Select the correct answer.
Which expression is a factor of this polynomial?
13 + 2x^2-9x-18
O
O A. (x - 2)
B. (x + 1)
Oc. (x - 6)
D. (x + 2)

Answer:

104

Step-by-step explanation:

Answer:

5/6

Step-by-step explanation:

2/

3

: 4/

5

= 2/

3

· 5/

4

= 2 · 5/

3 · 4

= 10/

12

= 2 · 5/

2 · 6

= 5/

6

Answer:

4x - 12 = 84

Step-by-step explanation:

The last answer choice is correct because when you cross-multiply:

you get 4x - 12 = 84.

Therefore, the last option is correct.

Answer:

D would be the answer (4x-12=84)

Step-by-step explanation:

4/7=12/x-3

=>1/7=3/x-3

=>x-3=21

Multiplying both sides by 4

4(x-3)=4x21

=>4x-12=84

Hope this helped :)

9514 1404 393

Answer:

  $94,473.31

Step-by-step explanation:

The multiplier in 25 years is ...

  e^(rt) = e^(0.03·25) = e^0.75 ≈ 2.117

To have an account value of $200,000 in 25 years, you need to deposit now ...

  $200,000/2.117 = $94,473.31

_____

When this amount is multiplied by 2.117, the result is 200,000.

25% = 25/100

25% of 28 is 7

~fractions

=====================

understand the steps below!

7 ÷ 25%

= 7 ÷ 25/100

= 7 × 100/25

= 7 × 4

= 28 ✔️

~ nice to help you ^^

Answer:

[tex]x=\frac{9}{4}[/tex]

Step-by-step explanation:

Answer:

[tex]\boxed{\boxed{\sf x=\frac{9}{4} }\:\sf or \:\boxed{x=2.25}}[/tex]

Step-by-step explanation:

[tex]\sf \cfrac{1}{2}\:x+\cfrac{3}{4}=\:x\cfrac{5}{6}[/tex]

Subtract x (5/6) from both sides:

[tex]\longmapsto\sf \cfrac{1}{2}\: x+\cfrac{3}{4} -x\left(\cfrac{5}{6}\right)=0[/tex]

Subtract 3/4 from both sides:

** Anything subtracted from zero gives its negation.**

[tex]\longmapsto\sf -\cfrac{1}{3}\:x=-\cfrac{3}{4}[/tex]

Multiply both sides by -3, reciprocal of - 1/3

[tex]\longmapsto\sf x=-\cfrac{3}{4} (-3)[/tex]

Express - 3/4 (-3) as single fraction:

[tex]\longmapsto\sf x=\cfrac{-3(-3)}{4}[/tex]

Multiply -3 and -3 = 9

[tex]\longmapsto\sf x= \cfrac{9}{4}[/tex]

______________________________________

Answer:

first put 2 in the numerator for the first blank and 2/9 in the second blank

Step-by-step explanation:

1/3 equals 3/9 and 3/9-1/9=2/9

Answer:

[tex]\frac{3}{9}[/tex]

Step-by-step explanation:

Answer: 2^5

Step-by-step explanation:

2^5= 2x2x2x2x2=32

5^2=5×5=25

Answer:

the value of x is 12

......

Answer:

9/n-2=7

We move all terms to the left:

9/n-2-(7)=0

Domain of the equation: n!=0

n∈R

We add all the numbers together, and all the variables

9/n-9=0

We multiply all the terms by the denominator

-9*n+9=0

We add all the numbers together, and all the variables

-9n+9=0

We move all terms containing n to the left, all other terms to the right

-9n=-9

n=-9/-9

n=1

Answer:

n = 1

Step-by-step explanation:

2 x 1 = 2

2 + 7 = 9

Answer:

No

Step-by-step explanation:

The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number

Yep!!! Your correct

[tex] \frac{{12}^{ \frac{1}{2} } }{ {3}^{ \frac{3}{2} } } \\ = \frac{(3 \times 4) ^{ \frac{1}{2} } }{ {3}^{ \frac{3}{2} } } \\ = \frac{ {3}^{ \frac{1}{2} } \times {4}^{ \frac{1}{2} } }{ {3}^{ \frac{3}{2} } } \\ = {3}^{ (\frac{1}{2} - \frac{3}{2}) } \times 2 ^{2 \times \frac{1}{2} } \\ = {3}^{ - \frac{2}{2} } \times 2 \\ = 3 ^{ - 1} \times 2 \\ = \frac{2}{3} [/tex]

[tex] \frac{2}{3} [/tex]

Hope it helps.

Do comment if you have any query.

Answer:

[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]

Step-by-step explanation:

If you look at the graph you see that:

before 0, the graph has same y as it has x, or y=x.

after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.

Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.

Answer:

Move it to the right by 3 spaces.

Step-by-step explanation:

10^3 is 1000

On a number line the negative numbers are on the left and the positive numbers are on the right. So since the exponent is a positive 3 we move it to the right by 3 spaces to get 140

Step-by-step explanation:

f(x) = -3x - 8

f(-3) = -3(-3) - 8

f(-3) = 9 - 8

f(-3) = 1

Answer:

x = -.1715 ≈ - .172    or x = -5.83

Step-by-step explanation:

x² + 6x + 1 = 0

x² + 6x = -1

Complete the square   Add to both sides (1/2 of the x-term, then square it.)

x² + 6x + 9  = -1 + 9

(x + 3)(x + 3) = 8

(x + 3)² = 8

[tex]\sqrt{(x + 3)^{2}[/tex]  = [tex]\sqrt{8}[/tex]

 x + 3 = ±  [tex]\sqrt{8}[/tex]

  x = -3 ± [tex]\sqrt{8}[/tex]

   x = -3 + [tex]\sqrt{8}[/tex]   or x = -3 - [tex]\sqrt{8}[/tex]

   x = -.1715 ≈ - .172    or x = -5.83

Answer:

3, 4, 5 and 5, 12, 13

Step-by-step explanation:

The square of the largest side is equal to the sum of the squares of the other 2 sides.

5² = 3² + 4²

13² = 5² + 12²

The 2 triplets are (3, 4, 5 ) and (5, 12, 13)

Answer:

hope it helps you.........

Answer:

y= -2x +6

Step-by-step explanation:

Step-by-step explanation:

Number 1

m = (y2 - y1)/(x2 - x1)

m = (3 - 1)/(5 - 2)

m = 2/3 POSITIVE

Number 2

m = (y2 - y1)/(x2 - x1)

m = (-3 - 1)/(1 + 2)

m = -4/3 NEGATIVE

Number 3

m = (y2 - y1)/(x2 - x1)

m = (1 - 1)/(5 - 4)

m = 0/1

m = 0 ZERO

Number 4

m = (y2 - y1)/(x2 - x1)

m = (5 - 1)/(7 - 7)

m = 4/0

m = UNDEFINED

Number 5

m = (y2 - y1)/(x2 - x1)

m = (6 - 1)/(3 + 2)

m = 5/5

m = 1 POSITIVE

Answer:

brainliest mo munako

Step-by-step explanation:

bago answer pede maliwaag ba

Answer:

hmmmmm

Step-by-step explanation:

Step-by-step explanation:

very simple thought experiment :

he is going 90 km/h (90 kilometers per hour), so, he moving 90 km in 1 hour.

how far is he going in just 2 seconds ?

so, we get two ratios.

90km/1 hour = 90,000 meter / 1 hour

x meter / 2 seconds

we need to bring both ratios (they are fractions) to the same dimension of the denominators, so that we can then bring them to the same denominator.

the first is dealing with an hour.

the second one with (2) seconds.

so, how many seconds are in 1 hour ?

60 seconds per minute, 60 minutes in the hour.

60×60 = 3600 seconds.

so, now we know, the first ratio is also

90,000 meter / 3600 seconds

now we need the factor to to multiply numerator and denominator with to bring 3600 down to 2.

3600 × f = 2

f = 2/3600 = 1/1800

now we get

90,000 / 3600 × (1/1800) / (1/1800) =

(90000 / 1800) / (3600 / 1800) = 50 / 2

so, 90km/h is the same speed as 50 meter / 2 seconds.

and therefore we know, the building was 50 meters long.

Answer:

(by using the first principle of differentiation)

We have the "Limit definition of Derivatives":

[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]

Here, f(x) = sec x, f(x+h) = sec (x+h)

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]

[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]

=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]

Substituting 0 for h and h/ 2

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]

[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]

[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]

Hence, we got

[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]

-  - - - -  - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

(by using other standard derivatives)

[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]

We have a standard derivative for variables in x raised to an exponent:

[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]

Therefore,

[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]

[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]

The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,

while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.

[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]

[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]

[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]

= sec x. tan x

Answer:

here the answer is 24

Step-by-step explanation:

answerrrrrerrr issss hereeeeeee

Answer:

0

Step-by-step explanation:

4 multiply by x(3) = 12

6 multiply by y(2) = 12

12 -12 =0