Primăvară
Lumina soarelui ne înfioară în suflet,
Înflorim ca mugurii în zori de zi.
What is the beauty that blossoms in spring?Primăvară is a Romanian word that translates to "spring" in English. It represents a season of renewal, growth, and vibrant energy. As the cold winter days fade away, the warmth of the sun awakens nature from its slumber. The poem captures the essence of spring by using an acrostic structure, where each line begins with a letter that spells out the word "Primăvară" vertically.
In the first stanza, "Lumina soarelui ne înfioară în suflet" (The sunlight sends shivers through our souls), we feel the transformative power of the sun's rays as they touch our being, igniting a sense of joy and anticipation.
The second stanza, "Înflorim ca mugurii în zori de zi" (We blossom like buds at dawn), paints a picture of nature awakening and blooming, mirroring the human spirit that is filled with hope and new beginnings.
This acrostic poem beautifully captures the essence of spring, symbolizing the rebirth of nature and the human spirit. It celebrates the beauty and vitality of this season, reminding us of the cyclical nature of life and the endless possibilities that come with each new spring.
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3-the-lamps are connected in parallel. The first lamp has a current of 2. A.
The second lamp has a voltage equal to 10V and a resistance equal to 6 Ohm. The
third-lamp has a current equal to 4A Find in this scheme the total voltage, the current
for all·lamps, the total resistance.
Total Voltage: 10V
Total Current: Approximately 7.67A
Total Resistance: 2 Ohm
How to solve for the volgtage and resistanceThe total voltage in the circuit is equal to the voltage across any of the lamps. In this case, the second lamp has a voltage of 10V, so the total voltage in the circuit is 10V.
Current for all lamps (I):
Since the lamps are connected in parallel, the total current flowing through the circuit is the sum of the individual currents through each lamp.
The first lamp has a current of 2A, the second lamp's current is not given, and the third lamp has a current of 4A. To find the total current, we need to calculate the current through the second lamp.
Since the second lamp has a resistance of 6 Ohm and a voltage of 10V, we can use Ohm's Law (V = I * R) to find the current through the second lamp:
10V = I * 6 Ohm
I = 10V / 6 Ohm
I ≈ 1.67A
Now we can calculate the total current:
Total Current (I) = 2A (first lamp) + 1.67A (second lamp) + 4A (third lamp)
Total Current ≈ 7.67A
Total Resistance (R):
In a parallel circuit, the total resistance is calculated using the reciprocal of the sum of the reciprocals of the individual resistances.
The second lamp has a resistance of 6 Ohm, so the total resistance is:
1 / Total Resistance = (1 / 6 Ohm) + (1 / 6 Ohm) + (1 / 6 Ohm)
1 / Total Resistance = 3 / 6 Ohm
1 / Total Resistance = 1 / 2 Ohm
Total Resistance = 2 Ohm
To summarize:
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