The layers of the earth include the following;troposphere, stratosphere, mesosphere, thermosphere, and exosphere. It's explanation will be discussed below.
What are the layers of the earth?The layers of the earth are grouped into five major layers that includes the following:
Troposphere: This is the layer of the earth that is closest to the earth's surface. It is characterized by having 78% nitrogen, 21% oxygen and remainder of trace gases (carbon dioxide, ozone, hydrocarbons, argon).
Stratosphere: This layers is located immediately above the troposphere. This layer is where ozone formation occurs and it's suitable for flying jets. It can be said that the stratosphere helps to protect us against ultraviolet rays of the sunlight.
Mesosphere: This is the layer found immediately above the stratosphere. This layer is characterized by having internal atmospheric gravity waves.
Thermosphere: This is the layer that is found immediately above the Mesosphere. It has the ability to absorb the sun's radiation.
Exosphere: This is the layer that is found immediately above the thermosphere. There is accumulation of the lightest gases such as hydrogen and helium in this layer.
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Which if these options best describes the diagnostic cleavage that is typical of the mica group of minerals (which includes muscovite and bietet A) Three perpendicular cleavage planes B) Two cleavage planes intersecting at 90° C) Two cleavage planes intersecting at 120 D) A single planar cleavage
D ) The answer that best depicts the diagnostic cleavage that is typical of the mica group of minerals which include muscovite and bietet is a single, planar cleavage .
Cleavage is the splitting of minerals along natural planes of weakness
When there is only one cleavage plane, a single, planar cleavage known as the basal or pinacoidal cleavage takes place. cleaved at the base of the graphite. Mica (like muscovite or biotite) has basal cleavage, that's why mica can be peeled into thin sheets.
So single planar cleavage is answer of this question.
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the equilibrium constant of a redox reaction can be calculated from the standard reduction potentials of involved redox couples at given temperature.
The Nernst equation and the link between the standard cell potential and free energy can be used to determine the equilibrium constant of the redox process in an electrochemical cell.
The ratio of the product concentration to the reactant concentration is the equilibrium constant. a fixed value for a certain reaction at a specific temperature. The letter "c" denotes the expression of the equilibrium constant in terms of concentrations.
The standard cell potential, temperature, reaction quotient, and the cell potential of an electrochemical cell are all related by the Nernst equation. The Nernst equation can be used to determine the cell potentials of electrochemical cells even under unusual circumstances.
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Identify the options below that are results of decreasing the temperature of a system that includes an exothermic reaction in the forward direction. A. The concentration of the reactants increases. B. The concentration of the products increases. C. The equilibrium constant decreases. D. The equilibrium shifts toward the products.
If the reaction is exothermic as described, a rise in temperature will thus trigger the opposite reaction, which will result in a decrease in the amount of the products and an increase in the number of reactants. The reverse outcome will occur if the temperature is lowered.
B. The concentration of the products increases.
A reaction is defined as exothermic if the overall standard enthalpy change (H) is negative. Exothermic processes typically produce heat. Exergonic reaction, which the IUPAC defines as "... a reaction for which the overall standard Gibbs energy change G is negative," is frequently mistaken with the phrase.
Because "H" contributes significantly to "G," a strongly exothermic process is typically also exergonic. Exothermic and exergonic chemical reactions make up the majority of the impressive demonstrations in schools.
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Find the volume, in mL, of an object whose density is 400 g/mL and has a mass of 600
mg.
The volume of the object is 1.5ml.
What is the volume of an object?This refers to the space occupied within the boundaries of an object in three-dimensional space. It is also called the capacity of the object.
In the question:
ρ = 400 g/mL
m = 600 mg
v = ?
Formular for calculating density ρ:
ρ = m/v
Where,
ρ= Density of the object
m= Mass of the object
v = volume of the object
Were are given the values of density and mass in the question. We are to calculate the volume.
Makinig v subject of the formular we have:
v = m/ρ
v = 600 mg
400 g/mL
v = 1.5ml
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