Please help me with the question; It is attached in the image

Answer:

The lines are:

and

Since after multiplying by -3 the equations sum to 0, the equations are same.

Same equations produce overlapping lines, hence you can see one line only.

Divide second equation by 3

LInes are same so you can see only one line

[tex]\boxed{\sf (a+b)^2=a^2+b^2+2ab}[/tex]

Now

[tex]\\ \sf\longmapsto x+\dfrac{1}{x}=12[/tex]

[tex]\\ \sf\longmapsto \left(x+\dfrac{1}{x}\right)^2=12^2[/tex]

[tex]\\ \sf\longmapsto x^2+2\times x\times \dfrac{1}{x}+\left(\dfrac{1}{x}\right)^2=144[/tex]

[tex]\\ \sf\longmapsto x^2+\dfrac{1}{x^2}+2=144[/tex]

[tex]\\ \sf\longmapsto x^2+\dfrac{1}{x^2}=144-2=142[/tex]

Answer:

122

Step-by-step explanation:

x+1/x = 12

x + 1 = 12x

x = 1/11

（1/11）² + 1 / （1/11）² = 1/121 +1 /1/121 = 122

Answer:

B

Step-by-step explanation:

x<15

There is an open circle at 15 and the line goes to the left

Answer:

If there were 20 children at a party, and each were given one cookie, then a total of 20 cookies were given out.

However, this is not the case, as 32 cookies were given out. So, we can see that 32 - 20 children, or 12 children, received one additional cookie.

Let me know if this helps!

Answer:

Time and rate is 4 years and 4% respectively.

Step-by-step explanation:

P = Rs 66000

so

T = R

I = 10560

so

I = PTR/100

Rs 10560 = (66000*T^2)/100

or, Rs 1056000 = 66000*T^2

or. 1056000/66000 = T^2

or, 16 = T^2

OR, T =√16

so T = 4

Then

T = R

so, R = 4

Answer:

The diameter is 6. The radius is 3. For the half of the orange circle.

The area of the half of the small orange circle is = pi*r*r = pi*3*3.

The diameter is 24. The radius is 12.

The area of the half of the light orange circle and the other colors is = pi*r*r = pi*12*12

The area of dark orange, light blue, purple and green figures = pi*12*12 – pi*3*3 = 135*pi

To get the area of the blue figure we need to divide 135*pi into ¼ and you will get the area of the blue figure.

The area of the blue figure =( ¼ )*135*pi *(1/2) = ¼ *1/2 = 1/8

The area of the blue figure is = 135pi / 8

B) outside perimeter of the window frame = 28 +pi*14 = 71.98

Hope this helps you :)

Answer:

D

Step-by-step explanation:

f(x) = -3x^3 + x^2 – 3       f(2) means that wherever you see a x, put in a 2.

f(2)= -3(2)^3 + (2)^2 - 3

f(2) = -3*8 + 4 - 3

f(2) = - 24 + 1

f(2) = - 23

[tex]\\ \sf \longmapsto f(2)[/tex]

[tex]\\ \sf \longmapsto -3(2)^3+(2)^2-3[/tex]

[tex]\\ \sf \longmapsto -3(8)+4-3[/tex]

[tex]\\ \sf \longmapsto -24+1[/tex]

[tex]\\ \sf \longmapsto -23[/tex]

Answer:

34

Step-by-step explanation:

let the missing value is x

(25+x) /2 = 29.5

25+x = 29.5(2)

25+x = 59

x = 59-25

x = 34

Answer:

it's hypotenuse

Step-by-step explanation:

Answer:

m = 4

k = 25.56

b = 20

The differential equation for damping motion is:

where,

Substitute the values in the differential equation and consider x" = r², x' =r and solve:

Therefore, solution is given by:

at t = 0, x = 1

at t = 0

x' =0

Step-by-step explanation:

Answer:

ask ya fadaaaaaaaaàaaa

Step-by-step explanation:

guvdhcjnhcxh

Answer:

0

Step-by-step explanation:

[tex]f(x)=2x-4\\f(2)=2(2)-4\\f(2)=4-4\\f(2)=0[/tex]

Answer:

0

Step-by-step explanation:

If f(x) = 2x - 4

Then f(2) = 2(2) -4

f(2) = 4 - 4

= 0

The median of a triangle divides it into two equal triangles of equal areas.

Must click thanks and mark brainliest

Real numbers can be expressed using the following interval,

[tex]\mathbb{R}=(-\infty,\infty)[/tex]

Of course infinities are not just normal infinities but thats out of the scope of this question.

Real numbers less than two can be expressed with,

[tex](-\infty,\infty)\cap(-\infty,-2)=\boxed{(-\infty,-2)}[/tex]

The [tex]\cap[/tex] is called intersection ie. where are both intervals valid. First we took real numbers then we intersected them with real numbers valued less than -2 and we got real numbers which are less than -2.

Similarly we can perform with "greater than or equal to 3" real numbers,

[tex](-\infty,\infty)\cap[3,\infty)=\boxed{[3,\infty)}[/tex]

So we have one interval stretching from negative infinity to (but not including) -2, and another interval stretching from including 3 to positive infinity.

If we want numbers in both intervals we can express this two ways,

First way is to use [tex]\cup[/tex] union operator to denote we want numbers from two intervals,

[tex]\boxed{(-\infty,2)\cup[3,\infty)}[/tex]

The second way is to specify which numbers we do not want, we do not want -2 and everything up to but not including 3, which is expressed with the following interval

[tex][-2,3)[/tex]

Now we just take out the not wanted interval from real numbers and we will remain with all wanted numbers,

[tex]\boxed{(-\infty,\infty)-[-2,3)}[/tex]

Hope this helps.

Answer:

I really can't read this

Step-by-step explanation:

Answer:

a. x = 3/a

Step-by-step explanation:

Add all like terms on left hand side of the equation:

5 ax + 3 ax => 8 ax

Bring like term 4ax on left hand side

8ax - 4ax

=> 4ax

Therefore we get 4ax = 12

ax = 12/4

ax = 3

x = 3/a

Answer:

-2

Step-by-step explanation:

3x + 8x - 3 = -25

Move the -3 over to the other side. This will make the -3 into positive 3

3x + 8x = -25 + 3

Now add like terms

11x = -22

Divide both sides by 11 to get x by itself

x = -2

Answer:

x= -2

Step-by-step explanation:

First you combine the like terms 3x and 8x which then gives you 11x

then you'll have 11x-3=-25

add 3 to both sides and you have 11x=-22

divide the 11 on both sides

then you'll have x=-2

Terms given

No of terms=8

We know

[tex]\boxed{\sf Mean=\dfrac{Sum\;of\:terms}{No\;of\:terms}}[/tex]

[tex]\\ \sf\longmapsto Mean=\dfrac{40+35+32+39+34+35+35+37}{8}[/tex]

[tex]\\ \sf\longmapsto Mean=\dfrac{270}{8}[/tex]

[tex]\\ \sf\longmapsto Mean=35[/tex]

Final Answer:

35

Step-by-step explanation:

-median is the middle number in the data set-

arrange the data set from least to greatest:

40, 30, 32, 39, 34, 35, 35, 37 ⇒ 30, 32, 34, 35, 35, 37, 39, 40

we start from the lowest number and the highest  number and work your way to the middle:

30, 32, 34, 35, 35, 37, 39, 40

notice that there is no middle number:

30, 32, 34, 35, ?, 35, 37, 39, 40

so what we do is add both 35's and then divide it by 2

35 + 35 = 70 ÷ 2 = 35

median: 35

A probability outcome gives theoretical probabilities of each possible event in an experiment so option (A) will be correct.

The probability of an event occurring is defined by probability.

Do not take underestimate probability it has several uses in daily life whether forecasts and like that.

Theoretical probability is the probability that shows by the probability formula while experimental probability is an actual probability that can obtain by experiments.

There are various situations in our daily lives where we might need to make predictions about how things will turn out.

Probability outcome which comes out by mathematical formula is always theoretical probability while actual experiment gives us experimental probability hence probability outcome will be the correct answer.

For more information about the probability

brainly.com/question/11234923,

#SPJ2

Solve for  x  by simplifying both sides of the equation, then isolating the variable.

x  ≈  0.13893498

Answer:

8 pieces.

Step-by-step explanation:

12 / 1.5

= 24 / 3

= 8.

Answer:

A

Step-by-step explanation:

the answer is A and not C. equation in form of y=mx+b

so start off by (0,2) and you can see the graph go by 1 x and 1 y.

C=n+2

Answer:

A

Step-by-step explanation:

its starting point is 2 up to +2 and it goes up at out by 1 so n also ik this was already answered but i want the brainly points

Answer:

1000

Step-by-step explanation:

I guess, something went wrong with the text up there.

I assume it should say 2cm×2cm×2cm cubes. right ? because a cube has 3 dimensions, not just 2.

otherwise an infinitely large number of "just squares" would fit into the box ...

so, the box is

1m×20cm×4cm = 100cm×20cm×4cm = 8000 cm³

a single cube would be

2cm×2cm×2cm = 8 cm³

therefore,

8000 / 8 = 1000 cubes can be packed into that box, since the dimensions of the box in relation to the dimensions of the cubes do not force to have some empty left over space. the box can be packed tightly.

Answer:

p=-7

Step-by-step explanation:

5p=-35

Divide both sides by 5

5p/5 =-35/5

therefore p=-7

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{5p= -35}\\\\\underline{\huge\text{DIVIDE 5 BOTH SIDES}}\\\\\mathsf{\dfrac{5p}{5p}= \dfrac{-35}{5}}\\\\\large\text{CANCEL out: }\dfrac{5}{5}\large\text{ because that gives you 1}\\\large\text{KEEP: }\dfrac{-35}{5}\large\text{ because that gives you the value of p.}\\\\\large\textsf{p = }\mathsf{\dfrac{-35}{5}}\\\\\mathsf{-35\div5= p}\\\\\large\text{Simplify above and you have your result to the p-value.}\\\\\boxed{\boxed{\huge\text{Therefore your answer is: \textsf{p = -7}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer:

5√3 / 2

Step-by-step explanation:

tan 30 = ( 5 / 2 ) / y

1 / √3 = 5 / 2y

2y = 5√3

y = 5√3 / 2

Problem 1

The idea here is to follow PEMDAS in reverse to undo what is happening to the variable b, so we can isolate it.

-11b + 7 = 40

-11b = 40-7

-11b = 33

b = 33/(-11)

b = -3

To check this value, plug it back into the original equation. You should get 40 on each side to help confirm the answer.

=====================================================

Problem 2

There are two ways we can solve. One method is to use the hint your teacher gave you. So we'll distribute first and then follow the same idea as problem 1

9(p-4) = -18

9p-36 = -18

9p = -18+36

9p = 18

p = 18/9

p = 2

Another method you can use is to follow these steps

9(p-4) = -18

p-4 = -18/9

p-4 = -2

p = -2+4

p = 2

Either way, we get the same result. To check the answer, replace every p with 2 in the original equation. You should get -18 on the left side after simplifying.