Answers
Answer:
C. 5/4
Step-by-step explanation:
Slope formula is y=mx+b so your slope is m
In your equation y=5/4x-7/4, your slope is where m would be, so 5/4
Answer:
the slope of the equation is 5/4
Related Questions
2. A house costs $30,000. A buyer is given a 1/10 discount. How much money does the buyer save?
Answers
Answer:
3000
Step-by-step explanation:
Today everything at a store is on sale the store offers a 20
% discount the regualr price of a t shirt is 18 what is the discount price
Answers
Answer:
$14.40 is the discount price.
Step-by-step explanation:
0.2 x 18 = 3.6
18 - 3.6 = 14.4
Identify the vertex of the parabola represented by the equation y=−2x2+8x−1.
(−4, −65)
(4, −1)
(2, 7)
(−2, −25)
Answers
Answer:
it is correct but -65 is not correct
solve pls brainliest
Answers
Answer:
Yes, This is a repeating decimal
No, This is a decimal that neither terminates or repeats
No, This is a decimal that neither terminates or repeats
Yes, This is a terminating decimal
What have you learned about geometric relationships?
PLEASE HELP 15 POINTS
Answers
Answer:
that you can define a tangent relationship between a line and an arc. If the adjoining elements change, the tangent relationship is maintained between the elements. Geometric relationships control how a sketch changes when edits are made.
Step-by-step explanation:
i took this i guess and it was gud
Using the appropriate Algebraic identity evaluate the following:(4a - 5b)²
Answers
[tex](4a - 5b)^{2} \\ by \: \: \: using \: \: \: (x - y)^{2} = {x}^{2} - 2xy + {y}^{2} \\ = {(4a)}^{2} - 2(4a)(5b) + {(5b)}^{2} \\ = {16a}^{2} - 40ab + 25 {b}^{2} [/tex]
Answer:[tex] {16a}^{2} - 40ab + {25b}^{2} [/tex]
Hope it helps.
Do comment if you have any query.
How many 2 digit numbers have unit digit 6 but are not perfect squares
Answers
9514 1404 393
Answer:
7
Step-by-step explanation:
Of the 9 2-digit numbers ending in 6, only 2 are perfect squares: 16 and 36. The other 7 are not perfect squares.
make a conjecture (prediction) about the table. what will happen if we continue the table, going down?
Answers
(20pts) I need to know who is incorect and why
Answers
Answer:
i thig it is hj
Step-by-step explanation:
jk
You plan on joining a gym. The joining fee is $30 and you must pay $12 a month fee. If you have $100, how many months can you use the gym? Write and solve an inequality to represent the solution.
I need the process for this otherwise I won't get credit for it!!
Answers
Answer:
Inequality: 30+12x < 100
x ≈ 5 months
Step-by-step explanation:
To solve, first create the inequality. In this problem, 30 dollars is the flat fee for joining the gym and thus a constant. Additionally, 12 is the monthly payment and thus the coefficient for a variable because it changes with the number of months. Finally, 100 is the most that can be spent (the max), so it should be on the other side of the inequality and the sign should be less than or equal to 100.
This makes the inequality: 30+12x < 100
To find the number of months solve the inequality for x.
30+12x<10012x<70x<5.8So, the inequality equals x<5.8. However, the question asks for the number of full months. And, no more than 100 dollars can be spent. So, while you would normally round up. In this case, you must round down to 5 months.
ABCD is a parallelogram and X and Y are any point on CD and AD respectively. Prove that triangle AXB and triangle BYC are equal in area. Prove that
Answers
Answer:
See answer below
Step-by-step explanation:
ABCD is a parallelogram Given
BC ≅ AD; AB ≅ DC opposite sides of a parallelogram ≅
Δ AXB = 1/2 (AB)(AD) Formula for the area of a Δ
Δ BYC = 1/2 (BC) (DC) Formula for the area of a Δ
1/2 (AB)(AD)= 1/2(BC)(DC) Substitution
∴ Area of Δ AXB = Area of ΔBYC
please help solve for RN
Answers
Answer:
I guess...
Step-by-step explanation:
Since QR and PN are parallels, I think what happens in MN and MP is proportional, so:
RN = x
8 is to 10 as
5 is to x
8 * x = 5 * 10
8x = 50
x = 50 / 8
x = 6.25
RN = 6.25
e
Week 6: Culmination Knowledge Check
CLEAR MY CHOICE
Question 8
You buy milk in 1-gallon containers. One portion of waffles requires 2 ounces of milk. How many portions can be made with one container? Select one
a 128
b. 16
c. 32
d. 64
CLEAR MY CHOICE
Question 9
You have 24 quarts of brown stock. You need 75 cups to make one serving of kidney beans. How many servings can you make? Select one
Answers
(2x+y)2-y2 if x=-3 y=4 and z=-5
Answers
-12
Hope this helps!
HURRY PLEASE! Do questions 4,5,6 on paper
Answers
This should be right , if any doubt please comment
Select all of the following that are ordered pairs of the given function.
ƒ(x) = 3 - 2x
Answers
Answer:
These are the answers
(-1,5)
(0,3)
(2,-1)
Step-by-step explanation:
A delivery company's charge for an overnight package weighing in excess of one pound is given by the formula c= 2.53w + 15, 16
where w is the weight of package in pounds. Find the following.
Answers
(27/8)^1/3×[243/32)^1/5÷(2/3)^2]
Simplify this question sir pleasehelpme
Answers
Step-by-step explanation:
[tex] = {( \frac{27}{8} )}^{ \frac{1}{3} } \times ( \frac{243}{32} )^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = { ({ (\frac{3}{2} )}^{3}) }^{ \frac{1}{3} } \times {( {( \frac{3}{2}) }^{5} )}^{ \frac{1}{5} } \div {( \frac{2}{3} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{3 \times \frac{1}{3} } \times {( \frac{3}{2} )}^{5 \times \frac{1}{5} } \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = \frac{3}{2} \times \frac{3}{2} \times {( \frac{3}{2} )}^{2} [/tex]
[tex] = {( \frac{3}{2} )}^{1 + 1 + 2} [/tex]
[tex] = {( \frac{3}{2} )}^{4} \: or \: \frac{81}{16} [/tex]
[tex]\large\underline{\sf{Solution-}}[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{27}{8} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{243}{32} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
We can write as :
27 = 3 × 3 × 3 = 3³
8 = 2 × 2 × 2 = 2³
243 = 3 × 3 × 3 × 3 × 3 = 3⁵
32 = 2 × 2 × 2 ×2 × 2 = 2⁵
[tex]\sf{\longmapsto{\bigg( \dfrac{3 \times 3 \times 3}{2 \times 2 \times 2} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{3 \times 3 \times 3 \times 3 \times 3}{2 \times 2 \times 2 \times 2 \times 2} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{{(3)}^{3}}{{(2)}^{3}} \bigg)^{\frac{1}{3}} \times \Bigg[\bigg( \dfrac{({3}^{5})}{{(2)}^{5}} \bigg)^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now, we can write as :
(3³/2³) = (3/2)³
(3⁵/2⁵) = (3/2)⁵
[tex]\sf{\longmapsto{\left\{\bigg(\frac{3}{2} \bigg)^{3} \right\}^{\frac{1}{3}} \times \Bigg[\left\{\bigg(\frac{3}{2} \bigg)^{5} \right\}^{\frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
Now using law of exponent :
[tex]{\sf{({a}^{m})^{n} = {a}^{mn}}}[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{3 \times \frac{1}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{5 \times \frac{1}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{\frac{3}{3}} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{\frac{5}{5}} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times\Bigg[\bigg(\frac{3}{2} \bigg)^{1} \div \bigg(\dfrac{2}{3} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \bigg)^{2}\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \frac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\frac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3}{2} \times \dfrac{3}{2} \bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{3 \times 3}{2 \times 2}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)^{1} \times \Bigg[\bigg(\dfrac{3}{2} \bigg)^{1} \times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex] \sf{\longmapsto{\bigg( \frac{3}{2} \bigg)\times \Bigg[\bigg(\frac{3}{2} \bigg)\times \bigg(\dfrac{9}{4}\bigg)\Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3}{2} \times \dfrac{9}{4} \: \: \Bigg]}}\\[/tex]
[tex]\sf{\longmapsto{\bigg( \dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{3 \times 9}{2 \times 4} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\bigg(\dfrac{3}{2} \bigg)\times \Bigg[ \: \: \dfrac{27}{8} \: \: \Bigg]}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3}{2} \times \dfrac{27}{8}}} \\[/tex]
[tex]\sf{\longmapsto{\dfrac{3 \times 27}{2 \times 8}}} \\[/tex]
[tex] \sf{\longmapsto{\dfrac{81}{16}}\: ≈ \:5.0625\:\red{Ans.}} \\[/tex]
When determining domain it is important to work from
Answers
Answer:
use graphs
Step-by-step explanation:
Another way to identify the domain and range of functions is by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis. The range is the set of possible output values, which are shown on the y-axis.
$4 is what percent of 50
Answers
Answer:
8%
Step-by-step explanation:
4/50 = 0.08 = 8%
Steps to solve "what percent is 4 of 50?" If you are using a calculator, simply enter 4÷50×100 which will give you 8 as the answer.
FInd the value of T - triangle measerments
Answers
JK=JH
[tex]\\ \sf\longmapsto 10t=7t+15[/tex]
[tex]\\ \sf\longmapsto 10t-7t=15[/tex]
[tex]\\ \sf\longmapsto 3t=15[/tex]
[tex]\\ \sf\longmapsto t=15/3=5[/tex]
Which of the following describes the transformation from Figure 1 to Figure 2? On a coordinate plane, figure A B C D E has points (negative 3, 5), (negative 2, 5), (negative 1, 4), (negative 2, 3), (negative 5, 3). Figure A prime B prime C prime D prime E prime has points (2, 2), (3, 2), (4, 1), (3, 0), (0, 0). CLEAR CHECK translation 2 units to the right and 3 units down translation 3 units to the left and 2 units up translation 5 units to the right and 3 units down translation 5 units to the left and 3 units up
Answers
Answer:
a
Step-by-step explanation:
The transformation from Figure 1 to Figure 2 is:
The transformation of 5 units to the right and 3 units down.
Option C is the correct answer.
What is translation?It is the movement of the shape in the left, right, up, and down directions.
The translated shape will have the same shape and shape.
There is a positive value when translated to the right and up.
There is a negative value when translated to the left and down.
We have,
A B C D E has points (-3, 5), (-2, 5), (-1, 4), (-2, 3), and (-5, 3).
A' B' C' D' E' has points (2, 2), (3, 2), (4, 1), (3, 0), and (0, 0).
Now,
A = (-3 + 5, 5 - 3) to A' = (2, 2)
B = (-2 + 5, 5 - 3) to B' = (3, 2)
C = (-1 + 5, 4 - 3) to C' = (4, 1)
D = (-2 + 5, 3 - 3) to A' = (3, 0)
E = (-5 + 5, 3 - 3) to E' = (0, 0)
We see that,
There is a translation of 5 units to the right and 3 units to the down.
Thus,
The transformation of 5 units to the right and 3 units down.
Learn more about translation here:
https://brainly.com/question/12463306
#SPJ1
The domain for f(x) is all real numbers ___ than or equal to 2
Answers
Step-by-step explanation:
f(x) = 2x² + 5√(x - 2)
Domain
√(x - 2) ≥ 0
x - 2 ≥ 0
x ≥ 2
x is greater than or equal to 2
Answer: Greater than
Step-by-step explanation:
PLEASE HELP ME!!! jacky starts biking to meet up with her friend. she knows that if she bikes at a speed of 10 mph, she will be 3 minutes late. jacky also know that if she bikes at a speed of 12 mph, she will be there 2 minutes before they agree to meet. how much time does she have left before the appointed time?
Answers
Answer:
27s
Step-by-step explanation:
d = distance to rendezvous point in miles
t = time of arrival at 10mph, i.e. 3 mins later than appointed time
10 mph = 10 miles per hour = ¹/₆ miles per min
12 mph = ¹/₅ miles per min
t = d/(¹/₆)
t = 6d
5 min = ¹/₁₂ hr
t - ¹/₁₂ = d/(¹/₅)
t = 5d + ¹/₁₂
Elimination of t:
6d = 5d + ¹/₁₂
d = ¹/₁₂ mi
t = 6(¹/₁₂)
t = ¹/₂ min
Time left to appointed time = ¹/₂ - ³/₆₀
= ¹⁰/₂₀ - ¹/₂₀
= ⁹/₂₀.min → 27 seconds
Answer:
27 min
Step-by-step explanation:
rsm
The dimensions of a rectangular prism are 3 cm, 15 cm, and k cm. Its volume is
90 cm. Find the value of k.
Answers
Answer:
k = 2 cm
Step-by-step explanation:
3 x 15 x k = 90 cm^3
45 x k = 90 cm^3
k = 90/45 = 2 cm
Over 5 days, Jaasiel practices soccer for a total of 3 hours. Jaasiel practices baseball for the same amount of time each day. If he practiced soccer and baseball for a total of 30 hours, how many hours per day did Jaasiel practice baseball? *
Answers
Answer:
3 HOURS
Step-by-step explanation:
HE PRACTICED 3 HOURS A DAY IN BOTH SPORTS MEANING IN 1 DAY HE PRACTICED A TOTAL OF 6 HOURS 6 HOURS A DAY FOR 5 DAYS IS EQUAL TO 30 HOURS OF PRACTICE A WEEK FOR BOTH SPORTS. SO 6 HOURS A DAY TOTAL AND 3 HOURS A DAY IF YOU ONLY COUNT 1 OF THE 2 SPORTS MENTIONED.
Write the equation of the line with x-intercept 3 and passing through the point (5.4)
Answers
Answer: y=(1/5)m+3
Step-by-step explanation:
Start with the standard form of an equation of a straight line: y=mx+b, whre m is the slope and b the y-intercept (the value of y when x=0).
y=mx+b
We know b (3), so:
y=mx + 3
To find the slope, m, we can use the one given point, (5,4):
y=mx + 3 for (5,4) would be:
4 = m*5+3
1 = 5m
m = (1/5)
y=(1/5)m+3
a number of students are standing in a circle. they are evenly spaced and the fith student is directly opposite the eleventh student. how many students are there all together
Answers
Answer:
There would be 12
Step-by-step explanation:
Answer this question for me ASAP
Answers
Answer:
Option A: (It's just that the y-intercept and slope are in different spots.)
Line in (y=mx+b) form is y = 2x + 4
Slooe is 2
y-intercept is 4
Step-by-step explanation:
Slope-intercept form is written as y=mx+b, where m is slope and b is y-intercept.
By looking at the graph, we can already tell that the y-intercept is positive 4, since the line crosses the y-axis at that point.
Now use rise/run to find slope. (Remember that rise is movement up or down, and run is movement left or right.) With this in mind, the slope is 4/2, and if we simplify it, it's 2/1 (or basically just 2). Because we go upwards 4 units and to the right 2 units.
Hope this helps :)
Please help this is my fifth time asking this question please answer it correctly with explanation
Answers
Step-by-step explanation:
There are two attachments to this post. The first attachment shows the numbered angles formed through the intersection of the transversal, t, into the parallel lines, m and n, which will be used to determine how each angle relates to other angles.
First attachment:The corresponding angles in the first attachment are:
∠1 and ∠5
∠2 and ∠6
∠3 and ∠7
∠4 and ∠8
Corresponding angles have the same measure.
The same-side exterior angles are the pair of angles that are outside the parallel lines, and on the same side of the transversal. In the first attachment, the same-side exterior angles are:
∠1 and ∠8
∠2 and ∠7
These angles are supplements of each other, meaning that the sum of their measure equal 180°.
Second Attachment:
Given parallel lines, m and n that are cut by a transversal, t.
The angle that has a measure of ∠(10x + 5)° is a supplement of ∠(5x + 25)°. In order to solve for the value of x, we must establish the following equation:
m∠(10x + 5)° + m∠(5x + 25)° = 180°
10x° + 5° + 5x° + 25° = 180°
Combine like terms:
15x° + 30° = 180°
Subtract 30 from both sides:
15x° + 30° - 30° = 180° - 30°
15x° = 150°
Divide both sides by 15:
15x°/15 = 150°/15
x = 10°
Verify whether we have correct value for x by substituting its value into the established equation:
m∠(10x + 5)° + m∠(5x + 25)° = 180°
10(10)° + 5° + 5(10)° + 25° = 180°
100° + 5° + 50° + 25° = 180°
180° = 180° (True statement).
Therefore, we have the correct value for x = 10°.
m∠(10x + 5)° = 105°
m∠(5x + 25)° = 75°
