. State the length of the missing side. Note: This quadrilateral is a parallelogram.

. State The Length Of The Missing Side. Note: This Quadrilateral Is A Parallelogram.

Answers

Answer 1

7.7

Step-by-step explanation:

In a parallelogram opposite sides are congruent.

Answer 2

The length of the missing side TQ in the parallelogram is 7.7.

Here, we have, from given figure that, SRQT is a parallelogram.

now, we have,

To find the length of the missing side TQ in the parallelogram,

we can use the properties of a parallelogram.

In a parallelogram, opposite sides are equal in length.

Therefore, we can determine the length of TQ by finding the length of its opposite side, SR.

Given that SR = 7.7,

we know that TQ must also have a length of 7.7.

So, we get,

the length of the missing side TQ in the parallelogram is 7.7.

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Related Questions

maths class 9
Multiply: 4√12 2√12

Answers

Answer:

[tex]4 \sqrt{122} \sqrt{12} \\ (4 \times 2) \times ( \sqrt{12} \times \sqrt{12} ) \\ (4 \times 2) \times 12 \\ 8 \times 12 \\ 96[/tex]

The answer:
48 the sign thing 16
Decimal form would be
117.57550765

Which of the following best describes the slope of the line below?
A. Zero
B. Negative
C. Positive
< PREVIOUS

Answers

Answer:

A. Zero.

Step-by-step explanation:

Technically, the correct answer is "undefined", as there will be infinite change in the slope amount. However, of all the given choices, Zero should be the best answer. However, if it is wrong, do ask your teacher, and state that undefined should be the answer choice, and that credit should be rewarded for such.

Pls help ———————————-

Answers

Answer:

Area of square 1 = 84

Step-by-step explanation:

a^2 + b^2 = c^2

√48^2 + 6^2 = c^2

48 + 36 = 84

area of square 1 = 84
The side of square 1 is 36/4 = 9 so the area = 9x9 = 81
The side of square 2 is 48/4 = 12 so the area = 12x22 = 144
Using Pythagoras the area of square 3 = 144 + 81 = 225 sq.units

You are not asked for the side of square 3 but it is 15 units

hlpppppppppppppppppppppppppppppppp

Answers

Answer:

c

Step-by-step explanation:

-7.5 is less than 6.5

Chris drives 240 miles from his home in Atlanta, Georgia, at 60 miles per hour. How many minutes longer would the return trip take if he travels at 50 miles per hour

Answers

Answer:

48 minutes

240 at 60mph = 4 hrs.

240 at 50 mph = 4.8 hrs.

it would take an extra 60*.8 or 48 minutes

Step-by-step explanation:

The trip will be of 48 minutes longer when the speed is decreased by 10 miles per hour.

What is the formula for time?

The time is given by distance/speed. The unit of time is minutes or seconds.

What will be the time difference?

When distance of 240 miles is cover by the speed of 60 miles per hour then the time take to travel this distance will be 240/60=4 hours

When distance of 240 miles is cover by the speed of 50 miles per hour then the time take to travel this distance will be 240/50=4.8 hours

The difference between 4.8 hours and 4 hours is of 0.8 hours or 0.8*60=48 minutes.

Therefore, the trip will be of 48 minutes longer.

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2t(t-1)-t+1 factorise​

Answers

Answer:

this is the answer of this question

hoping it will help u

Help me quick i need helppp

Answers

[tex]\\ \sf\longmapsto (m-8)+(m-8)+(m-8)+(m-8)+(m-8)+(m-8)=12[/tex]

[tex]\\ \sf\longmapsto 6(m-8)=12[/tex]

[tex]\\ \sf\longmapsto 6m-48=12[/tex]

[tex]\\ \sf\longmapsto 6m=12+48[/tex]

[tex]\\ \sf\longmapsto 6m=60[/tex]

[tex]\\ \sf\longmapsto m=\dfrac{60}{6}[/tex]

[tex]\\ \sf\longmapsto m=10[/tex]

Answer:

M=14

Step-by-step explanation:

First make an equation - m÷6 =8Then shift 6 to 8 - m=6×8Answer - m=14

find the slope of the tangent line of the curve r = cos (3theta) at theta = pi / 3

Answers

The slope of the tangent line to the curve at a point (x, y) is dy/dx. By the chain rule, this is equivalent to

dy/dθ × dθ/dx = (dy/dθ) / (dx/dθ)

where y = r(θ) sin(θ) and x = r(θ) cos(θ). Then

dy/dθ = dr/dθ sin(θ) + r(θ) cos(θ)

dx/dθ = dr/dθ cos(θ) - r(θ) sin(θ)

Given r(θ) = cos(3θ), we have

dr/dθ = -3 sin(3θ)

and so

dy/dx = (-3 sin(3θ) sin(θ) + cos(3θ) cos(θ)) / (-3 sin(3θ) cos(θ) - cos(3θ) sin(θ))

When θ = π/3, we end up with a slope of

dy/dx = (-3 sin(π) sin(π/3) + cos(π) cos(π/3)) / (-3 sin(π) cos(π/3) - cos(π) sin(π/3))

dy/dx = -cos(π/3) / sin(π/3)

dy/dx = -cot(π/3) = -1/√3

Condition for increasing decreasing and concavity of function

Answers

Answer:

If the concavity of f changes at a point (c,f(c)), then f′ is changing from increasing to decreasing (or, decreasing to increasing) at x=c. That means that the sign of f″ is changing from positive to negative (or, negative to positive) at x=c. This leads to the following theorem

Step-by-step explanation:

The previous section showed how the first derivative of a function,  f′ , can relay important information about  f . We now apply the same technique to  f′  itself, and learn what this tells us about  f . The key to studying  f′  is to consider its derivative, namely  f′′ , which is the second derivative of  f . When  f′′>0 ,  f′  is increasing. When  f′′<0 ,  f′  is decreasing.  f′  has relative maxima and minima where  f′′=0  or is undefined. This section explores how knowing information about  f′′

Let  f  be differentiable on an interval  I . The graph of  f  is concave up on  I  if  f′  is increasing. The graph of  f  is concave down on  I  if  f′  is decreasing. If  f′  is constant then the graph of  f  is said to have no concavity.

Note: We often state that " f  is concave up" instead of "the graph of  f  is concave up" for simplicity.

The graph of a function  f  is concave up when  f′  is increasing. That means as one looks at a concave up graph from left to right, the slopes of the tangent lines will be increasing. Consider Figure  3.4.1 , where a concave up graph is shown along with some tangent lines. Notice how the tangent line on the left is steep, downward, corresponding to a small value of  f′ . On the right, the tangent line is steep, upward, corresponding to a large value of  f′ .

Alex wants to test the reliability of “lie detector tests,” or polygraph tests. He performs a polygraph test on a random sample of 12 individuals. If there is more than a 50% chance that the tests result in no false positives (that is, the test does not result in a true statement being recorded as a lie), Alex will conclude that the tests are reliable. If the probability of a lie detector test resulting in a false positive is 5.5%, what will Alex conclude? Use Excel to find the probability, rounding to three decimal places.

Answers

The correct statement is test is reliable and authentic as the probability of no false positives is more than 0.5

Given that

[tex]H_o:P= 0.50\\\\H_1:P>0.50[/tex]

Now following calculations to be done to reach the conclusion:

There is no false positive as

= 100 - 5.5

= 94.5%

[tex]\hat P =0.945, n = 12[/tex]

Now

[tex]z = \frac{\hat P - P}{\sqrt\frac{P(1-P)}{n} }\\\\=\frac{0.945-0.5}{\sqrt\frac{0.5\times0.5}{12} } \\\\= 3.08[/tex]

So

P value = P(z >3.08) = 0.0010

Therefore we can conclude that test is reliable and authentic as the probability of no false positives is more than 0.5

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Tell whether the number pair (2,1) is a solution to the equation y = 3x - 5.

Answers

Answer:

Yes

Step-by-step explanation:

Plugging in the values in the equation, we have

1=3*(2)-5, 1=1 which is TRUE

Determine the period

Answers

Answer:

16 units

Step-by-step explanation:

period = length of an interval that contains exactly one copy of the repeating pattern, so from one peak to another peak.

in this graph its the peaks are 1 and 17, hence the period is 16

answer please lol so uh yeah

Answers

The answer would be option A. If you substitute x for 4 that would be 5(4) which equals 20! you’re welcome

Answer:

5x=20

5x/5=20/5

x=4

Step-by-step explanation:

substitute the 5x

divide both sides by 5 it will be 20 divide by 5

answer is x =4

There were 642 students enrolled in a freshman-level chemistry class. By the end of the semester, the number of students who passed was 5 times the number of students who failed. Find the number of students who passed and the number who failed.

Answers

Answer:

535 students passed and 107 students failed

Step-by-step explanation:

Create a system of equations where p is the number of students who passed and f is the number of students who failed:

p + f = 642

p = 5f

Solve by substitution by plugging in 5f as p into the first equation, then solving for f:

p + f = 642

5f + f = 642

6f = 642

f = 107

So, 107 students failed.

Find how many students passed by multiplying this by 5:

107(5)

= 535

535 students passed and 107 students failed.

Deion is saving up to buy a new phone. He already has $95 and can save an additional $7 per week using money from his after school job. How much total money would Deion have after 6 weeks of saving? Also, write an expression that represents the amount of money Deion would have saved in w weeks.

Answers

answer to part one of the question:
$95 + 7 x 6= 137

The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137.

What is an expression?

A statement expressing the equality of two mathematical expressions is known as an equation.

A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.

An expression is a mathematical proof of the equality of two mathematical expressions.

As per the given,

Initial fixed money = $95

Per week saving $7/week

Total money = fixed money + money in w weeks.

⇒ 95 + 7w

For 6 weeks, w = 6

⇒ 95 + 7× 6 = $137.

Hence "The expression that represents the amount of money Deion would have saved in w weeks is 95 + 7w and the total savings after 6 weeks will be $137".

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With the aid of an illustrative example, discuss the relationship between the area of a region and the definite integral. *​

Answers

Suppose there is a function f(x), the definite integral of the function is the difference between the upper and lower x-values.

There are three relationships between the definite integral and the area of the region. The relationships are:

Positive functionNegative functionRegion between two functions

Positive function

The area between the function itself and the x-axis represents the definite integral.

Negative function

The area between the function itself and the x-axis, multiplied by -1 represents the definite integral.

Region between two functions

The definite integral of the function is the difference between the region of both functions.

See attachment for further illustration

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Please help solve for x

Answers

Answer:

8.49

Step-by-step explanation:

there is a little formula related to the famous formula of Pythagoras.

it says that the height of a triangle is the square root of the product of both segments of the baseline (the segments the height splits the baseline into).

so, x is actuality the height of the triangle.

x = sqrt(3×24) = sqrt(72) = 8.49

pls help me asap !!!!

Answers

Answer:

9--7

Step-by-step explanation:

Answer:

distance = √74

Step-by-step explanation:

d = √((x2 - x1)²+(y2 - y1)²)

Where the first point = (x1, y1) and the second point = (x2, y2)

First point: (2, -2)

Second point: (7, -9)

Step 1. Plug these points into the formula

d = √((7 - 2)² + (-9 - -2)²)

Step 2. Subtract

d=√(( 5 )² + ( -7 )²)

Step 3. Simplify the exponents

d=√(25) + (49)

Step 4. Add

d=√74


√3 is a polynomial of degree ________.

Answers

Step-by-step explanation:

Therefore, the degree of polynomial √3 is zero.

[tex]\sf\huge\underline\color{pink}{༄Answer:}[/tex]

[tex]\tt{\sqrt{3}}[/tex] is a polynomial of degree 0

[tex]\sf\huge\underline\color{pinl}{༄Note:}[/tex]

The expression is constant, which means it can be rewritten with a factor of x^0. The degree is the largest exponent on the variable.

[tex]\color{pink}{==========================}[/tex]

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-Park Hana Moon

Find the values of the missing sides. You must use exact answers! PLEASE HURRY AND HELP

Answers

Answer:

x=4sqrt3 a=4 b=3  ,y=8sqrt3 c=8 d=3

Step-by-step explanation:

because this is a 30-60-90 triangle, it is easy to find the side lengths. the longer leg is sqrt(3) times the shorter leg so x= 12/sqrt(3) or 4sqrt(3). the hypotenuse is 2 times the shorter leg so y= 8sqrt(3)

Given the a center (-1, -2) and a radius r = 2. Identify the circle.

Answers

Answer:

1st option

1st graph has the centre on (-1,-2) and the distance of the circumference from the centre is 2

Answered by GAUTHMATH

Someone help please

Answers

Answer:  Choice A

[tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex]

============================================================

Explanation:

Recall that [tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex] and [tex]\cot(x) = \frac{\cos(x)}{\sin(x)}[/tex]. The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

[tex]\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is identical to [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]

Therefore, [tex]\tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is the same as [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

PLEASE HELP, solve for X

Answers

Answer:

27

Step-by-step explanation:

(whole secant) x (external part) = (tangent)^2

(48+x) * 48 = 60^2

(48+x)48=3600

Divide each side by 48

48+x =75

Subtract 48

48+x-48 = 75-48

x =27

Geometry I need help someone help me

Answers

Answer:

fohohcoufohohcouvhop

Step-by-step explanation:

typing mistake sorry

[tex]\\ \sf\longmapsto x+73=90[/tex]

[tex]\\ \sf\longmapsto x=90-73[/tex]

[tex]\\ \sf\longmapsto x=17[/tex]

Why?

Sum of two complementary angles is 90°

What is the shaded area of the figure?

Answers

Answer:

Step-by-step explanation:

The idea here is to find the area of the circle and then subtract from it the area of the triangle. That will give you the area of what's left in the circle (the shaded part). The area of a circle is:

[tex]A_c=\pi r^2[/tex] so

[tex]A_c=(3.14)(12.4)^2[/tex]   where 12.4 is the radius.

[tex]A_c=482.81[/tex] rounded to the nearest tenth. I used 3.14 for pi.

Now for the area of the triangle. The formula is

[tex]A_t=\frac{1}{2}bh[/tex] where h is the height of 12.4 and the base is the diameter which is 12.4 * 2 = 24.8

[tex]A_t=\frac{1}{2}(24.8)(12.4)[/tex] so

[tex]A_t=153.76[/tex]

Now subtract the triangle's area from the circle's area:

482.81 - 153.76 = 329.05 mm²

Factorize :solve no g and h ​

Answers

Answer:

Hello,

do you mean factorise but not solve ?

Just one formula:

[tex]\boxed{a^2-b^2=(a-b)(a+b)}[/tex]

Step-by-step explanation:

[tex]g)\\\\16x^3y-81xy^5\\\\=xy(16x^2-81y^4)\\\\=xy(4x^2+9y^2)(4x^2-9y^2)\\\\=xy(2x-3y)(2x+3)(4x^2+9y^2)\\\\\\\\h)\\\\x^8-y^8\\\\=(x^4+y^4)(x^4-y^4)\\\\=(x^4+y^4)(x^2+y^2)(x^2-y^2)\\\\=(x-y)(x+y)(x^2+y^2)(x^4+y^4)\\[/tex]

Answer:

here only one formula to use in both question

a^2+b^2= (a+b)(a-b)

Will Mark Brainnlest Please help me​

Answers

Answer:

l = 2, m = - 1, n = - 6

Step-by-step explanation:

A scalar matrix has its diagonal elements equal and all other elements zero, so

2l - 4 = 0 ( add 4 to both sides )

2l = 4 ( divide both sides by 2 )

l = 2

---------------------------------------

3l + n = 0

3(2) + n = 0

6 + n = 0 ( subtract 6 from both sides )

n = - 6

--------------------------------------

3m - n = 3

3m - (- 6) = 3

3m + 6 = 3 ( subtract 6 from both sides )

3m = - 3 ( divide both sides by m )

m = - 1

Which equation is equivalent to x^2 +24-8=0?

A.(x+12)^2 =152
B.(x-12)^2=136
C.(x+8)^2=144
D.(x+12)^2 =144

Answers

Answer:

D) is your correct answer

16. What is the measure of ZAOB?

Answers

Find angle a2 which is 40 degrees because it is parallel to angle c.

Find the total of d1 and d2.
total of d1 and d2: 180 - 40 - 40 = 100 degrees

Find d1 and d2 separately.
100 divided by 2 = 50 degrees

Use d1 to find b1 to find total of a1 and a2.

b1 is parallel to d1 so b1 = 50 degrees

a1 and a2 = 180 - 50 - 50 = 80 degrees

a1 = 80 divided by 2 = 40

Since a1 and c1 are parallel due to alternate angles, c1 is 40 degrees

Find b2 now which requires you to do total - minus all angles in the triangle with angle b2.

180 - 40 - 50 - 40 = 50 degrees (angle b2)

AOB has b1 and a1.

40 + 50 = 90 degrees (a1 + b1 = AOB)

The answer is 90 degrees

Calculus!

The volume of a substance, A, measured in cubic centimeters increases according to the exponential growth model dA/dt = 0.3A, where t is measured in hours. The volume of another substance, B, also measured in cubic centimeters increases at a constant rate of 1 cm^3 per hour according to the linear model dB/dt = 1. At t = 0, substance A has a volume A(0) = 3 and substance B has size B(0) = 5. At what time will both substances have the same volume?

Would it be correct to write the growth model of substance B as x + 5? And how could I write the growth model of substance A? Thank you in advance, and sorry for the poor formatting.

Answers

Answer:

The two substances will have the same volume after approximately 3.453 hours.

Step-by-step explanation:

The volume of substance A (measured in cubic centimeters) increases at a rate represented by the equation:

[tex]\displaystyle \frac{dA}{dt} = 0.3 A[/tex]

Where t is measured in hours.

And substance B is represented by the equation:

[tex]\displaystyle \frac{dB}{dt} = 1[/tex]

We are also given that at t = 0, A(0) = 3 and B(0) = 5.

And we want to find the time(s) t for which both A and B will have the same volume.  

You are correct in that B(t) is indeed t + 5. The trick here is to multiply both sides by dt. This yields:

[tex]\displaystyle dB = 1 dt[/tex]

Now, we can take the integral of both sides:

[tex]\displaystyle \int 1 \, dB = \int 1 \, dt[/tex]

Integrate. Remember the constant of integration!

[tex]\displaystyle B(t) = t + C[/tex]

Since B(0) = 5:

[tex]\displaystyle B(0) = 5 = (0) + C \Rightarrow C = 5[/tex]

Hence:

[tex]B(t) = t + 5[/tex]

We can apply the same method to substance A. This yields:

[tex]\displaystyle dA = 0.3A \, dt[/tex]

We will have to divide both sides by A:

[tex]\displaystyle \frac{1}{A}\, dA = 0.3\, dt[/tex]

Now, we can take the integral of both sides:

[tex]\displaystyle \int \frac{1}{A} \, dA = \int 0.3\, dt[/tex]

Integrate:

[tex]\displaystyle \ln|A| = 0.3 t + C[/tex]

Raise both sides to e:

[tex]\displaystyle e^{\ln |A|} = e^{0.3t + C}[/tex]

Simplify:

[tex]\displaystyle |A| = e^{0.3t} \cdot e^C = Ce^{0.3t}[/tex]

Note that since C is an arbitrary constant, e raised to C will also be an arbitrary constant.

By definition:

[tex]\displaystyle A(t) = \pm C e^{0.3t} = Ce^{0.3t}[/tex]

Since A(0) = 3:

[tex]\displaystyle A(0) = 3 = Ce^{0.3(0)} \Rightarrow C = 3[/tex]

Therefore, the growth model of substance A is:

[tex]A(t) = 3e^{0.3t}[/tex]

To find the time(s) for which both substances will have the same volume, we can set the two functions equal to each other:

[tex]\displaystyle A(t) = B(t)[/tex]

Substitute:

[tex]\displaystyle 3e^{0.3t} = t + 5[/tex]

Using a graphing calculator, we can see that the intersect twice: at t ≈ -4.131 and again at t ≈ 3.453.

Since time cannot be negative, we can ignore the first solution.

In conclusion, the two substances will have the same volume after approximately 3.453 hours.

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