Please help me im struggling and i need to get a 100%

Please Help Me Im Struggling And I Need To Get A 100%

Answers

Answer 1

Answer:

The answer is 29.

Step-by-step explanation:

a straight line is 180 degrees, to subtract 77 from 180 to figure out the red angle. Which is 103 degrees as shown also in red. Now we add 103 and 48 which is 151 degrees. And since all straight lines are 180 degrees, that means that angle p has to be 29. If you add 29 to 151, then you get 180 degrees.

Please Help Me Im Struggling And I Need To Get A 100%
Please Help Me Im Struggling And I Need To Get A 100%
Answer 2
We can picture that there is a straight line (see attached picture).

Since a straight line = 180 degrees, the two angles add up to 180 degrees.

One angle is already 77, so we can subtract 77 from 180, to get the other angle.

Now that we know the other angle=103 degrees, we can imagine another straight line (see 2nd attached image)

Again, since a straight line = 180 degrees, we can subtract the other two angles to find the value of p.

p=29 degrees.

If anything did not make sense, or this didn’t answer your question, feel free to leave a comment!
(For some reason it isn’t letting me add two pictures)

I got the 103 degrees by subtracting 77 from 180.
Please Help Me Im Struggling And I Need To Get A 100%

Related Questions

Please help asap! Also explain how you did it... Tys m!♡♡

Answers

Answer:

A" (-3, 0)

B" (9, 9)

C" (9, 0)

Step-by-step explanation:

The hint explains how to get the final coordinates.

The original figure ABC has vertices

A (-3, -1)
B (1, 2)

C (1, -1)

There are two separate transformations for this triangle, so let's take it one step at a time

The first transformation is a translation by the vector <2, 1>, This means we get a new figure A'B'C' where we add 2 to each of the x coordinates of the original figure and 1 to the y coordinates of the original figure

For A which is (-3,-1) the transformed coordinate becomes:
A -> A' -> A' (-3 + 2, -1 + 1) => A'(-1, 0)

Similarly

B(1, 2) -> B' is B'(1 + 2, 2 + 1) => B'(3, 3)

C(1, -1) -> C'(1 + 2, -1 + 1) or C'(3, 0)

So the first transformation results in a triangle A'B'C' with the following coordinates:

A'(-1, 0)
B'(3, 3)
C'(3, 0)

The second transformation is a dilation of A'B'C' which results in an expansion or compression of the image depending on the scale factor. Here the scale factor is 3 so the image is expanded by a factor of 3

Dilation simply requires you to multiply both x and y coordinates oof A'B'C' by 3

A' (-2 , 0) -> A"(-1 x 3, 0 x 3) => A"(-3, 0)
B'(3, 3) -> B"(9, 9)
C'(3, 0) -> C"(9, 0)

I have attached two images showing each of the transformations separately to give you a better idea

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