Solve: 3x - 1 = 8(x + 1) + 1
O A. x= -
3
5
O B. x= -2
O C. x = -
CT 00
O D. There are infinitely many solutions.

Answer:

2x+16

Step-by-step explanation:

PEMDAS

Answer: hello from the question the volume of tank = 6000 gallons while the value in the Torricelli's equation = 5000 hence I resolved your question using the Torricelli's law equation

answer:

1) a) -180  gallons/minute ,

  b)  -160 gallons/minute

  c)  -120 gallons/minute

  d) 0

2) The water is flowing out fastest when t = 5 min

3) The water is flowing out slowest after t = 20 mins

Step-by-step explanation:

Volume of tank = 5000 gallons

Time to drain = 50 minutes

Volume of water remaining after t minutes by Torricelli's law

V = 5000 ( 1 - [tex]\frac{1}{50}t[/tex] )^2 ----- ( 1 )

1) Determine the rate at which water is draining from the tank

First step : differentiate equation 1 using the chain rule to determine the rate at which water is draining from the tank

V' = [tex]-10000[ ( 1 - \frac{1}{50}t ) (\frac{1}{50}) ][/tex]

a) After t = 5minutes

V' = - 10000[ ( 1 - 0.1 ) * ( 0.02 ) ]

   = -180  gallons/minute

b) After t = 10 minutes

V' = - 10000[ ( 1 - 0.2 ) * ( 0.02 ) ]

   = - 160 gallons/minute

c) After t = 20 minutes

V' = - 10000 [ ( 1 - 0.4 ) * ( 0.02 ) ]

   = -120 gallons/minute

d) After t = 50 minutes

V' = - 10000 [ ( 1 - 1 ) * ( 0.02 ) ]

   = 0 gallons/minute

2) The water is flowing out fastest when t = 5 min

3) The water is flowing out slowest after t = 20 mins  because no water flows out after 50 minutes

Without knowing what Juan's exact steps were, it's hard to say what he did wrong. The least you could say is that his solution is simply not correct.

4 sin²(θ) - 1 = 0

==>   sin²(θ) = 1/4

==>   sin(θ) = ±1/√2

==>   θ = π/4, 3π/4, 5π/4, 7π/4

Answer:

the correct answer is B) 10 + 10 + x = 50

[tex]3x=x+10[/tex]

We tripple something and get 10 more than something.

Put the x-es on the left and non x-es to the right,

[tex]2x=10[/tex]

Divide both sides by 2,

[tex]x=5[/tex]

Et Viòla.

Hope this helps :)

When a number is tripled, its value increases by 10 then the original number is 5.

Let's call the original number "x". According to the problem, when this number is tripled, its value increases by 10. Mathematically, we can represent this as an equation:

3x = x + 10

Now, we can solve for "x" step by step:

1. Subtract "x" from both sides of the equation:

  3x - x = 10

2. Simplify the left side:

  2x = 10

3. Divide both sides by 2 to solve for "x":

  x = 10 / 2

  x = 5

So, the original number "x" is 5.

In other words, if you take a number, triple it (multiply by 3), and then increase the result by 10, you would end up with the value 5. This can be verified by checking:

3 * 5 = 15

15 + 10 = 25

The equation 3x = x + 10 represents the relationship between the original number and its tripled value with an increase of 10. Solving this equation helps us find the original value that satisfies the given condition.

To know more about Equation here

https://brainly.com/question/17387622

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Answer:

b

Step-by-step explanation:

sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{s\sqrt{3} }{2s}[/tex] ( cancel s on numerator/ denominator ), then

sinA = [tex]\frac{\sqrt{3} }{2}[/tex] → b

Answer:

56.5

I think this is right

Answer:

32

Step-by-step explanation:

3(8(3)-5(2))-2((3)+(2))

3(24-10) -2(5)

3(14) -10

42-10

32

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\textsf{3(8a - 5b) - 2(a + b)}\\\\\huge\textsf{= 3(8(3) - 5(2)) - 2(3 + 2)}\\\\\huge\textsf{= 3(24 - 10) - 2(3 + 2)}\\\\\huge\textsf{= (3)(14) - 2(3 + 2)}\\\\\huge\textsf{= 42 - 2(3 + 2)}\\\\\huge\textsf{= 42 - 2(5)}\\\\\huge\textsf{= 42 - 10}\\\\\huge\textsf{= 32}}[/tex]

[tex]\huge\boxed{\textsf{Answer: 32}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

2 elephants have short tusks.

Step-by-step explanation:

Long tusks: 4/5

Short tusks: 1/5

1/5 = x/10

x = 2

Answer:

Step-by-step explanation:

There are 3 zero's but we see the polynomial is of degree 4.

It means it has 2 same zero's. We can verify it is -2. Since -2 is doubled, it reflects the local minimum and it is on the x-axis.

In reality we need to consider the other two zero's.

It is obvious the negative interval is between -1/3 and 6 since the polynomial is of even degree and has positive leading coefficient.

Correct choice is c.

The graph is attached to confirm the theory.

Answer:

No

97/1000 is the same as 97 divided by 1000

the decimal would be .097, not .97

Answer:

diện tích đa giác trong hình là :

186 cm2

Step-by-step explanation:

hãy tách hình đa giác trên thành 4 hình chữ nhật và tính diện tích từng hình chữ nhật

Answer:

[tex]4x^2+4x+5[/tex]

Step-by-step explanation:

[tex]f(x)=5x^2-3\\g(x)=x^2-4x-8[/tex]

Set up an expression.

[tex]5x^2-3-(x^2-4x-8)[/tex]

Distribute the negative (-1)

[tex]5x^2-3-x^2+4x+8[/tex]

Solve / Simplify

[tex]4x^2+4x+5[/tex]

I'm late, but I hope this helps!

Answer:

17/25

Step-by-step explanation:

The equation for the probability of two events that are not mutually exclusive is:

p(A ∨ B) = p(A) + p(B) - p(A ∧ B)

A = the number is prime

B = the number is prime

The numbers are:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

Here are the 8 prime numbers that satisfy event A:

3, 5, 7, 11, 13, 17, 19, 23

p(A) = 8/25

Here are the 13 numbers that are greater than 12 that satisfy event B:

13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

p(B) = 13/25

Here are the 4 numbers that satisfy both event A and event B:

13, 17, 19, 23

p(A ∧ B) = 4/25

p(A ∨ B) = p(A) + p(B) - p(A ∧ B)

p(A ∨ B) = 8/25 + 13/25 - 4/25

p(A ∨ B) = 17/25

The probability that the number drawn is prime or greater than 12 = [tex]\frac{18}{25}[/tex]

"Probability is a branch of mathematics which deals with finding out the likelihood of the occurrence of an event."

P(A) = n(A)/n(S)

where,  n(A) is the number of favorable outcomes, n(S) is the total number of events in the sample space.

For given question,

In a lottery game, a single ball is drawn at random from a container that contains 25 identical balls numbered from 1 through 25.

n(S) = 25

Let event A: the number drawn is prime

The prime numbers from 1 to 25 are:

2, 3, 5, 7, 11, 13, 17, 19, 23

So, n(A) = 9

The  probability that the number drawn is prime,

[tex]P(A)=\frac{n(A)}{n(S)}\\\\ P(A)=\frac{9}{25}[/tex]

Let event B: the number drawn is greater than 12

So, n(B) = 13

The probability that the number drawn is greater than 12,

[tex]P(B)=\frac{n(B)}{n(S)}\\\\ P(B)=\frac{13}{25}[/tex]

The number drawn is prime as well as greater than 12.

Such numbers are : 13, 17, 19, 23

n(A ∩ B) = 4

So, the probability that the number drawn is prime as well as greater than 12,

[tex]P(A\cap B)=\frac{n(A\cap B)}{n(s)}\\\\ P(A\cap B)=\frac{4}{25}[/tex]

Using the equation P(AUB) = P(A) + P(B) - P(A ∩ B) to find the probability that the number drawn is prime or greater than 12,

[tex]\Rightarrow P(A\cup B)=P(A)+P(B)-P(A\cap B)\\\\\Rightarrow P(A\cup B)=\frac{9}{25}+ \frac{13}{25} -\frac{4}{25} \\\\\Rightarrow P(A\cup B)=\frac{9+13-4}{25}\\\\ \Rightarrow P(A\cup B)=\frac{18}{25}[/tex]

Therefore, the probability that the number drawn is prime or greater than 12 = [tex]\frac{18}{25}[/tex]

Learn more about probability here:

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Hi there!

[tex]\large\boxed{u + xy = 98}[/tex]

We can do substitution to solve.

We are given the values of all of the letters, so:

u = 18

x = 10

y = 8

Substitute:

(18) + (10)(8)

Use the order of operations:

18 + 80 = 98

Step-by-step explanation:

u + xy

make u = 18

x = 10

y = 8

18 + 10 × 8

18 + 80

= 98

I hope this answers your question

Answer:

$14.40

Step-by-step explanation:

my way of doing things:

15/100=0.15=1%of total amount

0.15 x 6=0.9= the 6% which is the tax

0.15 x 10 = 1.5=the coupon

Take the coupon amount $1.50 minus the tax amount $0.90 =$0.60. Because the coupon amount is greater than the tax the 60 cents gets taken away from the original 15 dollars leaving Mr. Longely only having to pay $14.40.

Answer:

Step-by-step explanation:

Consider principle =Rs.P, Time (T)=4 years

Consider principle =Rs.P, Time (T)=4 yearsRate =6

Consider principle =Rs.P, Time (T)=4 yearsRate =6 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P×

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200Therefore, Principle =Rs.3200

Answer:

9/4 = 2 1/4

Hope this Helps!?

Answer:

Hello,

I have reply too quick in comments (sorry)

Step-by-step explanation:

[tex]\left\{\begin{array}{ccc}log_x (27)+log_y (4)=5\\log_x (27)-log_y (4)=1\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}2*log_x (27)=6\\2*log_y (4)=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}log_x (27)=3\\log_y (4)=2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x^{log_x (27)}=x^3\\y^{log_y (4)}=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}27=x^3\\4=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x=3\\y=2\\\end{array}\right.\\\\[/tex]

Answer:

On the way out the train traveled at about 40 mph, while on the return it did so at 20 mph.

Step-by-step explanation:

Since an empty freight train traveled 60 miles from an auto assembly plant to an oil refinery, and there, its tank cars were filled with petroleum products, and it returned on the same route to the plant, and the total travel time for the train was 4.5 hours, if the train traveled 20 mph slower with the tank cars full, to determine how fast did the train travel in each direction the following calculation must be performed:

60/20 = 3

60/40 = 1.5

60/20 = 3

3 + 1.5 = 4.5

Therefore, on the way out the train traveled at about 40 mph, while on the return it did so at 20 mph.

Answer:

no

Step-by-step explanation:

Substitute the point into the equation and see if it is true

34 = 2(7) +8

34 = 14+8

34 = 22

Since this is not true, the point does not satisfy the equation

Answer:

No

Step-by-step explanation:

because 7 is X and 34 is Y

So its 2 *7 +8=22

so no

Answer:

4

Step-by-step explanation:

Factorizing we get the answer 4

Answer:

C

Step-by-step explanation:

3.8 is the answer

68.4÷18=3.8

Answer:

400

Step-by-step explanation:

First, the firm produces 100 sets its first year. This means that our equation starts at 100. Next, the total number of calculator sets in 5 years is 4500. With y₁ representing the amount of calculator sets produced during year 1, y₂ representing the amount of sets during year 2, and so on, we can say that

y₁+y₂+y₃+y₄+y₅ = 4500

100 + y₂+y₃+y₄+y₅ = 4500

Next, we are given that the production increases uniformly by an amount each year. Representing that amount as a, we can say that

y₁+a = y₂

y₂+a = y₃

y₁+a+a = y₃

y₁+ 2 * a = y₃

and so on, so we have

100 + y₂+y₃+y₄+y₅ = 4500

100 + (100+a) + (100+2a) + (100+3a) + (100+4a) = 4500

500 + 10a = 4500

subtract 500 from both sides to isolate the a and its coefficient

4000 = 10a

divide both sides by 15 to isolate a

a = 400

Answer:-

5

The highest degree included in the polynomial is known as degree of polynomial

[tex]\sf \checkmark[/tex] Polynomial with degree 1=monomial

[tex]\sf \checkmark[/tex] Polynomial with degree 2 =binomial

[tex]\sf \checkmark[/tex] Polynomial with degree 3=Trinomial

Answer:

..?.

Step-by-step explanation:

Answer:

[tex]\begin{array}{cc}{Status} & {Probability} & {1} & {0.0845} & {2} & {0.1127} & {3} & {0.1870} & {4} & {0.1927}& {5} & {0.4231} \ \end{array}[/tex]

Step-by-step explanation:

Given

The above table

Required

The discrete probability distribution

The probability of each is calculated as:

[tex]Pr = \frac{Frequency}{Total}[/tex]

Where:

[tex]Total = 2140+ 2853 + 4734 + 4880 + 10715[/tex]

[tex]Total = 25322[/tex]

So, we have:

[tex]P(1) = \frac{2140}{25322} = 0.0845[/tex]

[tex]P(2) = \frac{2853}{25322} = 0.1127[/tex]

[tex]P(3) = \frac{4734}{25322} = 0.1870[/tex]

[tex]P(4) = \frac{4880}{25322} = 0.1927[/tex]

[tex]P(5) = \frac{10715}{25322} = 0.4231[/tex]

So, the discrete probability distribution is:

[tex]\begin{array}{cc}{Status} & {Probability} & {1} & {0.0845} & {2} & {0.1127} & {3} & {0.1870} & {4} & {0.1927}& {5} & {0.4231} \ \end{array}[/tex]

Answer:

20 percent

Step-by-step explanation:

Each year is 10 percent so 10x2 or 10+10 will equal 20

Answer:

= 6 ways = Required number of ways = (120×6)=720