PLSSS I REALLY NEED HELP RIGHT NOW!! 20 POINTSS??

Answer:

5^3

Step-by-step explanation:

5^1 x 5^2

indices rules when multiplying you add the powers to 1+2=3

5^3

side of cube=5

We know

[tex]\boxed{\sf Side=\dfrac{Diagonal}{\sqrt{2}}}[/tex]

[tex]\\ \sf \longmapsto Diagonal =sude\times \sqrt{2}[/tex]

[tex]\\ \sf \longmapsto Diagonal=5\sqrt{2}[/tex]

[tex]\\ \sf \longmapsto Diagonal=5\times 1.4[/tex]

[tex]\\ \sf \longmapsto Diagonal=7cm[/tex]

Answer:

Hello,

Step-by-step explanation:

[tex]Using\ the\ Pythagorian's\ theorem,\\\\EC^2=EA^2+AC^2\\\\=EA^2+AB^2+BC^2\\\\=3*5^2\\\\EC=5\sqrt{3} \approx{8,660...}[/tex]

A general cosine function (we could also use a sine function) is written as:

y = A*cos(k*x + p) + M

We will find that the function of the graph is:

f(x) = 2*cos(2*x + 2.09) - 2

Let's return to the general function:

y = A*cos(k*x + p) + M

A is the amplitude, it defines the distance between the value of a maximum and the value of the minimum, such that A is exactly half of that difference.

Here we can see that the maximum is 0, and the minimum is -4

The differene is: 0 - (-4) = 4

Then:

A = 4/2 = 2

f(x) = 2*cos(k*x + p) + M.

M is the midline, this is, the horizontal line that cuts the graph in two halves. Here we can see that the midline is x = -2, then:

M = -2

f(x) = 2*cos(k*x + p) - 2

p is the phase shift.

In the graph, we can see that f(0) = -3, so we have:

f(0) = 2*cos(0 + p) - 2 = -3

      cos(p) = -1/2

             p = Acos(-1/2) = 2.09

Then we have:

f(x) = 2*cos(k*x + 2.09) - 2

Finally, k is related to the frequency of the function.

We can see that the function does a complete cycle at x = pi

This means that:

f(x) = f(x + pi)

Knowing that the period of a cosine function is 2*pi, then:

k*(x + pi) = k*x + 2*pi

k = 2

Then the equation of the graph is:

f(x) = 2*cos(2*x + 2.09) - 2

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Answer(s):

[tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2 \\ y = 2cos\:(2x - 1\frac{1}{4}\pi) - 2[/tex]

Step-by-step explanation:

[tex]\displaystyle y = Asin(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{-\frac{5}{8}\pi} \hookrightarrow \frac{-1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]

OR

[tex]\displaystyle y = Acos(Bx - C) + D \\ \\ Vertical\:Shift \hookrightarrow D \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \\ Amplitude \hookrightarrow |A| \\ \\ Vertical\:Shift \hookrightarrow -2 \\ Horisontal\:[Phase]\:Shift \hookrightarrow \frac{C}{B} \hookrightarrow \boxed{\frac{5}{8}\pi} \hookrightarrow \frac{1\frac{1}{4}\pi}{2} \\ Wavelength\:[Period] \hookrightarrow \frac{2}{B}\pi \hookrightarrow \boxed{\pi} \hookrightarrow \frac{2}{2}\pi \\ Amplitude \hookrightarrow 2[/tex]

You will need the above information to help you interpret the graph. First off, keep in mind that although this looks EXACTLY like the cosine graph, if you plan on writing your equation as a function of sine, then by all means, go for it, but be careful and follow what is explained here. Now, as you can see, the photograph on the right displays the trigonometric graph of [tex]\displaystyle y = 2sin\:(2x - 1\frac{1}{4}\pi) - 2,[/tex] in which you need to replase “cosine” with “sine”, then figure out the appropriate C-term that will make the graph horisontally shift and map onto the cosine graph [photograph on the left], accourding to the horisontal shift formula above. Also keep in mind that the −C gives you the OPPOCITE TERMS OF WHAT THEY REALLY ARE, so you must be careful with your calculations. So, between the two photographs, we can tell that the sine graph [photograph on the right] is shifted [tex]\displaystyle \frac{\pi}{4}\:unit[/tex] to the right, which means that in order to match the cosine graph [photograph on the left], we need to shift the graph BACKWARD [tex]\displaystyle \frac{\pi}{4}\:unit,[/tex] which means the C-term will be negative. Now, BEFORE we go any further, we must remember that this particular cosine graph [thank goodness it is a cosine graph we are working with] ALREADY has a horisontal shift and does not have a single crest oscıllαtıng about any endpoint on the y-axis. So, in this case we need to figure out how far the FIRST oscıllαtıng crest is from the origin, and that obviously would be [tex]\displaystyle \frac{5}{8}\pi\:units.[/tex] Though, sinse we want the sine equation of this graph, it must be “negative”; so, by perfourming your calculations, you will arrive at [tex]\displaystyle \boxed{-\frac{5}{8}\pi} = \frac{-1\frac{1}{4}\pi}{2},[/tex] in which the value of C is [tex]\displaystyle -1\frac{1}{4}\pi.[/tex] So, the sine equation of the cosine graph, accourding to the horisontal shift, is [tex]\displaystyle y = 2sin\:(2x + 1\frac{1}{4}\pi) - 2.[/tex] Now, with all that being said, in this case, sinse you ONLY have a graph to wourk with, you MUST figure the period out by using wavelengths. So, looking at where the graph hits [tex]\displaystyle [\frac{7}{8}\pi, -2],[/tex] from there to [tex]\displaystyle [-\frac{\pi}{8}, -2],[/tex] they are obviously [tex]\displaystyle \pi\:units[/tex] apart, telling you that the period of the graph is [tex]\displaystyle \pi.[/tex] Now, the amplitude is obvious to figure out because it is the A-term, but of cource, if you want to be certain it is the amplitude, look at the graph to see how low and high each crest extends beyond the midline. The midline is the centre of your graph, also known as the vertical shift, which in this case the centre is at [tex]\displaystyle y = -2,[/tex] in which each crest is extended two units beyond the midline, hence, your amplitude. So, no matter how far the graph shifts vertically, the midline will ALWAYS follow.

**As you can see, this is one of those moments where you will really need to be careful because if you notised, both equations have OPPOCITE horisontal shifts and C-values. Now, the ONLY TIME this occurs is when all crests in a SINUSOIDAL graph cycle half-way in between endpoints. Your best bet is to jot this down for when you see graphs like these in the future.

I am delighted to assist you at any time.

Answer:

Step-by-step explanation:

θ=l/r

θ=6/11 radians

≈0.555... radians

Answer:

100% - 76% = 24%

24% = 0.24

0.24*50 = 12

You got 12 questions wrong.

Step-by-step explanation:

Please mark brainliest!

Number of questions that got wrong are 12 .

Given,

76% on a 50 question test.

Here,

Let total percentage value be 100%.

Then,

100% - 76% = 24%

24% questions got wrong.

Number of questions that got wrong out of 50 will be ,

24% of 50

= 0.24*50

= 12

Therefore 12 questions got wrong.

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Answer:

always

Step-by-step explanation:

Zero is always greater than any negative integer.

Answer: C . 147π / 4 mi²

Concept:

The sector is the part of a circle is enclosed by two radii of a circle and their intercepted arc.

A = (θ / 360) πr²

θ = angle of the sector

π = constant

r = radius

Solve:

Given variable

θ = 270°

r = 7 mi

Given formula

A = (θ / 360) πr²

Substitute values into the formula

A = (270 / 360) π (7)²

Simplify exponents

A = (270 / 360) π 49

Simplify by multiplication

A = (147 / 4) π

A = 147π / 4

Hope this helps!! :)

Please let me know if you have any questions

Answer: 2, acute equilateral

Step-by-step explanation:

the image shows a triangle with all 3 sides congruent and 3 acute angles

Answer:

22/7, 23/7, 24/7, 25/7, 26/7, and 27/7.

Step-by-step explanation:

Answer:

cosA = 0.6

Step-by-step explanation:

Using the Pythagorean identity

sin²A + cos²A = 1 ( subtract sin²A from both sides )

cos²A = 1 - sin²A ( take the square root of both sides )

cosA = ± [tex]\sqrt{1-sin^2A[/tex]

Since only the positive value is required , then

cosA = [tex]\sqrt{1-(0.8)^2}[/tex]

         = [tex]\sqrt{1-0.64}[/tex]

         = [tex]\sqrt{0.36}[/tex]

         = 0.6

Answer:

Answer:

Answer:x = 25°

Answer:x = 25°Step-by-step explanation:

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2}

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 2

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2}

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 2

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )- x = - 25 ( multiply both sides by - 1 )

Answer:x = 25°Step-by-step explanation:The secant- secant angle FGE is one half the difference of the intercepted arcs, that is\frac{1}{2} 21 ( BD - FE ) = ∠ FGE, that is\frac{1}{2} 21 (135 - x) = 55 ( multiply both sides by 2 to clear the fraction )135 - x = 110 ( subtract 135 from both sides )- x = - 25 ( multiply both sides by - 1 )x = 25°

Answer:

(AB) is longer than (AC)

Step-by-step explanation:

1. Approach

Use the distance formula to find the length of the segments (AC) and (AB); substitute their endpoints into the distance formula and simplifying to solve for the length. After finding the length of each segment, compare their lengths to find out which of the statements is true. The distance formula is as follows:

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Where ([tex](x_1,y_1)[/tex]) and ([tex](x_2,y_2)[/tex]) are the endpoints of the segment.

2. Find the length of (AC)

Coordinates of point (A): [tex](-1,1)[/tex]

Coordinates of point (C): [tex](-4,4)[/tex]

Substitute these points into the distance formula,

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]D=\sqrt{((-1)-(-4))^2+((1)-(4))^2}[/tex]

Simplify,

[tex]D=\sqrt{((-1)-(-4))^2+((1)-(4))^2}[/tex]

[tex]D=\sqrt{(-1+4)^2+(1-4)^2}[/tex]

[tex]D=\sqrt{(3)^2+(-3)^2}[/tex]

[tex]D=\sqrt{9+9}[/tex]

[tex]D=\sqrt{18}[/tex]

3. Find the length of (AB)

Coordinates of point (A): [tex](-1,1)[/tex]

Coordinates of point (B): [tex](0,-4)[/tex]

Substitute these points into the distance formula,

[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]D=\sqrt{((-1)-(0))^2+((1)-(-4))^2}[/tex]

Simplify,

[tex]D=\sqrt{((-1)-(0))^2+((1)-(-4))^2}[/tex]

[tex]D=\sqrt{(-1-0)^2+(1+4)^2}[/tex]

[tex]D=\sqrt{(-1)^2+(5)^2}[/tex]

[tex]D=\sqrt{1+25}[/tex]

[tex]D=\sqrt{26}[/tex]

4. Find the correct statement

(AB) is longer than (AC)

This statement is true for the following reason:

[tex]\sqrt{18}>\sqrt{26}[/tex]

Answer:

a) 7085g

b) 6346g

c) 5342g

Step-by-step explanation:

1kg = 1000g

Answer:

10/3

Step-by-step explanation:

rate of change = gradient

(17-7)/(6-3) = 10/3

basically difference of y values / difference of x values

Step-by-step explanation:

> 2n³+4²+6n-6n-21

2n³+4n²-21

> -4n²-3n-8+2n+18

-4n²-3n-8+2n+18

-4n²-n-8+18

-4n²-n+10

Answer: 4. A base area of 16y^2 square units and height of y^2 + y + 3 units

Step-by-step explanation:

Using the distributive property; you can see that 16y^2(y^2+y+3)=

16y^4+16y^3+48y^2

Answer:

D. a base area of 16y2 square units and height of y^2 + y + 3 units

Step-by-step explanation:

Ed22

Answer:

13/45

Step-by-step explanation:

x = .2888888888

100(x + .2888888)

100x + 28.8888

 10x + 2.88888

90x = 26

x = 26/90 = 13/45

D is a vertical angle to the given 159 degrees.

E + D need to equal 180 degrees.

E = 180 - D

E = 180 - 159

E  = 21 degrees

Answer: 21 degrees.

Answer: e = 21°

Step-by-step explanation:

Angle d will be 159° because alternate exterior angles are equal.

Now angle e + angle d = 180 because they form linear pair

e + d = 180

e + 159 = 180

e = 180-159

e = 21

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Answer:

π - irrational

0.04053.. - irrational

0.76 - rational

3.565565565 - irrational

-17 - rational

3.275 - rational

Step-by-step explanation:

rational = can express as fraction

irrational = cannot

Answer:

(-2,4] and [7,α)

Step-by-step explanation:

the domain is open at -2 but closed at 4 and also closed at 7 but open till infinity..

The domain of the given function is (-2,4] U [7, ∞), which is the correct option (B).

A piecewise-defined function (also known as a piecewise function or a hybrid function) is a function defined by multiple sub-functions, each of which applies to a different interval of the main function's domain (a sub-domain).

The graph is given in the question, as shown

f(x) = x²+1 if (-2,0]

This the sub-function define between the interval (-2,0].

f(x) = -1 if (0, 4]

This the sub-function define between the interval (0, 4].

f(x) = -(x-7)² if [7, ∞)

This the sub-function define between the interval [7, ∞).

Thus, the domain of the given function is (-2,4] U [7, ∞).

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Answer:

1 mile = 5280 feet, then

Find 1000 feet in miles:

[tex]\\ \sf\longmapsto 1feet= \dfrac{1}{5280}miles[/tex]

Now

[tex]\\ \sf\longmapsto 1000feet[/tex]

[tex]\\ \sf\longmapsto 1000\times \dfrac{1}{5280}[/tex]

[tex]\\ \sf\longmapsto \dfrac{1000\times 1}{5280}[/tex]

[tex]\\ \sf\longmapsto \dfrac{1000}{5280}[/tex]

[tex]\\ \sf\longmapsto 0.18miles[/tex]

Answer:

right by 3 I think

Step-by-step explanation:

Answer: Right by 3 Units

Step-by-step explanation:

Right on edge 2021

Answer:

could u take a picture of the angles please

Step-by-step explanation:

Answer:

surface area of a square = 2 ( lb + bh + hl )

given that,

length = 8cm

breadth = 10cm

height = 15 cm

surface area = 2 ( 8* 10 + 10*15 + 15*8 )

                     = 2 ( 80 + 150 + 120 )

                     = 2 * 350

                     = 700 [tex]cm^{2}[/tex]

hope this answer helps you!!

Answer:

Step-by-step explanation:

In the equation y = mx + b, which is the form Ingrid's equation is in, the m stands for the rate of change. If the water level is decreasing, the rate at which it is decreasing is what goes in for m. The "b" of that equation indicates the starting height of the water, which is 170. The equation should be:

y = -4x + 170, negative because the water is decreasing.

Answer:

45 hours

Step-by-step explanation:

1 mile * 1609 meters  *     1 s           = 160900 sec

               1 mile               .01 meters

160900 sec / 60 /60 = 44.7 = 45 hours

Step-by-step explanation:

This is a cute question lol.

So this lil snail is trying to go 1609 meters, at a speed of 0.01 m/s (meters per second). Lets see how long that takes.

The way I like to do conversion problems is by starting with the value that doesn't have something on the bottom (1609 m) then multiplying to get rid of that variable.

I'll show you what I mean:

[tex]\frac{1609 m}{1} *\frac{1 s}{0.01 m} *\frac{1 min}{60s} *\frac{1 hr}{60 min}[/tex]

Then, we just multiply everything.

[tex]\frac{1609 *1*1}{1*0.01*60*60}hr[/tex]

Simplify.

[tex]\frac{1609}{36}hr[/tex]

Divide.

[tex]44.694444444...hr[/tex]

Round to the nearest whole hour.

[tex]45 hr[/tex]

Answer:

45 hours

Answer:

125g:1Kg

=> 125g : 1000g

Answer:

1:8

Step-by-step explanation:

125 g:1 kg

125g:1000 g

1 g:8 g

Keep smiling and hope u will be satisfied with my answer.Have a good day :)

Answer:

$17.5

Step-by-step explanation:

original price of shirt=$25

discount on shirt=30%

discount on shirt in $=$25*30%

discount on shirt=$7.5

cost of shirt after discount=origanl price-discount

=$25-$7.5

=$17.5

Answer:

Step-by-step explanation:

Remark

I have to assume that you know calculus. It is the only way the problem can be done that I know of. If you don't, I'm not sure how you will do this.

The curve is of y  = e^(-2x) + x^2 - 3

The curve crosses the y axis when x = 0. The y value is

y = e^0 + x^2 - 3

yint = 1 + 0 - 3

yint = -2

The slope at point (0,-2) is

y' = -2e^(-2x) +2x

y' = -2 at point A

Therefore the normal will have a slope

m1 * m2 = - 1

The slope of the curve C  at A = -2

The equation of the tangent line at A = -2x - 2

Call this m1

m2 = slope of the normal

-2 * m2 = -1

m2 = 1/2

Equation of the line (l) =

y = 1/2 x  - 2

The graph is shown below. Notice the two lines actually look like they are at a 90 degree angle.

Answer:

RS, RT, ST

Step-by-step explanation:

We require the third angle in the triangle

∠ T = 180° - (92 + 71)° = 180° - 163° = 17°

The shortest side is opposite the smallest angle

∠ T = 17° → opposite side RS

The longest side is opposite the largest angle

∠ R = 92° → opposite side ST

Then sides from shortest to longest is

RS, RT, ST