A water sprinkler covers the area shown in the figure.
It moves through the covered area at a rate of about 5 per second.
What is the measure of the are covered by the sprinkler?
If the sprinkler starts at the far left position,
how long will it take for the sprinkler to reach
the far right position?
Answers
A water sprinkler has a rotational motion in order to reach a broad area
from its stationary location.
The time it takes the sprinkler to reach the far right position is 36 seconds.
Reasons:
The given parameter are;
The angular speed of the water sprinkler, ω = 5° per second
Location where the sprinkler starts = The far left position
Required:
The time it takes the sprinkler to reach the far right position.
Solution;
The angle covered by moving from the far left to the far right, θ = 180°
Time required is given as follows;
[tex]\omega = \mathbf{\dfrac{\theta}{t}}[/tex]
Therefore;
[tex]t = \dfrac{\theta}{\omega}[/tex]
Which gives;
[tex]t = \dfrac{180 ^{\circ}}{5^{\circ}/s} = 36 \, s[/tex]
The time it takes the sprinkler to reach the far right position, t = 36 seconds.
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