Answer:
A. SAS
B. ASA
C. SSS
D. AAS
Answer:
A. SAS(2.) B.ASA(3.) C.SSS(1.) D.AAS(4.)
Step-by-step explanation:
Look at the markings.
Do anyone know this youll get 20 points
Answer:
A. Acute
B. 80 degrees
Step-by-step explanation:
Suppose that IQ scores in one region are normally distributed with a standard deviation of . Suppose also that exactly of the individuals from this region have IQ scores of greater than (and that do not). What is the mean IQ score for this region
Answer: Hello your question is poorly written attached below is the complete question
answer : 101.8
Step-by-step explanation:
Given data :
Standard deviation ( б ) = 14
55% have IQ scores > 100
45% have IQ scores < 100
Determine the mean IQ score for the region
P ( X > x ) =
P ( Z ≥ ( 100 - μ ) / 14 ) = 0.55 also
P ( Z ≤ ( 100 - μ ) / 14 ) = 0.45
using standard normal calculator
100 - μ / 14 = Z₀.₄₅ = - 0.126
resolving the relation above
100 - μ / 14 = - 0.126
μ = 100 - 14 ( -0.126 )
= 101.764 ≈ 101.8
Drag the tiles to the correct boxes to complete the palrs.
If f(x) = 2x+3 and g(x) = x -1, find the values of combining these functions. Match each combined function to its corresponding value.
(f+g)(2)
(f-g)(4)
(f ÷g)(2)
(f x g)(1)
-4
7/3
10
0
Answer:
(f+g)(2) = 4
(f-g)(4) = 8
(f ÷g)(2) = 7
(f x g)(1) = 0
Step-by-step explanation:
We are given these following functions:
[tex]f(x) = 2x + 3[/tex]
[tex]g(x) = x - 1[/tex]
(f+g)(2)
[tex](f+g)(x) = f(x) + g(x) = 2x + 3 + x - 1 = 3x - 2[/tex]
At [tex]x = 2[/tex]
[tex](f+g)(2) = 3(2) - 2 = 6 - 2 = 4[/tex]
Then
(f+g)(2) = 4
(f-g)(4)
[tex](f-g)(x) = f(x) - g(x) = 2x + 3 - (x - 1) = 2x + 3 - x + 1 = x + 4[/tex]
At x = 4
[tex](f-g)(4) = 4 + 4 = 8[/tex]
Then
(f-g)(4) = 8
(f ÷g)(2)
[tex](f \div g)(x) = \frac{f(x)}{g(x)} = \frac{2x+3}{x-1}[/tex]
At x = 2
[tex](f \div g)(2) = \frac{7}{1} = 7[/tex]
Then
(f ÷g)(2) = 7
(f x g)(1)
[tex](f \times g)(x) = f(x)g(x) = (2x+3)(x-1) = 2x^2 -2x + 3x - 3 = 2x^2 + x - 3[/tex]
Then
[tex](f \times g)(1) = 2(1)^2 + 1 - 3 = 3 + 1 - 3 = 0[/tex]
So
(f x g)(1) = 0
All of the benches in a park are red or blue. The ratio of red benches to blue benches in the park is 3 : 4. Based on this information, which of the following statements is true?
A. For every 4 benches in the park, 3 are red.
B. For every 7 benches in the park, 4 are red.
C. For every 3 red benches in the park, there are 4 blue benches.
D. For every 3 red benches in the park, there are 7 blue benches.
(I'll give brainly, likes, follow, etc for anybody who answers this question with some explanation.)
Answer:
The answer is C
Step-by-step explanation:
3 : 4
^ ^
II II
red blue
prove that tan theta * sin theta = (1 - cos^2 theta)/(sqrt(1 - sin^2 theta))
Answer:
This identity holds as long as [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex].
For the proof, make use of the fact that:
[tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] (definition of tangents,) and
[tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] (Pythagorean identity,) which is equivalent to [tex]1 - \cos^{2}(\theta) = \sin^{2}(\theta)[/tex].
Step-by-step explanation:
Assume that [tex]\displaystyle \theta \ne k\, \pi + \frac{\pi}{2}[/tex] for all integer [tex]k[/tex]. This requirement ensures that the [tex]\tan(\theta)[/tex] on the left-hand side takes a finite value. Doing so also ensures that the denominator [tex]\sqrt{1 - \sin^2(\theta)}[/tex] on the right-hand side is non-zero.
Make use of the fact that [tex]\displaystyle \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)}[/tex] to rewrite the left-hand side:
[tex]\begin{aligned} & \tan(\theta) \cdot \sin(\theta) \\ =&\; \frac{\sin({\theta})}{\cos({\theta})} \cdot \sin(\theta) \\ =&\; \frac{\sin^{2}(\theta)}{\cos(\theta)}\end{aligned}[/tex].
Apply the Pythagorean identity [tex]\sin^{2}(\theta) = 1 - \cos^{2}(\theta)[/tex] and [tex]\cos(\theta) = \sqrt{1 - \sin^{2}(\theta)}[/tex] to rewrite this fraction:
[tex]\begin{aligned} & \frac{\sin^{2}(\theta)}{\cos(\theta)}\\ =\; &\frac{1 - \cos^{2}(\theta)}{\cos(\theta)}\\ =\; & \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}\end{aligned}[/tex].
Hence, [tex]\displaystyle \tan(\theta) \cdot \sin(\theta) = \frac{1 - \cos^{2}(\theta)}{\sqrt{1 - \sin^{2}(\theta)}}[/tex].
Which
expression is equivalent to -3-4
Answer: wheres the photo ?
Step-by-step explanation:
Answer:
-3-4=-7
-3+(-4)
hope this helps
have a good day :)
Step-by-step explanation:
PLS HELP ASAP! Given a cone with a height of 6 cm and a base diameter of 6 cm, what is the volume of the cone? Use 3.24 for π
π
Answer:
56.52 cm³
Step-by-step explanation:
[tex]\boxed{volume \: of \: cone = \frac{1}{3} \pi {r}^{2}h }[/tex]
Diameter= 2 ×radius
Radius
= 6 ÷2
= 3cm
Height, h= 6cm
Volume of the cone
[tex] = \frac{1}{3} (3.14)( {3}^{2} )(6)[/tex]
= 56.52 cm³
What is the distance between A(-8, 4) and B(4, -1)?
Answer:
The distance between A(-8, 4) and B(4, -1) is 13 units.
Step-by-step explanation:
To find the distance between any two points, we can use the distance formula given by:
[tex]\displaystyle d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]
We have the two points A(-8, 4) and B(4, -1). Let A(-8, 4) be (x₁, y₁) and let B(4, -1) be (x₂, y₂). Substitute:
[tex]d=\sqrt{(4-(-8))^2+(-1-4)^2}[/tex]
Evaluate:
[tex]d=\sqrt{(12)^2+(-5)^2}[/tex]
So:
[tex]d=\sqrt{144+25}=\sqrt{169}=13\text{ units}[/tex]
The distance between A(-8, 4) and B(4, -1) is 13 units.
___________________________________
Problem:What is the distance between A(-8,4) and B(4,-1)Given:[tex]\quad\quad\quad\quad\tt{A.) x\tiny{1}\small{=-8}, y\tiny{1}\small{=4}}[/tex]
[tex]\quad\quad\quad\quad\tt{B.) x\tiny{2}\small{=4}, y\tiny{2}\small{=-1}}[/tex]
Formula for distance (d):[tex]\quad\quad\quad\quad\tt{d = \sqrt{(x \tiny{2} \small{ - x \tiny{1} \small {)}^{2} + (y \tiny{2} \small{ - y \tiny{1} \small{)}^{2} } }}} [/tex]
Solution:[tex]\quad\quad\quad\quad\tt{d = \sqrt{(4 - \small{ (- 8}{))}^{2} + ( \small{- 1)}\small{ - {4)}}^{2} }}[/tex]
[tex]\quad\quad\quad\quad\tt{d = \sqrt{ ( {12)}^{2} + {( -5)}^{2} }}[/tex]
[tex]\quad\quad\quad\quad\tt{d = \sqrt{ {144} + {25}}}[/tex]
[tex]\quad\quad\quad\quad\tt{d = \sqrt{ 169}}[/tex]
[tex]\quad\quad\quad\quad\tt{d = 13}[/tex]
So the final answer is:[tex]\quad\quad\quad\quad\boxed{\boxed{\tt{\color{magenta}d = 13}}}[/tex]
___________________________________
#CarryOnLearning
✍︎ C.Rose❀
There are 28 chocolate-covered peanuts in 1 ounce (oz). Jay bought a 62 oz. jar of chocolate-covered peanuts.
Problem:
audio
How many chocolate-covered peanuts were there in the jar that Jay bought?
Enter your answer in the box.
Answer:
1,736 chocolate cover peanuts
Step-by-step explanation:
do 28×62 hope this helps
Answer:
1736 chocolate-covered peanuts
Step-by-step explanation:
[tex]\frac{1}{62} :\frac{28}{y}[/tex]
1 · y = 62 · 28
y = 1736
Find the area of each sector. Round your answers to the nearest tenth.
Answer:
Area of the given sector = 130.9 cm²
Step-by-step explanation:
Area of a sector is given by the formula,
Area of the sector = [tex]\frac{\theta}{2\pi }\times (\pi r^{2})[/tex]
Area of the sector of the circle given in the picture = [tex]\frac{\frac{5\pi }{6} }{2\pi }[\pi (10)^{2}][/tex]
= [tex]\frac{5}{12}(100\pi )[/tex]
= 130.8996
≈ 130.9 cm²
please please help
100 points!!!
Answer:
x=9
Step-by-step explanation:
Answer:
the answer is 10
Step-by-step explanation:
PLEASE HELP
Libby flips a quarter 2 times in a row.
What is the probability of the quarter landing on heads at least 1 time?
A. 1/4
B. 1/3
C. 3/4
D. 1/2
Evaluate f(x) =
f(x) = x for x = 4.
3
Answer:
x=3
Step-by-step explanation:
Find the circumference of this circle
using 3 for T.
C~[?]
15
C = 27Tr
Answer: 90
Step-by-step explanation:
c = 2πr
r = 15
d = 30
30π = 90
Answer:
C≈90
Step-by-step explanation:
remember circumference formula
[tex] \displaystyle C = 2\pi r[/tex]
given that,r=15 thus substitute:
[tex] \displaystyle C = 2\pi .15[/tex]
simplify mutilation:
[tex] \displaystyle C = 30\pi [/tex]
substitute the given value of π:
[tex] \displaystyle C = 30.3[/tex]
simplify multiplication:
[tex] \displaystyle C = 90[/tex]
and we are done!
Consider the following data. 15,−4,−10,8,14,−10,−2,−11
Step 1 of 3: Determine the mean of the given data
Step 2 of 3: Determine the median of the given data.
Step 3 of 3: Determine if the data set is unimodal, bimodal, multimodal, or has no mode. Identify the mode(s), if any exist.
Answer:
(a) The mean is 0
(b) The median is -30
(c) The mode is unimodal
Step-by-step explanation:
Given
[tex]Data: 15,-4,-10,8,14,-10,-2,-11[/tex]
Solving (a): The mean.
This is calculated using:
[tex]\bar x = \frac{\sum x}{n}[/tex]
So, we have:
[tex]\bar x =\frac{15-4-10+8+14-10-2-11}{8}[/tex]
[tex]\bar x =\frac{0}{8}[/tex]
[tex]\bar x =0[/tex]
Solving (b): The median
First, arrange the data
[tex]Sorted: -11,-10, -10, -4, -2,8,14,15[/tex]
There are 4 elements in the dataset. So, the median is the mean of the 4th and 5th item.
[tex]Median = \frac{-4-2}{2}[/tex]
[tex]Median = \frac{-6}{2}[/tex]
[tex]Median = -3[/tex]
Solving (c): The mode
The item that has occurs most is -10.
Hence, the mode is -10. The dataset is unimodal because it has only 1 mode (-10).
y =cos((2pi/3) x )+2
what is the midline equation? y=?
Answer:
[tex]y=2[/tex]
Step-by-step explanation:
In [tex]y=a\cos(bx-c)+d[/tex], [tex]d[/tex] represents the vertical shift. The midline of the function is given by [tex]y=d[/tex], because the parent function [tex]y=\cos x[/tex] has a midline at [tex]y=0[/tex]. Therefore, the midline of the function [tex]y=\cos (\frac{2\pi}{3}x)+2[/tex] is [tex]\boxed{y=2}[/tex]
Fatima wants to mail three parcels to three village school she finds that the postal charges are rupees 20 rupees 28 and 36 respectively if she wants to buy stamps only of one denomination what is the greatest denomination of stamp she must buy to mail the three parcels
Answer:
84
Step-by-step explanation:
god bless stay safe po
one lap around a field is 4/5 of a mile .Adrian ran these laps . how far did he run?
A man travelled a distance of 61 miles in 7 hours. He covered a part of the distance at a speed of 8 miles/ hr and the remaining at a speed of 10 miles/ hr. How long did he travel at 8 miles/ hr?
Answer:
4.5 hours
Step-by-step explanation:
8t + 10(7-t) = 61
8t +70-10t=61
-2t = 61-70
-2t= -9
t = -9/-2
t = 4.5
Juan borrowed $1500 from a credit union for 7 years and was charged simple interest at a rate of 2.97%. What is the amount of interest he paid at the end of the loan
Answer:
The amount of interest he paid at the end of the loan is $ 311.85.
Step-by-step explanation:
Given that Juan borrowed $ 1500 from a credit union for 7 years and was charged simple interest at a rate of 2.97%, to determine what is the amount of interest he paid at the end of the loan, the following calculation must be performed:
(1500 x 0.0297) x 7 = X
44.55 x 7 = X
311.85 = X
Therefore, the amount of interest he paid at the end of the loan is $ 311.85.
Find the polynomial of minimum degree, with real coefficients, zeros at x=4+4i and x=2, and y-intercept at 64
Answer:
[tex]\displaystyle -x^3+10x^2-48x+64[/tex]
Step-by-step explanation:
We want to find the minimum-degree polynomial with real coefficients and zeros at:
[tex]x= 4+4i\text{ and } x = 2[/tex]
As well as a y-intercept of 64.
By the Complex Root Theorem, if a + bi is a root, then a - bi is also a root.
So, a third root will be 4 - 4i.
The factored form of a polynomial is given by:
[tex]P(x)=a(x-p)(x-q)...[/tex]
Where a is the leading coefficient and p and q are the zeros. More factors can be added if necessary.
Substitute:
[tex]P(x)=a(x-(2))(x-(4+4i))(x-(4-4i))[/tex]
Since we want the minimum degree, we won't need to add any exponents.
Expand the second and third factors:
[tex]\displaystyle \begin{aligned} (x-(4+4i))(x-(4-4i))&=(x-4-4i)(x-4+4i) \\ &= x(x-4-4i)-4(x-4-4i)+4i(x-4-4i)\\ &=x^2-4x-4ix-4x+16+16i+4ix-16i-16i^2\\ &= x^2-8x+32\end{aligned}[/tex]
Hence:
[tex]P(x)=a(x-2)(x^2-8x+32)[/tex]
Lastly, we need to determine a. Since the y-intercept is y = 64, this means that when x = 0, y = 64. Thus:
[tex]64=a(0-2)(0^2-8(0)+32)[/tex]
Solve for a:
[tex]-64a=64\Rightarrow a=-1[/tex]
Our factored polynomial is:
[tex]P(x)=-(x-2)(x^2-8x+32)[/tex]
Finally, expand:
[tex]\displaystyle \begin{aligned} P(x) &=-(x^2(x-2)-8x(x-2)+32(x-2)) \\&=-(x^3-2x^2-8x^2+16x+32x-64)\\&=-(x^3-10x^2+48x-64)\\&= -x^3+10x^2-48x+64\end{aligned}[/tex]
angle QPS is a straight angle
angle QPR = 7x-4 degrees
angle RPS = 9x-40 degrees
Find: angle QPR
Answer:
94
Step-by-step explanation:
We know that a straight line adds up to 180 degrees, and angle QPS, summed up by angles QPR and RPS, equals that.
Therefore,
angle QPS = QPR + RPS
180 = QPR + RPS
180 = 7x-4+9x-40
180 = 16x-44
224= 16x
x = 222/16 = 14
QPR = 7x-4 = 94
2. Two lines intersect at E. Find the value of x
Helpppp I will give Brainly
Answer:
38
Step-by-step explanation:
If 25% = 1 over 4. what fraction is 12.5%?
Whose answer will be the best will be marked as the brainlest
Answer:- Hey Buddy! Hope this helps:-
12.5%= 125/10 and when simplified becomes 25/2
pls mark brainliest
A study of college football games shows that the number of holding penalties assessed has a mean of penalties per game and a standard deviation of penalties per game. What is the probability that, for a sample of college games to be played next week, the mean number of holding penalties will be penalties per game or less
Answer:
The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.
Step-by-step explanation:
To solve this question, we need to understand the normal probability distribution and the central limit theorem.
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
Central Limit Theorem
The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
We have that:
The mean number of penalties per game is [tex]\mu[/tex] and the standard deviation is [tex]\sigma[/tex].
Sample of n games:
This means that [tex]s = \frac{\sigma}{\sqrt{n}}[/tex]
What is the probability that, for a sample of college games to be played next week, the mean number of holding penalties will be X penalties per game or less?
The probability that the mean number of holding penalties per game is of X or less is the p-value of [tex]Z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex], in which [tex]\mu[/tex] is the mean number of penalties per game, [tex]\sigma[/tex] is the standard deviation and n is the number of games that will be sampled.
Wally bought a television for $987.00. The finance charge was $205 and she paid for it over 24 months. (Finance Ch arg e: #Months)(12) Amount Financed Use the formula Approximate APR to calculate her approximate APR. Round the answer to the nearest tenth.
Answer:
10.4%Step-by-step explanation:
Principal is $987.Finance charge is $205Time is 2 yearsAPR = ((Finance charge/Principal)/Time)*100% (simplified for this case)APR = ((205/987)/2)*100% = 10.4%
What is the value of x?
Enter your answer in the box.
units
9514 1404 393
Answer:
x = 25
Step-by-step explanation:
The parallel lines divide the triangle sides proportionally.
x/40 = 15/24
x = 40(15/24) . . . . multiply by 40
x = 25
Issac wants the equation below to have no solution
Answer:
Where is the equation?
Step-by-step explanation:
Answer:
I don't understand
Step-by-step explanation:
Are you Issac?
What is the question?
find the value of x, do not round until the final answer.
thank you!
Answer:
[tex]x\approx 5.48[/tex]
Step-by-step explanation:
Draw a line from the center of the circle O to the end of either side of the line marked as 4. This line represents two things:
A radius of the circleThe hypotenuse of a right triangle with legs 5.1 and 2In this case, both are important. Since [tex]x[/tex] is also a radius of the circle, the line must be equal to [tex]x[/tex], since all radii of a circle are equal. To find the length of this line, use the Pythagorean Theorem:
[tex]a^2+b^2=c^2[/tex], where [tex]c[/tex] is the hypotenuse of the triangle and [tex]a[/tex] and [tex]b[/tex] are the two legs of the triangle.
Since we're solving for the hypotenuse and the two legs are 5.1 and 2, we have:
[tex]5.1^2+2^2=c^2,\\26.01+4=c^2,\\c^2=30.01,\\c=5.47813836992\approx \boxed{5.48}[/tex] (round as necessary).
In the radius of a circle with an area of 10 inches squared is reduced by half what is the area of the new circle
Answer:
Hence when the radius is halved the area is divided by 4
2.5 inches^2
Step-by-step explanation:
Given data
Area= 10inches^2
We know that the expression for the area of a circle is given as
Area= πr^2
10= 3.142*r^2
10/3.142= r^2
r^2= 3.18
Square both sides
r= √3.18
r= 1.78 inches
Now let us half the radius and find the area of the new circle
r/2= 1.78/2
r= 0.89
Area of the new circle is
Area= 3.142*0.89^2
Area= 3.142*0.7921
Area= 2.5 inches^2