Play the four digit 3,5,7,and 9 into the boxes pure in the position that would give the greatest results in the true numbers are multiplied

- 73X95
- 79X53
-97X35
-93X75

Answer:

8.9 lbs

9.5 lbs

10.4 lbs

are correct three options for this

Step-by-step explanation:

but u should give options too

It took me a long time to find the answer from book..

so If you had given options, I would not have spent so much time to find the ans..

From the next time you have to take care of it okay

seeya !! (◕ᴗ◕✿)

Answer:

tringlae mixed witha football goal take the fool goal out and go from there

Step-by-step explanation:

Answer:

5

Step-by-step explanation: i used a calculator and it said 5.099 but just round it up to 5

Answer:

1

Step-by-step explanation:

even if it is going back-wards, it is still one, think of it as absolute value

also again, if brainly tries to delete this answer, this community really is going down the dump

Answer:

x=4

Step-by-step explanation:

So basically first we see the angles of this triangle, and we learn that all the angles are congruent. Only a equilateral triangle can have all angles congruent, so this must be equilateral triangle. In equilateral triangles all the sides are congruent. So we just put 5x-12=3x-4. We then solve for x and get 4.

Answer:

Step-by-step explanation:

answer is   [tex](11010)_{2}[/tex]

Answer:

[tex]7[/tex]

Solution:

This is a linear function. This means means that r is our rate of change.

To find r recal following formula

[tex]r=\frac{\Delta y}{\Delta x} = \frac{y_2-y_1}{x_2-x_1}[/tex]

Since this is a linear function we can choose any two points. I will choose the first two for simplicity

[tex]\Displaystyle \therefore r = \frac{42-14}{6-2}=\frac{28}{4}=7[/tex]

Answer:

20 feet

Step-by-step explanation:

The distance between base of the ladder from the base of the building is given by option B) 20 feet.

Use the Pythagorean theorem to solve this problem.

The Pythagorean theorem states that in a right-angled triangle,

The square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.

Length of the ladder = 28 foot

Here, the ladder forms the hypotenuse, and the height of the window (20 feet)

And the distance from the base of the ladder to the base of the building (let's call it x feet) are the other two sides.

So, we have:

Ladder² = Height² + Distance²

28² = 20² + x²

Now, let's solve for x:

x² = 28²- 20²

x² = 784 - 400

x² = 384

Now, take the square root of both sides to find x:

x = √384

x ≈ 19.6 feet

Rounding to the nearest whole foot, the distance from the base of the ladder to the base of the building is 20 feet.

Therefore, the distance between base of the ladder and building is equal to option B) 20 feet.

learn more about distance here

brainly.com/question/15256256

#SPJ4

Answer:

70°

Step-by-step explanation:

m ∠L = 180-(55+55)

= 180-110

=70°

Answer:

[tex]34^{\circ}[/tex]

Step-by-step explanation:

The incenter of a triangle can be defined as the intersection of three angle bisectors that bisect all angles of the triangle.

By definition, an angle bisector divides an angle into two equal smaller angles.

Therefore:

[tex]\angle KJN=\angle LJN,\\\angle KLM=\angle JLM, \\\angle JKP=\angke LKP[/tex]

What we're given:

The sum of the interior angles of a triangle always add up to be 180 degrees. Since these six angles make up the total sum of the interior angles, we have the following equation:

[tex]\angle KJN+\angle LJN+\angle KLM +\angle KLM +\angle JKP+ \angle LKP=180^{\circ}[/tex]

Substituting given values:

[tex]30+30+26+26+\angle JKP+\angle LKP=180[/tex]

Since [tex]\angle JKP=\angle LKP[/tex],

[tex]30+30+26+26+2(\angle JKP)=180,\\112+2(\angle JKP)=180,\\2(\angle JKP)=180-112,\\2(\angle JKP)=68,\\\angle JKP=\frac{68}{2}=\boxed{34^{\circ}}[/tex]

Answer:

44

Step-by-step explanation:

substitute the 7 into the equation for x

f(x) = [tex]x^{2}[/tex] - 5

f(7)  = [tex]7^{2}[/tex] - 5

f(7) = 49 - 5

f(7) = 44

Answer:

f(7) = 44

Step-by-step explanation:

To evaluate the function f(x)=x^2-5 at x = 7, replace each instance of 'x' in this function by 7:

f(7) = 7^2 - 5 = 49 - 5 = 44

So:  f(7) = 44

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]

[tex]\huge\underline{\sf{\red{Choices:}}}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex] \quad \quad \underline{ \boxed{\sf{ \red{ B.)\: {y | y = –9, –3, 0, 5, 7} }} }}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

#CarryOnLearning

[tex]\sf{\red{✍︎ C.Rose❀}}[/tex]

Answer:

just look at the constant terms...

A: 5

B: 7

C: -5

1) 11-6 = 5 thus answer A

2) -3 -2 = -5 thus answer C

3) -5 - (12) = -5 + 12 = 7 thus answer B

Step-by-step explanation:

Answer:

Everything is correct except for the second one and the ones you checkmarked.

Step-by-step explanation:

Answer:

Step-by-step explanation:

Simplifying

2y + -3x = 18

Reorder the terms:

-3x + 2y = 18

Solving

-3x + 2y = 18

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2y' to each side of the equation.

-3x + 2y + -2y = 18 + -2y

Combine like terms: 2y + -2y = 0

-3x + 0 = 18 + -2y

-3x = 18 + -2y

Divide each side by '-3'.

x = -6 + 0.6666666667y

Simplifying

x = -6 + 0.6666666667y

1. Answer is option 3

2. Answer is option 3

Answer:

for #1 it's the 3rd one and for #2 it's the 4th one (2.8 meters)

Answers:

Blank 1 = p and r

Blank 2 = corresponding angles converse

==========================================================

Explanation:

Refer to the diagram below. I've marked lines p and r in red, and the angles 3 and 22 in blue. They are corresponding angles because they are both in the same southeast corner of their four-corner configuration.

If the corresponding angles are congruent, then the lines p and r are parallel by the aptly named corresponding angles converse

Answer:

36x

Step-by-step explanation:

OF= 6x (given radius of circle)

OB=OF+FB

= 6x +6x(given OF=FB)

= 12x

Angle D= angle B and angle O= 60°( given arc EF is 60°)

D + B + O= 180° ( sum of angles in a triangle)

x + x + 60= 180° ( let the value of remaining angles be x and D= B)

2x= 180 -60

x = 120/2

x= 60°

now, triangle DOB is a equilateral triangle because all angles are equal.

so, OB=DB=OD= 12x ( all sides are equal in equilateral triangle)

so,

perimeter of DOB= OB+DB+OD

= 12x+12x+12x

= 36x

follow me if this was helpful

Answer:

70

Step-by-step explanation:

the fraction 7/10 turns into 70% which means 70 out of 100 tickets were sold.

Answer:

70 tickets sold

Step-by-step explanation:

Multiply the number of tickets by the fraction of tickets sold

100 *7/10

Rewriting

100/10 * 7

10*7

70

Answer:

'the quotient of 4 and n ' is the correct answer

Answer:

N-8

Step-by-step explanation:

Answer:

∠AEC ≅ ∠BED by vertical angles theorem

Answer:

Answer:

∠AEC ≅ ∠BED by vertical angles theorem

Step-by-step explanation:

Answer: B

Step-by-step explanation:

Bc said so

Answer:

[tex]6 \sqrt{5} [/tex]

Step-by-step explanation:

Take out Square root 5 as common and then add numbers

[tex]4 \sqrt{5} + 2 \sqrt{5} \\ 6 \sqrt{5} [/tex]

Answer:

79.5 + 5.5x = Y

Step-by-step explanation:

Sumo wrestler gained 5.5 kg per month

After 11 month, he weighed 140 kg.

Let x be his current weight.

Then x + 11(5.5) = 140

  x = 140 - 60.5

  x = 79.5

If Y is the weight of the wrestler after t months, then the linear equation would be:

 79.5 + 5.5t = Y

i dont understand ur question pls make it more clear!

Answer:

a) 120

Step-by-step explanation:

B is twice the size of A

Answer:

Step-by-step explanation:

This is already factored for us, which is really nice, so now all we need to do is apply the Zero Product Property to the sets of parenthesis and solve for x, which will give us the 2 times that the object is on the ground.

x + 1 = 0 so

x = -1

x - 9 = 0 so

x = 9

We all know that time cannot ever be negative, so the time that the object is on the ground is 9 seconds after it's launched (which was from an initial height of 45 meters).

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex]\huge\underline{\sf{\red{Problem:}}}[/tex]

[tex]\underline{\sf{\red{Formula\:for\: area\: of \:rectangular\: form:}}}[/tex]

[tex]\quad\quad\quad\quad\boxed{\sf{\red{➢} \: \sf{a=l×b}} }[/tex]

[tex]\underline{\sf{\red{Given:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{Length\:of\:rectangular\:form = 45m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{Breadth\:of\:rectangular\:form = 15m} }[/tex]

[tex]\underline{\sf{\red{Solution:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=l×b} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=45m×15m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=\boxed{\sf{{675m}^{2}}}} }[/tex]

[tex]\underline{\sf{\red{For\:rectangular\: form\:with\:path:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{Length\:of\:rectangular\:form = 45m+2=47m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{Breadth\:of\:rectangular\:form = 15m+2=17m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=l×b} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=47m×17m} }[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a=\boxed{\sf{{799m}^{2}}}} }[/tex]

[tex]\huge\underline{\sf{\red{Area\:of\:path:}}}[/tex]

[tex]\quad\quad\quad\quad\sf{\red{➢} \: \sf{a={799m}^{2}-{675m}^{2}} }[/tex]

[tex]\quad\quad\quad\quad\boxed{\sf{\red{➢} \: \sf{a={124m}^{2}} }}[/tex]

[tex]\huge\underline{\sf{\red{Answer:}}}[/tex]

[tex]\huge\quad\quad\underline{\boxed{\sf{\red{a={124m}^{2}} }}}[/tex]

[tex]\underline \bold{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }[/tex]

[tex]\sf{\red{︎✰}ShineBrighter\red{︎✰}}[/tex]

[tex]\sf{✍︎ C.Rose\red{❀}}[/tex]

ฅ^•ﻌ•^ฅ