Sobre el plato menor de una prensa se coloca una masa de 16kg. Calcula qué masa se podría levantar colocada en el plato mayor, cuyo radio es el doble del radio del plato menor.

Answers

Answer 1

Answer:

Tenemos que el plato mayor de la prensa puede levantar una masa de 64 kg en relación con el plato menor.

Explicación:

Debemos aplicar principio de Pascal, tal que las presiones son iguales, por tal:

P₁ = P₂

Definimos en función del radio, tal que:

F₁/r₁² = F₂/r₂²

Sustituimos los datos y tenemos que:

(16 kg/r₁²) = F₂/(2r₁)²

F₂ = 64 kg

Por ende, tenemos que el plato mayor puede levantar una masa de 64 kg en relación con el plato menor

Explanation:

Answer 2

La máxima masa que podemos colocar en el plato mayor es de 64 kg.

¿Como aplicar el principio de pascal?

Este dice que las presiones en ambos extremos deben ser las mismas.

Recordando que presión se define como fuerza sobre area, podemos escribir:

P₁ = P₂

La presión en el primer plato está dada por:

P₁ = (16kgf)/(pi*r^2)

Donde r es el radio del plato menor, y 16kgf es el peso de la masa en kilogramos fuerza.

La presión en el plato mayor será:

P₂ = M/(pi*(2r)^2)

Pues el radio de este plato es 2r.

Entonces tenemos que la máxima fuerza que podemos aplicar en el plato mayor esta dada por:

(16kgf)/(pi*r^2) = M/(pi*(2r)^2)  = M/(4pi*r^2)

16 kgf = M/4

4*16kgf = M = 64kgf

Y un objeto que pesa 64kgf, tiene una masa de 64 kilogramos, la cual es la máxima masa que podremos colocar en el plato mayor.

Sí quieres aprender más sobre presión, puedes leer:

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Related Questions

1
2) Mighty Mouse can lift seven mammoths with a total mass of 525 kg. Using the acceleration of
gravity, find the total WEIGHT that Mighty Mouse is lifting. (answer: 5250 N)

Answers

Answer:

5250N

Explanation:

Weight= Mass × acceleration due to gravity

= 525kg × 10m/s^2

= 5250N

what is the approximate distance from the surface of the earth center 2900km 700km 50000km 6400km

Answers

Answer:

6400km is the closest

Explanation:

What is non examples of enlarged

Answers

reduction

deflation

these are examples of the opposite of enlarged to make something smaller is really the key thing here

A Scooter has a mass of 250 kg. A constant force is exerted on it for 6.0 s. During the time the force is exerted, the scooter increases its speed from 6.00 m/s to 280 m/s. What is the magnitude of the force exerted on the scooter

Answers

Answer:

917 N

Explanation:

917 N, this is your answer!!

Glad to help.

Option B.
Consider a setup in which two springs are attached to a mass in parallel.
Convince yourself that in this setup, the compression of each spring must be the same. Using
this fact, derive the effective spring constant for springs in parallel
This is asking, "ll1 replace the two springs by a single imaginary spring, what would its spring
constant be such that the force stays the same?" Your answer should only depend on k, and k

Answers

Answer:

it would be...

Explanation:

 what is the difference between repelling and attracting

Answers

Answer:

Attracting means pulling toward you and repelling means pushing away

Explanation:

Answer: Repelling is when something will not connect with another object. The force will cause a repel between the two objects. Attracting is when something is attracted or being pulled to another object.

Explanation: Hope this helps!

Why does air pressure decrease with increasing altitude? (Select all that apply.)
Colder air is less dense.
The weight of the air below is smaller.
Less air above pushes down.
Hot air rises.
The weight of the air above is smaller.
There is more air below to push up more strongly

Answers

The air pressure decrease with increasing altitude as less air above pushes down and the weight of the air above is smaller.

When the temperature cools, molecules often slow down and they do not move and bump into each other.

When altitude increases, the amount of gas molecules in the air also decrease.

The air becomes less dense than air nearer to sea level.

When the atmospheric pressure is high at lower altitudes, the density being higher.

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A girl of mass m1=60.0 kilograms springs from a trampoline with an initial upward velocity of vi=8.00 meters per second. At height h=2.00 meters above the trampoline, the girl grabs a box of mass m2=15.0 kilograms. (Figure 1)

For this problem, use g=9.80 meters per second per second for the magnitude of the acceleration due to gravity.

What is the speed vbefore of the girl immediately before she grabs the box?
Express your answer numerically in meters per second.

What is the speed vafter of the girl immediately after she grabs the box?
Express your answer numerically in meters per second.

What is the maximum height hmax that the girl (with box) reaches? Measure hmax with respect to the top of the trampoline.

Answers

The conservation of momentum and energy allows to shorten the results for the movement of the girl on the trampoline holding the box are:

     a) the girl's speed is v = 4.98 m / s

     b) The speed of the girl + box system is: v_f = 0.996 m / s

     c) the maximum height is: y = 2.05 m

 

Kinematics studies the movement of bodies, looking for relationships between the position, velocity and acceleration of bodies.

The momentum is defined by the product of mass and the velocity, when a system is isolated the momentum is conserved.

The mechanical energy is the sum of the kinetic energy plus the potential energies, when there is no friction in the system the mechanical energy is conserved.

Let's solve this exercise in parts:

a) Let's use kinematics to find the speed of the girl before she grabs the box

              v² = v₀² - 2 g y₁

              v² = 8² - 2 9.8 2.00

              v = R 24.8 = 4.98 m / s

b) Let's use momentum conservation for when the speed of the girl and the box together. Let's write the moment in two moments.

Initial instant. Just before you grab the box.

              p₀ = M v + 0

Final moment. Right after taking the box

             [tex]p_f[/tex]  = (m + M) [tex]v_f[/tex]

         

In system this form by the girl and the box therefore it is an isolated system and the momentum is conserved.

           [tex]p_o = p_f[/tex]  

           mv = (m + M) [tex]v_f[/tex]  

           [tex]v_f = \frac{m}{m+M} \ v[/tex]

Let's calculate

           [tex]v_f = \frac{15}{15+ 60} \ 4.98[/tex]  

           [tex]v_f[/tex]  = 0.996 m / s

c) Now we use conservation of energy after the girl has the box.

Starting point. When the girl has the box

           Em₀ = K + U

           Em₀ = ½ (m + M) v² + (m + M) g y₁

Final point. At the highest point of the trajectory

          [tex]Em_f[/tex]  = U

         [tex]Em_f[/tex] = (m + M) g y₁

As there is no friction, the energy is conserved.

           [tex]Em_o = Em_f[/tex]  

          ½ (m + M) v² + (m + M) g y₁ = (m + M) g y

          y = [tex]\frac{v^2}{2g} + y_1[/tex]  

Let's calculate

           y = [tex]\frac{0.996^2}{2 \ 9.8} + 2.0[/tex]

           y = 2.05 m

In conclusion using the conservation of momentum and energy we can shorten the results for the movement of the girl on the trampoline holding the box are:

     a) the girl's speed is v = 4.98 m / s

     b) The speed of the girl + box system is: v_f = 0.996 m / s

     c) the maximum height is: y = 2.05 m

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Answer:

Vbefore = 4.98 m/s

Vafter = 3.98 m/s

Hmax = 2.81 m

If you do 72 J of work in 1.2 seconds, how much power is produced

Answers

Answer:

Explanation:

Power is the rate of doing work

P = 72 / 1.2 = 60 Watts

12. A coconut falls out of a tree 12.0 m above the ground and hits a bystander 3.00 m tall on the top of the head. It bounces
back up 1.50 m before falling to the ground. If the mass of the coconut is 2.00 kg, calculate the potential energy of the
coconut relative to the ground at each of the following sites:
(a) while it is still in the tree,
(b) when it hits the bystandlar on the head,
(c) when it bounces up to its maximum height,
(d) when it lands on the ground,
(e) when it rolls into a groundhog hole, and falls 2.50 m to the bottom of the hole,

Answers

Explanation:

hhhhgyyytttfghjhnjhhhhhhbbbbbbbbh

Acceleration of a car that speeds from 4.3 m/s to 12.9 m/s in 2 seconds

Answers

Explanation:

let v1 = 4.3 m/s

v2 = 12.9 m/s

t = 2 seconds

v2 = v1 + at

12.9 = 4.3 + a×2

2a = 12.9 - 4.3 = 8.6

a = 8.6/2

a = 4.3 m/s^2

Write a question you would like to see on a quiz to calculate NET FORCE.

Answers

Answer:

How do you find the net force?

Explanation:

i think this is want you asked for?

Which force, in real life, will have the least effect on a bowling ball rolling down a lane toward bowling pins?

A) magnetism

B) air resistance

C) gravity

D) friction

Answers

Answer:

Its Friction

Explanation:

the pins are not floating and they are not a magnet and not involved with air

The force, in real life, that will have the least effect on a bowling ball rolling down a lane toward bowling pins is magnetism. The correct option is A.

What is magnetism?

Magnetism is basically the force which indeed magnets exert when they attract or even repel one another. The movement of electric charges resulting in magnetism.

Every substance is composed of tiny units referred to as atoms. Each atom contains electrons, which are charged particles.

To increase stability, the pins themselves have a low center of gravity. Because they are spherical in shape, they can roll and strike other pins in a variety of directions.

The force acting on the bowling ball is friction and air resistance. The friction force is equal to the friction coefficient multiplied by the normal force, and thus mass times acceleration.

Thus, the correct option is A.

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What on earth is equal to 9.8m/s/s

Answers

Answer:

Acceleration due to gravity

Alex is x years old . June is 7years older than Alex . their total combined ages is 29 years . find June,s age . show all work algebraically

Answers

Answer:

18 years

Explanation:

Given,

Let Alex be = x years

Then June will be = (7 + x) years

We know that,

Their total combined age is 29 years

Therefore,

By the problem,

=> x + (7 + x) = 29

=> 2x = 29 - 7

=> 2x = 22

=> x = 22 ÷ 2

=> x = 11

So,

Required age of June is = (7 + x) years

= (7 + 11) years

= 18 years (Ans)

1.25 is closer to 1.04 or not ?
plz heelp plz

Answers

Answer:

No, it is closer to 1.30

Explanation:

Compare and contrast isometric and isotonic exercises. Provide two examples of each.

Answers

Answer:

Isometric exercises are static and great for people who suffer from joint pain. Isometric exercises, like planks, don't require you to move or bend any joints. Isotonic exercises, like squats, involve straining the muscles while moving the joints and applying a constant amount of weight.

Explanation:

Answer:

Isometric exercises are static and great for people who suffer from joint pain. Isometric exercises, like planks, don't require you to move or bend any joints. Isotonic exercises, like squats, involve straining the muscles while moving the joints and applying a constant amount of weight.

Explanation:

Market researchers were interested in the relationship between the number of pieces in a brick-building set and the
cost of the set. Information was collected from a survey and was used to obtain the regression equation ý =
0.08x + 1.20, where x represents the number of pieces in a set and ŷ is the predicted price in dollars) of a set.
What is the predicted price of a set that has 500 pieces?
$40
$41.20
$600
$6,235

Answers

Plug in 500 for x and solve. 500(0.08) = 40

Then do 40 + 1.2 = 41.20

Answer B

Vesta is a minor planet (asteroid) that takes 3.63 years to orbit the Sun.
Calculate the average sun -Vesta distance

Answers

Using Kepler's third law, the average sun -Vesta distance is 2.36 AU.

According to Kepler's laws, the square of the period of revolution of planets are proportional to the cube of their average distances from the sun. Hence, we can write; [tex]T^{2} =r^{3}[/tex]

Where;

T = period of the planet

r = average distance of the planet

When;

T =  3.63 years

r = [tex]\sqrt[3]{T^2}[/tex]

r = [tex]\sqrt[3]{(3.63)^2}[/tex]

r = 2.36 AU

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Colette launches an air rocket in the upward, positive direction. It launches with an initial velocity of 25.5 m/s. It accelerates in the downward, negative direction at a rate of 9.81 m/s2. After 3.5 seconds, what is the magnitude of the rocket's displacement?

Answers

Answer:

Give me some hint please

60 POINT!!!!!!
PLEASE HELP THIS WORK IS VERY IMPORTANT FOR ME
IF YOU GIVE ME THE CORRECT ANSWER I WILL GIVE YOU THE CROWN!!
Miranda found four different bottles filled with unknown pure liquids. She measured the mass, volume, and boiling point of these liquids, and calculated the density which are displayed in Table 1.

What conclusion can you make on whether any of the liquids are the same. Explain based on the information in the table.

Answers

Answer:

Samples 2 and 4 are the same liquid

Explanation:

Samples 2 and 4 should be the same liquid because they have the same density as well as the same boiling point. The mass and volumes given do not matter in this case, however they could be used to calculate the density which was already given.

The liquid  present in sample 2 and 4 is same as according to forces of attraction they have same density and boiling points.

What are forces of attraction?

Forces of attraction is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different  states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases  as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

The physical properties such as melting point, boiling point, density  are all dependent on forces of attraction which exists in the substances.

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need some help plsss!

Answers

Answer:

1and4attract and1and 2repel

An object moves 45m due East and then 15m due West, the total distance is

Answers

Answer:30m east

Explanation: 45m-15m=30m, which cancels out the one to the west. All that is left is 30m east.

Is this a test/quiz btw?

For a horizontally projectile object if the initial velocity doubled, the Vertical displacement (angle y) will be :

Answers

Answer:

Unchanged

Explanation:

horizontal projection always has initial vertical velocity equal to zero.

gravity works pretty much the same at any point on earth and will accelerate any falling object at the same rate traveling the same vertical distance in the same time. Neglecting air resistance of course.

By the way, Δy is read "delta y" not "angle y" which would be "∠ y"

delta represents a change in something, in this case the y coordinate.

If the same change in velocity occurs in less time, does the magnitude of the corresponding average acceleration increase, decrease, or stay the
same? Explain

Answers

Answer:

increase

Explanation:

As acceleration is the time rate of change of velocity

a = Δv/t

with t in the denominator, smaller time values result in greater acceleration values with constant velocity change.

A 15 g bullet is fired at 630 m/s into a 4.9 kg block that sits at the edge of a 75-cm-high table. The bullet embeds itself in the block and carries it off the table.

How far from the point directly below the table's edge does the block land?

Answers

The horizontal distance traveled below the table's edge is 29.4 cm.

The given parameters;

mass of the bullet, = 15 g = 0.015 kgspeed of the bullet, = 630 m/smass of the block, = 4.9 kg

The final velocity of the bullet-block system is calculated as follows;

[tex]m_1 u_1 + m_2u_1 = v(m_1 + m_2)\\\\0.015(630) + 4.9(0) = v(0.015 + 4.9)\\\\9.45 = 4.915 v\\\\v = \frac{9.45}{4.915} \\\\v = 1.923 \ m/s[/tex]

The time for the bullet-block system to reach the ground from the table is calculated as follows;

[tex]h = v_0t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\2h = gt^2\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} } \\\\t = \sqrt{\frac{2\times 0.75}{9.8} }\\\\t = 0.153 \ s[/tex]

The horizontal distance traveled below the table's edge is calculated as follows;

[tex]X = vt\\\\X = 1.923 \times 0.153\\\\X = 0.294 \ m\\\\X = 29.4 \ cm[/tex]

Thus, the horizontal distance traveled below the table's edge is 29.4 cm.

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When heat is added to a solid how do its particles move

Answers

When heat is added to a solid, How do its particles move?

When a substance is heated, it releases energy, which causes the particles to become more active, vibrating, rotating, and even moving faster. If a substance has enough energy, it can overcome the bonding forces that hold the particles together and change state as a result.

A meter stick is attached to one end of a rigid rod with negligible mass of length l = 0.302 m. The other end of the light rod is suspended from a pivot point, as shown in the figure below. The entire system is pulled to a small angle and released from rest. It then begins to oscillate. A meter stick hung from a rod of length l. The rod is attached to the ceiling. The rod and meter stick extend downward in a straight line making a small angle with the vertical. (a) What is the period of oscillation of the system (in s)? (Round your answer to at least three decimal places.)

Answers

The period of oscillation of the system nearest to three decimal places

= 1.092 seconds

The period of an oscillation occurring in a system is the time taken to complete one cycle.

The formula that is used to calculate the period of oscillation (T) is

                = 2π√[tex]\frac{l}{g}[/tex]

But,

π = 3.14159 (constant)

g= 10m/s² (acceleration due to gravity)

l = 0.302 m

Therefore T = 2 × 3.14159 × √[tex]\frac{0.302}{10}[/tex]

                    = 6.28318 x √0.0302

                    = 6.28318 x 0.17378

                    = 1.09189s

                    = 1.092 seconds ( to the nearest three decimal places)

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50 Points Help Asap !!

Briefly describe V-T graph For every point please if its increasing if its flat or if its positive or negative help fast

Answers

#A

It's flat as no change can be seen on the graph of A part

#B

Its increasing as the line goes up in B part.

#C.

It's flat as no change can be seen on the graph of C part

#D

It's decreasing as the graph goes down in D part.

#E

It's decreasing as the graph goes down in E part

#F

It's decreasing as the graph goes down in F part.

#G

It's increasing as the graph goes up in G part.
G partt hope helpsss

Which scientist is credited with having the greatest contribution to early microscopy and was the first to observe and describe single-celled organisms?

Answers

Answer:

Antonie van Leeuwenhoek

Explanation:

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