Answer:
i. The pressure of due to the water, P, is given according to the following equation;
P = ρ·g·h
Where;
ρ = The density of the water (a constant) = 997 kg/m³
g = The acceleration due to gravity = 9.81 m/s²
h = The height of the water (minimum h = h₁, maximum h = h₂)
The pressure is directly proportional to the water height, and we have;
The pressure, P, will be maximum when the water height, h, is maximum or h = h₂, which is the level DC
ii. The thrust = The force acting on the body = Pressure × Area
The maximum areas exposed to the water are on side AB and DC
However, the pressure at level DC, which is the location of the maximum pressure, is larger than the pressure at level AB, therefore, the maximum thrust will be at the level DC
Explanation:
Raquel establece que la rapidez del sonido en el aire en un día es de 346 m/s . Días después hace la misma medición obteniendo una rapidez de 340 m/ s . ¿Cuál será la temperatura del aire en cada día?
Answer:
La ecuación para la velodiad del sonido en aire esta dada por:
[tex]v = \sqrt{ \frac{\gamma*R*T}{M} }[/tex]
Resolviendo esto para T, obtenemos:
[tex]T = v^2*(\frac{M}{\gamma*R} )[/tex]
donde:
T = temperatura del aire en grados Kelvin
γ = constante adiabatica = 1.4
R = constante del gas ideal =
M = masa molar del aire = 29*10^(-3) kg/mol
Si sabemos que el primer día la velocidad es 346 m/s, tenemos:
v = 346 m/s
Ahora podemos reemplazar todos esos valores en la ecuación para T, y asi obtener:
[tex]T = (346m/s)^2*(\frac{29*10^{-3}kg/mol}{1.4* 8.31 J/mol*K} ) = 298.42 K[/tex]
Para el segundo día la velocidad es 340 m/s, entonces ese día la temperatura va a ser:
[tex]T = (340m/s)^2*(\frac{29*10^{-3}kg/mol}{1.4* 8.31 J/mol*K} ) = 288.16 K[/tex]
Which of the following describes a sound wave?
A. Longitudinal wave that does not require a medium
c
B. Longitudinal wave that requires a medium
C. Transverse wave that does not require a medium
D. Transverse wave that requires a medium
The moon is 250,000 miles away. How many feet is it from Earth? (dimensional analysis)
Answer:
1.261 billion
Explanation:The distance between the earth and the moon in miles is 250,000,so in feet,The distance is 1.261 billion
List out the fundamental and derived units
Your new motorcycle weighs 2450 N.
What is
its mass in kilograms?
i understand the answer is 250kg because mass times gravity thing but why isn’t the answer negative cause gravity pulls down so wouldn’t be Negative answer not a positive answer
i was taught FW is always negative why isn’t it negative here
Answer:
Mass can never be negative. Everything has mass. Just like how they ask you to find area under the graph in maths. If the area is in the 3rd and 4th quadrant, when calculated, you would get negative answer.However, area can not be negative because it is a place/ location. It's exactly the same as mass.
A car moving round a circular rest of a car take 120/s to do a lap of 8/km what is the speed in kmlh
Answer:
speed = 240 kilometers per hour
Explanation:
so we know speed = distance over time
speed= 120s
distance= 8km
8km/120s=0.0666km/sec
0.0666km covered in 1 sec
3,600 seconds- 1km/hr
0.0666/1 times 3600= 239.76
239.76= 240km/hr
Performance Task 2: "TAKE HOME TASK
1. It took scientist a long time to reconcile the dual nature of light, which led to the idea of the duality of matter. To further see an
evidence of this concept try to observe the smoke coming from a barbeque drill. From a distance, you will see a
wave flow of smoke going up.
Guide Questions:
a. Look closely into it, what do you see?
ha Does your observation tell something about the dual nature of matter? Why? Why not?
2. Observe the colors on the soap bubbles on the surface of water.
Guide Questions:
a. What do you see?
b. What property of light is exhibited?
Pasagot po huhu
What is the lowest possible temperature?
a 273 K
b absolute zero
со °C
d 100 °C
Answer:
b- absolute zero
*( And it's called zero kelvin)
57. A red ball (m= 10 kg) is moving at 3 m/s. A green ball (m = 8 kg) is moving at 3.5 m/s. Which ball has more
energy and by how much (2)
Answer:
the green ball has 4J more energy
Explanation:
The kinetic energy is given by the formula
K = 0.5 m v^2
the kinetic energy of the red ball:
K(red) = 0.5*10*3^2= 45J
of the green ball:
K(green)=0.5*8*3.5^2 = 49J
therefore the green ball has more energy by 4 Joules
Hey please could somebody write a speech that i could read out in front of my class about Charles Darwin and the Theory of Evolution. Thank you so much :D
Answer:
Charles Robert Drawin was an English naturalist,Geologist and Biologist, Best known for his contributions to the science of evolution. His proposition that all species of life have descended from common ancestors is now widely accepted and considered a fundamental concept in science!
weight of the body will be more in air water Milk or Mercury
Answer:
Mercury is the answer..
Answer:
I believe mercury
Explanation:
How is the force useful to us?
Answer:
Force is useful to us because it changes or tries to change the positionof a body, it helps to change the direction of a moving object , it helps to change the speedof a moving body etc.
I hope this will help you
Which statement should he place in the region marked X?
Explanation:
The answer is Electrons move between objects.
what is measurment ?
Answer:
Measurement is the act or the process of finding the size, quantity or degree of something.
Explanation:
We can measure the length, weight, and capacity (volume) of any given object.
2. A student is pulling a 11.0 kg sled along flat ground. The students 30.0 kg sister then sits in the sled. The student then applies a 430 N force at an angle of 35° N of E. If the force of friction is 180 N, what is the acceleration of the sister sitting in the sled. (Ensure you draw a free body diagram.)
Answer:
Explanation:
The equation for this is
F - f = ma
The thing that gets strange here is that, because the student is pulling his sister on the sled with the rope at an angle, some of his efforts are being wasted. The sled is only going to move forward (horizontally), so the vertical component of that force is useless. He's not actually pulling horizontally with that much force; we have to figure out how much using the following equation:
[tex]F=430cos35[/tex] to get that
F = 352 N
Everything else falls into place quite easily into the equation now:
352 - 180 = 41a and
172 = 41a so
a = 4.2 m/s/s
tìm chỉ số của A1 và A2
Answer:
A1
Explanation:
The acidity model given by pH = -log10[H+] where acidity (pH) is a measure of the hydrogen ion concentration [H+] (measured in moles of hydrogen per liter) of a solution. Using this model, determine the pH of a solution with a hydrogen ion concentration of 2.3 X 10^-5 (round your answer to the nearest hundredth)
Answer:
Hydrogen ion concentration, [H+] :
[tex]{ \bf{[H {}^{ + } ] = 2.3 \times {10}^{ - 5} \: mol \: l {}^{ - 1} }}[/tex]
Substitute to the negative logarithmic model:
[tex] = { \tt{ - log(2.3 \times {10}^{ - 5} ) }} \\ pH = 4.64[/tex]
4. Interference is an example of which aspect of electromagnetic radiation?
A) Particle behavior
B) photon behavior
C) the photoelectric effect
D) wave behavior
Answer:
D is the answer wave behavior
Interference, refraction, diffraction, and dispersion are all aspects of wave behavior. (D). That is, particles don't do these things.
what changes must be done to the wire to increase its conductance.
Answer:
- Decreasing the resistance
- Using a shorter length
- Using a smaller area wire
Explanation:
Formula for conductance in wires is;
G = 1/R
Where;
G is conductance
R is resistance
This means that increasing the resistance leads to a larger denominator and thus a smaller conductance but to decrease the denominator means larger conductance.
Thus, to increase the conductance, we have to decrease the resistance.
Resistance here has a formula of;
R = ρL/A
Where;
ρ is resistivity
L is length of wire
A is area
Thus, to decrease the resistance, we will have to use a shorter length and smaller area of wire.
A lens has a radius of curvature of magnitude R R on its left surface and a radius of curvature of magnitude 2R 2 R on its right surface. Parallel rays entering the lens from the left are focused to a point 145 mm m m to the right of the right surface.
Answer:
[tex]v=-29cm[/tex]
Explanation:
From the question we are told that:
Radius [tex]R=2f[/tex]
Distance [tex]v=145mm=>14.5cm[/tex]
Generally the equation for is mathematically given by
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]
Therefore
[tex]\frac{1}{f}=\frac{1}{v}[/tex]
[tex]\frac{1}{f}=\frac{1}{14.5}[/tex]
[tex]f=14.5cm[/tex]
Therefore
[tex]R=2f\\\\R=2*14.5[/tex]
[tex]R=29cm[/tex]
Generally the equation for Focal Length of the Right surface is mathematically given by
[tex]f_r=\frac{R_r}{2}[/tex]
[tex]f_r=\frac{2R}{2}[/tex]
[tex]f_r=29cm[/tex]
Therefore
[tex]\frac{1}{29}-\frac{1}{14.5}=\frac{1}{v}[/tex]
[tex]\frac{1}{v}=-\frac{1}{29}cm[/tex]
[tex]v=-29cm[/tex]
In the diagram, q1 = +4.88*10^-8 C.
What is the potential difference when
you go from point A to point B?
Include the correct sign, + or - .
B
0.538 m
1.36 m
91 |
(Hint: Does V go up or down when you go
from B to A?) (Unit = V)
Answer:
ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)
Explanation:
The potential difference while moving from point A to Point B is given as follows:
[tex]\Delta V = V_B-V_A[/tex]
where,
ΔV = potential difference from A to B = ?
[tex]V_A[/tex] = Potential at point A = [tex]\frac{kq}{r_A}[/tex]
[tex]V_B[/tex] = Potential at point B = [tex]\frac{kq}{r_B}[/tex]
Therefore,
[tex]\Delta V = \frac{kq}{r_B}-\frac{kq}{r_A}\\\\\Delta V = kq(\frac{1}{r_B}-\frac{1}{r_A})[/tex]
where,
k = Colomb's Constant = 9 x 10⁹ N.m²/C²
q = magnitude of charge = 4.88 x 10⁻⁸ C
[tex]r_A[/tex] = distance of point A from charge = 1.36 m
[tex]r_B[/tex] = distance of point B from charge = 0.538 m
Therefore,
[tex]\Delta V = (9\ x\ 10^9\ N.m^2/C^2)(4.88\ x\ 10^{-8}\ C)(\frac{1}{0.538\ m}-\frac{1}{1.36\ m})\\\\\Delta V = (439.2 N.m^2/C)(2.59\ /m)[/tex]
ΔV = 1139.3 V = 1.139 KV (+ve sign shows V goes up)
The answer is 492.87.
Correct on Acellus
What efforts are made to bring uniformity in measurement
Answer: The use of S I Unit brings uniformity in measurements.
Explanation:
The S I unit is the international system of units which are used to express the magnitudes or quantities of important natural phenomena. It is used universally as a standard for measurements thereby creating an avenue for uniformity in measurements. The base units that makes up the SI unit are:
--> Length: this is measured in meters (m)
--> Time: this is measured in seconds (s)
--> Mass: this is measured in kilogram (kg)
--> Temperature: this is measured in Kelvin (k)
--> Electric current: this is measured in ampere (A).
--> Amount of substance: this is measured in mole
--> Luminous intensity: this is measured in candela (cd)
These units are used as the standard to make our judgement of measurement more reliable and accurate. And since there is only one basic unit for each quantity (example length which is measured in meters) there is no need for further conversions.
Calculate the maximum absolute uncertainty for R if:
R = 9A / B
A = 32 +/- 2 seconds
B = 11 +/- 3 seconds
1 second
0.33 seconds
9 seconds
2 seconds
6 seconds
Answer:
ΔR = 9 s
Explanation:
To calculate the propagation of the uncertainty or absolute error, the variation with each parameter must be calculated and the but of the cases must be found, which is done by taking the absolute value
The given expression is R = 2A / B
the uncertainty is ΔR = | [tex]\frac{dR}{dA}[/tex] | ΔA + | [tex]\frac{ dR}{dB}[/tex] | ΔB
we look for the derivatives
[tex]\frac{dR}{dA}[/tex] = 9 / B
[tex]\frac{dR}{dB}[/tex] = 9A ( [tex]- \frac{1}{B^2 }[/tex] )
we substitute
ΔR = [tex]\frac{9}{B}[/tex] ΔA + [tex]\frac{9A}{B^2}[/tex] ΔB
the values are
ΔA = 2 s
ΔB = 3 s
ΔR = [tex]\frac{9}{11}[/tex] 2 + [tex]\frac{9 \ 32}{11^2 }[/tex] 3
ΔR = 1.636 + 7.14
ΔR = 8,776 s
the absolute error must be given with a significant figure
ΔR = 9 s
please give me answer
A 105kg astronaut lands on the moon, with a weight of 170N. What is the acceleration due to gravity
Explanation:
given: m= 105kg,f=170N,a=?
F = m×a
a = f/m
a=170/105
therefore, a=1.62m/s^2
write any two features of capital
A projectile is shot from the edge of a cliff 125 m above ground level with an initial speed of 65.0 m/s at an angle of 37 degrees with the horizontal. (a) determine the time taken by the projectile to hit the point P at ground level. (b) determine the range X of the projectile as measured from the base of the cliff at the instant just before the projectile hits point P. Find (x) the horizontal and vertical components of its velocity and (d) the magnitude of the velocity and (e) the angle made by the velocity vector with the horizontal (f) Find the maximum height above the cliff top reached by the projectile
Answer:
(a) The time it takes the projectile to hit the ground is approximately 10.42 seconds
(b) The range of the projectile from the base of the cliff is approximately 540.92 meters
(c) The horizontal component of the velocity is approximately 51.91 m/s
The vertical component of the velocity is approximately 39.12 m/s
(d) The magnitude of the velocity of the projectile is 65.0 m/s
(e) The angle made by the velocity vector of the projectile with the horizontal is 37°
(f) The maximum height above the cliff top reached by the projectile is approximately 77.99 meters
Explanation:
The height of the cliff above ground level, y₀ = 125 m
The initial speed of the projectile, u = 65.0 m/s
The angle of elevation of the projectile, θ = 37°
(a) The time for the projectile to hit the ground, t, is given as follows;
y = y₀ + u·sin(θ)·t -(1/2)·g·t²
g = 9.81 m/s²
At ground level, y = 0, we get;
0 = 125 + 65·sin(37)·t - 4.905·t²
t = (-65·sin(37) ± √((65·sin(37))² - 4×(-4.905)×125))/(2 × (-4.905))
∴ t ≈ -2.45 or t ≈ 10.42
The time it takes the projectile to hit the ground, t ≈ 10.42 seconds
(b) The range of the projectile X = u·cos(θ) × t
∴ X = 65.0 × cos(37°) × 10.42 ≈ 540.92
The range of the projectile from the base of the cliff, X ≈ 540.92 meters
(c) The horizontal component of the velocity, uₓ = u×cos(θ)
∴ uₓ = 65.0 ×cos(37°) ≈ 51.91
The horizontal component of the velocity, uₓ ≈ 51.91 m/s
The vertical component of the velocity, [tex]u_y[/tex] = u×sin(θ)
∴ [tex]u_y[/tex] = 65.0 ×sin(37°) ≈ 39.12
The vertical component of the velocity, [tex]u_y[/tex] ≈ 39.12 m/s
(d) The magnitude of the velocity, [tex]\left | u \right |[/tex], is the given speed = 65.0 m/s
[tex]\left | u \right |[/tex] = √([tex]u_y[/tex]² + uₓ²)
∴ [tex]\left | u \right |[/tex] = √(39.12² + 51.91²) = 65
[tex]\left | u \right |[/tex] = 65.0 m/s
(e) The angle made by the velocity vector with the horizontal = The angle of elevation with which the projectile is launched = 37°
(f) The maximum height above the cliff top reached by the projectile, [tex]y_{max \ of \ cliff}[/tex], is given as follows;
[tex]y_{max \ of \ cliff}= \dfrac{ \left(u \times sin(\theta)\right)^2}{2 \cdot g}[/tex]
∴ [tex]y_{max \ of \ cliff}[/tex] = (65.0 × sin(37°))²/(2 × 9.81) ≈ 77.99
[tex]y_{max \ of \ cliff}[/tex] ≈ 77.99 meters.
why our eyes donot feel cold ?
Answer:
The corneal tissue at the front of the eye has high thermal conductivity so it doesn't stray too far from body temperature even when the ambient temperature is extreme. For example, if the environment is at -11°C, the surface temperature of a human cornea only falls to 28.6°C.
can u guys help me with this question.
State one example of the cause of a short circuit. Explain your answer
Answer:
the positive and negative terminals of a battery are connected with a low resistance conductor.
On the graph of voltage versus current, which line represents a 3.0 resistor
Answer:
C. Line A
Explanation:
V = A*R
12V = 4A*R
R = 12V/4A
R = 3ohms