Students are completing a lab in which they let a lab cart roll down a ramp. The students record the mass of the cart, the height of the ramp, and the velocity at the bottom of the ramp. The students then calculate the momentum of the cart at the bottom of the ramp.

A 4 column table with 3 rows. The first column is labeled Trial with entries 1, 2, 3, 4. The second column is labeled Mass of Cart in kilograms with entries 200, 220, 240, 260. The third column is labeled Height of ramp in meters with entries 2.0, 2.1, 1.5, 1.2. The fourth column is labeled Velocity at Bottom in meters per second with entries 6.5, 5.0, 6.4, 4.8.

Which trial’s cart has the greatest momentum at the bottom of the ramp?

Answers

Answer 1

Answer:

second column

Explanation:

Answer 2

Answer:

Trial 3 is the answer.

Explanation:


Related Questions

una caja en reposo se traslada 93 cm con un peso de 67N en un tiempo de 9,89h.¿cual es la aceleración la masa y la fuerza de dicho objeto

Answers

Answer:

a. Acceleration, a = 1.47 * 10^{-9} m/s²

b. Mass = 4.57 * 10^{10} kilograms

c. Force = 67.12 Newton

Explanation:

Given the following data;

Distance = 93 cm to meters = 93/100 = 0.93 meters

Weight = 67 N

Time = 9.89 hours to seconds = 35604 seconds

Initial velocity = 0 m/s (since it's starting from rest)

Acceleration due to gravity, g = 9.8 m/s

a. To find the acceleration, we would use the second equation of motion;

[tex] S = ut + \frac{1}{2} at^{2} [/tex]

Where;

S is the distance covered or displacement of an object.

u is the initial velocity.

a is the acceleration.

t is the time.

Substituting the values into the equation, we have;

[tex] 0.93 = 0*35604 + \frac{1}{2} * a*35604^{2} [/tex]

[tex] 0.93 = 0 + \frac{1}{2} * 1267644816a [/tex]

[tex] 0.93 = 633822408a [/tex]

[tex] Acceleration, a = \frac{0.93}{633822408} [/tex]

Acceleration, a = 1.47 * 10^{-9} m/s²

b. To find the mass

Weight = mass * acceleration due to gravity

67 = mass * 1.47 * 10^{-9}

[tex] Acceleration, a = \frac{67}{1.47 * 10^{-9}} [/tex]

Mass = 4.57 * 10^{10} kilograms

c. To find the force;

Force = mass * acceleration

Force = 4.57 * 10^{10} * 1.47 * 10^{-9}

Force = 67.12 Newton

s27253129 ,,, message me please, I can't ask you my homework question in the comments :c

Answers

What’s the problem what do u need help on

Sort the processes based on the type of energy transfer they involve. condensation freezing deposition sublimation evaporation melting thermal energy added thermal energy removed

Answers

Answer:

condensation - thermal energy removed

freezing -thermal energy removed

deposition - thermal energy removed

sublimation - thermal energy added

evaporation - thermal energy added

melting - thermal energy added

Explanation:

Thermal energy is heat energy. Processes in which heat is added involve the addition of thermal energy while processes in which heat energy is removed involves removal of thermal energy.

Condensation involves a change from gas to liquid, freezing involves a change from liquid to solid while deposition involves the settling of mobile particles at a place. All these processes involve a decrease in energy of particles.

On the other hand, sublimation is a direct change from solid to gas, melting involves a change from solid to liquid while evaporation involves a change from liquid to gas. All these processes occur when energy is added to the particles in a system.

Answer:

condensation - thermal energy removed

freezing -thermal energy removed

deposition - thermal energy removed

sublimation - thermal energy added

evaporation - thermal energy added

melting - thermal energy added

If Earth's gravity pulls an object, causing it to accelerate to the ground, what

must be true about Earth?

A. It accelerates just as quickly in the direction away from the object.

B. It is being pulled toward the object by the object's gravity.

C. It accelerates just as quickly in the direction of the object.

D. It is being pushed away from the object by that same force.

Answers

Ans

It is being pulled toward the object by the objects gravity

Gravity:-

Sir Eizak Newton Founded the gravity.Gravity is a force between any object and earth by which they pull each other .The Acceleration due to gravity is represented by g =9.8m/s^2

giving me the points are enough

Answers

Answer:

the product of mass and velocity

....in my syllabus

the masses of your hand and your notebook are quite small, so the force of attraction between them is

Answers

The force of attraction is decreased

a small object is placed between two plane mirrors inclined at an angle of 60° to each other in a dark room how many images are seen explain​

Answers

Answer:

nothing

Explanation:

bocouse of darkness

La resistencia de un termómetro de platino es de 6Ω a30°C. Hallar su valor correspondiente a 100°C,sabiendo que el coeficiente de temperatura de resistividad del platino vale 0,00392°C^(-1).

Answers

Respuesta:

7,6 Ω

Explicación:

Paso 1: Información dada

Resistencia a 30 °C (R₀): 6 ΩCoeficiente de temperatura (α): 0,00392 °C⁻¹

Paso 2: Hallar la resistencia (R) a 100 °C

Podemos ver la relación entre la resistencia de un material y la temperatura usando la siguiente ecuación.

R = R₀ (1  + α × ΔT)

R = 6 Ω (1  + 0,00392 °C⁻¹ × (100 °C - 30 °C)) = 7,6 Ω

A 250–g piece of gold is at 19 °C. 5.192 kJ of energy is added to it by heat. The specific heat of gold is 129 J/(kg·°C). Calculate its final temperature.




We heat a 25–g sample of metal from 10 °C to 100 °C. 1.082 kJ of energy is added to it by heat. Calculate
the specific heat of the metal.

Answers

Answer:

A. DT is given by Q= MCs DT

m = mass of the substances

Cs= is it's specific heat capacity

Ck= Q

Mk ×DTk

=250 × 9 × 5

129

=Dt = 180.1085271

answer is 180degree C.

Explanation:

B. = 25×10 ×100

1.082

=2500

1.082

= 23105.360 g/kj.

The final temperature is 180 degree. and the specific heat of the metal is 23105.360 g/kj.

How to calculate the specific heat?

Q = m . C . ΔT

Q = heat; m = mass; C is the specific heat and

ΔT = Final T° - Initial T°

Q = C lat . m

Q = Heat

m = mass

C lar = Latent heat of fusion

A) DT is given by Q= M Cs DT

where, m = mass of the substances

Cs= is it's specific heat capacity

Ck= Q

Mk × DTk

=250 × 9 × 5

129 =Dt = 180.1085271

Thus, the final temperature is 180 degree.

B) We heat a 25–g sample of metal from 10 °C to 100 °C. 1.082 kJ of energy is added to it by heat = 25×10 ×100

=2500

1.082

Q = 23105.360 g/kj

Hence, the specific heat of the metal is 23105.360 g/kj.

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The mass of objects is 4kg and it has a density of 5gcm^-3. what is the volume ​

Answers

Answer:

4kg×5gm^3=60

Explanation:

the object if heavy

round off 20.96 to 3 significant figures. a.20.9 b.20 c.21.0 d.21​

Answers

Answer:

option c. 21.0

Explanation:

It was given that to find 3 significant figures. So the answer is 21.0

A ball is launched from the ground with the horizontal speed of 30 m/s and vertical speed of 30 m/s what angle was the ball launch at?

Answers

Answer:

45 degrees

Explanation:

angle of launch=arctan(vertical velocity/ horizontal velocity)

angle = arctan(30/30) = 45 degrees

what ia measurement in science?
= The process of comparing an unknown quantities with an standard known quantities is called measurement.​

Answers

Yes it is the measurement in science

Numerical problems:
a. convert the following as instructed:
i) 340 cm into m
ii)86400 seconds into day​

Answers

Answer:

a=3.4m because of the m

b=1day because 86400=a day

please halp me solve this question!

Answers

current in 3ohm resistor is 0.9

Explanation:

total

Define Metrology
define Metrology ​

Answers

Answer:

the scientific study of measurement.

1. A bicycle initially moving with a velocity
5.0 m s-1 accelerates for 5 s at a rate of 2 m s? Wh
will be its final velocity ?

Answers

Answer:

[tex]\boxed {\boxed {\sf 15 \ m/s \ or \ 15 \ m*s^{-1}}}[/tex]

Explanation:

We are asked to find the final velocity. We are given the acceleration, time, and initial velocity, so we can use the following kinematics formula.

[tex]v_f= v_i+ at[/tex]

In this formula, [tex]v_f[/tex] is the final velocity, [tex]v_i[/tex] is the initial velocity, [tex]a[/tex] is the acceleration, and [tex]t[/tex] is the time.

The bicycle has an initial velocity of 5.0 m *s⁻¹ or m/s, acceleration of 2 m/s², and a time of 5 seconds.

[tex]\bullet \ v_i = 5.0 \ m/s \\\bullet \ a= 2\ m/s^2\\\bullet \ t= 5 \ s[/tex]

Substitute the values into the formula.

[tex]v_f=5.0 \ m/s + ( 2\ m/s^2 * 5 \ s)[/tex]

Solve inside the parentheses.

[tex]\frac {2 \ m}{s^2}* 5 \ s = \frac{ 2 \ m}{s} * 5 = \frac{ 10 \ m}{s} = 10 \ m/s[/tex]

[tex]v_f= 5.0 \ m/s + (10 \ m/s)[/tex]

Add.

[tex]v_f= 15 \ m/s[/tex]

The units can also be written as:

[tex]v_f= 15 \ m*s^{-1}[/tex]

The bicycle's final velocity is 15 meters per second.

a car takes 10 minutes to travel 10 km calculate average speed of car.​

Answers

Answer:

(km/mins) × ( mins/hr) = km/hr

(10/10)×(60/1) =600/10 = 60 km /hr

......

what are the examples of Inertia of motion​

Answers

Seat belts tighten in a car when it stops quickly.

Men in space find it more difficult to stop moving because of a lack of gravity acting against them.

When playing football, a player is tackled, and his head hits the ground.

EXAMPLES ARE GIVEN BELOW:

HOPE IT'S HELPFUL FOR U MATE

diffusion in physics​

Answers

Answer:

sorry but which class your talking 'bout

What unit is used in MKS system and FPS system​

Answers

The "second" is the base unit of time in both systems.

Que. I : A mass of 10kg is suspended from the end of a steel of length 2m and radius 1mm, what is the elongation of the rod beyond its original length?

Que 2 : A pressure of sea water increases by 1.0atm for each 10metres increase in the depth. by what what percentage is the density of water increased in the deepest ocean of about 12km; compressibility = 5.0 × 10^-5 ​

Answers

Question 1; The elongation of the steel is approximately 0.3123 mm

Question 2; The percentage the density of water increased in the deepest

ocean is approximately 6.4%

The strategy of obtaining the above solution is presented as follows;

Que. 1; The given parameters are;

The mass of the suspended block, m = 10 kg

The length of the steel, l = 2 m

The radius of the steel, r = 1 mm = 1 × 10⁻³ m

The modulus of elasticity of steel, E = 200 GPa = 200 × 10⁹ Pa

The stress, σ, on the steel due to the mass, m, is given as follows;

[tex]\mathbf{\sigma = \dfrac{F}{A}}[/tex]

Where;

F = The force acting on the steel = The weight of the mass

A = The cross sectional area of the steel = π·r²

∴ F = 10 kg × 9.81 m/s² = 98.1 N

A = π × (1 × 10⁻³)² = 3.14159 × 10⁻⁶ m²

Therefore;

σ = 98.1 N/(3.14159 × 10⁻⁶ m²) ≈ 31,226,226.2 Pa

We have;

[tex]\mathbf{ E = \dfrac{\sigma}{\epsilon}}[/tex]

From which we have;

[tex]\epsilon = \dfrac{\sigma}{E}[/tex]

Where;

= The tensile strain = Δl/l

Δl = The elongation of the steel

Therefore;

∈ = 31,226,226.2/(200 × 10^9) = 0.00015613113

∴ Δl = 0.00015613113 × 2 m = 0.00031226226 m = 0.31226226 mm

The elongation of the steel, Δl = 0.31226226 mm ≈ 0.3123 mm

Question 2

The given parameters are;

The change in pressure per unit depth, Δp = 1.0 atm per 10 meters

The depth of the ocean = 12 km = 12,000 m

The compressibility = 5.0 × 10⁻⁵

The formula for compressibility, C, is presented as follows;

[tex]C = \dfrac{1}{V} \times \dfrac{\partial V}{\partial P}[/tex]

The change in pressure, [tex]\partial P[/tex] = 12,000 m × 1.0 atm/(10 m) = 1,200 atm

For a unit volume, V = 1 m³

We get;

[tex]5 \times 10^{-5} = \dfrac{1}{1} \times \dfrac{\partial V}{1,200}[/tex]

[tex]\partial V[/tex] = 5 × 10⁻⁵ m³/(atm) × 1,200 = 0.06 m³

The volume occupied 1 m³ at 12,000 km depth = V - [tex]\partial V[/tex]

∴ The volume occupied 1 m³ at 12,000 km depth = 1 m³ - 0.06 m³ = 0.94 m³

The percentage density increase, [tex]\partial[/tex]ρ% = (m/0.94 - m/1)/m/1 × 100

∴ (1/0.94 - 1/1)/1/1 × 100 ≈ 6.4%

The percentage increase in density  ≈ 6.4%

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What is the minimum value of force acting between two charges placed at 1 m apart from each other?
(a)Ke²
(b)Ke
(c)Ke/4
(d)Ke² /2

Answers

Answer:

Ke²

Explanation:

So,

q1 = e

q2 = e

r = 1m

By coulumb's law,

F = K (q1q2/r²)

F = K (e)(e)/(1)²  

F = Ke²  

 

Option(a)

Many people believe that if the human race continues to use energy as we are now, without change, we'll witness a significant worldwide environmental impact in this century. Research this topic and discuss this possibility. Include concrete examples of specific environmental consequences of global warming.

Answers

Answer:

It is correct to say that if the human race continues to use energy as it is now, without change, we will witness negative environmental impacts around the world in this century.

As a concrete example, we can cite the means of transport that use fossil fuels, such as cars and buses, which release polluting gases into the atmospheric layer and cause the greenhouse effect, contributing to global warming.

To solve these problems, it is necessary to raise the awareness of individuals, so that there is more and more interest and search for environmentally responsible solutions, such as the large-scale production of electric cars, which do not pollute the environment.

Lúc 7g bạn an đi từ nhà đến trường với tóc độ trung bình là 20km/h . Bạn đến trường lúc 7g20. Tính khoảng cách từ nhà tới trường?

Answers

Answer:

Distance = 6.667 kilometres

Explanation:

Given the following data;

Speed = 20 km/h

Departure time = 7:00

Arrival time = 7:20

Time taken = 20 minutes

To calculate the distance travelled from home to school;

First of all, we would have to convert the value of time in minutes to hours.

Conversion:

60 minutes = 1 hour

20 minutes = X hours

Cross-multiplying, we have;

X = 20/60 = 1/3 hours

Mathematically, the distance travelled by an object is calculated by using the formula;

Distance = speed * time

Distance = 20 * 1/3

Distance = 20/3 =

Distance = 6.667 kilometres

I let go of a piece of bread from a balcony. A bird flying 5.0 m overhead sees me drop it, and starts to dive straight down towards the bread the instant that I release it. She catches it after it falls 3.0 m. Assuming she accelerates constantly from rest (v0 = 0) at the time I let go of the bread, what is her acceleration? Show your work

Answers

This question can be solved using the equations of motion. There are two scenarios where the equations of motion can be used. The first scenario is the free-fall motion of the piece of bread. The second scenario is the uniformly accelerated motion of the bird.

The acceleration of the bird is  "a = 26.13 m/s²".

First, we will calculate the time taken by the bread to fall 3 m. Using the second equation of motion for this free-fall motion:

[tex]h = v_it + \frac{1}{2}gt^2[/tex]

where,

h = height fall = 3 m

vi = initial velocity = 0 m/s

g = acceleration due to gravity = 9.8 m/s²

t = time taken = ?

Therefore,

[tex]3\ m = (0\ m/s)t+\frac{1}{2}(9.8\ m/s^2)t^2\\t = \sqrt{\frac{(3\ m)(2)}{9.8\ m/s^2}}\\\\t = 0.78\ s[/tex]

The bird took the same time to catch the bread. Now applying the second equation of motion to the bird's motion:

[tex]s = v_it + \frac{1}{2}at^2[/tex]

where,

s = distance covered by the bird = 5 m + 3 m = 8 m

vi = initial velocity of the bird = 0 m/s

a = acceleration of the bird = ?

t = time taken = 0.78 s

Therefore, using these values we get:

[tex]8\ m = (0\ m/s)(0.78\ s)+\frac{1}{2}a(0.78\ s)^2\\\\a = \frac{16\ m}{(0.78\ s)^2}[/tex]

a = 26.13 m/s²

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10. Match the following varibles to their relationship in Newton's 2nd Law. Questions 1. Force and Acceleration 2. Mass and Acceleration 3. Speed and Distance Answer Choices A. Direct Relationship B. Inverse Relationship C. Not in Newton's 2nd Law​

Answers

Explanation:

based on the above information

1.A

2.B

3. C

A comet of mass 2 × 10^8 kg is pulled toward the star. If the comet's initial velocity is very small, and the comet starts moving toward the star from 700,000,000 km away, how fast is it going right before it hits the surface of the star? (Assume that it does not lose any mass by melting as it approaches the star.)

Answers

Answer:

The speed of the comet at the surface of the star is approximately 1,208,694.7 m/s

Explanation:

Question parameter obtained online; The mass of the star, M = 5 × 10³¹ kg

Explanation;

The given mass of the comet, m = 2 × 10⁸ kg

The initial velocity of the comet, v → 0

The distance of the comet from the star, d = 700,000,000 km

The gravitational potential at d = G·M·m/d

The kinetic energy of the comet, K.E. = m·v²/2

The kinetic energy of the comet at d = m·(0)²/2 = 0

The gravitational potential at the surface of the star, R = G·M·m/R

The kinetic energy of the comet at the surface of the star, R = m·(v)²/2 = 0

Where;

M = The mass of the star = 5 × 10³¹ kg

[tex]M_{Sun}[/tex] = The mass of the Sun = 1.989 × 10³⁰ kg

M/[tex]M_{Sun}[/tex] = 5 × 10³¹/(1.989 × 10³⁰) ≈ 25

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

R = The radius of the star

Therefore, we have;

m·(0)²/2 - G·M·m/d = m·v²/2 - G·M·m/R

∴ v = √((G·M·m/R - G·M·m/d)×2/m) = √(2·G·M(1/R - 1/d))

Therefore; v = (2 × 6.67430 × 10⁻¹¹ × 5 × 10³¹ × (1/R - 1/700,000,000,000))

v = 81696389149.1×√(1/R - 1/700,000,000,000).

The speed of the comet at the surface of the star, v = 81696389149.1×√(1/R - 1/700,000,000,000)

The mass radius relationship is given as follows;

[tex]\dfrac{R}{R_{Sun}} = 1.30 \times \left(\dfrac{M}{M_{Sun}} \right)^{\dfrac{1}{2} }[/tex]

[tex]R = R_{Sun} \times 1.30 \times \left(\dfrac{M}{M_{Sun}} \right)^{\dfrac{1}{2} }[/tex]

The radius of the Sun = 696,340,000 M

∴ R ≈ 696,340,000 × 1.3 × √(25.14) = 4538865694.76

R = 4538865694.76 m

v = 81696389149.1×√(1/4538865694.76 - 1/700,000,000,000) ≈ 1208694.7  m/s

sort out electric current as fundamental or derived unit.​

Answers

Answer:

electric current is derived unit.

Explanation:

According to the definition of electric current, it appears to be a derived quantity. Charge on the other hand seems more fundamental than electric current.

The answer is electric current

Because it shows that the unit and it sorted out the electric

Bonds Quick Check
Metallic bonds are responsible for many properties of metals, such as conductivity. Why is this possible? (1 point)
A Metals have low electronegativity, so they are conductive because they pass charges easily.

Two metals bonded together are going to be more conductive than a metal bonded with a
nonmetal
C An attraction between a positive charge and a negative charge is created.
The bonds can shift because valence electrons are held loosely and move freely.

Answers

Answer: The bonds can shift because valence electrons are held loosely and move freely.

Explanation:

Other Questions
from chapter 5 of Animal Farm. Which figure from Russian history does Napoleon most likely represent? ealer explained privately to the other leon had never in reality been opposed in the contrary, it was he who had beginning, and the plan which vn on the floor of the incubator shed stolen from among Napoleon's nill was, in fact, Napoleon's own n, asked somebody, had he spoken so 2 Here Squealer looked very sly. That, rade Napoleon's cunning. He had e the windmill, simply as a maneuver Dall, who was a dangerous character e. Now that Snowball was out of the d go forward without his interference. er, was something called tactics. He er of times, "Tactics, comrades, Cound and whiskina his tail with a O Lenin, who led the rebellion against the tsar in the name of communism O Marx, who outlined a new social philosophy in the Communist Manifesto O Stalin, who built a dictatorship under the guise of communism O Trotsky, who was ultimately banished from the Communist Party What is the purpose behind a saying like "Black is beautiful"?O A. To discourage diversityO B. To combat internalized racismC. To suggest feelings of defensivenessD. To promote feelings of racial superiority Choose the appropriate word or phrase from the drop down menu to complete the sentences: The mean of the quantitative variable of interest in the population is called the [ Select ] . The mean of the quantitative variable of interest in the sample is called the [ Select ] . The standard deviation of the quantitative variable of interest in the population is called the [ Select ] . The standard deviation of the quantitative variable of interest in the sample is called the [ Select ] . 3. Which choice below correctly identifies the weight of a fetus at each trimester of pregnancy?A. first trimester: 1 oz; second trimester: 1 lb; third trimester: 6.5-10 lbsB. first trimester: 1 oz; second trimester: 3 lbs; third trimester: 6.5-10 lbsC. first trimester: 1 g; second trimester: 1 oz; third trimester: 6.5-10 lbsD. first trimester: 1 lb; second trimester: 2 lbs; third trimester: 6.5-10 lbs Is 237405 divisible by 11 We the People of the United States, in order to form amore perfect Union, establish Justice, insure domesticTranquility, provide for the common defence, promote thegeneral Welfare, and secure the Blessings of Liberty toourselves and our Posterity, do ordain and establish thisConstitution for the United States of America. 1Which idea is expressed in this excerpt from the Constitution?A. The government's power should be limited to protect individualrights.B. The government is divided into three branches,G. State governments should have as much power as the federalgovernment.OD. The government is responsible for protecting citizens.My explain what characterises a sound as noise or music Technical facilities for tourism in the Southeast region in Vietnam Joshua is a citizen of the United States. He practices the religion of Judaism freely. Which amendment to the Constitution gives Joshua this freedom? List the key events that ledup to the first battle of theAmerican Revolution atConcord and Lexington,Massachusetts in 1775. Solve the two step equations1. -3x - 4 = 232. x/2 - 12 = -43. 6a + ( -1) = 104. - ( x + 2 ) = 125. 7a + 12 = 106. -4 ( a + 2 ) = 12 Can the use of badger control (including culling) be justified in theprevention of the spread of bovine tuberculosis ( Hi can anyone help check my work English is not my first language. My teacher told me to use definition from sheet bellow. Pls help The number of periods/series in Mendeleev's Periodic table isA. 10B. 13C. 12D. 14 You have been asked to create a synthetic short position in a forward contract that permits you to sell 10 units of the underlying one year from now at a price of $50 per unit. (1) Describe the positions you need to take in call and put options to achieve the synthetic short forward position. (2) If the underlying is selling for $48 today (i.e. So = 48), what is the cost of your synthetic short position? What are common benefits of positive relationships with adults?Select all that apply.improved coping skillsfresh perspectivesO reduced work ethiclow self-efficacy Tamisha's shampoo bottle holds 1/2 bottle of shampoo.She used 5/6 of the bottle.How many gallons of shampoo has Tamisha used? Which value is 10,000 times larger than 1,300?Explain. A gym at a school is being painted. The four walls and the ceiling are to be painted (but not the floor). The gym measures 100 ft x 65 ft x 25 ft. A 5 gallon can of paint costs $151.99 and covers 1750 ft. How many cans should be purchased? What will it cost to paint two coats for this gym (include HST)? Pls help! Answer the question