please help!!!! Use the graph to complete the statement. O is the origin. Ry−axis ο Ry=x: (-1,2)
A. (1, -2) B. (-1, -2) C. (2, -1) D. (-2, -1)

Please Help!!!! Use The Graph To Complete The Statement. O Is The Origin. Ryaxis Ry=x: (-1,2) A. (1,

Answers

Answer 1

Answer:  D. (-2, -1)

Step-by-step explanation:

Here we do two reflections to the point (-1, 2).

First, we do a reflection over the line x = y.  Remember that a reflection over a line keeps constant the distance between our point and the given line, so we have that for a pint (x, y), the reflection over the line y = x is:

Ry=x (x, y) = (y, x)

so for our point, we have:

Ry=x (-1, 2) = (2, -1)

Now we do a reflection over the y-axis, again, a reflection over a line keeps constant the distance between our point and the given line, so if we have a point (x,y) and we do a reflection over the y-axis, our new point will be:

Ry-axis (x,y) = (-x, y)

Then in our case:

Ry-axis (2, -1) = (-2, -1)

The correct option is D.


Related Questions


Hey, please help solve the question.​

Answers

Answer:

75%=x-125

90%=x+250

subtract the second from the first

15%=375

100%=?

100%×375/15

100%=2500marked price is 2500

2500+250=2750

90%=2750

100%=?

cost price=3055.56

Write an expression that can be used to find the price of a television that is on sale for 20% off the regular price of p dollars. Can you write a second expression equivalent to the one you wrote in the last questions.

Answers

Answer:

The expression that could help calculate the price of the TV is;

$P - 20% of $P

Step-by-step explanation:

Here, we want to write an expression that corresponds to the price of a television set that is on sale at a price which is 20% off the regular price.

From the question, we can see that the regular price is $P

So now we are having 20% off;

This corresponds to;

20/100 * p = p/5 = 0.2p

So in the expression form, we can have;

$P - 20% of $P

PLEASE HELP!! what is the equation of a line that is perpendicular to y = 2x + 4 and passes through the point (4, 6)?

Answers

Answer:

The answer is B)

[tex]y = - \frac{1}{2}x + 8[/tex]

Answer:

B.  y = -[tex]\frac{1}{2}[/tex]x + 8

Step-by-step explanation:

The line is perpendicular to line whose equation is:

y = 2x + 4 and;

passes through point (4,6) .

The product slopes of two perpendicular lines is -1.

The slope of the line whose equation is y = 2x + 4 is; 2

Let the slope of the perpendicular line (l2) be [tex]m_{l2}[/tex]

[tex]m_{l2} * 2 = -1[/tex]

[tex]m_{l2}[/tex] = [tex]-\frac{1}{2}[/tex]

Taking another point xy on line l2;

[tex]\frac{y - 6}{x - 4} = -\frac{1}{2}[/tex]

Cross multiplying this gives;

y = -[tex]\frac{1}{2}[/tex]x + 8 which is the equation of the perpendicular line!

HELP ASAP WILL MARK BRAINLIEST!!!!!! Use the number line​ below, where ​RS=9y+2, ST = 4y+9 and RT = 115. a. What is the value of​ y? b. Find RS and ST. a. What is the value of​ y?

Answers

Answer: y = 7

Step-by-step explanation:

if a man works 400km in 6 minutes.How long will he work in 9 minutes​

Answers

Answer:

600 km

Step-by-step explanation:

400 km  =       x    

  6 min         9 min  

cross multiply:

6x = 400 ( 9)

x = 3600 / 6

x = 600 km

Pregunta N° 1: ¿Cuántas fracciones propias e irreductibles con denominador 24 existen? 1 punto A) 2 B) 4 C) 6 D) 8 E) 10 Pregunta N° 2: ¿Cuántas fracciones impropias e irreductibles con numerador 25 existen? 1 punto A) 19 B) 21 C) 25 D) 29 E) 33 Pregunta N° 3: La edad de Miguel es 4/5 de la edad de su novia. Si las edades de los dos suman 63 años, calcule la edad de la novia de Miguel. 1 punto A) 20 años B) 26 años C) 32 años D) 35 años E) 40 años Pregunta N° 4: Si son las 8 a. m., ¿qué fracción del día ha transcurrido? 1 punto A) 1 B) 2 C) 1/2 D) 1/3 E) 1/5

ayuden porfavor

Answers

Answer:

Pregunta 1: Opcion D. 8

Pregunta 2: Opción A. 19 (aunque lo correcto es decir que son 20)

Pregunta 3: 28 años (no está como opción)

Pregunta 4: Opción D. 1/3

Step-by-step explanation:

Las fracciones irreductibles son aquellas que después de dividirlas por un común divisor, una vez que no se pueden dividir más se dice que son irreducibles, por lo tanto no existe ningún número que sea divisor común del numerador y del denominador más que 1.

Fracciones irreductibles con común denominador 24.

Como máximo divisor tenemos el 24 y como mínimo el 1

entre 1/24 y 1 estarán nuestras fracciones o sea:

1/24 < x/24 < 1. Ahora convertimos el 1 en fracción de 24, lo que sería 24/24 para igualar el numerador en ambos lados de la ecuación, para poder determinar x

1/24 < x/24 < 24/24

Como vemos que x tiene que estar entre 1 y 24, las respuestas serán:

2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22 y 23

Eliminamos los números divisores de 24, aquellos pares, y nos focalizamos en los que no podriamos dividir por nada con 24, o sea los números primos

5, 7, 11, 13, 17, 19, 23. Como nos falta el 1, obtenemos un total de 8 fracciones: 1/24, 5/24, 7/24, 11/24, 13/24, 17/24, 19/24, 23/24

Mismo procedimiento para el 25:

1/25 es una de las fracciones irreductibles. Pensamos en los valores de x

1/25 < x/25 < 25/25

2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25

Los números divisibles por 25, son los multiplos de 5, asi que esas respuestas no irían. Las fracciones irreductibles son:

1/25, 2/25, 3/25, 4/25, 6/25, 7/25, 8/25, 9/25, 11/25, 12/25, 13/25, 14/25, 16/25, 17/25, 18/25, 19/25, 21/25, 22/25, 23/25 y 24/25 haciendo un total de

20. Por alguna razón está mal formulada la pregunta, son 20 pero no está como opción y como te piden fraccion impropia (numerador > denominador), contamos a partir de 26. FIjate que hasta el proximo entero que sería 50/25, también son 20 fracciones (irreductibles e impropias)

26/25, 27/25, 28/25, 29/25, 31/25, 32/25, 33/25, 34/25, 36/25, 37/25, 38/25, 39/25, 41/25, 42/25, 43/25, 44/25, 46/25, 47/25, 48/25, 49/25

Próxima pregunta:

Miguel tiene 4/5 de la edad de la novia, y ambas edades suman 63.

Plantiemos la siguiente ecuacion donde x es la edad de la novia

4/5x + x = 63

9/5x = 63

x = 63 . 5/9 (como 9/5 pasa al otro lado de la igualdad dividiendo, damos vuelta la fraccion multiplicandola)

x = 35

Si la novia tiene 35 años y la edad de Miguel es 4/5 de esa edad

4/5 .35 = (35 .4) /5 = 28

Es raro porque no está la respuesta como tal.

Próxima pregunta:

Al ser las 8 am, quiere decir que han pasado 8 horas de que empezó el día

y el día tiene 24 horas.

8 horas transcurridas / 24 horas totales = 1/3

Determine if the ordered pair (6, 4) is a solution to the inequality

Answers

Answer:

[tex]\Large \boxed{\mathrm{Option \ D}}[/tex]

Step-by-step explanation:

(6, 4)

x = 6 and y = 4

y > -1/2x + 7

Plug in the values to check if it is true.

4 > -1/2(6) + 7

4 > -3 + 7

4 > 4

This statement is false.

(6, 4) lies on the line.

a rectangular garden is fenced on all sides with 128 feet of fencing. The garden is 4 feet longer than it is wide. Find the length and width of the garden

Answers

Answer:

Length = 34 feet

Breadth = 30 feet

Step-by-step explanation:

Perimeter= 128 ft

Let the breadth be = [tex]x[/tex]

Let the length be = [tex]x+4[/tex]

∴by the problem ,

2(length+breadth)= perimeter

[tex]2(x+4+x)=128\\2(2x+4)=128\\4x+8=128\\4x=128-8\\4x=120\\x=120/4\\x=30[/tex]

Therefore, length of the garden = 30+4= 34 feet

breadth of the garden = 30 feet  

The fraction subtracted from 5/3 to get 1 is_____​

Answers

Answer:

2/3

Step-by-step explanation:

I am not sure

Answer:

2/3

Step-by-step explanation:

[tex]Let \:the \: unknown \: fraction \: be \: x\\\\\frac{5}{3} -x = 1\\\\\frac{5}{3}-x=1\\\\\mathrm{Subtract\:}\frac{5}{3}\mathrm{\:from\:both\:sides}\\\\\frac{5}{3}-x-\frac{5}{3}=1-\frac{5}{3}\\\\\frac{5}{3}-x-\frac{5}{3}=-x\\\\1-\frac{5}{3}=-\frac{2}{3}\\-x=-\frac{2}{3}\\\\x=\frac{2}{3}\\[/tex]

in the equation z=x^2-3y, find the value of z when x=-3 and y=4

Answers

Answer:

z=-3

Step-by-step explanation:

z=(-3)^2 - 3(4)

z=9 - 12

z=-3

9 ÷ (-4 1/2) = L.
What is L.​

Answers

Answer:

[tex]\huge\boxed{L = -2}[/tex]

Step-by-step explanation:

L = 9 ÷ [tex](-4 \frac{1}{2} )[/tex]

L = 9 ÷ [tex](-\frac{9}{2} )[/tex]

L = 9 × [tex](-\frac{2}{9} )[/tex]

L = 1× (-2)

L = -2

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[tex]\boxed {l = \frac{-18}{41} }[/tex]

[tex]\frac{\frac{9}{-41} }{2} = l[/tex]

Simplifies to:

[tex]\frac{-18}{41} = l[/tex]

Let's solve your equation step-by-step.

[tex]\frac{-18}{41} = l[/tex]

Step 1: Flip the equation.

[tex]l = \frac{-18}{41}[/tex]

So your answer would be : [tex]\boxed {l = \frac{-18}{41} }[/tex]

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Have a great day/night!

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4. The rental for a television set changed from $80 per year to $8 per month
What is the percentage increase in the yearly rental?​

Answers

Answer:

16%

Step-by-step explanation:

rental charge per year = $80

rental charge at the rate $8 per year = 8 * 12 = 96

the increased amount = 96 - 80 = 16

% = 16 / 100 = 16%

Please help I did the first 2

Answers

Answer:

x = 1.5

Step-by-step explanation:

6 - 2x = 3

→ Minus 6 from both sides to isolate -2x

-2x = -3

→ Divide -2 from both sides to isolate x

x = 1.5

Do the ratios 2/3 and 12/18 form a proportion?
yes
no​

Answers

Answer:

Yes

Step-by-step explanation:

Because 12/18 = 2/3..(cancel 12 and 18 by 6)

Answer:

yes

Step-by-step explanation:

2x6=12

3x6=18

6 is the multiplying number

( the 2 equations are the same amount )

A radioactive substance decays exponentially. A scientist begins with 350 milligrams of a radioactive substance. After 14 hours, 175 mg of the substance remains. How many milligrams will remain after 20 hours

Answers

Answer:

N(t)=N∗.5t/h where n(t) is amount of substance left, N = initial amount, t = current time, and h = half-life time.h = 24 hours t= 45 hours, N = 130mg

therefore, N(t)=130∗.545/24=35.44mg

Step-by-step explanation:

N(t)=N∗.5t/h where n(t) is amount of substance left, N = initial amount, t = current time, and h = half-life time.h = 24 hours t= 45 hours, N = 130mg

therefore, N(t)=130∗.545/24=35.44mg

Answer:

≈ 130 mg

Step-by-step explanation:

This is about the half-life of the substance.

There is a formula for this kind of calculations:

N(t)= N₀*(0.5)^(t/T), where

N(t) = substance left after time period of t,t = time passed,N₀ = initial amount of the substance,T = hal-life time of the given substance.

In our case, we have:

N₀ = 350 mg,t= 20 hours,T = 14 hours  as half of substance decays during this time period,

And the calculation:

N(20)= 350*(0.5)^(20/14)N(20) ≈ 130 mg

Answer: about 130 mg of substance remains after 20 hours

Select the correct answer. This set of ordered pairs defines a function. {(-49,7), (-56,8), (-63,9), (-70,10)} Which table represents the inverse of the function defined by the ordered pairs? A.

Answers

In the future, you should post all possible answer choices to have a complete post. However, there's enough information to get the answer.

The original set has points in the form (x,y)

The first point is (x,y) = (-49,7) making x = -49 and y = 7. When we find the inverse, we simply swap the x and y values. The inverse undoes the original function and vice versa. So if (-49, 7) is in the original function, then (7, -49) is in the inverse. The rest of the points follow the same pattern.

We end up with this answer

{ (7, -49), (8, -56), (9, -63), (10, -70) }

Sarah has $20 saved. She gets $10 per week for her allowance, and she saves her allowance for the next 3 weeks. At the end of the week, she gets $150 in birthday money. How much money will she have after the 3 weeks? Which of the following sets of equations represents this problem?

Answers

Answer:

$200

Step-by-step explanation:

We know that she already has $20. And we know that every week, for three weeks she gets $10.

20+3(10)+150=m

We add all of this up, and we find that at the end of 3 weeks Sarah has $200 saved.

solve the following: - 3 raised to 1 by 5 the whole raised to 4 (3^1/5)^4

Answers

Answer:

8.30256

Step-by-step explanation:

Step 1: Write out expression

[tex]((-3)^{\frac{1}{5} })^{4(3^{\frac{1}{5} })^4[/tex]

Step 2: Use BPEMDAS to evaluate

[tex](-1.24573)^{4(3^{\frac{1}{5} })^4[/tex]

[tex](-1.24573)^{4(1.24573)^4[/tex]

[tex](-1.24573)^{4(2.40822)[/tex]

[tex](-1.24573)^{9.6329}[/tex]

= 8.30256

And we have our answer!

inscribed angles. help asap!​

Answers

Answer:

20°

Step-by-step explanation:

The measure of the inscribed angle is equal to the half of the arc it sees

Since AC is the diameter the measure of arc ABC is 180°

and since A sees arc BC and C sees the arc AB

A< + C< = 90° so angle C = 20°

write each number in scientific notation.



1,050,200

The number between 1 and 10:
The power of 10:
The number in scientific notation:

34,600

The number between 1 and 10:
The power of 10:
The number in scientific notation:

Answers

1,050,200

The number between 1 and 10: 1
The power of 10: 6
The number in scientific notation: 1.05^6 or 1.050200^6

34,600

The number between 1 and 10: 3
The power of 10: 4
The number in scientific notation: 3.46^4

Peter has one of each of the following coins in his pocket: a penny, a nickel, a dime, a quarter, and a half-dollar. Four of these coins are taken out of the pocket and the sum of their values is calculated. How many different sums are possible?

Answers

Answer:

10

Step-by-step explanation:

This is a combinations problem, involving factorials.

5!/3!*2!=5*4/2=20/2=10

The different sum of the 4 coins from the list of 5 coins is an illustration of combination or selection. There are 5 different possible sums.

Given

[tex]n = 5[/tex] --- number of coins

[tex]r = 4[/tex] --- coins to be selected to calculate sum

For the sum of the coin value to be calculated, the 4 coins must be selected. This means combination.

So, we make use of:

[tex]^nC_r = \frac{n!}{(n - r)!r!}[/tex]

This gives

[tex]^5C_4 = \frac{5!}{(5 - 4)!4!}[/tex]

[tex]^5C_4 = \frac{5!}{1!4!}[/tex]

Expand

[tex]^5C_4 = \frac{5*4!}{1*4!}[/tex]

[tex]^5C_4 = \frac{5}{1}[/tex]

[tex]^5C_4 = 5[/tex]

Hence, there are 5 different possible sums.

Read more about combinations at:

https://brainly.com/question/15401733

A set of furniture was sold for GH cedis 3000 at a profit of 25%. Find the cost price.

Answers

Answer:

2400GH Cedis

Step-by-step explanation:

[tex]Selling \:price = 3000gh Cedis\\Profit \% = 25\%\\Cost\:price =?\\\\CP =\frac{ ( Selling\:price \times 100 )}{ ( 100 + percentage profit)} \\\\C.P = \frac{3000\times 100 }{100+25}\\\\ C.P = \frac{300000}{125} \\\\Cost\: Price = 2400gh Cedis[/tex]

how do you solve this problem ? 4(-3x+1)-3x=71

Answers

Answer:

x = -67/15 = -4-46667

Step-by-step explanation:

4(-3x+1) - 3x = 71

4*-3x + 4*1 - 3x = 71

-12x + 4 - 3x = 71

-15x = 71-4

-15x = 67

x = 67/-15

x = -4.46667

check:

4(-3*-4.46667 + 1) - 3*-4.4666= 71

4(13.4+1) + 13.4 = 71

4*14.4 + 13.4 = 71

57.6 + 13.4 = 71

Hey there please help me with this question

Answers

Answer:

see explanation

Step-by-step explanation:

sum the parts of the ratio, 2 + 1 = 3 parts , thus

81 cm² ÷ 3 = 27 cm² ← value of 1 part of the ratio

2 parts = 2 × 27 = 54 cm²

Area of A = 54 cm² and area of B = 27 cm²

The side of the original square = [tex]\sqrt{81}[/tex] = 9 cm

The width of both rectangles is 9 cm ( width remains unchanged after cut )

Thus

Rectangle A

9 × length = 54 ( divide both sides by 9 )

length = 6 cm

Rectangle B

9 × length = 27 ( divide both sides by 9 )

length = 3 cm

Rectangle A → length = 6 cm, width = 9 cm

Rectangle B → length = 3 cm , width = 9 cm

Answer:

Rectangle A                 Rectangle B

length = 9 cm                length = 9 cm

width = 6 cm                  width = 3 cm

Step-by-step explanation:

Area of square At = 81 cm²

Square is cut into two pieces = A + B

The ration of area A to B = 2:1

Find

Rect A        Rect B

length         length

width           width

---------------------------------

first, get the side of the square = A = s²

81 = s²,      

s = √81      

s = 9 cm

since the ratio is 2:1, therefore the side can be divided into 3

9 ÷ 3 = 3 cm ----- take note of this to get the Width

Rectangle A

L = 9 cm (which is the s = 9 cm)

W = 3 cm (2 ratio) = 6 cm

Rectangle B

L = 9 cm  (which is the s = 9 cm)

W = 3 cm (1 ratio) = 3 cm

Proof:

At = A + B

81 = (9x6) + (9x3)

81 = 54 + 27

81 = 81  ----- OK


someone please expain how to do this, i’m really confused.

Answers

Answer:

13

Step-by-step explanation:

Basically, we have to plug in 4 for r into g(r). Doing so gives us g(4) = 25 - 3 * 4 = 25 - 12 = 13.

Some more examples:

g(6) = 25 - 3 * 6 = 25 - 18 = 7

g(1) = 25 - 3 * 1 = 25 - 3 = 22

Answer:g(4)=13

Step-by-step explanation:

g(4)=25-3r

25-3(4)

25-12

g(4)=13

Coordinate plane with two lines graphed. The equations of the lines are y equals negative two-thirds x plus four and the other line is y equals two-thirds x. Determine the number of solutions the system of linear equations has and the solution(s) to the equations represented by these two lines? The system of equations has 0 solutions, because the graph has no point of intersection. The system of equations has infinite number of solutions and all real numbers satisfy both equations. The system of equations has 1 solution and it is (3, 2). The system of equations has 1 solution and it is (3, 0).

Answers

Answer:

Step-by-step explanation:

y = -2/3x + 4

y = 2/3x

2/3x = -2/3x + 4

4/3x = 4

4x = 12

x = 3

y = 2/3(3)

y = 2

(3,2) one solution

option 3

Jorge’s monthly bill from his Internet service provider was $25. The service provider charges a base rate of $15 per month plus $1 for each hour that the service is used. Find the number of hours that Jorge was charged for that month.

Answers

Answer:

10 hours for the month

Step-by-step explanation:

What you know: The total amount Jorge was charged for the month was $25

The base rate is $15

He gets charged $1 per each hour

Setting it up:

15+1h=25

(the 15 is the base rate, plus the 1 dollar per hour (h) which both add to the total of 25 dollars for the month)

Subtract 15 from both sides of the equation to get your variable by itself

1h=10

then divide the 1 on both sides to get h (hours) by itself

h=10

And there's your answer, 10 is the number of hours that Jorge was charged for the month

Hopefully this helped :))

Answer:

10

Step-by-step explanation:

$25 - $15 = $10

and its $1 per hour so the answer is 10hrs

The heights of two similar parallelograms are 16 inches and 20 inches. Their

respective areas are (3x+5) square inches and 9x square inches. Find the value of

X?

Answers

Answer: [tex]x=\dfrac{25}{21}[/tex]

Step-by-step explanation:

Area of parallelogram = Base x height

If two parallelograms are similar, then their corresponding sides are proportional.

That means, [tex]\dfrac{\text{Area of first parallleogram}}{\text{Area of second parallleogram}}=\dfrac{\text{height of first parallelogram}}{\text{height of second parallelogram}}[/tex]

[tex]\Rightarrow \dfrac{3x+5}{9x}=\dfrac{16}{20}\Rightarrow \dfrac{3x+5}{9x}=\dfrac{4}{5}\\\\\Rightarrow 5(3x+5)=4(9x)\\\\\Rightarrow\ 15x+25 = 36x\\\\\Rightarrow\ 36x-15x=25\\\\\Rightarrow\ 21x = 25\\\\\Rightarrow\ x=\dfrac{25}{21}[/tex]

Hence, [tex]x=\dfrac{25}{21}[/tex]

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of days and a standard deviation of days. ​(a) What is the minimum pregnancy length that can be in the top ​% of pregnancy​ lengths? ​(b) What is the maximum pregnancy length that can be in the bottom ​% of pregnancy​ lengths? ​(a) The minimum pregnancy length is 280 days.

Answers

Answer:

(a) 283 days

(b) 248 days

Step-by-step explanation:

The complete question is:

The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. ​(a) What is the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths? ​(b) What is the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths?

Solution:

The random variable X can be defined as the pregnancy length in days.

Then, from the provided information [tex]X\sim N(\mu=268, \sigma^{2}=12^{2})[/tex].

(a)

The minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths implies that:

P (X > x) = 0.11

⇒ P (Z > z) = 0.11

z = 1.23

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\1.23=\frac{x-268}{12}\\\\x=268+(12\times 1.23)\\\\x=282.76\\\\x\approx 283[/tex]

Thus, the minimum pregnancy length that can be in the top 11​% of pregnancy​ lengths is 283 days.

(b)

The maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths implies that:

P (X < x) = 0.05

⇒ P (Z < z) = 0.05

z = -1.645

Compute the value of x as follows:

[tex]z=\frac{x-\mu}{\sigma}\\\\-1.645=\frac{x-268}{12}\\\\x=268-(12\times 1.645)\\\\x=248.26\\\\x\approx 248[/tex]

Thus, the maximum pregnancy length that can be in the bottom ​5% of pregnancy​ lengths is 248 days.

What's the correct answer to this..? Need help

Answers

Answer:

A.

Step-by-step explanation:

All of those graphs represent functions. You are able to tell because they all pass the vertical line test. The vertical line test is conducted by drawing a line that goes vertically and intercepts any point of the line in question. If the function crosses the vertical line twice, it is not a function. If it only intercepts once, it is a function. In this case, every graph is a function because they would intercept a vertical line once.  

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