please answer these diagrammatic questions ASAP and please no spam answers​

Answer:

C. Line A

Explanation:

V = A*R

12V = 4A*R

R = 12V/4A

R = 3ohms

Answer:

Mercury is the answer..

Answer:

I believe mercury

Explanation:

Answer:

La ecuación para la velodiad del sonido en aire esta dada por:

[tex]v = \sqrt{ \frac{\gamma*R*T}{M} }[/tex]

Resolviendo esto para T, obtenemos:

[tex]T = v^2*(\frac{M}{\gamma*R} )[/tex]

donde:

T = temperatura del aire en grados Kelvin

γ = constante adiabatica = 1.4

R = constante del gas ideal =

M = masa molar del aire = 29*10^(-3) kg/mol

Si sabemos que el primer día la velocidad es 346 m/s, tenemos:

v = 346 m/s

Ahora podemos reemplazar todos esos valores en la ecuación para T, y asi obtener:

[tex]T = (346m/s)^2*(\frac{29*10^{-3}kg/mol}{1.4* 8.31 J/mol*K} ) = 298.42 K[/tex]

Para el segundo día la velocidad es 340 m/s, entonces ese día la temperatura va a ser:

[tex]T = (340m/s)^2*(\frac{29*10^{-3}kg/mol}{1.4* 8.31 J/mol*K} ) = 288.16 K[/tex]

Answer:

D is the answer wave behavior

Interference, refraction, diffraction, and dispersion are all aspects of wave behavior. (D).  That is, particles don't do these things.

Answer:

(a) The time it takes the projectile to hit the ground is approximately 10.42 seconds

(b) The range of the projectile from the base of the cliff is approximately 540.92 meters

(c) The horizontal component of the velocity is approximately 51.91 m/s

The vertical component of the velocity is approximately 39.12 m/s

(d) The magnitude of the velocity of the projectile is 65.0 m/s

(e) The angle made by the velocity vector of the projectile with the horizontal is 37°

(f) The maximum height above the cliff top reached by the projectile is approximately 77.99 meters

Explanation:

The height of the cliff above ground level, y₀ = 125 m

The initial speed of the projectile, u = 65.0 m/s

The angle of elevation of the projectile, θ = 37°

(a) The time for the projectile to hit the ground, t, is given as follows;

y = y₀ + u·sin(θ)·t -(1/2)·g·t²

g = 9.81 m/s²

At ground level, y = 0, we get;

0 = 125 + 65·sin(37)·t - 4.905·t²

t = (-65·sin(37) ± √((65·sin(37))² - 4×(-4.905)×125))/(2 × (-4.905))

∴ t ≈ -2.45 or t ≈ 10.42

The time it takes the projectile to hit the ground, t ≈ 10.42 seconds

(b) The range of the projectile X = u·cos(θ) × t

∴ X = 65.0 × cos(37°) × 10.42 ≈ 540.92

The range of the projectile from the base of the cliff, X ≈ 540.92 meters

(c) The horizontal component of the velocity, uₓ = u×cos(θ)

∴ uₓ = 65.0 ×cos(37°) ≈ 51.91

The horizontal component of the velocity, uₓ ≈ 51.91 m/s

The vertical component of the velocity, [tex]u_y[/tex] = u×sin(θ)

∴ [tex]u_y[/tex] = 65.0 ×sin(37°) ≈ 39.12

The vertical component of the velocity, [tex]u_y[/tex] ≈ 39.12 m/s

(d) The magnitude of the velocity, [tex]\left | u \right |[/tex], is the given speed  = 65.0 m/s

[tex]\left | u \right |[/tex] = √([tex]u_y[/tex]² + uₓ²)

∴ [tex]\left | u \right |[/tex] = √(39.12² + 51.91²) = 65

[tex]\left | u \right |[/tex] = 65.0 m/s

(e) The angle made by the velocity vector with the horizontal = The angle of elevation with which the projectile is launched = 37°

(f) The maximum height above the cliff top reached by the projectile, [tex]y_{max \ of \ cliff}[/tex], is given as follows;

[tex]y_{max \ of \ cliff}= \dfrac{ \left(u \times sin(\theta)\right)^2}{2 \cdot g}[/tex]

∴ [tex]y_{max \ of \ cliff}[/tex] = (65.0 × sin(37°))²/(2 × 9.81) ≈ 77.99

[tex]y_{max \ of \ cliff}[/tex] ≈ 77.99 meters.

Answer:

ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)

Explanation:

The potential difference while moving from point A to Point B is given as follows:

[tex]\Delta V = V_B-V_A[/tex]

where,

ΔV = potential difference from A to B = ?

[tex]V_A[/tex] = Potential at point A = [tex]\frac{kq}{r_A}[/tex]

[tex]V_B[/tex] = Potential at point B = [tex]\frac{kq}{r_B}[/tex]

Therefore,

[tex]\Delta V = \frac{kq}{r_B}-\frac{kq}{r_A}\\\\\Delta V = kq(\frac{1}{r_B}-\frac{1}{r_A})[/tex]

where,

k = Colomb's Constant = 9 x 10⁹ N.m²/C²

q = magnitude of charge = 4.88 x 10⁻⁸ C

[tex]r_A[/tex] = distance of point A from charge = 1.36 m

[tex]r_B[/tex] = distance of point B from charge = 0.538 m

Therefore,

[tex]\Delta V = (9\ x\ 10^9\ N.m^2/C^2)(4.88\ x\ 10^{-8}\ C)(\frac{1}{0.538\ m}-\frac{1}{1.36\ m})\\\\\Delta V = (439.2 N.m^2/C)(2.59\ /m)[/tex]

ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)

The answer is 492.87.

Correct on Acellus

Answer:

- Decreasing the resistance

- Using a shorter length

- Using a smaller area wire

Explanation:

Formula for conductance in wires is;

G = 1/R

Where;

G is conductance

R is resistance

This means that increasing the resistance leads to a larger denominator and thus a smaller conductance but to decrease the denominator means larger conductance.

Thus, to increase the conductance, we have to decrease the resistance.

Resistance here has a formula of;

R = ρL/A

Where;

ρ is resistivity

L is length of wire

A is area

Thus, to decrease the resistance, we will have to use a shorter length and smaller area of wire.

Answer:

the positive and negative terminals of a battery are connected with a low resistance conductor.

Answer:

ΔR = 9 s

Explanation:

To calculate the propagation of the uncertainty or absolute error, the variation with each parameter must be calculated and the but of the cases must be found, which is done by taking the absolute value

The given expression is      R = 2A / B

the uncertainty is                 ΔR = | [tex]\frac{dR}{dA}[/tex] | ΔA + | [tex]\frac{ dR}{dB}[/tex] | ΔB

we look for the derivatives

     [tex]\frac{dR}{dA}[/tex] = 9 / B

     [tex]\frac{dR}{dB}[/tex] = 9A ( [tex]- \frac{1}{B^2 }[/tex] )

we substitute

     ΔR = [tex]\frac{9}{B}[/tex]  ΔA + [tex]\frac{9A}{B^2}[/tex]  ΔB

the values ​​are

     ΔA = 2 s

     ΔB = 3 s

     ΔR = [tex]\frac{9}{11}[/tex]   2 + [tex]\frac{9 \ 32}{11^2 }[/tex]  3

     ΔR = 1.636 + 7.14

     ΔR = 8,776 s

the absolute error must be given with a significant figure

     ΔR = 9 s

Answer:

Force is useful to us because it changes or tries to change the positionof a body, it helps to change the direction of a moving object , it helps to change the speedof a moving body etc.

I hope this will help you

Answer:

Measurement is the act or the process of finding the size, quantity or degree of something.

Explanation:

We can measure the length, weight, and capacity (volume) of any given object.

Explanation:

given: m= 105kg,f=170N,a=?

F = m×a

a = f/m

a=170/105

therefore, a=1.62m/s^2

Answer:

1.261 billion

Explanation:The distance between the earth and the moon in miles is 250,000,so in feet,The distance is 1.261 billion

Answer:

the green ball has 4J more energy

Explanation:

The kinetic energy is given by the formula

K = 0.5 m v^2

the kinetic energy of the red ball:

K(red) = 0.5*10*3^2= 45J

of the green ball:

K(green)=0.5*8*3.5^2 = 49J

therefore the green ball has more energy by 4 Joules

Answer:

Charles Robert Drawin was an English naturalist,Geologist and Biologist, Best known for his contributions to the science of evolution. His proposition that all species of life have descended from common ancestors is now widely accepted and considered a fundamental concept in science!

Answer:

The corneal tissue at the front of the eye has high thermal conductivity so it doesn't stray too far from body temperature even when the ambient temperature is extreme. For example, if the environment is at -11°C, the surface temperature of a human cornea only falls to 28.6°C.

Answer:

Explanation:

The equation for this is

F - f = ma

The thing that gets strange here is that, because the student is pulling his sister on the sled with the rope at an angle, some of his efforts are being wasted. The sled is only going to move forward (horizontally), so the vertical component of that force is useless. He's not actually pulling horizontally with that much force; we have to figure out how much using the following equation:

[tex]F=430cos35[/tex] to get that

F = 352 N

Everything else falls into place quite easily into the equation now:

352 - 180 = 41a and

172 = 41a so

a = 4.2 m/s/s

Answer:

b- absolute zero

*( And it's called zero kelvin)

Explanation:

The answer is Electrons move between objects.

Answer:

[tex]v=-29cm[/tex]

Explanation:

From the question we are told that:

Radius [tex]R=2f[/tex]

Distance [tex]v=145mm=>14.5cm[/tex]

Generally the equation for is mathematically given by

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]

Therefore

[tex]\frac{1}{f}=\frac{1}{v}[/tex]

[tex]\frac{1}{f}=\frac{1}{14.5}[/tex]

[tex]f=14.5cm[/tex]

Therefore

[tex]R=2f\\\\R=2*14.5[/tex]

[tex]R=29cm[/tex]

Generally the equation for Focal Length of the Right surface is mathematically given by

[tex]f_r=\frac{R_r}{2}[/tex]

[tex]f_r=\frac{2R}{2}[/tex]

[tex]f_r=29cm[/tex]

Therefore

[tex]\frac{1}{29}-\frac{1}{14.5}=\frac{1}{v}[/tex]

[tex]\frac{1}{v}=-\frac{1}{29}cm[/tex]

[tex]v=-29cm[/tex]

Answer: The use of S I Unit brings uniformity in measurements.

Explanation:

The S I unit is the international system of units which are used to express the magnitudes or quantities of important natural phenomena. It is used universally as a standard for measurements thereby creating an avenue for uniformity in measurements. The base units that makes up the SI unit are:

--> Length: this is measured in meters (m)

--> Time: this is measured in seconds (s)

--> Mass: this is measured in kilogram (kg)

--> Temperature: this is measured in Kelvin (k)

--> Electric current: this is measured in ampere (A).

--> Amount of substance: this is measured in mole

--> Luminous intensity: this is measured in candela (cd)

These units are used as the standard to make our judgement of measurement more reliable and accurate. And since there is only one basic unit for each quantity (example length which is measured in meters) there is no need for further conversions.

Answer:

speed = 240 kilometers per hour

Explanation:

so we know speed = distance over time

speed= 120s

distance= 8km

8km/120s=0.0666km/sec

0.0666km covered in 1 sec

3,600 seconds- 1km/hr

0.0666/1 times 3600= 239.76

239.76= 240km/hr

Answer:

Hydrogen ion concentration, [H+] :

[tex]{ \bf{[H {}^{ + } ] = 2.3 \times {10}^{ - 5} \: mol \: l {}^{ - 1} }}[/tex]

Substitute to the negative logarithmic model:

[tex] = { \tt{ - log(2.3 \times {10}^{ - 5} ) }} \\ pH = 4.64[/tex]

Answer:

Mass can never be negative. Everything has mass. Just like how they ask you to find area under the graph in maths. If the area is in the 3rd and 4th quadrant, when calculated, you would get negative answer.However, area can not be negative because it is a place/ location. It's exactly the same as mass.

Answer:

A1

Explanation: