} }[/tex]
Calculate
⇒[tex] \sf{w = 8}[/tex]
Hope I helped!
Best regards!!
4x-8+9-6x=3x+6 cual es el valor de la x?
Answer:
El valor de x en esta ecuación es -1.
Step-by-step explanation:
4x - 8 + 9 - 6x = 3x + 6
En primer lugar, combinar términos similares en cada lado de la ecuación.
-2x + 1 = 3x + 6
A continuación, resta 3 veces en ambos lados de la ecuación.
-5x + 1 = 6
Ahora, resta 1 de ambos lados de la ecuación.
-5x = 5
Por último, divida por -5 en ambos lados de la ecuación.
x = -1
Point E is on line segment DF. Given DE
EF.
6 and DF =9, determine the length EF
Answer:
3Step-by-step explanation:
IF point E lies on the line segment DF, this means that all the points DEF are collinear and DE+EF = DF.
Given parameter
DE = 6
DF = 9
Required
EF
Substituting the given parameter into the expression above to get the required will be;
DE+EF = DF.
EF = DF-DE
EF = 9-6
EF = 3
Hence the length of EF is equivalent to 3
4. Suppose you make $12 an hour as a lifeguard at the community pool during the summer. Let h
represent the number of hours you work in a week. Write an expression that represents the
amount of money you earn in a week and evaluate it for ) = 15.
O 12.; $180
O 12 + 1; $27
7(12.1); $1,260
O5(127); $900
Answer:
Option A
Step-by-step explanation:
Expression: y = 12h
If h = 15, then:
y = 12(15)
y = $180
Option A
Pablo graphs a system of equations. One equation is quadratic and the other equation is linear. What is the greatest
number of possible solutions to this system?
Answer:
greatest number of solutions is 2
Step-by-step explanation:
one is a parabola, the other is a line
so it can intersect in 0, 1, 2 points
What is the solution to:
[tex] \frac{5}{8} = \frac{m}{12} [/tex]
HELP! answer if you can.
Answer:
[tex]\boxed{m=7.5}[/tex]
Step-by-step explanation:
Hey there!
Cross multiply the given info
60 = 8m
Divide both sides by 8
m = 7.5
Hope this helps :)
Possible Points: 100 One January day, the low temperature in Fargo, ND was -8 degrees. Over a period of six hours, the temperature rose 4 degrees per hour. After si hours, what was the temperature?
Someone please help me ASAP
Answer:
the percentage share for BBC2 remained almost the same at about 11 % each year
if you look at the chart the BBC2 almost remains stable between 10 and 12 %
1980 ( between 39 and 51)
1985 ( between 37 and 49 ) and so on
( these numbers are not exactly the same , it is about or approximately)
Figure a is a scale image of figure b. what is the value of x? please answer asap!
Answer:
[tex]\boxed{x = 20}[/tex]
Step-by-step explanation:
Hey there!
Well to find x we need to set up the following.
[tex]\frac{10}{12.5} = \frac{16}{x}[/tex]
Cross multiply
10x = 200
Divide both sides by 10
x = 20
Hope this helps :)
Jerry wants to gravel an area represented by a square with side lengths of 3/4ft. What is the area he needs to fill.
Answer:
0.5625 ft^2
Step-by-step explanation:
area of square = side * side
A = s^2
A = (0.75 ft)^2 = (0.75 ft)(0.75 ft) = 0.5625 ft^2
Megan buys condiments in bulk for her restaurant. The company that she orders ketchup from charges $14.78 per gallon for orders less than 8 gallons. For orders of 8 gallons or more, the cost is $11.99 per gallon of ketchup. Which function represents this situation?
side note: f(x)= blank
Answer:
Below
Step-by-step explanation:
● Orders of 8 gallons or more can be modeled as: x》 8
● For each gallons in the situation above the company charges 11.99 per gallon so: 11.99x
● For orders that are less than 8, the comapny charges 14.78 per gallon
● => 14.78x for x < 8
So the function that represent the situation is the second one
Find the distance across the lake. Assume the triangles are similar.
80 m
х
у
20 m
60 m
Answer:
A. L = 240 m
Step-by-step explanation:
use similar triangle
L / 60 = 80 / 20
L = (80 * 60) / 20
L = 240 m
The required distance across the lake is 240 m. Hence correct option is A.
Similar triangles, are those triangles which have similar properties i.e. angles and proportionality of sides.
Since, triangles are similar.
The ratio of their sides are also equal
60/20= L/80
L=80 x 3
L = 240 m
Thus, the required distance across the lake is 240 m.
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The midpoint (x, y) and the end point (x2, y2) are known. Find (x1, Y1) using the midpoint formula.
a. (x1,y1) = (2x + x2, 2y+y2)
b. (x1,y1) = (2x - x2, 2y - y2)
c. (x1,y1) = (x + x2, y + y2)
d. (x1,y1) = (x - x2, y - y2)
Answer:
(x1,y1) = (2x - x2, 2y - y2)
Step-by-step explanation:
Given:
Midpoint = (x , y)
End point = (x2, y2)
Find:
(x1, y1)
Computation:
Mid-point formula
x = (x1 + x2) / 2 , y = (y1 + y2) / 2
So,
2x = x1 + x2 , 2y = y1 + y2
x1 = 2x - x2 , y1 = 2y - y2
So,
(x1,y1) = (2x - x2, 2y - y2)
please help me on this
Answer:
YZ = 8.5
Step-by-step explanation:
Since RY is an angle bisector then the ratio of the sides of the triangle are equal to the corresponding ratio of the base, that is
[tex]\frac{YX}{YZ}[/tex] = [tex]\frac{XR}{ZR}[/tex] , substitute values
[tex]\frac{11.9}{YZ}[/tex] = [tex]\frac{7}{5}[/tex] ( cross- multiply )
7YZ = 59.5 ( divide both sides by 7 )
YZ = 8.5
What are the vertical and horizontal asymptotes for the function f(x)=
3x2/x2-4
Answer: f(x) will have vertical asymptotes at x=-2 and x=2 and horizontal asymptote at y=3.
Step-by-step explanation:
Given function: [tex]f(x)=\dfrac{3x^2}{x^2-4}[/tex]
The vertical asymptote occurs for those values of x which make function indeterminate or denominator 0.
i.e. [tex]x^2-4=0\Rightarrow\ x^2=4\Rightarrow\ x=\pm2[/tex]
Hence, f(x) will have vertical asymptotes at x=-2 and x=2.
To find the horizontal asymptote , we can see that the degree of numerator and denominator is same i.e. 2.
So, the graph will horizontal asymptote at [tex]y=\dfrac{\text{Coefficient of }x^2\text{ in numerator}}{\text{Coefficient of }x^2\text{ in denominator}}[/tex]
i.e. [tex]y=\dfrac{3}{1}=3[/tex]
Hence, f(x) will have horizontal asymptote at y=3.
Mukat has five times as many book as usha.If mukat gave 16 books to usha,they each would have the same number.how many books did each girl have?
Mukat gets 40, Usha gets 8
Step-by-step explanation:
Mukat = 5 × Usha
After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)
Then Mukat = final number of books for Usha
5 × Usha - 16 = Usha + 16
(5 × Usha ) - Usha = 16+16
4 × Usha = 32
Usha = 8 i.e her number of books.
Mukat = 5×8=40.
I HOPE IT'S OK
What is the sign of -xy? Will give the brainlest to who ever answers it
Answer:
positive
Step-by-step explanation:
X is positive since it is to the right of zero
Y is negative since it is to the left of zero
-xy
- ( +) ( -)
negative times positive times negative
negative times negative
positive
Let P (2,-3), Q (-2, 1) be the vertices of the triangle PQR. If the centroid of ΔPQR lies on the line 2x +3y = 1, then the locus of R is a. 2x + 3y = 9 b. 2x - 3y = 9 c. 3x + 2y = 5 d. 3x - 2y = 5
Answer:
Correct answer is a. 2x + 3 y = 9.
Step-by-step explanation:
Let the coordinates of centroid be (h,k)
{h/3 , (-2+k)/3}
h = (2 – 2 + a)/3 = a/3 ---eqn 1
k= ( - 3+ 1 + b )/3 = (-2 + b)/3 -----eqn 2
Where (x,y) are any point on the line 2x+3y=1
3h = a and 3k + 2 = b
From 2x +3y = 1,
Then, 2h +3k = 1, 3k = 1 - 2h -----eqn 3
b = 1 - 2h + 2 = 3 - 2h
also b = 3 - 2a/3
b = (9 -2a)/3
3b = 9 - 2a
3b + 2a = 9
Now (x,y) satisfy the point on the line 2x+3y=9
So the locus is 2x + 3 y = 9.
Simplify 27^(-2/3) x 25^(1/2) x 5^0 9 5 9/5 5/9
Answer:
[tex]\frac{5}{9}[/tex]
Step-by-step explanation:
Using the rules of exponents/ radicals
[tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex] , [tex]a^{0}[/tex] = 1
[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]
Given
[tex]27^{-\frac{2}{3} }[/tex] × [tex]25^{\frac{1}{2} }[/tex] × [tex]5^{0}[/tex]
= [tex]\frac{1}{27^{\frac{2}{3} } }[/tex] × [tex]\sqrt{25}[/tex] × 1
= [tex]\frac{1}{9}[/tex] × 5 × 1
=[tex]\frac{5}{9}[/tex]
What angle does an arc 6.6cm in length subtends at the centre of a circle of radius 14cm. Use π = 22/7)
Answer:
STEP 1: Find the circumference:
Circumference = 2πr
Circumference = 2π(14) = 28π cm
............................................................................................
STEP 2: Find the length of the arc:
Length of the arc = 36/360 x 28π
Length of the arc = 8.8 cm
.............................................................................................
Answer: The length of the arc is 8.8 cm
............................................................................................
hope it helpssss
Mark it as brilliant answer plzzz
ФωФ
Answer:
27°
Step-by-step explanation:
arc length = circumference × fraction of circle
let x be the central angle, then
2πr × [tex]\frac{x}{360}[/tex] = 6.6
2 × [tex]\frac{22}{7}[/tex] × 14 × [tex]\frac{x}{360}[/tex] = 6.6
88 ×[tex]\frac{x}{360}[/tex] = 6.6 ( multiply both sides by 360 )
88x = 2376 ( divide both sides by 88 )
x = 27
Thus central angle is 27°
Someone pls HELP MEEEE i’m giving the rest of my points away . i have like 20 mins to turn this in
Answer:
1) 27.89
2) 20
Step-by-step explanation:
#1)
9.5x + 75 --> 340
340 - 75 --> 265
265 / 9.5 = 27.89
#2)
120 / 6 =
20 minutes
Help please will give brainiest if correct
Answer:
(x + 1)^2 + (y - 1)^2 = (8.5)^2
Step-by-step explanation:
Consider the general equation of a circle:
(x - h)^2 + (y - k)^2 = (r)^2
Where (h,k) represent the center point of the circle, and r represents the radius of the circle.
For this circle, our center point appears to be at (-1,1) and the circle has a radius of 8.5.
Using this information, we simply plug these values into the general equation to get the following:
(x + 1)^2 + (y - 1)^2 = (8.5)^2
Cheers.
X
5x – 3y = -20
4x + 5y = -2
Answer:
x=-106/37
y=70/37
Step-by-step explanation:
I chose to set up the problem as a matrix to solve here.
(Another way to do this would be to isolate one variable in one of the equations, substitute it into the other equation, solve for that, and then plug it back in to get the final variable.)
My work is in the attachment. Lmk if you have any questions.
Answer:
[tex]\huge\boxed{\left\{\begin{array}{ccc}x=-\dfrac{106}{37}\\y=\dfrac{70}{37}\end{array}\right}[/tex]
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}5x-3y=-20&\text{multiply both sides by 5}\\4x+5y=-2&\text{multiply both sides by 3}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}25x-15y=-100\\12x+15y=-6\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad37x=-106\qquad\text{divide both sides by 37}\\.\qquad\boxed{x=-\dfrac{106}{37}}[/tex]
[tex]\text{Substitute it to the first equation}\\\\5\left(-\dfrac{106}{37}\right)-3y=-20\\\\-\dfrac{530}{37}-3y=-20\qquad\text{multiply both sides by (-37)}\\\\(-37\!\!\!\!\!\diagup)\left(-\dfrac{530}{37\!\!\!\!\!\diagup}\right)-(-37)(3y)=(-37)(-20)\\\\530+111y=740\qquad\text{subtract 530 from both sides}\\\\111y=210\qquad\text{divide both sides by 111}\\\\y=\dfrac{210}{111}\\\\y=\dfrac{210:3}{111:3}\\\\\boxed{y=\dfrac{70}{37}}[/tex]