PLEASE help me solve this question! No nonsense answers please!

Answer:

The answer is below

Step-by-step explanation:

To find the maximum amount of cargo the truck can carry, we need to find the volume of the truck.

Volume = length × width × height.

Firstly 1 feet (1') = 12 inches (12"),

For the extra ledge that sticks out, the height = 7'8" = 7.667 feet, the width = 16'9" - 14'3" = 16.75 - 14.25 = 2.5 feet, the length = 2'7" = 2.583 feet

Volume of extra ledge = length × width × height = 2.583 × 2.5 × 7.667 = 49.5 feet³

For the truck, the height = 7'8" = 7.667 feet, the length = 14'3" = 14.25 feet, the width = 6'6" = 6.5 feet

Volume of truck = length × width × height = 14.25 × 6.5 × 7.667 = 710.16 feet³

The maximum volume = volume of extra ledge + volume of truck = 49.5 + 710.16 = 759.66 feet³

Answer:

-1

Step-by-step explanation:

The formula for finding a slope is: m = (change in y)/(change in x)

Find the change in each value

Y: 9 - 6 = 3

X: -3 - 0 = -3

Input the values

m = 3/-3

m = -1

I would start this problem by setting up a table.

In the left column, we will have our x values

and in the right column, we have our y values.

Put our first ordered pair on the top and second on bottom.

We can see the y values go from 6 to 9 so change in y is 3.

The x values go from 0 to -3 so change in x is -3.

The slope is equal to the rate of change or change in y / change in x.

So our slope is 3/-3 of -1.

Answer:

7000 (7 thousand)

700 (7 hundred)

20 (2 tens)

2 (2 units)

Step-by-step explanation:

what is the relationship between the values of the given digits?

1. The 7s in 7,700

2. The 2's in 522

From the knowledge of place values;

7,700 could be broken down thus :

7000 + 700 + 0 + 0

The first 7 depicts thousands as it has 3 trailing digits (7000)

The second 7 depicts hundred as it has 2 trailing digits (700)

522 could be broken down thus :

500 + 20 + 2

From 522

The first '2' has one trailing digit = tens

The ending / last digit ia always = Unit value

Answer:

Step-by-step explanation:

This a right triangle so we will use the Pythagorian theorem. x is the hypotenus.

■■■■■ Pythagorian theorem ■■■■■

● x^2 = √10^2 + √10^2

● x^2 = 10 + 10

● x^2 = 20

● x = √20 yd

Answer:

86°

Step-by-step explanation:

b = 29× 2 = 58

d= [180-(86+29)]×2 = 130

a=c=x

a+b+c+d = 360

2x+188= 360

2x= 172

x= 86

a = c = 86°

Answer:

Step-by-step explanation:

Since the sequence is a geometric sequence

For an nth term in a geometric sequence

[tex]A (n) = a ({r})^{n - 1} [/tex]

where

a is the first term

r is the common ratio

n is the number of terms

To find the eighth term we must first find the first term

4th term = 108

common ratio = 3

That's

[tex]A(4) = a ({r})^{4 - 1} [/tex]

[tex]108 = a ({3})^{3} [/tex]

[tex]27a = 108[/tex]

Divide both sides by 27

For the eighth term

[tex]A(8) = 4 ({3})^{8 - 1} [/tex]

[tex]A(8) = 4({3})^{7} [/tex]

The final answer is

Hope this helps you

Answer: 14%

Step-by-step explanation:

Complete question is provided in the attachment below:

Probability that members of the junior varsity swim team wear glasses = 55%=0.55

Given: P(wear glasses) = 0.55

P(not wear glasses) = 1-0.55 = 0.45

P(member in 10th grade | not wear glasses) = 30%

Using conditional probability formula:

[tex]P(B|A)=\dfrac{P(A\text{ and } B)}{P(A)}[/tex]

[tex]\Rightarrow\ 0.30=\dfrac{P(\text{not wear glasses and in 10th grade})}{0.45}\\\\\Rightarrow\ P(\text{not wear glasses and in 10th grade})=0.45\times0.30\\\\0.135=13.5\%\approx14\%[/tex]

Hence, the probability that a randomly chosen member of the JV swim team does not wear glasses and is in the 10th grade = 14%.

So, the correct option is "14%".

Answer:

1.734

Step-by-step explanation:

Given that:

A local trucking company fitted a regression to relate the travel time (days) of its shipments as a function of the distance traveled (miles).

The fitted regression is Time = −7.126 + .0214 Distance

Based on a sample size n = 20

And an Estimated standard error of the slope = 0.0053

the critical value for a right-tailed test to see if the slope is positive, using ∝ = 0.05 can be computed as follows:

Let's determine the degree of freedom df = n - 1

the degree of freedom df = 20 - 2

the degree of freedom df =  18

At the level of significance ∝ = 0.05 and degree of freedom df =  18

For a right tailed test t, the critical value from the t table is :

[tex]t_{0.05, 18} =[/tex] 1.734

Answer:

- 24 - 70i

Step-by-step explanation:

Given

([tex]\sqrt{5}[/tex] - 7i)²

= ([tex]\sqrt{5}[/tex] - 7i)([tex]\sqrt{5}[/tex] - 7i)

= 5 - 7[tex]\sqrt{5}[/tex] i - 7[tex]\sqrt{5}[/tex] i + 49i² ( note that i² = - 1 )

= 5 - 14[tex]\sqrt{5}[/tex] i - 49

= - 44 - 14[tex]\sqrt{5}[/tex] i

Answer:

Step-by-step explanation:

(a - b)² = a² - 2ab + b²

[tex][\sqrt{5} - 7i]^{2}= (\sqrt{5})^{2} - 2*\sqrt{5}*7i + (7i)^{2}\\\\\\= 5 - 14i\sqrt{5}+7^{2}*i^{2}]]= 5 -14i\sqrt{5} +49 * -1\\\\= 5 -14i\sqrt{5} - 49\\\\= -44 - 14i\sqrt{5}[/tex]

Answer:

x = 8.4

y = -2

Step-by-step explanation:

Step 1: Sub y=-2 into y=5x + 40

-2 = 5x + 40

Step 2: Solve for 'x'

-2 = 5x +40

-42 = 5x

x = 42/5

x = 8.4

Step 3: Solve for 'y'

y is given in the question, y=-2

Answer:

$1.60 a crate

Step-by-step explanation:

t= 95.94/(6x20)

(6x20)= 60

95.94/60

$1.60

Answer:

Step-by-step explanation:

i) Cost per box = cost of a crate ÷ Number of boxes in the crate

b = 95.94 ÷ 6

b = $ 15.99

ii) Cost per tile = Cost per box ÷ Number of tiles in a box

 t = b ÷ 20

 t = 15.99 ÷20

t = $ 0.7995

Answer:

Longer than

Step-by-step explanation:

The lengths of sides A C and F E are congruent. The lengths of sides B C and D E are congruent. Therefore:

AC = FE, BC = DE

Also m∠C is greater than m∠E

∠C is the angle opposite to line AB and ∠E is the angle opposite to line DF. Since AC = FE, BC = DE and m∠C is greater than m∠E. The length of a side of a shape is proportional to its opposite angle, since the opposite angle of AB is greater than the opposite angle of DF  therefore AB is greater than DF

From the given two triangles under the given conditions of congruency, we can say that;

Line segment AB is longer than Line segment FD.

The image showing both triangles is missing and so i have attached it.

Therefore, we can say that line AB and line FD do not have the same length.

Now, we see that angle BCA is larger than angle DEF, and as such we can say that the line segment AB is longer than line segment FD.

Read more about congruency at; https://brainly.com/question/3168048

Answer:

x = -6; v = 4.

Step-by-step explanation:

–14 = –(-2x + 2)

-14 = 2x - 2

2x - 2 = -14

2x = -12

x = -6.

51 = 7(-1 + 2v) + 2

51 = -7 + 14v + 2

51 = 14v - 5

14v = 56

v = 4.

Hope this helps!

Answer:

The monthly growth rate is 3.5%.

Step-by-step explanation:

The exponential growth function is given as follows:

[tex]y=a(1+r)^{x}[/tex]

Here,

y = final value

a = initial value

r = growth rate

x = time taken

The provided expression for the monthly growth of membership in the new drama club at a school is:

[tex]f(x) = 12\cdot(1.035)^{x}[/tex]

Comparing this function with the exponential growth function:

[tex]a(1+r)^{x}=12(1.035)^{x}\\\\a(1+r)^{x}=12(1+0.035)^{x}[/tex]

Then value of r is 0.035 or 3.5%.

Thus, the monthly growth rate is 3.5%.

Answer:

The highest power of the equation is 2, since the equation is y = 4x^2 - 1. That means that the graph is a parabola. And because the 4 is positive, the parabola curves into a smile.

You can use the Math is Fun Function and Calculator to graph the parabola.

Hope this helps!

Answer:

6. No. See explanation below.

7. 18 months

8. 16

Step-by-step explanation:

6. To rewrite a sum of two numbers using the distributive property, the two numbers must have a common factor greater than 1.

Let's find the GCF of 85 and 99:

85 = 5 * 17

99 = 3^2 + 11

5, 3, 11, and 17 are prime numbers. 85 and 99 have no prime factors in common. The GCF of 85 and 99 is 1, so the distributive property cannot be used on the sum 85 + 99.

Answer: No because the GCF of 85 and 99 is 1.

7.

We can solve this problem with the lest common multiple. We need to find a number of a month that is a multiple of both 6 and 9.

6 = 2 * 3

9 = 3^2

LCM = 2 * 3^2 = 2 * 9 = 18

Answer: 18 months

We can also answer this problem with a chart. We write the month number and whether they are home or on a trip. Then we look for the first month in which both are on a trip.

Month                Charlie          Dasha

1                          home             home

2                          home             home

3                          home             home

4                          home             home

5                          home             home

6                         trip                home

7                          home             home

8                          home             home

9                          home             trip

10                         home             home

11                         home             home

12                         trip               home

13                         home             home

14                         home             home

15                         home             home

16                         home             home

17                         home             home

18                         trip                 trip

Answer: 18 months

8.

First, we find the prime factorizations of 96 an 80.

96 = 2^5 * 3

80 = 2^4 *5

GCF = 2^4 = 16

Answer: 16

Answer:

see explanation

Step-by-step explanation:

point on left is -1 and 3/6 = -9/6 = -3/2

point on right is 5/6

Difference 5/6 - -3/2 = 14/6 = 7/3

Answer:

Step-by-step explanation:

We will get m when we multiply (m/2)*(2/3) &  m *(-3/2)

[tex]\frac{m}{2}*\frac{2}{3}+m*\frac{-3}{2}=\frac{m}{3}-\frac{3m}{2}\\\\\\=m(\frac{1}{3}-\frac{3}{2})\\\\\\=m(\frac{2}{6}-\frac{9}{6})\\\\\\=\frac{-7}{6}m[/tex]

Coefficient of m = -7/6

Answer:

A.       (-4,8) and (2,-4)

Step-by-step explanation:

Because you already have a value for "y" you can plug in that value of "y" into the next equation and then solve for Y and X

Answer:

h=6.003 cm

Step-by-step explanation:

[tex] \frac{1}{3} \pi {r}^{2} h \: \: is \: the \: volume \: of \: cone[/tex]

1/3×22/7×7×7×h=308

h=308/51.3

Answer:

h = 6 cm

Step-by-step explanation:

r = 7 cm

Volume of cone = 308 cm³

[tex]\frac{1}{3}\pi r^{2}h=308\\\\\\\frac{1}{3}*\frac{22}{7}*7*7*h=308\\\\\\h=\frac{308*3*7}{22*7*7}\\\\\\h=2*3[/tex]

h = 6 cm

Answer:

Step-by-step explanation:

This study investigated three mathematics teachers' construction process of geometric structures using compass and straightedge. The teacher-student-tool interaction was analysed. The study consists of the use of a compass and straightedge by the teachers, the ideas of the teachers about their use, and the observations regarding the learning process during the construction of the geometric structures. A semi-structured interview was conducted with the teachers about the importance of the use of a compass and straightedge to construct geometric structures. It was found that teachers taught compass and straightedge constructions in a rote manner where learning is little more than steps in a process. The study concludes with some suggestions for the use of a compass and straightedge in mathematics classes based on the research results. SUMMARY Purpose and significance: For more than 2,000 years, the way in which geometric structures could be constructed with the help of compasses and straightedges has caught the attention of mathematicians. Nowadays, mathematics curriculums place an emphasis on the use of the compass and straightedge. The compass and straightedge is more important in constructing geometric structures than other drawing tools such as rulers and protractors. Because steps taken with a compass and straightedge cannot be seen at first glance and this situation become a problem for students. However, 'doing compass and straightedge construction early in the course helps students to understand properties of figures'

Answer:

Step-by-step explanation:

Since we are finding cos A we have

From the question

AC = √96

AB = 14

Substitute the values into the above formula

That's

We have the final answer as

Hope this helps you

Answer:

Step-by-step explanation:

We first need to figure out what the equation is for this set of circumstances before we can answer any questions. We will use the equation

[tex]A(t)=P(1+r)^t[/tex] which is just another form of an exponential equation where

(1 + r) is the growth rate, P is the initial investment, and t is the time in years. We will fill in the values we know first to create the equation:

[tex]A(t)=4000(1+.11)^t[/tex] which simplifies to

[tex]A(t)=4000(1.11)^t[/tex]

Now we'll just sub in a 1 for t and solve, then a 2 for t and solve.

When t = 1:

A(t) = 4000(1.11) so

A(t) = 4440

When t = 2:

[tex]A(t)=4000(1.11)^2[/tex] which simplifies to

A(t) = 4000(1.2321) so

A(t) = 4928.40

Answer:

[tex]\large \boxed{\mathrm{B. \ 84}}[/tex]

Step-by-step explanation:

[tex]LU[/tex] bisects [tex]RU[/tex] and [tex]UA[/tex].

[tex]RU=UA[/tex]

[tex]3m+21=6m[/tex]

Solve for m.

Subtract 3m from both sides.

[tex]21=3m[/tex]

Divide both sides by 3.

[tex]7=m[/tex]

Calculate [tex]RA[/tex].

[tex]RA=3m+21+6m[/tex]

[tex]RA=9m+21[/tex]

Put m = 7.

[tex]RA=9(7)+21[/tex]

[tex]RA=63+21[/tex]

[tex]RA=84[/tex]

Answer:

B) 84

Step-by-step explanation:

ΔLRU ≅ ΔLAU   {SAS congruent}

Therefore, UA = UR    {CPCT}

 6m = 3m +21

Subtract 3m from both sides

6m - 3m = 3m + 21 -3m

        3m = 21

Divide both sides by 3

    3m/3 = 21/3

m = 7

RA = RU + UA

    = 3m + 21 + 6m {add like terms}

    = 9m + 21   {Plug in m =7}

    = 9*7 + 21

    = 63 + 21

RA = 84 units

Answer:

The formula for the lateral surface area (LSA) of a right cone is:

LSA = π x r x l

where: r as radius, and l as the slant height of the cone

If NASA need to do two coats of the sealant, the number of square feet that they are painting is: 2 x LSA = 2 x π x r x l

Step-by-step explanation:

Answer:

56.5 ft^2

Step-by-step explanation:

After you calulate the the surface area and double it, subtract the area of the circle.

Step-by-step explanation:

[tex]\text{Discriminant} =\Delta = b^2-4ac\\

\implies \Delta = 7^2-4(1)(10)=49-40=9\\

\therefore \Delta >0\\[/tex]

Since the discriminant is greater than zero, there are two real solutions.

Also, the solutions are $x=5$ and $x=2$

It depends really. If you stay close to the present, then predicting future results isn't too bad. The further you go out, the more unpredictable things get. This is because the points may deviate from the line of best fit (aka regression line) as time wears on. Of course, it also depends on what kind of data we're working with. Some pairs of variables are naturally going to correlate very strongly together. An example would be temperature versus ice cream sales.

A best-fit line shows an association between two variables and can therefore be used to make predictions.

An example is a scatterplot attached below showing a best-fit line that depicts the association between the number of people that bath in a pool and daily temperature.

(see attachment below).

Recall:

Therefore, a best-fit line shows an association between two variables and can therefore be used to make predictions.

An example is a scatterplot attached below showing a best-fit line that depicts the association between the number of people that bath in a pool and daily temperature.

(see attachment below).

Learn more here:

https://brainly.com/question/2396661

Answer:

Matrix multiplication is associative: ( A B ) C = A ( B C ) \displaystyle \left(AB\right)C=A\left(BC\right) (AB)C=A(BC).

Matrix multiplication is distributive: C(A+B)=CA+CB,(A+B)C=AC+BC. C ( A + B ) = C A + C B , ( A + B ) C = A C +

Answer:

73.5in³

Step-by-step explanation:

You multiply the three numbers.

3.5x5.25x4=73.5in³