Simplify:

5x+2(3−2x)+7


x + 13

12x

9x + 13

Answer: ¿Hablas español porque no entiendo esto? Si lo haces, ¿puedes decirme en español?

Step-by-step explanation:

Answer:

y = 250 + 810x

Step-by-step explanation:

Let

y = total charges

x = cost per hour

Sally: building

y = 100 + 420x

Mia: painting

y = 150 + 390x

Find their total charges of building and painting

Add the total charges of both of them

y = 100 + 420x + 150 + 390x

y = 250 + 810x

Answer:

108 squared centimeters

Step-by-step explanation:

Let's exchange π for 3:

area = πr^2

        = 3r^2

Now, as you can see, the radius of this circle is 6. Let's plug in the value of r:

area = 3r^2

        = 3 · 6^2

Simplify 6^2:

area = 3 · 6^2

        = 3 · 36

Multiply 3 by 36:

area = 3 · 36

area = 108

108 squared centimeters

The area of one side of the coin is 41.605 mm².

Given that, the diameter of a $1 coin is 26.5 mm.

We need to find the area of one side of the coin.

The area of a circle formula is A=πr².

Now, radius=26.5/2=13.25 mm.

Area of a coin=3.14×13.25=41.605 mm².

Therefore, the area of one side of the coin is 41.605 mm².

To learn more about the area of the circle visit:

https://brainly.com/question/11952845.

#SPJ2

Answer:

Given,

[tex] \sqrt{ {x}^{2} + 4x + 4} - 3 = 0 \\ = > \sqrt{ {x}^{2} + 4x + 4} = 3 \\ = > {( \sqrt{ {x}^{2} + 4x + 4} })^{2} = {3}^{2} \\ = > {x}^{2} + 4x + 4 = 9 \\ = > {x}^{2} + 4x + 4 - 9 = 0 \\ = > {x}^{2} + 4x - 5 = 0 \\ = > {x}^{2} + 5x - x - 5 = 0 \\ = > x(x + 5) - 1(x + 5) = 0 \\ = > (x - 1)(x + 5) = 0 \\ \\ \sf \: either \: x - 1 = 0 \: \: \: \: \\ = > x = 1 \: \: \\ \\ \sf \: or \\ x + 5 = 0 \\ = > x = - 5 \\ \\ \green{ \boxed{ \bf \: \: \: \: \: x = 1 \: \: or \: - 5}}[/tex]

But if we put the value of x = 5 then it doesn’t satisfy the equation.

So,

X = 1

Answer:

The answer is [tex]x=1[/tex].

Step-by-step explanation:

To solve this problem, start by factoring the equation using the perfect square trinomial rule, which is states that the middle term is the first term multiplied by the last term, and then multiplied by 2. The formula for the perfect square trinomial rule looks like [tex]a^2+2ab+b^2[/tex], where [tex]a=x[/tex] and [tex]b=2[/tex]. The equation will look like [tex]\sqrt{(x+2)^2}-3=0[/tex].  

Next, pull out the terms from under the radical, assuming positive real numbers, which will look like [tex]x+2-3=0[/tex]. Then, simplify the equation by subtracting 3 from 2, which will look like [tex]x-1=0[/tex]. Finally, add 1 to both sides of the equation, and the answer will be [tex]x=1[/tex].

Answer: 81, 243, 729

Step-by-step explanation:

STEP ONE: Find a pattern in the sequence

3 ÷ 1 = 3

9 ÷ 3 = 3

27 ÷ 9 = 3

As we can see from the given sequence, each number multiplies 3 to get the next term.

STEP TWO: Find the next three terms

27 × 3 = 81

81 × 3 = 243

243 × 3 = 729

Hope this helps!! :)

Please let me know if you have any questions

Answer:

enlarge it

Step-by-step explanation:

I ft = 12 inches

Thus 8 in → 12 in makes the transformation larger.

Thus going from 8 in to 12 in is an enlargement

Answer:

its C  option which is 12

Answer:

A

Step-by-step explanation:

Using Pythagoras' identity in either of the 2 right triangles

a² = (4[tex]\sqrt{3}[/tex] )² + (8[tex]\sqrt{3}[/tex] )² = 48 + 192 = 240 ( take square root of both sides )

a = [tex]\sqrt{240}[/tex] → A

Answer:

B

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Here the vertex = (- 2, - 3 ) , then

y = a(x - (- 2))² - 3 , that is

y = a(x + 2)² - 3

To find a, substitute any point on the graph into the equation

Using the coordinates of the y- intercept (0, 5 )

5 = a(0 + 2)² - 3 ( add 3 to both sides )

8 = a(2)² = 4a ( divide both sides by 4 )

2 = a

y = 2(x + 2)² - 3 → B

Answer:

Hello,

[tex]\boxed{Answer: 75}[/tex]

Step-by-step explanation:

x,y integers, x,y >0 ,x≠y

[tex]\dfrac{1}{x} +\dfrac{1}{y} =\dfrac{1}{18}\\\\\dfrac{x+y}{xy} =\dfrac{1}{18}\\\\x+y=\dfrac{xy}{18}\\\\x=\dfrac{18y}{y-18}\\x=\dfrac{18y-324 +324}{y-18}\\x=18+\dfrac{324}{y-18}\\[/tex]

[tex]\dfrac{1}{x} +\dfrac{1}{y} =\dfrac{1}{18}\\\\\dfrac{x+y}{xy} =\dfrac{1}{18}\\\\x+y=\dfrac{xy}{18}\\\\x=\dfrac{18y}{y-18}\\x=\dfrac{18y-324 +324}{y-18}\\x=18+\dfrac{324}{y-18}\\\begin{array}{|c|c|c|c|}y-18&y&x&x+y\\---&---&---&---\\1&19&18+324=342&362\\2&20&18+162=180&200\\3&21&126&147\\4&22&99&121\\6&24&108&132\\12&30&45&75\\18&36&36&72\\\end{array}\\\\\\\boxed{Answer: 75}\\\\[/tex]

Step-by-step explanation:

Asymptote: y = 2 y-intercept: (0,8)

Step-by-step explanation:

The given function is

f(x) = 6(0.5)^{x} + 2f(x)=6(0.5)

x

+2

This function is of the form:

f(x) = a {b}^{x} + cf(x)=ab

x

+c

where y=c is the horizontal asymptote.

By comparing , we have c=2 hence the horizontal asymptote is

y = 2y=2

To find the y-intercept, we put x=0 into the function to get:

f(0) = 6(0.5)^{0} + 2 = 6 + 2 = 8f(0)=6(0.5)

0

+2=6+2=8

Therefore the y-intercept is (0,8).

Answer:

-2

Step-by-step explanation:

-10 x 12 x -4 + 40 x -2 x 6 - 2

-120 x -4 - 80 x 6 - 2

480 - 480 - 2

0 - 2

-2

Answer:

0.23923444976

Answer

33.3

Step-by-step explanation:

if u multiply the 2, and then find the ratio of them in comparison to the number under, you will find the rate decreases by 10 percent every time, the first situation it is 4/8 = 5/10, second situation is it 32/80= 4/10, and htis situation is most like 3/10, right ? so the answer would be 33.3 :)

Answer:

(mn+3m)(n+p)

Step-by-step explanation:

Answer:

(mn + 3m)(n + p)

Step-by-step explanation:

Factorize by grouping:

[tex]mn^2+mnp\\mn(n+p)\\\\3mn+3mp\\3m(n+p)\\\\(mn+3m)(n+p)[/tex]

Answer:

Rajan = 436.36 rupees and Kamal = 363.63 rupees

Step-by-step explanation:

Total ratio = 11/30

Amount to be shared = 800

Rajan = Individual ratio / Total ratio x the total amount to be shared

1/5 ÷11/30 × 800 = 436.36

Kamal = 1/6 ÷ 11/30 × 800 = 363.63

Answer:

2,196;    549;     131.76;     8;     175.68;      1339.56

Step-by-step explanation:

2,196 is the biggest number, so use that as the first number.

.25x2196=549

.06x2196=131.76

.08x2196=175.68

2196-(549+131.76+175.68)=1339.56

SEE THE IMAGE FOR SOLUTION

HOPE IT HELPS

HAVE A GREAT DAY

Solution :

Case I :

If Collen is late on [tex]0[/tex] out of [tex]5[/tex] days.

[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} $[/tex]

[tex]$=\frac{1}{32}[/tex]

Case II :

When Collen is late on [tex]1[/tex] out of [tex]5[/tex] days.

[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_1$[/tex]

[tex]$=\frac{1}{32} \times 5$[/tex]

[tex]$=\frac{5}{32}[/tex]

Case III :

When Collen was late on [tex]2[/tex] out of [tex]5[/tex] days.

[tex]$= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2} \times ^5C_2$[/tex]

[tex]$=\frac{1}{32} \times 10$[/tex]

[tex]$=\frac{5}{16}[/tex]

Therefore, the [tex]\text{probability}[/tex] that Collen will arrive late to work no more than [tex]\text{twice}[/tex] during a [tex]\text{five day workweek}[/tex] is :

[tex]$=\frac{1}{32} + \frac{5}{32} + \frac{5}{16} $[/tex]

[tex]$=\frac{1}{2}$[/tex]

Answer:

To determine the type of triangle using side lengths, you could use the converse of the Phythagorean theorem, acute triangle inequality theorem, and the obtuse inequality theorem. For example, if the square of the longest side of a triangle is greater than the sum of the squares of the other two sides, than its obtuse. And if the square of the longest side is less than the sum of the squares of the other two sides, then it would be acute. And if the square of the longest side is equal to the sum of the squares of the two other sides, then it would be a right triangle.

Step-by-step explanation:

it marks it correct on edge and it is not a sample answer.

have a jolly day!

Answer:

D. linear; y = –x – 1

Step-by-step explanation:

Linear; y=-x - 1

The slope is negative since it’s decreasing. So it’s not the first equation. It’s not a quadratic equation because there is no forming U shape for this data. It’s not a exponential function because the slope is not 3 and a exponential function is in the form y=a(b)^x

...............................................................................................................................................

Answer:

The correct answer is D) linear; y = –x – 1

Step-by-step explanation:

To find this, use any values in the table and it will produce a true statement. This is how we check to see if a model is correct. See the two examples below for proof.

(4, 5)

y = -x - 1

-5 = -4 - 1

- 5 = -5 (TRUE)

(0, -1)

y = -x - 1

-1 = 0 - 1

-1 = -1 (TRUE)

Answer:

12 degrees

Step-by-step explanation:

Answer:

15 degrees

Step-by-step explanation:

okay haha

so basically the cosine of an angle is the side adjacent to it, divided by the hypotenuse. the sine is the side opposite to that angle divided by the hypotenuse, and the tangent is the side opposite to that angle divided by the side adjacent to it.

in this case we are given the angle and the side opposite to it which is 10, and we are also given the hypotenuse of 39.

what trig function deals with opposite and hypotenuse?

the answer is sine

so we would find the sine of that angle which equals to opposite over hypotenuse:

sin(angle) = 10/39

but, they are asking for the inverse trig function. the inverse of sine is arcsin.

so :

arcsin(10/39) = angle

in a calculator, this would be equal to about 14.857 which is closest to 15.

The equation your teacher has given you is an identity. We can prove this by transforming one side into the other. I'll transform the right hand side (RHS) into the left hand side (LHS).

This means I'll keep the LHS the same for each line. I'll only change the RHS. The goal is to get the same thing on both sides (I could go the other way around but I find this pathway is easier).

[tex]\tan^4(\theta)+\sec^2(\theta) = \sec^4(\theta)-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\sec^2(\theta)\right)^2-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\tan^2(\theta)+1\right)^2-\tan^2(\theta) \ \text{ ... see note 1}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+2\tan^2(\theta)+1-\tan^2(\theta)\\\\[/tex]

[tex]\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\tan^2(\theta)+1\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta)-1+1 \ \text{ ... see note 2}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta) \ \ \Large \checkmark\\\\[/tex]

So because we've arrived at the same thing on both sides, the original equation is an identity. It always true no matter what theta value you plug in, as long as theta is in the domain. So something like theta = pi/2 won't work because tan(pi/2) = undefined and sec(pi/2) = undefined. It's based on how cos(pi/2) = 0 and this value is in the denominator. Dividing by zero is undefined.

Consequently, this means all solutions to cos(theta) = 0 will be excluded from the domain. Everything else works.

Answer: The expression is 7/2.

I thing it lies on the negativity side of the number line between -2,24