Answer:
d = 245Step-by-step explanation:
d is directly proportional to the square of a speed v
d = av²
5 = a•10²
5 = 100a
a = 0.05
d = 0.05v²
d = 0.05•70²
d = 0.05•4900
d = 245
Plz Help I Will Mark Brainliest If Right f(x) = x^2 + 3 A). y > -3 B). All real numbers C). y ≥ 3 D). y ≤ 3
Answer:
C) y ≥ 3
Step-by-step explanation:
The answer choices suggest that you're interested in the range of the function. x^2 cannot be negative, so its value will be 0 or greater. Adding 3 to x^2 ensures that the value of f(x) will be 3 or greater.
y ≥ 3 . . . . matches C
Solve for X in the diagram below
PLS HELP BRAINLIST AND A THANK YOU WILL BE REWARDED :)
The 3 angles need to equal 180
The middle angle is given as 100.
180 -100 = 80
There is an x on each side so you have 2x
2x = 80
X = 80/2
X = 40 degrees
6
PO
2. In school of 900 studonts, it was
found that 600 students participate
in singing 500 students
in dancing and 125
do not participate
in both the activities.
participate
Answer:
[tex]B = 325[/tex]
Step-by-step explanation:
Given
Total = 900
Singing = 600
Dancing = 500
None = 125
Required
Determine the number of students that participate in both
Representing; Singing with S, Dancing with D, Both singing and dancing with B and None with N;
In Set Notation;
[tex]Total = (S - B) + (D - B) + N + B[/tex]
Substitute 900 for Total, 600 for S, 500 for D and 125 for N
[tex]900 = (600 - B) + (500 - B) + 125[/tex]
Open Brackets
[tex]900 = 600 - B + 500 - B + 125 + B[/tex]
Collect Like Terms
[tex]900 = 600 + 500 + 125 - B - B + B[/tex]
[tex]900 = 1225- B - B + B[/tex]
[tex]900 = 1225- B[/tex]
Collect Like Terms
[tex]900 - 1225 = -B[/tex]
[tex]-325 = -B[/tex]
Multiply both sides by -1
[tex]-1 * -325 = -B * -1[/tex]
[tex]325 = B[/tex]
Reorder
[tex]B = 325[/tex]
Hence, the number of students that do not participate in both is 325
12 people can paint the orchard in one hour How long would it take five people Give your answer in minutes
Answer:
[tex] \boxed{144 \: \: \: minutes}[/tex]Step-by-step explanation:
Let's solve :
[tex] \mathsf{ \: people \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:time \: ( \: in \: minutes)}[/tex]
[tex] \mathsf{12 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: 1 \: hour \: = \: 60 \: minutes }[/tex]
[tex] \mathsf{5 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: t }[/tex]
The amount of time needed for completion is inversely proportional to the number of people working on the orchard. Let t be the amount of time ( in minutes ) needed when there are 5 people working.
[tex] \mathsf{ \frac{12}{5} = \frac{t}{60} }[/tex]
Apply cross product property
[tex] \mathsf{5t = 12 \times 60}[/tex]
Multiply the numbers
[tex] \mathsf{5t = 720}[/tex]
Divide both sides of the equation by 5
[tex] \mathsf{ \frac{5t}{5} = \frac{720}{5} }[/tex]
Calculate
[tex] \mathsf{t = 144 \: minutes}[/tex]
Hope I helped!
Best regards!!
It will take five people 144 minutes to paint the orchard.
12 people can paint the orchard in one hour, which is 60 minutes.
If there are five people, it will take them 12 × 60 / 5 = 144 minutes to paint the orchard.
So the answer is 144
Here's the explanation:
We know that the number of people and the time it takes to paint the orchard are inversely proportional. This means that if we increase the number of people, the time it takes to paint the orchard will decrease.
We can also set up a proportion to find the time it takes five people to paint the orchard. The proportion will look like this:
12 people : 5 people :: 60 minutes : x minutes
Cross-multiplying, we get:
12 × x = 5 × 60
x = 5 × 60 / 12
x = 144 minutes
Therefore, it will take five people 144 minutes to paint the orchard.
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Two mechanics worked on a car. The first mechanic charged $85 per hour, the second mechanic charged $90 per hour. The mechanic worked for a combined total of 25 hours, and together they charged a total of $2200. How lond did each mechanic work?
Answer:
First mechanic worked for = 10 hours
Second mechanic worked for = 15 hours.
Step-by-step explanation:
Let the number of hours the First mechanic worked = X
Let the number of hours the Second mechanic worked = Y
The first mechanic charged = $85 per hour
The second mechanic charged = $90 per hour
We are told in the question that: The mechanic worked for a combined total of 25 hours, and together they charged a total of $2200
Hence, we have the following equations from the above question
85X + 90Y = 2200....... Equation 1
X + Y = 25 ........ Equation 2
X = 25 - Y
Substitute 25 - Y for X in equation 1
85(25 - Y) + 90Y = 2200
2125 - 85Y + 90Y = 2200
Collect like terms
5Y = 2200 - 2125
5Y = 75
Y = 15
Since Y is the number of hours the second mechanic worked, hence, the second mechanic worked for 15 hours.
X + Y = 25 ........ Equation 2
Y = 15
X + 15 = 25
X = 25 - 15
X = 10
Since X represents the number of hours that the first mechanic worked, hence, the first mechanic worked for 10 hours.
Therefore, the first mechanic worked for 10 hours and the second mechanic worked for 15 hours.
What is the possibility that a red or green marble will be selected from a bag containing 9 red marbles, 6 blue marbles , 7 green marbles and 11 yellow marbles
Answer:
16/33
Step-by-step explanation:
We have a bag of :
9 red marbles
6 blue marbles
7 green marbles
11 yellow marbles
Total number of marbles = 33 marbles.
The possibility that a red or green marble will be selected from a bag
P( Red or Green) = P(Red) + P(Green)
In the question we are not told if it is with replacement or without. We do both
With replacement
P( R or G) = P(Red) + P(Green)
P(Red)= 9/33
P(Green) = 7/33
= 9/33 + 7/33
= 16/33
Therefore, the possibility that a red or green marble will be selected from a bag is 16/33
Write 30+x^2-11 in standard form.
Answer:
x^2+19
Step-by-step explanation:
Translate the following phrase into an algebraic expression using the variable m. Do not simplify
the cost of renting a car for one day and driving m miles if the rate is $48 per day plus 50 cents per mile
Answer:
y = 0.5X + 48
Answer:
48 + 0.50m
Step-by-step explanation:
m, the variable, equals to the number of miles driven. Since there is a base fare of $48, that will be the constant. It is $0.50 per mile, so it's 0.50m. Substituting for m, the miles driven, will give you the final cost.
Kevin ordered some books online for seven dollars each he paid a total of six dollars for shipping the total cost of the purchase was $97 how many books did he buy?
Answer:
a) 7b+6=97
b)b=13
Step-by-step explanation:
Total cost = $97
Cost of each book = $7
Cost of shipping =$6
Therefore ,
Cost of the total no. of books+ Cost of shipping = Total Cost
=>7b+6= 97 <------- Answer to part(a)
=>7b=97-6
=>7b=91
=>b=13
No. of books = 13 <--------- Part (b)
A recipe for peanut butter cookies calls for 1 cup of sugar, 1 cup of chunky peanut butter, and 1 medium egg. The recipe yields 18 cookies. If the baker has 12.5 cups of sugar, 15 cups of chunky peanut butter, and 10 eggs. How many full batches of cookies can the baker make
Answer:
10 batches - they only have 10 eggs, so they can't make any more batches without them
Which phrase best describes the relationship indicates by the scatter plotting?
Answer: negative correlation
Step-by-step explanation: If you look at the points in this graph here, I would say that those points are very close to a perfect line.
Notice that the slope of the line is negative.
This means it will be a negative correlation.
So the line is a very good estimate of the points.
Solve for x : 2^(x-5) . 5^(x-4) = 5
Answer:
x = 5
Step-by-step explanation:
Notice that there is also a base 5 on the right hand side of the equation, therefore, let's move [tex]5^{x-4}[/tex] to the right by dividing both sides by it. and then re-writing the right hand side as 5 to a power:
[tex]2^{x-5}\,*\,5^{x-4}=5\\2^{x-5}=5/5^{x-4}\\2^{x-5}=5\,*\,5^{4-x}\\2^{x-5}=5^{5-x}[/tex]
Now apply log to both sides in order to lower the exponents (where the unknown resides):
[tex](x-5)\,log(2)=(5-x)\,log(5)[/tex]
Notice that when x = 5, this equation is true because it makes it the identity: 0 = 0
So, let's now examine what would be the solution of x is different from 5, and we can divide by (x - 5) both sides of the equation:
[tex]log(2)=\frac{5-x}{x-5} \,log(5)\\log(2)=-1\,\,log(5)\\log(2)=-log(5)[/tex]
which is an absurd because log(2) is [tex]\neq[/tex] from log(5)
Therefore our only solution is x=5
Answer:
if decimal no solution
if multiply x =5
Step-by-step explanation:
If this is a decimal point
2^(x-5) . 5^(x-4) = 5
Rewriting .5 as 2 ^-1
2^(x-5) 2 ^ -1 ^(x-4) = 5
We know that a^ b^c = a^( b*c)
2^(x-5) 2 ^(-1*(x-4)) = 5
2^(x-5) 2 ^(-x+4) = 5
We know a^ b * a^ c = a^ ( b+c)
2^(x-5 +-x+4) = 5
2^(-1) = 5
This is not true so there is no solution
If it is multiply
2^(x-5) * 5 ^(x-4) = 5
Divide each side by 5
2^(x-5) * 5 ^(x-4) * 5^-1 = 5/5
We know that a^ b * a^c = a^ ( b+c)
2^(x-5) * 5 ^(x-4 -1) = 1
2^(x-5) * 5 ^(x-5) = 1
The exponents are the same, so we can multiply the bases
a^b * c*b = (ac) ^b
(2*5) ^ (x-5) = 1
10^ (x-5) = 1
We know that 1 = 10^0
10^ (x-5) = 10 ^0
The bases are the same so the exponents are the same
x-5 = 0
x=5
I need help will rate brainliest please
Answer:
the stone fell in the air for 7 sec and fell in the water for 5 sec
Answer:
Let time taken in air be 'a'
And the time taken in water be 'b'
a+b=12
Distance covered in air = 16a
′′′′′ ′′″″ water= 3b
16a + 3b = 127
Solve the two equations simultaneously
a= 7 secs
b= 5 secs
WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!
In the following graph, ∆ABC is congruent to ∆A’B’C’. A teacher asks Janine to state the translation rule for this transformation. She focuses on point C’ and states that “the translation rule is
(x,y)→(x-2, y-6).
In other words, to shift from the blue to the red triangle, you must shift each point two units to the left and six units down. Janine made an error.
Explain how to correct her rule by either using transformation notation showing each step or explain using 2-3 sentences.
Answer:
She moved 3 to the left and 5 down.
She could have calculated each point seperately.
A(1,-1) then subtract 2 and subtract 6 from the x and then the y-coordanate, which gets you to A'(-1,-7). Then, do this with every other coordanate and you will get your answer. Hope this helped!
Find the volume of the tank below. * PLEASE ANSWER ASAP *
Answer:
63
Step-by-step explanation:
pie multiply 2 sq. 2 multiply with 5
Here's a graph of a linear function. Write the
equation that describes that function.
Express it in slope-intercept form.
there is no visible graph
Step-by-step explanation:
Need help give you a good rating pls.
Answer:
x^(1/2)
Step-by-step explanation:
For this, we need to understand exponent rules. This one is like this, "A power to a power, you multiply the exponents". This is simply, because this expression would be equivalent to 3 base terms:
(x^(1/6))^3 = (x^(1/6)) * (x^(1/6)) * (x^(1/6))
And when you perform this multiplication "Powers of like bases, you add the exponents", you will get the following
(x^(1/6)) * (x^(1/6)) * (x^(1/6)) = x^(1/6 + 1/6 + 1/6) = x^(3/6) = x^(1/2)
Hence, this expression simplifies to x^(1/2).
Cheers.
Answer:
[tex] \boxed{ {x}^{ \frac{1}{2} } }[/tex]Option D is the correct option.
Step-by-step explanation:
[tex] \mathrm{ ({x}^{ \frac{1}{6} } ) ^{3} }[/tex]
[tex] \mathrm{simplify \: the \: expression \: by \: multiplying \: exponents}[/tex]
[tex] \mathrm{ = {(x)}^{ \frac{1}{6} \times 3 } }[/tex]
[tex] \mathrm{ = {x}^{ \frac{1}{2} } }[/tex]
Hope I helped!
Best regards!
What is the average time for the toy car to move 1.0 m on dirt? 20.2 s, 24.4 s, 28.1 s or 60.7 A student collected data about the distance a ball falls over time. Which type of graph should he use to represent the data? circle graph, scatterplot, histogram or bar graph
Answer:
1) Incomplete question
2) Scatterplot
Step-by-step explanation:
1) The question is incomplete. To calculate the average time required for the toy car to move, the formula to be used will be
velocity = distance ÷ time
Hence; time = distance ÷ velocity
2) There are two variables in the question; the distance (it takes the ball to fall) and the time. The type of graph (from the option) that can have two variables represented on it is a scatterplot.
Answer:
answer; A. 20.2 s.
Step-by-step explanation:
i had the same question but i had a graph to help me anyways
20.0 + 19.2 + 21.5 = 60.7 s, but you divide the total by 3, then here is your answer: 20.23333333333333 and you simplify it to 20.2 s,
2x/9 +x/3 = 13/6, solve for x
Answer:
x = 3 9/10
Step-by-step explanation:
2x/9 +x/3 = 13/6
Get a common denominator on the left side
2x/9 + x/3 *3/3 = 13/6
2x/9 + 3x/9 = 13/6
5x/9 = 13/6
Multiply each side by 9/5 to isolate x
5x/9 *9/5 = 13/6 * 9/5
x = 117/30
Divide the top and bottom by 3
x = 39/10
x = 3 9/10
Answer:
[tex]\bold{\red{\boxed{\blue{ x = 3.9}}}}[/tex]
Step-by-step explanation:
[tex] \frac{2x}{9} + \frac{x}{3} = \frac{13}{6} \\ \frac{2x + 3x}{9} = \frac{13}{6} \\ \frac{5x}{9} = \frac{13}{6} \\ use \: \: cross \: \: multipication \\ 5x \times 6 = 9 \times 13 \\ 30x =11 7 \\ \frac{30x}{30} = \frac{117}{30} \\ x = 3.9[/tex]
6 points are placed on the line a , 4 points are placed on the line b . How many triangles is it possible to form such that their vertices will be the given points, if a ∥ b ?
Answer:
7
Step-by-step explanation:
Given line a with 6 points on it, and line b with 4 points on it. Line a is parallel to line b, such that the two lines do not meet at any point even when extended.
Join the first point on line a to that on b, then back to the second point on a, return back to the second point on b, and continue till the line stops at the 5th point on line a. This forms triangles with vertices at the given points on the lines. The possible number of triangles that can be formed is 7.
Please help I did the first 2 already.
The answer to C is 1.5 or 3/2
Since we know that 2x is equal to 3 because the solution is three and 3+3=6 then we divide 3 by 2 to get 3/2
When factoring 6x2−7x−20 by grouping, how should the middle term be rewritten? It should be written as 8x−15x. It should be written as −2x−5x. It should be written as x−8x. It should be written as −x−7x. I think it should be B but im not quite sure Is the given equation a quadratic equation? x(x−6)=−5 The equation is not a quadratic equation because there is no x2-term. The equation is a quadratic equation because there is an x2-term. The equation is not a quadratic equation because the expression is not equal to zero. The equation is not a quadratic equation because there is a term with degree higher than 2. For this one i think its A but once again im not sure. Which of the following is an example of the difference of two squares? x2−9 x3−9 (x+9)2 (x−9)2 this one i have no clue i would appreciate it if anyone could explain this one.
Answer:
(3x+4)(2x-5)
Step-by-step explanation:
Factor by grouping.
Please answer this question now in two minutes
Answer:
m∠C = 102°
Step-by-step explanation:
This diagram is a Quadrilateral inscribed in a circle
The first step is to determine what m∠B
is
The sum of opposite angles in an inscribed quadrilateral is equal to 180°
m∠D + m∠B = 180°
m∠B = 180° - m∠D
m∠B = 180° - 80°
m∠B = 100°
Second step is we proceed to determine the exterior angles of the circle
m∠ADC = 2 × m∠B
m∠ADC = 2 × 100°
m∠ADC = 200°
m∠ADC = m∠CD + m∠AD
m∠AD = m∠ADC - m∠CD
m∠AD = 200° - 116°
m∠AD = 84°
The third step is to determine m∠BAD
m∠BAD = m∠AD + m∠AB
m∠BAD = 84° + 120°
m∠BAD = 204°
The final step Is to determine what m∠C is
It is important to note that:
m∠BAD is Opposite m∠C
Hence
m∠C = 1/2 × m∠BAD
m∠C = 1/2 × 204
m∠C = 102°
How many and of which kind of roots does the equation f(x) = x3 – x2 – x + 1 have?
A. 2 real; 1 complex
B. 1 real; 2 complex
C. 3 real
D. 3 complex
The kind of roots does the equation f(x) is option (C) 3 real roots is the correct answer.
What is a polynomial equation?A polynomial equation is a sum of constants and variables. A polynomial is an expression consisting of indeterminate's (also called variables) and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.
For the given situation,
The equation [tex]f(x) = x^3 - x^2 - x + 1[/tex]
The roots of the polynomial equation can be found as follows,
Step 1:
Substitute the value of x in which the equation f(x) equals zero.
⇒ Put [tex]x = 1[/tex], the equation becomes
⇒ [tex]f(1) = 1^3 - 1^2 - 1 + 1[/tex]
⇒ [tex]f(1) = 0[/tex]
Thus [tex](x - 1)[/tex] is the one root of the equation.
Step 2:
The other roots can be found by framing the quadratic equation on dividing the equation [tex]f(x) = x^3 - x^2 - x + 1[/tex] by [tex](x - 1)[/tex]
On dividing [tex]f(x) = x^3 - x^2 - x + 1[/tex] by [tex](x - 1)[/tex] we get the quotient,
⇒ [tex](x^{2} -1)[/tex]
Step 3:
Now factorize the quadratic equation, [tex](x^{2} -1)[/tex]
It can be expand using the identity,
⇒ [tex](x^{2} -1^{2} ) = (x+1)(x-1)[/tex] [∵ (a^2 - b^2) = (a+b)(a-b) ]
Thus the factors of the equation are [tex](x-1)(x+1)(x-1)[/tex]. So the roots are [tex]1,-1,1[/tex].
Hence we can conclude that the kind of roots does the equation f(x) is option (C) 3 real roots is the correct answer.
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Please help with 6 and 7
Answer:
6a) i- 2hrs 36mins ii- 3hrs 12mins
b) car A≈ 76.9km/h car B≈ 62.5km/h
c)------
7a) 35km
b) car A=75km car B=60km
c) 30km
d) car A≈36mins car B≈48mins
Step-by-step explanation:
6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.
b) Using the answer from a, you divide 200km by the time.
For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6
∴ car A: 200/2.6≈ 76.92km/h
For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2
∴ car B: 200/3.2≈ 62.5km/h
7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.
b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).
c) Difference from car A line to car B:
155km-125km=30km
d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.
Hope this helps.
Which equation represents a population of 320 animals that decreases at an annual rate of 19% ?
A. p=320(1.19)t
B. p=320(0.81)t
C. p=320(0.19)t
D. p=320(1.81)t
Use the ^ symbol to indicate exponents. So for instance 4^2 = 4 squared.
A decrease of 19% means we have r = -0.19 and 1+r = 1+(-0.19) = 0.81 as the base of the exponent. A decrease of 19% means the population retains 81% each year.
the area of a trapezium is 14.7cmsquare. if the parallel sides are 5.3cm and 3.1cm long,find the perpendicular distance between them
The perpendicular distance of the trapezoid is 3.5 cm
How to determine the perpendicular distance?The given parameters are:
Parallel sides = 5.3 cm and 3.1 cmArea = 14.7 square cmThe area of a trapezoid is:
Area = 0.5 * (Sum of parallel sides) * perpendicular distance
So, we have:
14.7 = 0.5 *(5.3 + 3.1) * perpendicular distance
Evaluate
Perpendicular distance = 3.5
Hence, the perpendicular distance of the trapezoid is 3.5 cm
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In pentagon ABCDE, A = 87º, B = 1250, C = 63º, and E = 95º. Find
D.
A. 160
B. 169
C. 170
D 530
Answer:
[tex]D = 170\º[/tex]
Step-by-step explanation:
Given
Shape: Pentagon
[tex]A = 87\º[/tex]
[tex]B = 125\º[/tex]
[tex]C = 63\º[/tex]
[tex]E = 95\º[/tex]
Required
Find D
From the sum of angles in a Pentagon; we have that
[tex]A + B + C + D + E = 540[/tex]
Substitute values for A, B, C and E
[tex]87\º + 125\º + 63\º + D + 95\º = 540\º[/tex]
Collect Like Terms
[tex]87\º + 125\º + 63\º + 95\º + D = 540\º[/tex]
[tex]370\º + D = 540\º[/tex]
Collect Like Terms
[tex]D = 540\º - 370\º[/tex]
[tex]D = 170\º[/tex]
Hence, from the list of given options, the correct answer is 170
Given that ∆MTW ≅ ∆CAD, which angles are corresponding parts of the congruent triangles? ∠T ≅ ∠C ∠T ≅ ∠A ∠T ≅ ∠D
Answer:
∠T ≅ ∠A
Step-by-step explanation:
Since, ∆MTW ≅ ∆CAD
Therefore, ∠T ≅ ∠A (cpct)
Which of the following statements is false? A. A rectangle is an equiangular quadrilateral. B. Opposite sides of a parallelogram are congruent. C. A square is a regular quadrilateral. D. The diagonals of a rectangle are perpendicular.
Answer:
D.
Step-by-step explanation:
Choices A., B., and C. are always true.
Choice D. is true only for rectangles with congruent sides, which are squares.
Answer: D.
