Answer: Noble Gases (Blue)
what's the correct answer.
The coordinated functions of the Nervous, Endocrine, and Reproductive systems are:
D. CerebrumN. Wernicke's AreaF. Occipital LobeH. HypothalamusJ. ThalamusH. HypothalamusC. CerebellumL. Superior ColliculusA. AmygdalaM. Pineal GlandWhat are coordinated functions?Coordinated functions refer to the integration and communication between different organs, systems, and tissues in the body to achieve a common goal or purpose. In biological terms, coordinated functions often involve multiple physiological systems working together to maintain homeostasis, respond to stimuli, or carry out complex behaviors or processes.
Examples of coordinated functions include the regulation of blood glucose levels by the pancreas and liver, the coordination of movement by the nervous and musculoskeletal systems, and the release of hormones by the endocrine system to control various physiological processes.
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The question is:
"COORDINATED FUNCTIONS OF THE NERVOUS, ENDOCRINE, AND REPRODUCTIVE SYSTEMS"
Directions: Identify the part of the brain that is involved in each situation below. Write only the letter of your answer.
A. Amygdala
B. Brocka's Area
C. Cerebellum
D. Cerebrum
E. Hippocampus
F. Occipital Lobe
G. Hippocampus
H. Hypothalamus
I. Inferior Colliculus.
J. Thalamus
K. Pons
L Superior Colliculus
M. Pineal Gland
N. Wernicke's Area
O. Pituitary Gland
1. "My heart tells me that you are the one. I love you so much!"
2. "IAOCEVOY! I don't know what that means. It's all Greek to me!"
3. "Chartreuse, Olive,Turquoise, and Mint are all shades of green."
4. "Janna always wakes up at 4 in the morning, regardless of whether she uses an alarm clock or not."
5. "I don't remember the way going to Myla's house. Can you accompany me there?"
6. Jenny's mother is about to give birth, she complains about contraction and pain usually when the baby is kicking
7. "Anthony is a very skilled dancer. He just won the school hip hop dance competition last week."
8. "As Nica was walking on the road she readily moved to the side for she heard an incoming ambulance"
9. "Elsa loves making faces whenever she talks to her friends."
10. "Ryan usually talks about how happy his high school days were to his grandchildren."
the surface of the sun appears sharp in visible light because
"The surface of the sun appears sharp in visible light because the photosphere is thin compared to the other layers in the sun."
Most of the electromagnetic energy that reaches the earth begins in the photosphere, the area of the sun that is visible to us. The photosphere is referred to as the sun's surface, despite the fact that it is a gaseous entity.
The gas in the photosphere appears to have a sharp surface, but in reality, it is heavier lower in the Sun and less dense higher up. It is more transparent the less thick it is. The area of the gas that is visible to us is where it has largely become translucent. About 300 km of this layer are deep.
The photosphere is the line separating the core of the Sun from its atmosphere. It is the part of the Sun's surface that is visible to us. The photosphere is not like a planet's surface; even if you could stand in the sun, you couldn't do so on the photosphere.
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When Joselyn went to the store she bought 2.7kg of salt water taffy. What would Joselyn do to find out how many grams she bought?A. Divide by 1000B. Multiply by 1000C. Divide by 100D. Multiply by 100
At the shop, Joselyn purchased 2700 grammes of salt water taffy.
To convert kilograms (kg) to grams (g), Joselyn would need to multiply the weight in kilograms by 1000. This is because there are 1000 grams in 1 kilogram. Therefore, to find out how many grams of salt water taffy Joselyn bought, she would need to multiply 2.7kg by 1000.
The correct answer is (B) Multiply by 1000.
Multiplying 2.7kg by 1000 gives:
2.7kg x 1000 = 2700g
So Joselyn bought 2700 grams of salt water taffy at the store.
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hydroelectric, wind, geothermal, and parabolic solar collection all rely on spinning turbines (connected to a generator) to produce electricity. explain how each provides the force to do so.
Hydroelectric energy is generated by capturing the energy of flowing water. As water flows through a turbine, the blades of the turbine spin and generate electricity.
How does the different energies provide force?Wind energy is generated by capturing the kinetic energy of the wind. As wind passes through the turbine, the blades spin and generate electricity.
Geothermal energy is generated by harnessing the natural heat of the Earth’s core. Heat from the Earth’s core is used to generate steam, which is then used to spin a turbine and generate electricity.
Parabolic solar collection is a method of collecting the sun’s energy using large reflective mirrors. The mirrors focus the sunlight onto a central point, which is then used to spin a turbine and generate electricity.
Thus, all of these power sources rely on spinning turbines connected to a generator to produce electricity.
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as noted in this chapter, plants help to reduce water runoff and soil erosion, both of which affect the health of streams and rivers by impacting water quality. soil erosion increases the silt load in water and this literally smothers living organisms, particularly plants and invertebrate species. runoff water can carry pollutants, particularly pesticides and herbicides from agricultural land. read the description of each landscape and rank them from best stream quality to worst stream quality. 1: streams cutting through small farms with several different crop types and natural vegetation buffers between the fields and the streams. 2: a large floodplain area covered with lowland forests and swamps full of emergent vegetation, with small streams cutting through the area. 3: an urban housing development where the trees growing along the streams were removed and replaced with lawns. 4: a system of large farms with no buffer vegetation between the fields and the streams that cut through the farms. question list (4 items) (drag and drop into the appropriate area) landscape 1 landscape 2 landscape 3 landscape 4 correct answer list best stream quality
Plants help to reduce water runoff and soil erosion, both of which affect the health of streams and rivers by impacting water quality.
Soil erosion increases the silt load in the water, which can smother living organisms, particularly plants and invertebrate species. Runoff water can carry pollutants, particularly pesticides, and herbicides from agricultural land.
Landscape 1 (streams cutting through small farms with a variety of crop types and natural vegetation buffers between the fields and the streams) would be the best quality, followed by Landscape 2 (a large floodplain area covered in lowland forests and swamps full of emergent vegetation, with small streams cutting through the area) and Landscape 3 (an urban housing development where the streams are surrounded by emergent vegetation).
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Discuss three applications of the effects of surface tension.
A student walks 1.0 kilometer due east and 1.0 kilometer due south. Then
she runs 2.0 kilometers due west. The magnitude of the student's
resultant displacement is closestto
A. 3.4 km
B. 1.4 km
C. 4.0 km
D. O km
The resulting displacement will be 3.4 km. The correct option is A.
The displacement is calculated by finding the displacement from east to west, which is 2.0 km, and subtracting the displacement from north to south, which is 1.0 km.
A student walks 1.0 kilometers due east and 1.0 kilometers due south. Then she runs 2.0 kilometers due west. The magnitude of the student's resultant displacement is closest to 3.4 km.
To begin with, we may use the Pythagorean Theorem to determine the resultant displacement's magnitude. The Pythagorean Theorem is a formula that is used to determine the length of a right triangle's sides when one is missing. This theorem is used to calculate the magnitude of the resultant displacement, which is a quantity. It's a good idea to draw a diagram to help you understand the problem.
Here's a rough sketch of the scenario: We will now apply the Pythagorean theorem in this way: The resultant displacement's magnitude is 3.4 kilometers. Thus, the correct option is A.
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in one cycle a heat engine absorbs 480 j from a high-temperature reservoir and expels 320 j to a low-temperature reservoir. if the efficiency of this engine is 56% of the efficiency of a carnot engine, what is the ratio of the low temperature to the high temperature in the carnot engine?
The ratio of the low temperature to high temperature of the Carnot engine is 2.38.
What is the efficiency of Carnot engine?The efficiency of the Carnot engine can be defined as the ratio of network done per cycle by the engine to the heat energy absorbed by the engine per cycle by the working substance from the source.
Efficiency = 1 - (Tlow/Thigh)
Heat absorbed by engine = 480J
Heat expelled by engine = 320J
Efficiency of the engine = 56% of efficiency of Carnot engine
The ratio of low temperature to high temperature in the Carnot engine.
Let's assume the efficiency of the Carnot engine is 'ηc' = 1 - T₂/T₁
Where, T₂ = Low temperature and T₁ = High temperature
To calculate the efficiency of the engine given, η = (Q1 - Q2)/Q1
η = (480 - 320)/480
η = 160/480
η = 1/3
η = 33.33%
Now, η = 56% × ηc
0.56ηc = 1/3ηc = (1/3)/0.56 = 0.58
As we already know, ηc = 1 - T₂/T₁
T₂/T₁ = 1 - ηc
T₂/T₁ = 1 - 0.58
T₂/T₁ = 0.42
T₁/T₂ = 1/0.42
T₁/T₂ = 2.38
Therefore, the ratio of low temperature to high temperature in the given Carnot engine with an efficiency of 56% will be about 2.38.
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Consider the spectra of the two main sequence stars below (Star 1 on the left and Star 2 on the right) and sort the statements into the true or false bins. The intensity axes are not necessarily on the same scale. 350 450 550 Wavelength (nm) 350 45Q750 650 750 Wavelength (nm) true false Star 1 has a longer lifetime than Star 2 Star 2 is bluer than Star 1 Star 2 has a lower mass than Star 1 Star 1 has prominent hydrogen lines Star 2 has a higher luminosity than Star 1 Star 2 is cooler than Star 1.
. Additionally, Star 1 has prominent hydrogen lines, indicating a lower temperature than Star 2. Therefore, the statements can be sorted into the true and false bins as indicated above.
True: Star 1 has a longer lifetime than Star 2; Star 2 is bluer than Star 1; Star 2 has a lower mass than Star 1; Star 1 has prominent hydrogen lines.
False: Star 2 has a higher luminosity than Star 1; Star 2 is cooler than Star 1.
The spectra of the two main sequence stars illustrate some differences between the two stars. Star 1 is on the left and has a longer lifetime than Star 2, which is on the right. This is evident from the intensity axes that are not on the same scale. Star 2 has a lower mass than Star 1, is bluer than Star 1, and has a lower luminosity
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charge q1 is distance s from the negative plate of a parallel-plate capacitor. charge is distance 2s from the negative plate. what is the ratio of their potential energies?
The electric potential energy, U, of two point charges is given by the equation, U = kq1q2/r where k is Coulomb's constant, q1 and q2 are the charges and r is the distance between the two charges. Now, let's solve the question using this equation. There are two charges, q1 and q2, and a parallel plate capacitor between them. The distance of q1 from the negative plate is s, and the distance of q2 from the negative plate is 2s. The charges have the same magnitude of charge, so let's assume q1 = q2 = q. Using the formula mentioned earlier, we get U1= kq^2/sU2= kq^2/2s. Therefore, the ratio of their potential energies is U2/U1= kq^2/2s / kq^2/sU2/U1= (kq^2/2s) × (s/kq^2)U2/U1= 1/2.
Therefore, the ratio of their potential energies is 1:2.
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Imagine another solar system, with a star of the same mass as the Sun. Suppose a planet with a mass twice that of Earth (2MEarth) orbits at a distance of 1 AU from the star. What is the orbital period of this planet? Hint: Think about how the mass of the Sun compares with the mass of the Earth. a. 3 months b. 6 months
c. 1 year d. 2 years
e. It would not be able to orbit at this distance.
The correct answer is option D.2 years
What is Kepler's third law of planetary motion?According to Kepler's Third Law of Planetary Motion, T² is proportional to r³, where T is the period of revolution of the planet and r is the distance between the planet and the star.
In order to solve for T,
AU = 1
Astronomical Unit = the average distance between the Earth and the Sun = 149.6 million kilometres
Therefore, the planet is orbiting at a distance of 149.6 million kilometres from the star.
Substituting the values of r and solving for
T².T² ∝ r³T² ∝ (149.6)³T²
= (149.6)³T²
= 3.522 x 10¹²T
= √3.522 x 10^¹²T
= 1.87 x 10⁶ seconds
T = 31,100 minutes
T = 518 hours
T = 21.6 days
T = 2 years
Therefore, the orbital period of the planet with twice the mass of Earth orbiting at a distance of 1 AU from a star with the same mass as the Sun is 2 years.
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