Answer:
1 - 1/3
Step-by-step explanation:
Since 1/2 * 2/3 = 1/3, it should be the case that 1/3 divided by 2/3 gives 1/2 and that 1/3 divided by 1/2 gives 2/3. To divide fractions, we multiply the numerator by the reciprocal of the denominator, where the reciprocal of a number just interchanges the numerator and denominator of the number.
i need help trying to solve this question to the nearest tenth of a degree
I just need to know how I would be able to find x
Answer:
[tex]x=15[/tex]°
Step-by-step explanation:
The sum of degree measures in a full angle (a circle) is (360) degrees. This means that the sum of all of the angles in this diagram is (360) degrees, as the angles form a full arc. Therefore, one can form an equation by adding up all of the angles and setting the equation equal to (360) degrees. Then one can substitute each angle value with the equation that is used to represent it, simplify, and use inverse operations to solve for the value of (x).
[tex](m<AMB)+(m<BMC)+(m<CMD)+(m<AMD)=(360)[/tex]
Substitute,
[tex](46)+(4x-2)+(9x+6)+(8x-5)=360[/tex]
Simplify,
[tex](46)+(4x-2)+(9x+6)+(8x-5)=360[/tex]
[tex]21x+45=360[/tex]
Inverse operations,
[tex]21x+45=360[/tex]
[tex]21x=315[/tex]
[tex]x=15[/tex]
An x-method chart shows the product a c at the top of x and b at the bottom of x. Below the chart is the expression a x squared + b x + c. What are the factors of x2 – 144? And
Answer:
[tex](x -12)(x + 12)[/tex]
Step-by-step explanation:
Given
See attachment for chart
Required
The factors of [tex]x^2 - 144[/tex]
First, express [tex]x^2 - 144[/tex] as [tex]ax^2 + bx + c[/tex]
So, we have:
[tex]x^2 - 144 = x^2 + 0x - 144[/tex]
Compare the above expression to: [tex]ax^2 + bx + c[/tex]
We have:
[tex]ax^2 + bx + c = x^2 + 0x - 144[/tex]
So:
[tex]a =1[/tex]
[tex]b =0[/tex]
[tex]c = -144[/tex]
and
[tex]a * c = d * e[/tex]
Calculate ac
[tex]a* c = 1 * -144[/tex]
[tex]a* c = -144[/tex]
Rewrite as:
[tex]a* c = -12 * 12[/tex]
Recall that:
[tex]a * c = d * e[/tex]
Hence:
[tex]d = -12; e = 12[/tex]
So, on the x chart, we have:
ac
d e
b
This gives:
-144
-12 12
0
The factors are
[tex](x + d)(x + e)[/tex]
[tex](x -12)(x + 12)[/tex]
Answer:
✔ (x – 12)
and
✔ (x + 12)
Step-by-step explanation:
The length of a side of an equilateral triangle is 40 centimeters.
What is the length of the altitude of the triangle?
Answer:
34.64 cm
Step-by-step explanation:
sin 60 = [tex]\frac{x}{40}[/tex]
sin 60 (40) = x
34.64 = x
equilateral triangles have 60° angles.
sin Ф = [tex]\frac{opposite}{hypotenuse}[/tex]
hypotenuse is 40. All sides are 40.
x = opposite or height of triangle.
Find the area of the figure below
Answer:
35.2 cm²Step-by-step explanation:
The area is:
A = 2(3.5*2) + 7*2 + 2(1.8*2) = 35.2 cm²We can find the area,
→ 2(3.5 × 2)+ (7 × 2) + 2(1.8 × 2)
→ 14 + 14 + 7.2
→ 35.2 cm²
Thus, the area is 35.2 cm².
HELP PLEASE 50 points !!! Given a polynomial function describe the effects on the Y intercept, region where the graph is increasing and decreasing in the end behavior when the following changes are made make sure to account for even and odd functions
When f(x) becomes -f(x)+ 2
When f(x) becomes f(x+3)
Even function:
A function is said to be even if its graph is symmetric with respect to the , that is:
Odd function:
A function is said to be odd if its graph is symmetric with respect to the origin, that is:
So let's analyze each question for each type of functions using examples of polynomial functions. Thus:
FOR EVEN FUNCTIONS:
1. When becomes
1.1 Effects on the y-intercept
We need to find out the effects on the y-intercept when shifting the function into:
We know that the graph intersects the y-axis when , therefore:
So:
So the y-intercept of is one unit less than the y-intercept of
1.2. Effects on the regions where the graph is increasing and decreasing
Given that you are shifting the graph downward on the y-axis, there is no any effect on the intervals of the domain. The function increases and decreases in the same intervals of
1.3 The end behavior when the following changes are made.
The function is shifted one unit downward, so each point of has the same x-coordinate but the output is one unit less than the output of . Thus, each point will be sketched as:
FOR ODD FUNCTIONS:
2. When becomes
2.1 Effects on the y-intercept
In this case happens the same as in the previous case. The new y-intercept is one unit less. So the graph is shifted one unit downward again.
An example is shown in Figure 1. The graph in blue is the function:
and the function in red is:
So you can see that:
2.2. Effects on the regions where the graph is increasing and decreasing
The effects are the same just as in the previous case. So the new function increases and decreases in the same intervals of
In Figure 1 you can see that both functions increase at:
and decrease at:
2.3 The end behavior when the following changes are made.
It happens the same, the output is one unit less than the output of . So, you can write the points just as they were written before.
So you can realize this concept by taking a point with the same x-coordinate of both graphs in Figure 1.
FOR EVEN FUNCTIONS:
3. When becomes
3.1 Effects on the y-intercept
We need to find out the effects on the y-intercept when shifting the function into:
As we know, the graph intersects the y-axis when , therefore:
And:
So the new y-intercept is the negative of the previous intercept shifted one unit upward.
3.2. Effects on the regions where the graph is increasing and decreasing
In the intervals when the function increases, the function decreases. On the other hand, in the intervals when the function decreases, the function increases.
3.3 The end behavior when the following changes are made.
Each point of the function has the same x-coordinate just as the function and the y-coordinate is the negative of the previous coordinate shifted one unit upward, that is:
FOR ODD FUNCTIONS:
4. When becomes
4.1 Effects on the y-intercept
In this case happens the same as in the previous case. The new y-intercept is the negative of the previous intercept shifted one unit upward.
4.2. Effects on the regions where the graph is increasing and decreasing
In this case it happens the same. So in the intervals when the function increases, the function decreases. On the other hand, in the intervals when the function decreases, the function increases.
4.3 The end behavior when the following changes are made.
Similarly, each point of the function has the same x-coordinate just as the function and the y-coordinate is the negative of the previous coordinate shifted one unit upward.
Please help me... I stink at math
Answer:
142 [tex]cm^3\\[/tex]
Step-by-step explanation:
You have to do [tex](7*5)+(5*3)+(7*3)+(7*3)+(5*7)+(3*5)[/tex].
This equals 142 [tex]cm^3\\[/tex].
Answer:
The answer is 142cm
Step-by-step explanation:
plz help ASAP with explanation
Answer:
(in image attached)
Step-by-step explanation:
A.
Left: 6×-3
Right: -3×-2
Bottom: 6×-2
B.
48÷6 = 8
-42÷6 = -7
-56÷8 = -7
-56÷-7= 8
lic/activity/6000001/assessment
1 Pretest: Unit 6
Question 1 of 21
What is the domain of the exponential function shown below?
Rx) = 5.3x
Given:
The exponential function is:
[tex]R(x)=(5.3)^x[/tex]
To find:
The domain of the given exponential function.
Solution:
We know that the general form of an exponential function is:
[tex]f(x)=ab^x[/tex]
Where, a is the initial value and b is growth/decay factor.
This function is defined for all real values of x, so the domain of these type of functions is the set of all real number.
We have,
[tex]R(x)=(5.3)^x[/tex]
Here, a is 1 and b is 5.3. This function is defined for all real values of x
Therefore, the domain of these type of functions is the set of all real number or it can be written as [tex](-\infty,\infty)[/tex].
Find the area of the region between the curve x^3+2x^2-3x and the x-axis over the interval [-3,1]
Answer:
[tex]\displaystyle A = \frac{32}{3}[/tex]
General Formulas and Concepts:
Calculus
Integrals
Definite IntegralsArea under the curveIntegration Rule [Reverse Power Rule]: [tex]\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C[/tex]
Integration Rule [Fundamental Theorem of Calculus 1]: [tex]\displaystyle \int\limits^b_a {f(x)} \, dx = F(b) - F(a)[/tex]
Integration Property [Multiplied Constant]: [tex]\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx[/tex]
Integration Property [Addition/Subtraction]: [tex]\displaystyle \int {[f(x) \pm g(x)]} \, dx = \int {f(x)} \, dx \pm \int {g(x)} \, dx[/tex]
Area of a Region Formula: [tex]\displaystyle A = \int\limits^b_a {[f(x) - g(x)]} \, dx[/tex]
Step-by-step explanation:
Step 1: Define
Identify
Curve: x³ + 2x² - 3x
Interval: [-3, 1]
Step 2: Find Area
Set up: [tex]\displaystyle A = \int\limits^1_{-3} {(x^3 + 2x^2 - 3x)} \, dx[/tex][Integral] Rewrite [Integration Property - Addition/Subtraction]: [tex]\displaystyle A = \int\limits^1_{-3} {x^3} \, dx + \int\limits^1_{-3} {2x^2} \, dx - \int\limits^1_{-3} {3x} \, dx[/tex][Integrals] Rewrite [Integration Property - Multiplied Constant]: [tex]\displaystyle A = \int\limits^1_{-3} {x^3} \, dx + 2\int\limits^1_{-3} {x^2} \, dx - 3\int\limits^1_{-3} {x} \, dx[/tex][Integrals] Integrate [Integration Rule - Reverse Power Rule]: [tex]\displaystyle A = (\frac{x^4}{4}) \bigg| \limits^1_{-3} + 2(\frac{x^3}{3}) \bigg| \limits^1_{-3} - 3(\frac{x^2}{2}) \bigg| \limits^1_{-3}[/tex]Evaluate [Integration Rule - Fundamental Theorem of Calculus 1]: [tex]\displaystyle A = -20 + 2(\frac{28}{3}) - 3(-4)[/tex]Evaluate: [tex]\displaystyle A = \frac{32}{3}[/tex]Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Integration
Book: College Calculus 10e
Determine the value of x.
8 2
8 3
4
8
Answer:
Step-by-step explanation:
the width of a newspaper is 13 3/4 inches. The left margin is 7/16 inch and the right margin is 1/2 inch. what is the width of the written page inside the margin?
Answer:
biggafigure a
mnn
Step-by-step explanation:
Which is the graph of the linear inequality x - 2y > -6?
-10-
2
108
0
o
Answer:
the fourth option
Step-by-step explanation:
1/2x - 2y > -6
1/2x + 6 > y
or
y < 1/2x + 6
so, the solution is all the y values smaller (= below) the line function.
and because it is "<" and not "<=" the line itself is not included
Solve the system of equations.
−5x−3y−9=0
4x−18y−54=0
y=? x=?
Answer:
Step-by-step explanation:
Eq. 1 ) −5x−3y−9=0
Eq. 2) 4x−18y−54=0
there are two routes to solve this, Substitution or elimination, I'll go for the 2nd one because I can see that the y values are a multiple of each other :)
6 *( −5x−3y−9=0 )
Eq. 3) -30x -18y =54
subtract Eq. 2 from Eq. 3 :)
-30x -18y =54
-( 4x−18y=54)
-34x = 0
so according to the equations then x =0 but, that's not really a full answer, so now we should go back and try the other method, substitution,
then:
-5x = 9 +3y
x = - 9/5 + (-3/5)y
now plug that into Eq. 2
4( - 9/5 + (-3/5)y ) - 18y = 54
-36/5 + (-12/5)y -18y = 54
(-12/5)y - (90/5)y = 54+36/5
-(102/5)*y =270/5+36/5
-(102/5)y = 306/5
y = (-5/102)*(306/5)
y = -306/102
y = -3
then plug in for either equation
-5x-3( -3) = 9
-5x + 9 = 9
-5x = 0
x = 0
now we have the full answer
check it by plugging in both x and y into the 2nd equation
4(0) - 18(-3) = 54
54= 54
this seems good
someone help me with my algebra homework please
Answer:
D.
Step-by-step explanation:
x = number of glasses of iced tea
y = number of glasses of lemonade
The total number of glasses is
x + y
The total number of glasses is 44
x + y = 44
This is not a choice, but the answer must be equivalent to this equation.
Solve for x by subtracting y from both sides.
x = 44 - y
Answer: D.
Given that the expression 2x^3 + mx^2 + nx + c leaves the same remainder when divided by x -2 or by x+1 I prove that m+n =-6
Given:
The expression is:
[tex]2x^3+mx^2+nx+c[/tex]
It leaves the same remainder when divided by x -2 or by x+1.
To prove:
[tex]m+n=-6[/tex]
Solution:
Remainder theorem: If a polynomial P(x) is divided by (x-c), thent he remainder is P(c).
Let the given polynomial is:
[tex]P(x)=2x^3+mx^2+nx+c[/tex]
It leaves the same remainder when divided by x -2 or by x+1. By using remainder theorem, we can say that
[tex]P(2)=P(-1)[/tex] ...(i)
Substituting [tex]x=-1[/tex] in the given polynomial.
[tex]P(-1)=2(-1)^3+m(-1)^2+n(-1)+c[/tex]
[tex]P(-1)=-2+m-n+c[/tex]
Substituting [tex]x=2[/tex] in the given polynomial.
[tex]P(2)=2(2)^3+m(2)^2+n(2)+c[/tex]
[tex]P(2)=2(8)+m(4)+2n+c[/tex]
[tex]P(2)=16+4m+2n+c[/tex]
Now, substitute the values of P(2) and P(-1) in (i), we get
[tex]16+4m+2n+c=-2+m-n+c[/tex]
[tex]16+4m+2n+c+2-m+n-c=0[/tex]
[tex]18+3m+3n=0[/tex]
[tex]3m+3n=-18[/tex]
Divide both sides by 3.
[tex]\dfrac{3m+3n}{3}=\dfrac{-18}{3}[/tex]
[tex]m+n=-6[/tex]
Hence proved.
Which method is used in elimination to find the solutions of a - b = 9 and a + b = 5?
The substitution method is used in elimination to find the solution to the equation.
What is the system of two equations?A set of two linear equations with two variables is called a system of linear equations. They create a system of linear equations when evaluated collectively.
The given equation in the problem is;
Equation P: a - b = 9
Equation Q: a+b=5
The value obtained from the equation P is;
a - b = 9
a=b+9
Substitute the value in the equation Q;
a+b=5
b+9+b=5
2b=9-5
b=2
The value of a is;
a-b=9
a-2=9
a=9+2
a=11
Hence the value of a and b will be 11 and 2.
To learn more about the system of two equations, refer to the link;
https://brainly.com/question/21620502
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What is the measure of angle ABC of a circle
Answer:
the angle <ABC is equal to 65°
which graph best represents the line y= -1/5x+2
Answer:
B
Step-by-step explanation:
Line crosses y-axis at 2.
Slope = [tex]\frac{-1}{5}[/tex]
For each 1 square the line rises/falls it moves to the right/left 5 squares.
Negative slope lines are downhill left to right.
The correct graph to represent the line y = -1/5 x + 2 will be;
⇒ Graph 2
What is Equation of line?
The equation of line with slope m and y intercept at point b is given as;
y = mx + b
Given that;
The equation of line is;
⇒ y = - 1/5 x + 2
Now,
The standard form of the equation of line with slope m and y intercept at point b is given as;
y = mx + b
By comparing we get;
Slope (m) = - 1/5
In the second figure;
Let two points on the graph (0, 2) and (5 , 1).
So, Slope is defined as;
m = (1 - 2) / (5 - 0)
m = - 1 / 5
And, Clearly the y - intercept is at point 2.
Therefore,
Graph 2 shows the correct graph to represent the line y = -1/5 x + 2.
Learn more about the equation of line visit:
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can anyone help with integers?
Fill in the blanks.
6) 83 + 17 = 17 +
7) |46| – |50| =
8) 42 – 2 + (18 – 10) =
9) 18 – (3 – 1) =
10) 8 - 0 =
Answer:
a) 83,b) -4,c) 48,d) 16,e) 8
The perimeter of a square is 16 cm. Find the length of its diagonal.
Answer:
perimeter of a square is l+l+l+l
16+16+16+16=64
Answer:
4√2 cm
Step-by-step explanation:
Perimeter of square = 4a = 16cm
a = 16 / 4
a = 4 cm
Length of each side = 4 cm
Diagonal^2 = side^2 + side^2
= 4^2 + 4^2
= 16 + 16
Diagonal^2 = 32
Diagonal = 4√2 cm
Someone please help me ASAP!
Answer:
y axis then translate x+1,y+1
Maria has 72 flowers and four vases she put the same number of flowers in each vase how many flowers are in one vase
Find the measures of the angles formed by two intersecting lines if the
sum of the measures of three of the four angles is 270°
50 points! Please help quick!
Answer:
every single angle is 90°
Step-by-step explanation:
remember that,
4 angles will form if two lines intersect and the sum of those 4 angles is 360°
we are given the sum of 3 angles i.e 270
so one of the angles should be
[tex] \displaystyle {360}^{\circ} - {270}^{\circ}[/tex]
simplify substraction:
[tex] \displaystyle {90}^{\circ}[/tex]
therefore since one of the angles is 90° the intercepting lines are Perpendicular as a result every single angle formed by the two intercepting lines is 90°
Answer:
90°
Step-by-step explanation:
We know that sum of angle around a point is 360° . Here its already given that sum of three Angles out of 4 is 270°
Therefore :-
Measure of remaining one angle ,
360 - 270 90 °Therefore the measure of the fourth angle is 90°
Mr. Lord borrowed $100,000 from a bank at a rate of 8% per annum for 3 years. Calculate the amount accruing for the loan
Answer: [tex]\$125,971.2[/tex]
Step-by-step explanation:
Given
Principal amount [tex]P=\$100,000[/tex]
Rate of interest [tex]r=8\%[/tex]
Time period [tex]t=3\ yr[/tex]
Amount in compound interest is given by
[tex]\Rightarrow A=P\left(1+r\%\right)^t\\\Rightarrow A=100,000(1+0.08)^3\\\Rightarrow A=\$125,971.2[/tex]
Thus, the amount accruing for loan is [tex]\$125,971.2[/tex]
When a constant force acts upon an object, the acceleration of the object varies inversely with its mass. When a certain constant force acts upon an object with
mass 7 kg, the acceleration of the object is 4 m/s?. If the same force acts upon another object whose mass is 2 kg, what is this object's acceleration?
Answer:
14 m/s²
Step-by-step explanation:
From the question
a ∝ F/m.............. Equation 1
Where a = aceleration, m = mass, F = force
make F the subject of the equation
F = ma............ equation 2
Given: m = 7 kg, a = 4 m/s²
Therefore,
F = 7(4)
F = 28 N
For another object whose mass is 2 kg,
Make a the subject of equation 2
a = F/m
a = 28/2
a = 14 m/s²
Find the rate of change for the function of change from x=-3 to x=1
Answer:
She's, "HOT"!
Step-by-step explanation:
suppose you start with a single bacterium of streptococcus at hour 0 , and it has a generation time of 60 minutes. how many bacteria will you have at the end of hour 24
Answer:
60x24
Step-by-step explanation:
60x24=1224
Find the value of x,rounded to the nearest tenth
Answer:
Step-by-step explanation:
The formula for this is
14(20) = 25x and
280 =25x so
x = 11.2
Which equation can be used to determine the reference angle
Answer:
2nd option
Step-by-step explanation:
[tex]\frac{7\pi }{12}[/tex] is an angle in the second quadrant
Thus to find the reference angle, subtract from π , that is
r = π - θ
