Point B is located at
(-3,0)
(3,0)
(0,3)
(0,-3)

The inequality which represents the possible number of hours , x, the salesperson works this week is 20x + 800 ≥ 1400 where x ≥ 30,

using equation formation steps.

What is an equation ?

In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal.

For instance, 3x + 5 = 14 is an equation.

Equations and inequalities are both mathematical sentences formed by relating two expressions to each other. In an equation, the two expressions are deemed equal which is shown by the symbol =. Where as in an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.

In given que,

minimum earning = $1400

The possible number of hours = x

No. of cars sold = 8

Price earned by sold cars = $800

Price earned per hour =$20

Price earned for x hours = $20x

So, the total amount = 20x + 800

The equation become 20x + 800 ≥ 1400

Solving inequality que,

20x >= 600

x ≥ 30

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After using trigonometric function the value of to the nearest tenth digit is 11.11

What is Trigonometric function ?

Trigonometric functions are mathematical functions that are used to describe relationships between certain angles and lengths in a triangle. They are based on the ratios of the sides of a right triangle and are used in a variety of applications including surveying, navigation, engineering, and physics. Trigonometric functions are commonly referred to as sine, cosine, tangent, cotangent, secant, and cosecant. Each of these functions can be used to calculate the angle of a triangle, the length of the sides, or the area of the triangle.

Function of Sine

The ratio of the opposing side's length to the hypotenuse is known as an angle's sine function.
Sin a =Opp/Hypot = CB/CA

Cos Function
The cosine of an angle is the ratio of the neighbouring side's length to the hypotenuse's length.
Adjacent/Hypotenuse = AB/CA is the cosine of.

Functional Tan
The ratio of the lengths of the adjacent and opposing sides is known as the tangent function. It should be noted that the ratio of sine and cosine to the tan may also be used to express the tan.
Tan a = Opposite/Adjacent = CB/BA
In terms of sine and cos, tan is also equivalent to:
Tan = cos a/sin a
Sin 46° = 8/x
x = 8/Sin 46°
x= 8/0.72
x=11.11

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Susie is correct as it is not a right triangle

        Square of the hypotenuse side = 289

        Squares of the other two sides = 12 * 12 = 144

                                                             =9 * 9 = 81

        Sum of the squares of the other two sides = 144 + 81

                                                                               = 225

        So, here 225 ≠ 289

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The pair of Linear angles are 51° and 129°.

When two lines intersect at a point then they will form two linear angles. The sum of angles of a linear pair is always equal to 180°. Such angles are also known as supplementary angles.

In other words, if the sum of two adjacent angles is 180° then the pair of angles are said to be Linear Angles.

Here we have

Two angles form linear angles

Let x and y be the two angles

=> x + y = 180 ------ (1)  [ since both are linear angles ]  

Given that the sum of one angle plus 27 is equal to two times the sum of the other angle

=> x + 27 = 2y

=> x = (2y - 27) ---- (2)

Substitute (2) in (1)

=> 2y - 27 + y = 180

=> 3y = 153

=> y = 153/3

=> y =  51  

Now substitute y = 51 in (1)

=> x + 51 = 180

=> x = 180 - 51

=> x = 129

The pair of Linear angles are 51° and 129°.

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The image of (10,-6) after dilation by a scale factor of 1/2 centered at the origin is (-5,-3).

What is dilation?

A dilation is a function f from a metric space M into itself that, for any points x, y in M, fulfills the identity d=rd, where d is the distance between x and y and r is a positive real number. Such a dilatation is a resemblance of the space in Euclidean space.

Here, we have

Given

The image of (10,-6) after dilation by a scale factor of 1/2 centered at the origin.

We have to find the image after dilation.

The coordinates of an image (-10,-6), dilating the coordinate by 1/2 means reducing the image by multiplying each coordinate by the factor of 1/2.

Image = (1/2(-10), 1/2(-6))

Image = (-5,-3)

Hence, the image of (10,-6) after dilation by a scale factor of 1/2 centered at the origin is (-5,-3).

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Answer:

Below

Step-by-step explanation:

.94 % is .0094 in decimal

   this exponential growth is like a bank account compounded yearly

         factor =  ( 1+.0094)^30  = 1.3240  

                   which would represent 32.40% growth

Answer:

Factored form is (x - 5) (x² + 5x + 25)

Step-by-step explanation:

You can get the factors directly by using the formula for a³ - b³.

Answer:

a) 1 degree above

b) 4 degrees below

c) 12 degrees above

d) 7 degrees above

Step-by-step explanation:

For binary class classification, assumptions are necessary in a way:

Given that

From Boyer Naive classifier,

We evaluate (ai | vj) is given below

(ai | vj) = n(e) + m(p) / n + m

Here,

m = equivalent sample size

n(e) = number of training examples

for which v = vj and a = ai

n(i) = number of training example for which v = vj

P = a prior estimate for P(ai | vj)

Here, we calculate that

P(SUV | yes), P(Red | yes), P(Domestic | yes)

P(SUV | no), P(Red | no), P(Domestic | no)

We evaluating this value like

yes:

RED :                             SUV:                            DOMESTIC:

n = 5                              n = 5                             n = 5

n(c) = 3                          n(c) = 1                           n(c) = 2

P = 0.5                          P = 0.5                           P = 0.5

m = 3                              m = 3                            m = 3

Therefore, with the above calculation we can justify that the simplifying assumptions are necessary in a binary class classification.

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The greatest number of snack bags is 10.

The largest of all the common factors between two or more numbers is known as the Highest Common Factor (HCF). It is also known as the Greatest Common Element (GCF).

HCF is a fundamental method that allows you to equally distribute items throughout a group or set.

We can use the idea of HCF to determine the same when you are organizing a party and want to make sure that nothing is wasted or you require a proper calculation.

Here we have

Number of carrots = 75

Number of celery sticks = 40

Here we are making snack bags such that each bag contains the same combination of carrot and celery sticks.

To find the greatest number of snack bags we need to find HCF of 70 and 40 as given below

Write given numbers as the product of prime numbers

=> 70 = 2 × 5 × 7

=> 40 = 2 × 2 × 2 × 5  

List out the common factors

=> 2 × 5  

=> HCF (70, 40) = 10

Therefore,

The greatest number of snack bags is 10.

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Answer:

  (a)  2

Step-by-step explanation:

You want the greatest common factor of 18, 24, 40.

The prime factorization of these numbers is ...

The only common factor is 2.

2 is the greatest common factor of 18, 24, and 40.

Answer:

The original price of the tie was 20 dollars

Step-by-step explanation:

The price of the t-shirt was originally 24, but because he bought it on sale, he would have payed 12 because 24x.5=12.  This means we can subtract the value payed for the shirt from the total money payed. 22(total)-12(shirt)=.  10 (tie). However, 10 is the price he payed for the tie, not its original value. We can find this by multiplying 10x2, which gives us our answer.

Answer:

20 dollars is the original price

Answer:5 cm

Step-by-step explanation:

Answer: w=2.5cm

Step-by-step explanation:

when solving for a right triangle, you need to to the length multiplied by the width and then divided by two. You then get (6*5)/2=30/2=15.

When solving for a rectangle, it’s the same, but without dividing by two. But you need them to be equal, and you already have the measure six.
So 5/2=2.5 therefore w=2.5cm.

Answer:

A

Step-by-step explanation:

The answer is option A

Hope this helps :)

2x⁶ + 4x⁵ - x⁴ + 6x² - 5x is the product of multiplying the polynomials (2x³ + 4x² − 5x)(x³ + 2x - 1).

Multiplication in elementary algebra is the process of figuring out what happens when a number is multiplied by itself. Each of the numbers and is referred to as a factor of the product, which is the outcome of a multiplication.

Given

Polynomial

(2x³ + 4x² − 5x)(x³ + 2x - 1)

Multiplying by distributive method,

2x³(x³ + 2x - 1) + 4x²(x³ + 2x - 1) - 5x(x³ + 2x -1)

2x⁶ + 4x⁴ - 2x³ + 4x⁵ + 2x³ - 4x² - 5x⁴ + 10x² - 5x

Adding polynomials with same powers

2x⁶ + 4x⁵ + 4x⁴ - 5x⁴ - 2x³ + 2x³ - 4x² + 10x² - 5x

2x⁶ + 4x⁵ - x⁴ + 6x² - 5x

2x⁶ + 4x⁵ - x⁴ + 6x² - 5x is the product of multiplying the polynomials (2x³ + 4x² − 5x)(x³ + 2x - 1).

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Answer:

[tex]\boxed{1.1914285714285713}[/tex]

Step-by-step explanation:

Jill earned a total of 9 + 6/7 = <<9+6/7=9.857142857142857>>9.857142857142857 points.

Alice earned a total of 8 + 2/3 = <<8+2/3=8.666666666666666>>8.666666666666666 points.

Therefore, Jill earned 9.857142857142857 - 8.666666666666666 = <<9.857142857142857-8.666666666666666=1.1914285714285713>>1.1914285714285713 more points than Alice. Answer: \boxed{1.1914285714285713}.

Alice earned approximately 1.19 points more than Jill.

To find the difference between the number of points earned by Jill and the number of points earned by Alice, we need to first convert both amounts to a common denominator.

Since the denominators of the fractions representing the number of points earned by Jill and Alice are different, we will need to find a common denominator. To do this, we can find the least common multiple (LCM) of 7 and 3, which is 21.

We can then rewrite the fraction representing the number of points earned by Jill as 9 + 6/7 = (9 * 3 + 6)/21 = 27/21 + 6/21 = 33/21, and the fraction representing the number of points earned by Alice as 8 + 2/3 = (8 * 7 + 2)/21 = 56/21 + 2/21 = 58/21.

To find the difference between the number of points earned by Jill and the number of points earned by Alice, we can subtract the number of points earned by Alice from the number of points earned by Jill:

33/21 - 58/21

We can simplify this expression by combining like terms:

(33 - 58)/21 = -25/21

This represents a difference of -25/21 points, or approximately -1.19 points. Since a negative difference represents a smaller quantity, this means that Alice earned approximately 1.19 points more than Jill.

The average speed of the winning car is  79.38 miles per hour.

Given : Distance covered by rally car race course = 515.97 miles

Time taken to complete the course by winning car = 6.5 hours

The average speed of the winning car = ( Distance covered by rally car race course) ÷  (Time taken to complete the course by winning car)

= (515.97)÷ (6.5) miles per hour

= 79.38 miles per hour

Hence, the average speed of the winning car =  79.38 miles per hour.

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Answer:

The correct answer to this expression is 9x + 7y. To find this answer, you need to combine like terms. This means that you need to add together any terms that have the same variable and coefficient. In this case, the expression has two terms with the variable x and two terms with the variable y. The coefficients of the x terms are 2 and 7, and the coefficients of the y terms are 3 and 4. To combine these terms, you need to add the coefficients of the x terms together to get 9, and add the coefficients of the y terms together to get 7. Therefore, the combined expression is 9x + 7y.

The equation in the form Ax+ By=C is 4x-3y=27 if the line passes through the point (-6, 1) and slope is 4/3.

A mathematical formula that connects two expressions with the equals sign (=) expresses the equality of the two expressions. The word equation and its translations in several languages might have slightly different meanings. For instance, in French, an equation is defined as including one or more variables, whereas in English, an equation is defined as any properly expressed formula that consists of two expressions joined by the equals sign.

The values of the variables that must fulfill the equality to make up the solution are referred to as the unknowns, together with the variables for which the equation must be solved.

Given point is (-6, 1)

Slope m=4/3

The equation of the line is:

y-y₁=m(x-x₁)

y-1=(4/3)(x+6)

3y-3=4x+24

4x-3y=27

Therefore, the equation in the form Ax+ By=C is 4x-3y=27

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The perimeter of triangle XYZ is 48 units

What is the perimeter of a triangle?

The total of a triangle's sides equals the triangle's perimeter. The space encircled by a triangle's three sides is known as its area.

Here, we have

In The triangle XYZ

A is the midpoint of XY

B is the midpoint of YZ

AB = 1/2 XZ

AB = 5 units

Substitute the value of XZ in AB

5 = 1/2 × XZ

XZ = 10 units

B is the midpoint of YZ

C is the midpoint of XZ

BC =  1/2 XY

XY = 24 units

BC = 1/2 × 24 = 12 units

A is the midpoint of XY

C is the midpoint of XZ

AC = 1/2 YZ

AC = 7

7 = 1/2 YZ

YZ = 14

The perimeter of a triangle = the sum of the lengths of its sides

Perimeter ΔXYZ = XY + YZ + ZX

Perimeter ΔXYZ = 24 + 14 + 10

Hence, the perimeter of triangle XYZ is 48 units

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Answer: The correlation coefficient is a measure of the strength and direction of the relationship between two variables. A correlation coefficient of -0.993 indicates a very strong negative relationship, which means that as one variable increases, the other variable decreases. This suggests that you can be quite confident that your predicted value will be reasonably close to the actual value.

Answer:

Yes this is a resendable prediction

Step-by-step explanation:

Answer:

[tex]x = -2[/tex]

Step-by-step explanation:

[tex]\textsf {Square both sides:}\\\\(\sqrt{3x+12} )^2 = 3x + 12\\\\(\sqrt{x+8} )^2 = x + 8[/tex]

(The square of the square root of a value is the value itself

[tex](\sqrt{x} )^2 \;is\;x[/tex])

The original identity then becomes
[tex]3x + 12 = x + 8\\\\3x - x = 8 - 12\\\\2x = -4\\\\x = -4/2\\\\x = -2[/tex]

The value of river garden's common stock is $24.79.

In order to determine the value of the common stock, the constant dividend model would be used.

According to this model, the value of a common stock is determined by its dividend, the growth rate and the required return.

Value of the stock = Dividend / (required return - growth rate)

The first step is to determine the dividend of the common stock.

Dividend = pay out ratio x expected earnings

Dividend = 0.45 x $3.25

Dividend = $1.46250

Value of the stock = $1.46250 / (0.124 - 0.065)

Value of the stock = $24.79

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An algorithm for navigating or searching through tree or graph data structures is called depth-first search. The algorithm begins at the root node (choosing an arbitrary node to serve as the root node in the case of a graph) and proceeds to investigate each branch as far as it can go before turning around.

Thus, the basic concept is to begin at the root or any other random node, mark that node, then advance to the next nearby node that is not marked. This process is repeated until there are no more adjacent nodes that are unmarked. Then go back and look for more unmarked nodes to cross. Print the path's nodes lastly.

To solve the issue, adhere to the instructions listed below:

Make a recursive function that accepts a visited array and the node's index.

STEP -1

// C++ program to print DFS traversal from

// a given vertex in a given graph

#include <bits/stdc++.h>

using namespace std;

// Graph class represents a directed graph

// using adjacency list representation

class Graph {

public:

map<int, bool> visited;

map<int, list<int> > adj;

// function to add an edge to graph

void addEdge(int v, int w);

// DFS traversal of the vertices

// reachable from v

void DFS(int v);

};

void Graph::addEdge(int v, int w){

adj[v].push_back(w); // Add w to v’s list.}

void Graph::DFS(int v)

{

// Mark the current node as visited and

// print it

visited[v] = true;

cout << v << " ";

// Recur for all the vertices adjacent

// to this vertex

list<int>::iterator i;

for (i = adj[v].begin(); i != adj[v].end(); ++i)

if (!visited[*i])

DFS(*i);

}

// Driver's code

int main()

{

// Create a graph given in the above diagram

Graph g;

g.addEdge(0, 1);

g.addEdge(0, 2);

g.addEdge(1, 2);

g.addEdge(2, 0);

g.addEdge(2, 3);

g.addEdge(3, 3);

cout << "Following is Depth First Traversal"

" (starting from vertex 2) \n";

// Function call

g.DFS(2);

return 0;

STEP- 2

Time complexity: O(V + E), where V is the number of vertices and E is the number of edges in the graph.

Auxiliary Space: O(V), since an extra visited array of size V is required.

Pseudocode:

Depth_First_Search(matrix[ ][ ] ,source_node, visited, value)

{

If ( sourcce_node == value)                

return true // we found the value

visited[source_node] = True

for node in matrix[source_node]:

  If visited [ node ] == false

  Depth_first_search ( matrix, node, visited)

  end if

end for

return false //If it gets to this point, it means that all nodes have been explored.

                   //And we haven't located the value yet.

}

final answer-

A tree data structure or a graph's vertices can be searched using a recursive technique called t. Beginning with the first node of graph G, the depth-first search (DFS) algorithm digs down until it reaches the target node, also known as the node with no children.

The DFS method can be implemented using a stack data structure due to its recursive nature. The DFS algorithm implementation procedure is comparable to that of the BFS algorithm.

The following describes how to implement DFS traversal step-by-step. -

Create a stack with all of the graph's vertices in it first.

Select whatever vertex you want to use as the first vertex in the traverse, and add it to the stack.

uses for the DFS algorithm

The following list of uses for the DFS algorithm includes:

The topological sorting can be implemented using the DFS algorithm.

It can be applied to determine the routes connecting two vertices.

It can also be used to find graph cycles.

DFS technique is also applied to puzzles with a single solution.

If a graph is bipartite or not, it can be determined using DFS.

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The values of the probability in both scenarios are 0

First two dice show aces, and the next three do not

From the question, we have the following parameters that can be used in our computation:

Experiment = rolling of dice

The outcome of an ace is not in the sample space of rolling a die

This means that the probability is 0.

Two of the five dice show aces, and the other three do not

Here, we have

Experiment = rolling of dice

The outcome of an ace is not in the sample space of rolling a die

This means that the probability is 0.

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a) The probability that Cathy passes the CPA on the first try is of: 0.56 = 56%.

b) The probability that Cathy passes the CPA exam on the second or third try is of: 0.3548 = 35.48%.

A probability is the division of the number of desired outcomes by the number of total outcomes.

56% of students who graduated pass the CPA exam, hence the probability of passing on each test, including the first, is of:

0.56 = 56%.

Then the probabilities for the second or the third test are given as follows:

Then the probability that Cathy passes the CPA exam on the second or third try is calculated as follows:

p = 0.44 x 0.56 + 0.44² x 0.56 = 0.3548 = 35.48%.

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there you go i think

Answer: 2.795

Step-by-step explanation:

[tex]cos 56= \frac{x}{5}[/tex]