NEED IN NEXT HOUR solve the following equation: 20= 4t -5t^2

Answer:

Step-by-step explanation:

[tex](5^{-2}[/tex] × [tex]4^{-4}[/tex] [tex])^{-2}[/tex]

=[tex](5^{-2}[/tex][tex])^{-2}[/tex] x [tex](4^{-4})^{-2}[/tex]                            ∴[tex](a.b)^{n} =a^{n} .b^{n}[/tex]

=[tex]5^{-2.-2}[/tex] x [tex]4^{-4 . -2}[/tex]                              ∴[tex](a^{n} )^{m}[/tex] = [tex]a^{nm}[/tex] // here m is an exponent of [tex]a^{n}[/tex].

=[tex]5^{4}[/tex] x [tex]4^{8}[/tex]

Answer:

The correct option is;

SSS congruency theorem

Step-by-step explanation:

Given that opposite sides of a parallelogram are equal, whereby side AB is congruent to side CD and  side BC is congruent to side DA and also that side AC is congruent to side CA, we have;

Triangle ABC with sides AB, BC, and AC is congruent to triangle CDA with corresponding sides CD, DA, and CA, by the Side-Side-Side (SSS) rule of congruency (two or more triangles that have all three sides of one triangle congruent to the three sides of the other triangle are congruent).

The missing reason in the proof is: SSS Congruence Theorem.

Thus, ΔABC and ΔCDA has been shown to have three pairs of congruent sides, therefore, the missing reason in the proof is: SSS Congruence Theorem.

Learn more about SSS Congruence Theorem on:

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Answer:

See below.

Step-by-step explanation:

This is how you prove it.

<B and <F are given as congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

<DEC and <DCE are given as congruent.

Using vertical angles and substitution of transitivity of congruence of angles, show that angles ACB and GEF are congruent.

This is 1 pair of congruent angles for triangles ABC and GFE.

Now you need another side to do either AAS or ASA.

Look at triangle DCE. Using the fact that angles DEC and DCE are congruent, opposite sides are congruent, so segments DC and DE are congruent. You are told segments DF and BD are congruent. Using segment addition postulate and substitution, show that segments CB and EF are congruent.

Now you have 1 pair of included sides congruent ABC and GFE.

Now using ASA, you prove triangles ABC and GFE congruent.

Answer:

Ok, we know that the driving accuracy is of 71%.

Then the first step is to get a spinner that is enumerated from 1 to 100 (in such way that each number is equispaced)

Now, we can mark a section between numbers 1 and 71. (this regio represents the cases where the shot lands in the fairway) and the unmarked region represents the cases where the shot does not land in the fairway.

Now, for each shot, we can spin our spinner next to a fixed pencil, depending on the section of the spinner that is marked by the pencil when the spinner fully stops, we can guess if the shot landed or not in the fairway.

In this way the shot has the region from 1 to 71 (71%) to land in the fairway

and the region from 72 to 100 to not land in the fairway.

If you want to simulate Sorenstam’s performance in a round of golf where she attempts 15 drives, you need to spin the spinner 15 times, and record the oucomes.

Answer:

-7/2

Step-by-step explanation:

cuz thats right

Answer:

C. Point A lies on ray BC

Step-by-step explanation:

Points A and C can be connected by a segment which would be a measure of the distance between the points. Locating point B between AC, makes the three points lying on segment AC.

A ray extends from a point to infinity, a line extend to infinity on both sides, while a segment is known to have two endpoints. Therefore, points AC are the end points of the segment AC, and point B between this segment confirms that point B lies on the segment AC. Therefore, Point A lies on ray BC is not correct.

Answer:

y = 6x - 2

Step-by-step explanation:

slope-intercept form: y = mx + b

Note that:

m = slope = 6

b = y-intercept = -2

x = (x , y)

y = (x , y)

Plug in the corresponding numbers to the corresponding variables:

y = 6x + (-2)

y  = 6x - 2

y = 6x - 2 is your answer.

~

Answer:

y = 6x-2

Step-by-step explanation:

The slope intercept equation  form of a line is

y = mx+b where m is the slope and b is the y intercept

y = 6x-2

Answer:

The correct option is;

b) 0 sq, units

Step-by-step explanation:

The vertices of the triangle are;

(4, 0), (2, 3), (8, -6)

The distance formula fr finding the length of a segment is given as follows;

[tex]l = \sqrt{\left (y_{2}-y_{1} \right )^{2}+\left (x_{2}-x_{1} \right )^{2}}[/tex]

Where, (x₁, y₁) and (x₂, y₂) are the coordinates of the end points of the line

For the points (4, 0) and (2, 3) , we have;

√((3 - 0)² + (2 -4)²) = √13

Distance from (4, 0) to (2, 3) = √13

For the points (4, 0) and (8, -6) , we have;

√((-6 - 0)² + (8 -4)²) = √13 =

Distance from (4, 0) to (8, -6) = 2·√13

For the points (2, 3) and (8, -6) , we have;

√((-6 - 3)² + (8 -2)²) = 3·√13 =

Distance from (2, 3) to (8, -6) = 3·√13

Therefore, the perimeter of the triangle = 6·√13

The semi perimeter s = 3·√13

The area of the triangle,  [tex]A = \sqrt{s\cdot \left (s-a \right )\cdot \left (s-b \right ) \cdot \left ( s-c \right )}[/tex]

Where;

a, b, and c are the length of the sides of the triangle;

[tex]A = \sqrt{3\cdot \sqrt{3} \cdot \left (3\cdot \sqrt{3} -\sqrt{3} \right )\cdot \left (3\cdot \sqrt{3} -2 \cdot \sqrt{3} \right ) \cdot \left ( 3\cdot \sqrt{3} -3\cdot \sqrt{3} \right )} = 0[/tex]

Therefore, the area = 0 sq, units.

Answer: Hi!

Row A: 7, 11, 15, 19, 23

Row B: 51, 42, 33, 24, 15

Row C: 4, 8, 16, 32, 64

Row D: 64, 32, 16, 8, 4

(If you notice, Row C and Row D are just swapped in order!)

Hope this helps!

Hi there! Hopefully this helps!

--------------------------------------------------------------------------------------------------------------

A's rule, add 4: 7, 11, 15, 19, 23

B's rule, Subtract 9: 51, 42, 33, 24, 15

C's rule, Multiply by 2: 4, 8, 16, 32, 64

D's rule, Divide by 2: 64, 32, 16, 8, 4

Answer:Answer:

[tex]\sum\left {{7} \atop {1}} \right -n(3+n)[/tex]

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as [tex]S_n = \frac{n}{2}[2a+(n-1)d][/tex]

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

[tex]S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70[/tex]

The sum of the nth term of the sequence will be;

[tex]S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)[/tex]

The sigma notation will be expressed as [tex]\sum\left {{7} \atop {1}} \right -n(3+n)[/tex]. The limit ranges from 1 to 7 since we are to  find  the sum of the first seven terms of the series.

Answer:

C (1,11) and (-1,-5)

Step-by-step explanation:

Answer:

center=0,0 vertices=(0,5)(0,-5) foci=(0,4)(0,-4)  

Step-by-step explanation:

used calculator

Answer:

D. 9

Step-by-step explanation:

Let

abc=100a+10b+c

bca=100b+10c+a

cab=100c+10a+b

abc + bca + cab=(100a+10b+c) + (100b+10c+a) + (100c+10a+b)

=100a + 10b + c + 100b + 10c + a + 100c + 10a + b

Collect like terms

=100a + a + 10a + 10b + 100b + b + c + 10c + 100c

=111a + 111b + 111 c

Factorise

=111(a+b+c)

abc + bca + cab = 111(a+b+c)

Factors of 111(a+b+c)= 1, 3, 37, 111, and (a+b+c)

abc + bca + cab is divisible by a+b+c because it is a factor of 111(a+b+c)

abc + bca + cab is divisible by 3 because 3 is a factor of 111(a+b+c)

abc + bca + cab is divisible by 37 because 37 is a factor of 111(a+b+c)

abc + bca + cab is not divisible by 9 because 9 is not a factor of 111(a+b+c)

ABCDEFGHIJKLMNOPQRSTUVWXYZ

Answer:

-3

Step-by-step explanation:

First we need to distribute the -4.

-6x+20+4x=26

-2x+20=26

subtract 20 on both sides

-2x=6

divide out -2

x=-3

Answer:

SSS

Step-by-step explanation:

Answer:

SSS

Step-by-step explanation:

Option c or "SSS"

Answer:

(C) [tex]y = 2x+5[/tex]

Step-by-step explanation:

Looking at this graph, we can see that the slope of it is 2. We know this because for every time x increases by 1, y increases by 2.

We also know that the y-intercept of this graph is 5, since it intercepts the y-axis at the value 5.

We can easily create an equation with this info.

[tex]y = 2x + 5[/tex].

Hope this helped!

Answer:

C. y= 2x+5

Step-by-step explanation:

y=mx+b

(+b) is y- intercept

(mx) is the slope.

plot the y- intercept first which the line starts at (0,5)

since the slope isn't a fraction you turn it into one which would be

[tex] \frac{2}{1} [/tex]

Answer:

3

Step-by-step explanation:

2 tangents of a circle drawn from an external point are said to be congruent, according to the two-tangents theorem. Thus:

MN = ML (both tangents from external point M)

ML = 6 - KL

KL = KJ (tangents from point K)

PQ = QJ = 1 (tangents from point Q)

Therefore, KJ = 4 - 1 = 3

Since kJ = KL = 3,

ML = 6 - KL = 6 - 3

ML = MN = 3

Answer:

Step-by-step explanation:

AO = CO = radius

AO = CO  ⇒  AB = BC  and  m∠AOB = m∠BOC = ¹/₂m∠AOC

From BDOE:

m∠EOB + m∠OBC + m∠CDE + m∠DEO = 360°

(65° + 75°) + 90° + x + 90° = 360°

140° + 180° + x = 360°

x = 40°

Answer:

Sorry

Correct

Close

Step-by-step explanation:

Answer:

Ivy's definition will go with third comment, Ethan's definition will go with the first comment, hence, Ebuka's definition will go with the second comment.

Step-by-step explanation:

Answer: 1

Step-by-step explanation:

Given : A, B, c are three points.

We know that a plane exist that pass through three points.

So 1 plane exist that pass through points A, B,  and C.

A point (gives location) , a line(gives length) and a plane(2 dimensional flat surface) are 3 undefined terms.

We need two points two make a line and three points to make a plane.

Answer:

Step-by-step explanation:

The answer is 1

Answer:

9.35

Step-by-step explanation:

Using basic trigonometric ratios,

tan X° = opposite/adjacent

but,X° = 12°

opposite = AC.

adjacent = 44

tan X° = AC/44

AC = tan(12°) × 44

AC = 9.35

Answer:

(2, 2 )

Step-by-step explanation:

Given endpoints (x₁, y₁ ) and (x₂, y₂ ) then the midpoint is

[ [tex]\frac{1}{2}[/tex] (x₁ + x₂ ) , [tex]\frac{1}{2}[/tex] (y₁ + y₂ ) ]

Here (x₁, y₁ ) = (A(5, 8) and (x₂, y₂ ) = B(- 1, - 4) , thus

midpoint = [ [tex]\frac{1}{2}[/tex] (5 - 1), [tex]\frac{1}{2}[/tex] (8 - 4 ) ] = (2, 2 )

Answer:

each angle is less than 90 degrees. angle 1+angle2=90 degrees

Step-by-step explanation:

Answer:

It would be y = -x + 9

Step-by-step explanation:

Answer:

Y=-x+9

Step-by-step explanation:

Answer:

v . w= -13

Step-by-step explanation:

Evaluate the expression: v ⋅ w Given the vectors: r = <8, 1, -6>; v = <6, 7, -3>; w = <-7, 5, 2>

Solution

Given the vectors:

r = <8, 1, -6>

v = <6, 7, -3>

w = <-7, 5, 2>

If you're asking about the dot product.

The dot product is a scalar. It is the sum of the product of the corresponding components.

v.w = (6*-7) + (7*5) + (-3*2)

= -42+35-6

= -13.

[tex](2n+1)^2=4n^2+4n+1[/tex] therefore, the first blank is 1.

[tex]4n^2+4n+1=2(2n^2+2n)+1[/tex] therefore, the two other blanks are both 2.

The number in the proof ''The square of the sum of two consecutive integers is odd'' is 2 and 2.

To prove that, The square of the sum of two consecutive integers is odd.

The expression to prove is,

Let us assume that two consecutive integers are n and (n + 1).

Hence, the expression is written as,

[n + (n + 1)]² = (2n + 1)²

= (2n)² + 2 × 2n × 1 + 1²

= 4n² + 4n + 1

= 2 (2n² + 2n) + 1

= odd

Therefore, the number in the blanks are 2 and 2.

To learn more about the Number system visit:

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Answer:  A & C

Step-by-step explanation:

HL is Hypotenuse-Leg

A) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   a leg from ΔABC ≡ a leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

B) a leg from ΔABC ≡ a leg from ΔFGH

   the other leg from ΔABC ≡ the other leg from ΔFGH

   Therefore LL (not HL) Congruency Theorem can be used.

C) the hypotenuse from ΔABC ≡ the hypotenuse from ΔFGH

   at least one leg from ΔABC ≡ at least one leg from ΔFGH

   Therefore HL Congruency Theorem can be used to prove ΔABC ≡ ΔFGH

D) an angle from ΔABC ≡ an angle from ΔFGH

   the other angle from ΔABC ≡ the other angle from ΔFGH

   AA cannot be used for congruence.

Step-by-step explanation:

log54 = log(2×3³)

= log2 + log3³

= log2 + 3log3

Hey there! I'm happy to help!

Since we are using graphs, we will do not need to algebraically solve this system of equations.

When you graph a system of equations, the solution is always the point at which the two lines intersect.

Here is our system of equations graphed. We see that the lines intersect at about (1 1/3, 2 1/3). Therefore, the correct answer is C. x=1 1/3, y=2 1/3

Have a wonderful day! :D