A uniform horizontal beam with a length of 8m and weigh of 200N is attached to a wall by a pin connection ..Its far end is supported by the cable tha makes an angle of 53.0 with the beam. If 600N person stands 2m from the wall , find the tension in the cable as well as the magnitude and direction of the force exerted by the wall on the beam.

Answer:  La velocidad inicial es 6m/s

Explanation:

Primero escribamos las ecuaciones de movimiento:

Sabemos que la aceleración es 8m/s^2.

a(t) = 8m/s^2.

Para obtener la velocidad, tenemos que integrar sobre el tiempo:

v(t) = (8m/s^2)*t + v0

donde v0 es la velocidad inicial.

Para la posición volvemos a integrar sobre el tiempo, y tenemos:

p(t) = (1/2)*(8m/s^2)*t^2 + v0*t + p0 = (4m/s^2)*t^2 + v0*t + p0  

Donde p0 es la posición inicial.

Nosotros sabemos que en el tercer segundo, el móvil recorre 26m

Esto significa que:

p(3s) - p(2s) = 26m = (4m/s^2)(3s^2 - 2s^2) + v0(3s - 2s) + p0 - p0

26m = (4m/s^2)*5s^2 + v0*1s

De aquí podemos despejar el valor de v0:

26m  = 20m + v0*1s

6m = v0*1s

v0 = 6m/s

Explanation:

The electric force is:

F = k q₁ q₂ / r²

F = (9×10⁹ Nm²/C²) (-1.6×10⁻¹⁹ C) (+1.6×10⁻¹⁹ C) / (6.5×10⁻¹¹ m)²

F = 5.4×10⁻⁸ N

The gravitational force is:

F = G m₁ m₂ / r²

F = (6.67×10⁻¹¹ Nm²/kg²) (9.11×10⁻³¹ kg) (1.67×10⁻²⁷ kg) / (6.5×10⁻¹¹ m)²

F = 2.40×10⁻⁴⁷ N

Answer:

h = 35857 km

Explanation:

A geosynchronous orbit can be defined as circular orbit which lies on the Earth's equatorial plane and follows the direction of the Earth's rotation in a period that's equal to the Earth's rotational period and thereby appearing motionless, at a fixed position in the sky relative to the ground observers.

We are given;

Radius of earth(R) = 6.37 x 10^(6) m

Mass of earth (Me) = 5.97 x 10^(24) kg

Gravitational constant = 6.67 × 10^(-11) m³/kg.s²

The earth has a rotational period of 24 hours per day. This gives in seconds

T = 24 × 60 × 60

T = 86400 s

Let's make the height of the orbit from Earth's surface to be h

Also, let ω be the uniform angular velocity in rad/s with which the satellite rotates in the geosynchronous orbit

Now, equating the centripetal force with the gravitational force gives us;

mω²(R + h) = G•Me•m/(R + h)²

m will cancel out. Also ω can be written as 2π/T

Thus,we now have;

(R + h) = ∛(G•Me•T²/(4π²))

Plugging in the relevant values, we have;

(R + h) = ∛(6.67 × 10^(-11) × 5.97 x 10^(24) × 86400²/(4π²))

(R + h) = 42227 Km

Since R = 6.37 x 10^(6)m = 6370 km

Thus;. h = 42227 - 6370 = 35857 km

Answer:

North of west

Explanation:

Acceleration is the change in velocity over change in time.

a = Δv / Δt

The x component of the acceleration is:

aₓ = (0 − v₁ₓ) / (t₂ − t₁)

aₓ = -v₁ₓ / (t₂ − t₁)

aₓ < 0

The y component of the acceleration is:

aᵧ = (v₂ − v₁ᵧ) / (t₂ − t₁)

aᵧ > 0

Therefore, the acceleration points northwest.

The average acceleration of the object between time t1 and t2 was directed north of west.

What is Vector?

                             a = v/t

Now, The x component of the acceleration is:

          aₓ = (V2 − V1x) / (t2 − t1)

          aₓ = -V1x/ (t2 − t1)

Because the x component of V2 is 0.

          aₓ < 0

Similarly, The y component of the acceleration is:

          aᵧ = (v₂ − v₁ᵧ) / (t₂ − t₁)

          aᵧ > 0

Thus, The average acceleration of the object between time t1 and t2 was directed north of west.

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Answer:

40085 Hz

Explanation:

We are given; Sound frequency emmision of bat;f = 38.9 kHz = 38900 Hz

Bat is moving at 0.015 times the speed of sound in air.

Speed of sound in air = 343 m/s

The formula for waves reflected off the wall is calculated from Doppler equation as:

f' = f(v + v_d)/(v - v_s)

Where;

f is the frequency = 38900 Hz

f' is the detected frequency,

v_d is the velocity of the detector = 0.015 × 343 = 5.145

v_s is the velocity of the source = 0.015 × 343 = 5.145 m/s

v is the velocity of the sound = 343 m/s

Thus;

f' = 38900(343 + 5.145)/(343 - 5.145)

f' ≈ 40085 Hz

Answer:

velocity

Explanation:

Unbalanced forces on an object cause it to accelerate.  Acceleration is a change in velocity over time.

Answer:

a

Explanation:

none

Answer:

D. 15.65 meters/ seconds**

Explanation:

You're correct. Use kinematic equation to find V_final.

[tex] {v}^{2} = {v 0}^{2} + 2a(xf - x0)[/tex]

Then use the following to find time.

[tex]t = (vf - v0) \div a[/tex]

Then 50m/3.2s = 15.65m/s

Answer:

This is called restricted speed

Answer:

Kelvin

Explanation:

The SI unit to use in measuring the temperature of hot liquid is kelvin (K)

Answer:

Mass will not change based on location, while weight will change based on gravitational pull.

Explanation:

The formula for weight is mass*gravitational pull, hence weight changes based on gravitational pull

Mass will not change based on location, while weight will change based on gravitational pull. This is a true statement about mass and weight.

The most fundamental characteristic of matter is mass, which is one of the fundamental quantities in physics. Mass is a term used to describe how much matter is there in a body. The kilograms is the SI unit of mass (kg). A body's mass remains constant at all times.

The amount of weight t indicates how much gravity is pulling on a body. The weight formula is provided by: w = mg

Weight being a force The SI unit of weight is the Newton, which is also the same as the SI unit of force (N). When we look at how weight is expressed, we can see that it depends on both mass and the acceleration caused by gravity; while the mass may not change from one location to another, the acceleration caused by gravity does.

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Answer:

C. 1.50×10¹¹ m

Explanation:

First, convert the time to seconds.

8 min × (60 s/min) + 20 s = 500 s

Distance = speed × time

d = (3×10⁸ m/s) (500 s)

d = 1.50×10¹¹ m

The distance from the Sun to the Earth is 1.50 × 10¹¹. Speed is the distance travelled by an object in a particular time period. Thus, the correct option is C.

The speed of light in vacuum is commonly denoted by c. It is a universal physical constant. The speed of light (c) is exactly equal to 3.00 x 10⁸m/s (meter per second).

The speed of an object is the rate of change of position with respect to time. It is also defined as the distance covered by an object with respect to time. It can be calculated by dividing the distance travelled by an object by the time taken. It is a scalar quantity as it has only magnitude and no direction.

Speed = Distance / time

Distance = Speed × Time

Distance = 3.00 × 10⁸ × 500

Distance = 1500 × 10⁸

Distance =  1.50 × 10¹¹

Therefore, the correct option is C.

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Explanation:

Let 'F' be force acting perpendicularly, 'A' be the area and 'P' be the pressure exerted.

Then,

Pressure is directly proportional to the the force acting perpendicularly i.e.

P ∝ F ............. (i)

Pressure is inversely proportional to the area on which force acts i.e.

P ∝ 1/A ........... (ii)

Combining equations (i) and (ii),

P ∝ F/A

or, P = K × F/A [where K is a constant]

If F is 1N, A is 1m² and P is 1 N/m², then K is 1.

So, P = F/A proved...

Observation: The chimpanzee climbed the tall tree.

Inference: The chimpanzee must be very strong,

Explanation:

An inference differs from an observation because an inference is a guess or possible explanation about a phenomenon. On the other hand, an observation is a statement based on evidence gathered through the senses. In this context, the sentence that is an observation is "The chimpanzee climbed the tall tree" because this statement is based on visual evidence. Moreover, the inference is "The chimpanzee must be very strong" because this is just a guess to explain how the chimpanzee climbed up the tree.

Answer: The frequency increases as the pitch increases, and the amplitude increases as the volume increases

Explanation:

Waves have the property of:

v = f*λ

where v is the speed of the wave (which is almost constant for soundwaves, v = 340 m/s)

f is the frequency of the wave, and λ is the wavelength.

Now, we know that when the pitch of a note increases, also does the frequency of the soundwave (so the wave oscillates faster).

Now, we also want to include the amplitude of the soundwave in this.

The amplitude is related to the volume of the soundwave (actually is related to the energy, and as higher is the energy, more "loud" is the sound).

As the high pitch part is usually "louder", we can assume that we have an amplitude increase.

Then the answer would be:

"The frequency increases as the pitch increases, and the amplitude increases as the volume increases"

Answer:

6097 = x

Explanation:

x = VT + at²/2

x= 2.7 * 35 + 9.8 * (35)²/2

x=6097

Answer:

1. option a

2. option d

Explanation:

HOPE IT HELPS YOU

Answer:

HELLO BELOW IS THE ATTACHED DIAGRAM USED TO ANSWER YOUR QUESTION AS IT WAS MISSING

A) 1270⁰c

B) 65%

C) 1320⁰c

D)  62%

Explanation:

Nickel alloy composition : 50 wt% Ni - 50 wt%

initial temperature = 1200⁰c = 2190⁰F

A) The temperature at which the first liquid phase form

from the attached diagram the temperature at which the first liquid if formed is 1270⁰c ( at point 2 )

B ) The composition of this liquid phase ( THE FIRST LIQUID )

the composition is found at point 3

wt % of Nickel = 35%, wt% of copper = 100 - 35 = 65%

C ) The temperature at which the alloy melts completely

from the attached diagram the temperature = 1320⁰c ( point 4 )

D)  The composition of the last solid remaining prior to complete melting

this can be gotten at point 5 and calculated as

wt % of Ni = 62%

wt % of Cu = 100 - 62 = 38%

Answer:

The correct option is;

C) Equatorial coordinate system

Explanation:

The equatorial coordinate system is which has the most wide spread use in coordinate system for astronomy for mapping the location of celestial bodies such as stars by use of an imaginary projected celestial sphere or to rectangular coordinates with the Earth at the center.  Extending the Earth's axis onto the celestial sphere is essentially the projection of the Earths axis outwards to intersect the sphere at the celestial poles.

c, 'equatorial coordinate system'

its the correct answer on the test,,, goodluckk :))!!

Answer:

Diffusion depends among many other things also upon the concentration gradient of the diffusing substance.For example if there are two boxes with given particles first isolated from each other and if they are bought in contact, then there is a net diffusion of particles from a box with higher concentration of particles to box with lower concentration. And also diffusion rate depends at any instant directly on the concentration difference between them at that instant.Now the vaccum is equivalent to an empty box which means with this one leads to a maximum diffusion rate when bought in contact with a box with particles because there is maximum concentration difference.That is vaccum is empty ( except for energy perturbations and a small concentration of particles which will be zero for our purpose) and any bunch of particles will find least resistance to diffuse as just outside this bunch there is ‘0' concentration of the particles.

Answer:

Explanation:

It is the case of perfectly elastic collision . So we shall apply formula of velocity after collision as follows .

Let  m₁ and m₂ be the mass colliding with velocity u₁ and u₂ and their velocity become v₁ and v₂ after collision .

[tex]v_1=\frac{(m_1-m_2)u_1 }{m_1+m_2)} +\frac{2 m_2u_2}{(m_1+m_2)}[/tex]

Putting the values

[tex]v_1=\frac{ (.30-.80).40 }{( .30+.80)} +\frac{2\times .80\times(-.15) }{(.30+.80 )}[/tex]

= - 0.4 m /s

So direction of .30 kg mass will be reversed .

[tex]v_2=\frac{ ( m_2-m_1) u_2 }{( m_1+m_2)} +\frac{2 m_1u_1}{(m_1+m_2)}[/tex]

putting the values

[tex]v_2=\frac{ ( .80-.30)(-.15) }{( .30+.80)} +\frac{2 \times.30\times.40}{(.30+.80)}[/tex]

= .15 m /s

The direction of .80 kg will become from left to right ie its direction will be reversed .

b ) Minimum amount of kinetic energy will be at the position when they move with common velocity

common velocity

v = .3 x .4 - .8 x .15 / (.3 + .8)

= 0

c )

Missing energy is stored as elastic potential energy in the spring .

Answer:

first part the skater goes down a constant slope ramp, initially he has Newton's second law

pply Newton's third law, the normal is the reaction to the support of the body on the surface

the ramp shoots off.  axis becomes zero and therefore with Newton's first law its speed

Explanation:

It is the description of this movement let's write Newton's laws.

* The first law that a body goes at constant speed or zero if the sum of the external forces is zero

* the second law is F = m a

* The third law states that the forces act in pairs of equal magnitude and opposite direction, one applied to each body.

Let's apply these laws to our case

In the first part the skater goes down a constant slope ramp, initially he has Newton's second law when he accelerates from the initial velocity of zero to a terminal velocity.

The expression for this is

             Wₓ - fr = ma

             W sin θ - μ W cos θ = m a

             W = mg

             g (sin θ - μ cos) = a

the value of the coefficient of kinetic friction depends on the condition of the surface, dry, wet or muddy

This is Newton's second law

On the Y axis, which is perpendicular to the ramp we have

            N- [tex]W_{y}[/tex] = 0

If we apply Newton's third law, the normal is the reaction to the support of the body on the surface, note that it can be different from the weight.

In the second part when he is on the ramp.

In the ramp the skater enters with a speed v, suppose that the ramp has an incline so that the skater can jump, in this case the angle is positive with respect to the axis x

In this case the analysis is similar to the previous one

Newton's second law gives the acceleration of the skater, who when he reaches the end of the ramp shoots off.

 At this point the force in the x (horizontal) axis becomes zero and therefore with Newton's first law its speed this axis remains constant and the force in the y axis is the force of gravity and has an acceleration that changes if velocity according to Newton's second law

Answer:look at explanations

Explanation:

Answer:

0.4113772 s

Explanation:

Given the following :

Mass of bullet (m1) = 8g = 0.008kg

Initial horizontal Velocity (u1) = 280m/s

Mass of block (m2) = 0.992kg

Maxumum distance (x) = 15cm = 0.15m

Recall;

Period (T) = 2π√(m/k)

According to the law of conservation of momentum : (inelastic Collison)

m1 * u1 = (m1 + m2) * v

Where v is the final Velocity of the colliding bodies

0.008 * 280 = (0.008 + 0.992) * v

2.24 = 1 * v

v = 2.24m/s

K. E = P. E

K. E = 0.5mv^2

P.E = 0.5kx^2

0.5(0.992 + 0.008)*2.24^2 = 0.5*k*(0.15)^2

0.5*1*5.0176 = 0.5*k*0.0225

2.5088 = 0.01125k

k = 2.5088 / 0.01125

k = 223.00444 N/m

Therefore,

Period (T) = 2π√(m/k)

T = 2π√(0.992+0.008) / 233.0444

T = 2π√0.0042910

T = 2π * 0.0655059

T = 0.4113772 s

The period of the simple harmonic motion (SHM) is 0.42 s.

The given parameters;

The final velocity of the system after the impact is calculated as follows;

[tex]m_1 u_1 + m_2u_2 = v(m_1 + m_2)\\\\0.008(280) \ + \ 0.992(0) = v(0.008 \ + \ 0.992)\\\\2.24 = v(1) \\\\v = 2.24 \ m/s[/tex]

The spring constant is calculated as follows;

[tex]\frac{1}{2} kx^2 = \frac{1}{2} mv^2\\\\k = \frac{mv^2}{x^2} \\\\k = \frac{(0.008 + 0.992))\times 2.24^2}{(0.15)^2} \\\\k = 223 \ N/m[/tex]

The angular speed of the simple harmonic motion (SHM) is calculated as follows;

[tex]\omega = \sqrt{\frac{k}{m} } \\\\\omega = \sqrt{\frac{223}{(0.008 + 0.992)} }\\\\\omega = 14.933 \ rad/s[/tex]

The period of the oscillation is calculated as follows;

[tex]T = \frac{2\pi }{\omega} \\\\T = \frac{2\pi }{14.933} \\\\T = 0.42 \ s[/tex]

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Answer:

From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table

Please find attached the graph

Explanation:

The initial velocity of the body =  m/s

The acceleration of the body = 8 m/s²

The velocity after 5 seconds can be determined graphically and by calculation as follows;

Graphically, we have the data points which can be found by the straight line relation  v = u + a×t,

Where ,

a = The slope = 8 m/s²

u = 10 m/s = The y-intercept

Which gives;

v = 10 + 8 × t

The following data can be calculated for various time t;

Time, t     Velocity , v

0,             10

1,              18

2,             26

3,             34

4,             42

5,             50

6,             58

From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table

Please find attached the graph

By calculation, we have;

v = u + a×t

Where;

v = The final velocity

u = The initial velocity = 10 m/s

a = The acceleration = 8 m/s²

t = The time = 5 seconds

v = 10 + 5× 8 = 50 m/s.

Answer:

I assume its c. Since its talking about testing.

Explanation:

Answer:

The answer is test of durability

Explanation:

Answer:

C. Walk four times per week

Explanation:

If she wants to increase her time then, she has to walk four times per week.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.

The mathematical expression for speed is given by

speed = total distance /Total time

As given in the problem Lyla walks three times per week for 45 minutes at a speed of 4.0 miles per hour. She must walk four times a week if she wants to extend her time.

Thus, the correct answer is option C.

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The question is incomplete, the complete question is,

Lyla walks three times per week for 45 minutes at a speed of 4.0 miles per hour. She wants to increase her time. What should she do?

A. Walk at 4.5 miles per hour.

B. Walk for 50 minutes.

C. Walk four times per week.

D. Walk up and down more hills.

your answer is...

C. potassium

Answer:

Gravitational fields are determined only by the mass ( or mass-energy) of a body. ... magnetic fields are produced by charged particles in motion, and depend on the charge and velocity of these particles, but not on their mass. Magnetic fields are 'polar' fields with a North and South polarity.

Explanation:

Answer:

The angular acceleration is 3.33 rad/s²

Explanation:

Here is the preceding problem as well as the given problem:

A boy rides his bicycle 2.00 km. The wheels have radius 30.0 cm. What is the total angle the tires rotate through during his trip?

21.

If the boy on the bicycle in the preceding problem accelerates from rest to a speed of 10.0 m/s in 10.0 s, what is the angular acceleration of the tires?

Explanation:

From one of the equations of kinematics for linear motion

v = u + at

Where v is the final speed

u is the initial speed

a is the linear acceleration

and t is time

From the question,  the boy starts from rest, hence,

u = 0.0 m/s

v = 10.0 m/s

t = 10.0 s

a = ??

From, v = u + at

a = [tex]\frac{ v - u}{t}[/tex]

a = [tex]\frac{10 - 0}{10}[/tex]

a = 1 m/s²

Now, for the angular acceleration, [tex]\alpha[/tex]

The relationship between linear acceleration, a and angular acceleration, [tex]\alpha[/tex] is

a = [tex]\alpha[/tex]r

where r is radius

From the previous question, r = 30.0cm = 0.3m

From the equation, a = [tex]\alpha[/tex]r

[tex]\alpha[/tex] = a / r

[tex]\alpha[/tex] = 1 / 0.3

[tex]\alpha[/tex] = 3.33 rad/s²

Explanation:

To find the average of these numbers, we just have to add the three numbers together and divide by 3.