Another of Bhaskara's problems results in a quadratic equation Parthava was enraged and seized a certain number of arrows to slay Karna. He expended one-half of them in defending himself. Four times the square root of the number of arrows were discharged against the horses. With six more, he transfixed Shalya, the charioteer. With three more, he rent the parasol, the standard, and the bow; and with the last one he pierced the head of Karna. How many arrows did Parthava have?
Answer:
Parthava had 100 arrows.
Step-by-step explanation:
Let's define N as the number of arrows that Parthava originally has.
He uses one-half of them in defending himself, so he used N/2 arrows
Now he uses four times the square root of the number of arrows, so now he uses:
4*√N
Then he uses 6
Then he uses 3
Then he uses the last one.
If we add all these numbers of arrows that he used, we should get the initial number of arrows that he used, then:
N/2 + 4*√N + 6 + 3 + 1 = N
Now we have an equation that we can try to solve.
First, let's move all the terms to the same side:
N/2 + 4*√N + 6 + 3 + 1 - N = 0
now we can simpify it:
(N/2 - N) + 4*√N + (6 + 3 + 1) = 0
-(1/2)*N + 4*√N + 10 = 0
Now we can define a new variable x = √N
Then we have: x^2 = N
now we can replace these new variables in our equation to get:
-(1/2)*x^2 + 4*x + 10 = 0
Now we just have a quadratic equation.
Remember that for a quadratic equation of the form:
0 = a*x^2 + b*x + c
The solutions were given by:
[tex]x = \frac{-b \pm \sqrt{b^2 - 4*a*c} }{2a}[/tex]
Then in our case, the solutions will be:
[tex]x = \frac{-4 \pm \sqrt{4^2 - 4*(-1/2)*10} }{2*(-1/2)} = \frac{-4 \pm 6 }{-1} = 4 \pm 6[/tex]
So there are two solutions:
x = 4 + 6 = 10
x = 4 - 6 = -2
And remember that x = √N
Then x should be positive, then we take x = 10 as our solution here.
then we can use the equation:
x = 10 = √N
then
10^2 = √N^2 = N
10^2 = 100 = N
Parthava had 100 arrows.
find the missing length indicated
Answer:
x = 240
Step-by-step explanation:
Apply the leg rule to find the value of x.
Leg rule is given as:
Hypotenuse/leg 1 = leg 1/part 1
Hypotenuse = 400
Leg 1 = x
Part 1 = 144
Plug in the known values into the formula
400/x = x/144
Cross multiply
x*x = 144*400
x² = 57,600
Take the square root of both sides
√x² = √57,600
x = 240
equivalent expression: 3 + 4(2z - 1)
Answer:
8z - 1
Step-by-step explanation:
Given
3 + 4(2z - 1) ← multiply each term in the parenthesis by 4
= 3 + 8z - 4 ← collect like terms
= 8z - 1
Answer:
-1 + 8z
Step-by-step explanation:
First use the distributive property of multiplication (Just multiply 4 with all numbers in the parenthesis):
3 + 4(2z - 1)
3 + 8z - 4
Group like terms:
3 + 8z - 4
-1 + 8z
The answer is -1 + 8z
Hope this helped.
ncert maths class 10 solution 5.1 4
Can you attach a picture to your question?
I would love to help you out.
Answer:
Step-by-step explanation:
NCERT Solutions for Class 10 Maths Chapter 5 Arithmetic Progressions Ex 5.1
where is question ??
Please Help !
Which of the following describes point D? (-4, 0) (0, -4) (0, 4) (4, 0)
Answer:
D(0 , 4)
Step-by-step explanation:
Point D is on the y axis. So, x-coordinate = 0
y- coordinate is the vertical length from origin which is 4
Answer:
D(0 , 4)
Step-by-step explanation:
please answer this question!!
Answer:
a
Step-by-step explanation:
all angles of an equilaterall triangle are equal therefore 180÷3 = 60
Rob cuts a circular hole out of a rectangular piece of paper. The paper measures 20 centimeters by 30 centimeters. The hole is 10 centimeters in diameter. How much of the piece of paper, in square centimeters, is left over after the hole is cut out?
Answer:
521.25
Step-by-step explanation:
the circle is 78.75 in area and the square is 600 so 600- 78.75 = 521.25
If a wheel has a radius of 5cm
how much is one rotation of the wheel
How many rotations can the wheel do within a distance of 50km
Answer:
circumference = 2*PI*radius
circumference = 2 * PI * 5 cm
circumference = 31.4159265358979 cm
50 km = 500,000 centimeters
rotations = 500,000 / 31.4159 cm
15,915.51 rotations
Step-by-step explanation:
Jim removed 27 gallons of water from a rainwater storage tank. There are 59 gallons left in the tank. What equation can Jim use to find how much water was in the tank earlier? Use x to represent the amount of water originally in the tank.
Answer: X = 86 gallons
Step-by-step explanation:
X-27=59
X=59+27
NEED HELP ASAP!!!!!!!
Answer the question to get points
Answer:
4. E=4x-15(vertically opposite)
F=E(corresponding angles)
E=4x-15
5.3x+6x+O=180(angles on a straight line)
9x+0=180
9x=180-0
9x/9=180/9
x=20
Find all complex numbers z such that z^4 = -4.
Note: All solutions should be expressed in the form a+bi, where a and b are real numbers.
(cos^2x-sin^2x)-sin4x+sin^22x=0
Answer:
x=22.5
Step-by-step explanation:
(there's a correction in the question since the I did this one before, so I know)
(cos²x-sin²x)²-sin4x+sin²2x=0
or, cos²2x-sin4x+sin²2x=0
or, 1-sin4x=0
or, sin4x=1
or, 4x=90
or, x=22.5
How many solutions does the system have?
⎪
⎪
⎨
⎪
⎪
⎧
x+y=3
5x+5y=15
Lorraine writes the equation shown. x²+4-15=0 She wants to describe the equation using the term relation and the term function. The equation represents a relation and a function a relation but not a function a function but not a relation neither a relation nor a function
Answer:
Neither a relation nor a function
Step-by-step explanation:
A relation in mathematics is a relationship between two or more set of values in an ordered pair, such as related x and y-values
An equation is a statement that gives declare the equality between two expressions
A function is a mapping rule that maps each element in the domain set to only one element in the range set
Therefore, the given equation in one variable, x, that asserts the equality of the expressions on the left and right hand side, is neither a relation nor a function
Solve 4 sinx + 9 cosx=0 for 0°
4 sin(x) + 9 cos(x) = 0
4 sin(x) = -9 cos(x)
tan(x) = -9/4
x = arctan(-9/4) + nπ … … … (in radians)
or
x = arctan(-9/4) + 180n ° … … … (in degrees)
where n is any integer.
I'm guessing you're solving for x over some domain, probably 0° ≤ x < 360°. In that case, you would have two solutions for n = 1 and n = 2 of
x ≈ 113.96° and x ≈ 293.96°
the polygons in each pair are similar. find the scale factor of the smaller figure to larger figure.
Answer:
Scale factor = [tex]\frac{1}{2}[/tex]
Step-by-step explanation:
From the picture given in the question,
If the larger figure is dilated to form the smaller figure,
Scale factor by which a figure is dilated with is determined by the expression,
Scale factor = [tex]\frac{\text{Measure of one side of the smaller figure}}{\text{Measure of the corresponding side of the larger figure}}[/tex]
= [tex]\frac{3}{6}[/tex]
= [tex]\frac{1}{2}[/tex]
Find the values of x and y if (-x + 5, 1) = (-y, 2x - 5y).
Answer:
x = 8, y = 3
Step-by-step explanation:
Equating corresponding x and y coordinates , then
- y = - x + 5 ( multiply through by - 1 )
y = x - 5 → (1)
2x - 5y = 1 → (2)
Substitute y = x - 5 into (2)
2x - 5(x - 5) = 1 ← distribute and simplify left side
2x - 5x + 25 = 1
- 3x + 25 = 1 ( subtract 25 from both sides )
- 3x = - 24 ( divide both sides by - 3 )
x = 8
Substitute x = 8 into (1) for corresponding value of y
y = 8 - 5 = 3
Plz help similarity theorems
Answer:
b is the answer bro and try first then ask questions
Find the area of the bolded outlined sector.
Outlined sector:
2 πr x 225/360 +2r
=2x3.14x10 x 225/360 +20
=59.25 cm
Hope this helped!
Find the length of the third side. If necessary, round to the nearest tenth. 16 12
Answer:
20
Step-by-step explanation:
Use the Pythagorean theorem. a^2+b^2=c^2
12^2+16^2=c^2
144+256=c^2
400=c^2
20=c
Determine the quotient of .    
Can somebody help me with this problem. And make sure that u can explain how to do it don't just give me the answer.
Answer:
x=50
Step-by-step explanation:
Look at the triangle as a whole. This is a 30-60-90 triangle by speculation. You can see that the hypotenuse is equal to 100. By using sine (you can use cosine as well) , you get the expression, "(sin 30 degrees) = x/100" since sin is the opposite side over the hypotenuse. Do some basic trigonometry to get "1/2 = x/100". By now, you should know that 50/100 is the same as 1/2.
if A is a subset and equal to B then B'-A' is equal to
Answer:
A-B
Step-by-step explanation:
It doesn't say A=B... But just that A is a subset of B.
Anyways, why not try an example to help reveal the answer.
Let the universe set, U, be U={1,2,3,4,5,6}.
Let B={1,2,3,4} and A={1,3,5}
First choice would become A'={2,4,6}
Second choice would become B'={5,6}
Third choice would become A-B={5}
Fourth choice is just { }
B'-A'={5}
The only choice matching is A-B
*Just so you know X-Y is the set of elements contained in X only if they are not also in Y.
Which angles are adjacent to each other?
Angle CHG and Angle HDL
Angle AEB and Angle DEA
Angle CHG and Angle HCE
Angle JCH and Angle CHG
Please make sure it's correct because one person once tried it and got it wrong..lol.
Answer:
B
Step-by-step explanation:
Adjacent angles must have the same vertex, so if the middle letter of the three letters used to name each of the angles in a pair are not the same, the angles cannot be adjacent.
That eliminates choices A, C, and D.
Answer: B
Look in the picture first below. Each pair of angles with the same vertex marked in blue is a pair of adjacent angles. For two angles to be adjacent angles, they must be next to each other, have the same vertex, and one cannot be inside the other.
Now look in the second picture below. Each pair of angles marked in red is not a pair of adjacent angles. Some of them are not next to each other. Others have one angle inside the other.
help someone!! which one is it?
Answer:
not great with math but I'm sure it's the second circle
Find the height of the triangle by applying formulas for the area of a triangle and your knowledge about triangles.
This is a triangle. side a has a length of 6 yards. side b has a length of 10 yards. side c has a length of 14 yards. The altitude to side c has a length of X yards. what is x
Answer:
3.71 yd
Step-by-step explanation:
Heron's formula:
area = 0.25 * √((a + b + c) * (-a + b + c) * (a - b + c) * (a + b - c))
so h = 0.5 * √((a + b + c) * (-a + b + c) * (a - b + c) * (a + b - c)) / c
a = 6
b = 10
c = 14
a+b+c = 30
-a+b+c = 18
a-b+c = 10
a+b-c = 2
x = h = 0.5×sqrt(30×18×10×2)/14 = sqrt(30×18×10×2)/28 =
= sqrt(10800)/28 = sqrt(400×9×3)/28 =
= 20×3×sqrt(3)/28 = 60×sqrt(3)/28 = 15×sqrt(3)/7 =
= 3.711537 yd
Geometry, please answer question ASAP
Answer:
m<D = 170°
Step-by-step explanation:
In a pentagon, the angles add up to 540°. This means the sum of <A, <B, <C, <D, and <E add up to that, and we can write an equation:
m<A + m<B + m<C + m<D + m<E = 540°
We are already given the measures of all the angles except D, so we can substitute them in:
87° + 125° + 63° + m<D + 95° = 540°
Now, we can simplify and solve for <D:
m<D + 370° = 540°
m<D = 170°
Convert 5π∕6 radians to degrees. Question 1 options: A) 25° B) 150° C) 150π° D) 1080°
Step-by-step explanation:
Hi there!
Given;
= 5(π\6)
We have;
π = 180°
Keeping value of π in the question;
= 5(180°/6)
= 5*30°
= 150°
Therefore, answer is option B.
Hope it helps!
Pressure varies inversely as volume. When the pressure is 8 Pascals, the volume is 22 liters. What would the volume be if the pressure were increased to 16 pascals?
Answer:
we can use 2 formule to solve your question: One is P*V=n(mol)*R*T(KELVIN)
Step-by-step explanation:
And other is P(first)*V(first)=P(last)*V(last)
8*22=16*?
the ?=11