Instructions: Answer the following questions in the space provided. Be sure to write your responses in complete sentences.
A father pushes his daughter and son on a sled down a hill.
Part A: Other than the force exerted by the father pushing the sled, identify two additional forces that act on the sled as it travels from the top of the hill to the bottom. (2 pts)
Part B: Explain how each force you identified in Part A will affect the motion of the sled. (2 pts)
(A) The two additional forces that act on the sled as it travels from the top of the hill to the bottom are friction force and weight of the children.
(B) The force of friction is opposing the motion while the weight of the children is assisting the downward motion.
What are the forces exerted on the sled?
The forces that act on the sled as it travels from the top of the hill to the bottom with either aid the downward motion or oppose the downward motion.
The forces acting on the sled include the following;
the force applied by the fatherthe weight of the children acting normal to the surface of the sledthe force of friction acting upwards to oppose the downward motionThe weight of the children is acting downwards and it will increase the motion downwards since there in the same direction.
The force of friction between the surface of the sled and the hill will oppose the downward motion of the children as the father exerts the downward force.
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what is the formula to find the volume of a sphere
9. A 1,500-kg Lamborghini Aventador is moving forward with a force of
5,000 N. It experiences 1,250 N of air resistance (air friction). What is the
car's acceleration? (Remember: you need the NET force first!)
1.500
Answer:
Below
Explanation:
The friction subtracts from the forward force
F = ma
(5000 - 1250) / 1500 = a = 2.5 m/s^2
Maddy tripped and accidentally threw her phone off the hollywood cliff at 5m/s. It landed 20 away from the base of the cliff. how high is the cliff then?
The height of the cliff, given that her phone landed 20 m away when she accidentally threw her phone with a velocity of 5 m/s is 78.4 m
How do I determine the height of the cliff?To determine the height of the cliff, we must first obtain the time taken for her phone to reach the ground. This is obtained as follow:
Horizontal velocity (u) = 5 m/sHorizontal distance (s) = 20 mTime taken (t) =?s = ut
20 = 5 × t
Divide both sides by 5
t = 20 / 5
t = 4 s
Finally, we shall determine the height of the cliff. Details below:
Time taken (t) = 4 sAcceleration due to gravity (g) = 9.8 m/s²Height (h) = ?h = ½gt²
h = ½ × 9.8 × 4²
h = 4.9 × 16
h = 78.4 m
Thus, the height of the cliff is 78.4 m
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collin was thrown from his horse while riding and subsequently received a blow to the back of his head. what might collin have trouble with?
After thrown from his horse, Collin might have trouble with his occipital lobe.
The occipital lobe is one of the four significant lobe of the cerebral cortex in the mind of warm blooded creatures. The name gets from its situation at the rear of the head, from the Latin ob, "behind", and caput, "head".
The occipital lobe is the visual handling focus of the mammalian mind containing a large portion of the physical locale of the visual cortex. The essential visual cortex is Brodmann region 17, ordinarily called V₁(visual one). Human V₁ is situated on the average side of the occipital curve inside the calcarine sulcus; the full degree of V₁ frequently go on onto the occipital shaft.
V₁ is much of the time likewise called striate cortex since it tends to be distinguished by a huge stripe of myelin, the Stria of Gennari. Outwardly determined locales outside V₁ are called extrastriate cortex. There are numerous extrastriate districts, and these are specific for various visual errands, for example, visuospatial handling, variety separation, and movement insight. Two-sided injuries of the occipital curve can prompt cortical visual deficiency.
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3. A force of 70N is applied to a 10kg box with a friction force of 30N opposing it's motion. The box starts
from rest and reaches a speed of 5m/s. Determine the distance over which the force acts on the box.
The distance over which the force acts on the box, given that 70 N is applied to the 10 Kg box is 3.125 m
How do I determine the distance ?We'll begin by obtaining the acceleration of the box. Details below:
Force applied = 70 NForce of friction = 30 NNet force = Force applied - Force of friction = 70 - 30 = 40 N Mass of box = 10 KgAcceleration (a) =?Net force = mass × acceleration
40 = 10 × acceleration
Divide both sides by 10
Acceleration = 40 / 10
Acceleration = 4 m/s²
Finally, we shall determine the distance. Details below
Initial velocity (u) = 0 m/sFinal velocity (v) = 5 m/s Acceleration(a) = 4 m/s²Distance (s) =?v² = u² + 2as
5² = 0² + (2 × 4 × s)
25 = 0 + 8s
25 = 8s
Divide both side by 8
s = 25 / 8
s = 3.125 m
Thus, we can conclude that the distance covered is 3.125 m
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Which type of eclipse makes the Sun appear in the form of a ring?
A.
total solar eclipse
B.
partial solar eclipse
C.
annular solar eclipse
D.
partial lunar eclipse
E.
total lunar eclipse
Answer: D. Annular Solar Eclipse
Explanation:
An annular solar eclipse happens when the Moon passes between the Sun and Earth, but when it is at or near its farthest point from Earth. Because the Moon is farther away from Earth, it appears smaller than the Sun and does not completely cover the Sun.
FILL IN THE BLANKS
12) When two objects interact through the gravitational force between them, the more massive one has a lower __acceleration_________ than the less massive object.
Answer: Acceleration
Explanation:
When two objects interact through the gravitational force between them, the more massive one has a lower acceleration than the less massive object.
true or false: we can determine if a star is moving toward or away from earth by measuring its brightness.
We can determine if a star is moving toward or away from earth by measuring its brightness.
The correct answer would be:
[tex]\fbox{False}[/tex]
tarzan has a mass of 73 kg. he swings from a 26.1 m vine. at the lowest point in his swing, tarzan is moving at 3.65 m/s. what is the tension in the vine at the lowest point in the swing? g
Tarzan weighs 73 kg. From a 26.1 m vine, he swings. Tarzan is travelling at 3.65 m/s when he is at his lowest point in his swing. The vine is under 2635.3 kg-m/s^2 of tension at the swing's lowest point.
The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force pulls energy equally on the bodies at the ends and is applied along the entire length of the wire. Every physical object in contact with another one applies some force to that object. For items that are hung, the tension is equal to the gravitational acceleration times the mass of the object.
Here m=73kg
acc (a) = 26.1 m
g=10
d= 3.65 m/s
Tension t = mg + ma.
Tension t = m(g + a).
t = m(g + a)
t= 73(10+26.1)
t= 73(36.1)
t= 2635.3 kg-m/s^2
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A particle with a charge of 11.2 μC moves with a velocity of 11.7 m/s toward geographic West (BE = 5.01 × 10–5 T). If the Lorentz force on the particle is9.12 × 10–9 N, what is the magnitude and direction of the electric field?
The magnitude of electric field is 5.08×10^-4 N/C in North direction.
What is Lorentz force?The electromagnetic field-induced magnetic and electric forces acting on a point charge are referred to as the Lorentz force. It is also referred to as electromagnetic force and is employed in electromagnetism.
Given that: charge of the particle: q = 11.2 μC.
Velocity of the particle in the west direction: v = 11.7 m/s.
Magnetic field acting on it: B = 5.01 × 10^–5 T.
Lorentz force on the particle is: F = 9.12 × 10^–9 N.
Let the electric field = E.
So, Lorentz force on the particle is: F = q (V×B + E)
9.12 × 10^–9 = 11.2 × 10^-6 ( 11.7 × 5.01 × 10^–5 × sin90° + E)
⇒ 11.7 × 5.01 × 10^–5 ×1 + E = 7.79×10^-5
⇒ E = 7.79×10^-5 - 11.7 × 5.01 × 10^–5 ×1
⇒ E = - 5.08×10^-4 N/C
Hence, the electric field is 5.08×10^-4 N/C in North direction as magnetic force is acting south direction according to cork screw law.
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-. The magnitude of vector A is 18.5 Vector lies in the fourth
quadrant and forms an angle of 55° with the x-axis. What are
the components of vector A?
(+ , -)
- sin(55)=y/18.5 -> 18.5sin(55)=y
- cos(55)=x/18.5 -> 18.5cos(55)=x
How can you determine a vector's direction given its magnitude?The magnitude will be given by |v|=a2+b2 if v=a,b is indeed the coordinates.In accordance with the application the direction usually equal to the angle made with the x-axis or the y-axis.The formula tan=(ba)=tan1(ba) can be used to determine the direction of a position vector, as shown in Figure 8.8.
How do you calculate that magnitude of a four-part vector?Any number of dimensions can be included in the generalization of the vector magnitude formula.For instance, the formula for the magnitude of a four-dimensional vector a=(a1,a2,a3,a4) is a=a21+a22+a23+a24.
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(a) what is the magnitude of the tangential acceleration of a bug on the rim of an 11.0-in.-diameter disk if the disk accelerates uniformly from rest to an angular speed of 79.0 rev/min in 3.50 s?
The magnitude of the tangential acceleration is 0.329m/s².
The degree of tangential acceleration can be calculated in what way?At=r a t = r is the formula for tangential acceleration, where r is the circle's radius and is the angular acceleration. The definition is derived from the fact that the arc length is equal to the circle's radius times the angle in radians.
d = Diameter of rim = 11.0 in = 11 × 0.0254 = 0.2794m
r = Radius = d/2 = 0.2794/2 = 0.1397m
[tex]\omega_{f}[/tex] = Final angular velocity = 79 × 2π/60 = 8.26rad/s
[tex]\omega_{i}[/tex] = Initial angular velocity = 0
∝ = Angular acceleration
t = Time taken = 3.5s
Rotational motion equation,
[tex]\omega_{f}[/tex] = [tex]\omega_{i}[/tex] + ∝t
∝ = [tex]\omega_{f}[/tex] - [tex]\omega_{i}[/tex]/t
∝ = 8.26 - 0/3.5
∝ = 2.36 rad/s²
Magnitude of the tangential acceleration given by
[tex]a_{t}[/tex] = r∝
[tex]a_{t}[/tex] = 2.36 × 0.1397
[tex]a_{t}[/tex] = 0.329m/s².
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example 10.11 discusses the conversion of spring potential energy to kinetic energy. how much energy is initially stored in the spring?
A spring-loaded to gun is used to launch a 10 plastic ball. The spring, which has a spring constant of 10 N/m, is compressed by 10 cm as the ball is pushed into the barrel. When the trigger is pulled, the spring is released and shoot the ball back out horizontally.
Answer:
Below
Explanation:
ESE = 1/2 k d^2
= 1/2 * 10 N/m * .1 m = .5 J
Earth has a very strong gravitational force that can pull the objects to fall to the Earth's surface. How do satellites overcome this problem and stay in its orbit?
g a spacecraft is moving at a speed of 0.800 c relative to the earth. what is the ratio of the length of the spacecraft, as viewed through a telescope on earth, to its length when measured after landing on earth? (assume that the spacecraft is moving at a right angle to the line of observation.
If the spacecraft is moving at a speed of 0.800c , then the ratio of length of spacecraft to its length after landing is 0.600 .
Speed of Spacecraft is given as = 0.800c ,
the spacecraft is viewed through telescope ,
we have to find the ratio of the lengths of the spacecraft as viewed through the telescope on earth to its length measured after landing on earth .
let length of spacecraft viewed from telescope be = L
let length of spacecraft after landing be = L₀ :
So , by formula of length: L = L₀√(1 - v²/c²)
Substituting the values of V , we get
L/L₀ = √(1 - (0.800c)²/c²)
= √(1 - 0.800²)
= 0.600 .
Therefore , the ratio of the lengths of the spacecraft is 0.600 .
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what is the system's potential energy when its kinetic energy is equal to 34e ? view available hint(s)for part a what is the system's potential energy when its kinetic energy is equal to ? ka2 ka22 ka24 ka28
The energy that results from an object's location in relation to other things is known as potential energy. Potential energy is frequently connected to restorative forces like the force of gravity or a spring.
What happens when kinetic energy and potential energy are equal?The mechanical energy of an item is the total of its potential and kinetic energies. A falling object loses potential energy while gaining kinetic energy. The difference between the increase in kinetic energy and the reduction in potential energy is exact.
Potential energy and kinetic energy vary primarily in that one is the energy of what can be and the other is the energy of what is. In other words, stored energy is ready to be released but potential energy is immobile.
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one force of 6.2 newtons and one force of 4.4 newtons act on a body at the same point so that the resultant force is 9.1 newtons. find the angle between the resultant and the larger force, to the nearest 10th of a degree.
The angle between the resultant and the larger force is 60 degree if resultant force value is value 9.1Newtons.
We know that resultant force is given by the superposition principle which uses a formula
Resultant force =√((F₁)² + (F₂)² + 2 ˣ F₁ ˣ F₂ ˣ cosθ)
Superposition principle of electric force to find the resultant power, all accuses are thought about independently of that specific charge as though any remaining charges are missing. Along these lines, for each charge, the power on that specific charge is to be found out. Then the vector amount of the multitude of forces gives the resultant forces on that charge.
We have resultant force as 9.1Newton,F₁=6.2newton,F₂=4.4 newton
So,on putting the values,we get
=>(9.1) = √[(6.2)² + (4.4)² + 2 × 6.2×4.4×cosθ]
Squaring on both sides,we get
=>9.1 × 9.1 =(6.2)² + (4.4)² + 2× 6.2×4.4×cosθ
=>82.81=38.44 + 19.36 + 54.56×cosθ
=>82.81=57.8+ 54.56×cosθ
=>82.81-57.8= 54.56×cosθ
=>25.01=54.56×cosθ
=>cosθ=25.01/54.56
=>cosθ = 0.458
=>cosθ=cos(62.5)°
=>θ=62.5°
=>θ=60°(nearest 10th)
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9. a soap bubble is 100 nm thick and illuminated by white light incident perpendicular to its surface. what wavelength and color of visible light is most constructively reflected, assuming the same index of refraction as water?
When a soap bubble 100 nm thick and illuminated by white light incident perpendicular to its surface, then wavelength, λ is calculated = 5.32 *10^-7 m.
What is index of refraction?The ratio of the speed of light in a vacuum, c, to the speed of light in a medium, c' is called as index of refraction. One of the consequence of this difference in speed is that when light goes from one medium to another at an angle, then the propagation vector in the new medium has a different angle with respect to normal.
Given, t= 100nm= 100 * 10 ^-9 n= 1.33
ΔФ1 = λ/4
ΔФ2 = 2√2 t λ n/2 λ
=2 t n
=2 * 100 * 10 ^-9 * 1.33
= 2.66 *10^-7
2.66 *10^-7= λ/2
λ= 5.32 *10^-7 m.
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What is the correct answer for this question?
Answer:
Which is correct? "The answer to this question.." or "The answer of this question "?
1
Newton's third law states that any action will have a(n) _______ and ______ reaction.
Newton's third law states that any action will have a(n) equal and opposite reaction.
what was the value of the scale factor a when the dark energy density became equal to the matter density? show your work, please.
The parameter of the dark energy equation of state is viewed as an arbitrary constant with a value falling between the range $w in [-1.5, -0.5]$, the upper and lower bounds of which are determined by recent measurements. We get scale factor approximations with better than 1% accuracy.
What's density in science?Mass of a solid substance per unit volume. The equation for density is d = M/V, where d represents density, M is mass, and V is volume. Density is often measured in grammes per cubic centimetre. Its mass per unit of volume is a measure of a substance's density. Although the sign can also represent the Latin letter D, it is most frequently used to represent density. Mass divided by volume is the formula for density in mathematics: displaystyle rho = frac mV. where V is the volume, is the density, and m is the mass.
How does density work?How much mass there is in a specific volume or area is determined by its density. The formula for determining a substance's density is to divide its mass by its volume.
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a system absorbs heat from the surroundings and has work done on it by the surroundings. what are the signs of qsystem and wsystem?
The sign of qsystem and qsystem are - qsystem>0 and qsystem>0.
What is q and w system?The Q-system for rock mass-containing classifications is developed by the barton, Lien, and Lunde. It expresses the quality of the rock mass-containing in the so-called Q-value, on whichs designe are based and support recommendations of the underground excavations.
systems is a portions of the Universe that had been chosen up for studying in the changed that takes places withing it in responses to varying conditions. A systematic may be complexity, such as a planet, or relatively simple, as the liquid withing a glass.
Beacuse when system gain extra heat then surrounding q is posetive and when the surrounding works on the system then w is also positive.
Thus both qsystem and
qsystem are same.
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a typical tendon has a strength of 16000 pounds per square inch (psi). let's assume the achilles tendon is roughly rectangular in cross section with dimension of .4 inches x .2 inches. you can use this to calculate the force at which the achilles tendon will start to fail. at what force might the achilles tendon start to fail (in pounds, lb)?
An average tendon can withstand 16000 per square inch of force (psi). The Achilles tendon may begin to fail at a force of F = 1280 pounds.
How does science define force?That meaning of the term "force" is obvious. At this point, it is quite acceptable to refer to a force as a push or possibly a pull. An item does not "have energy in it" or "encompass energy." A force is applied to one thing by another. A factor is anything that affects non-living things as well.
Inertia or a force?Inertia is what holds the cosmos together. Literally. That could prevent matter from having the electric forces necessary to produce its system layout. Vibrating particles generate heat and rotational motion, which operate to counteract inertia.
Briefing:Area of tendon 0.4×0.2
=0.08 square inch.
0.08 square inch tendon =16000×0.08
F =1280 pound.
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A car advertisement states that a certain car can accelerate from rest to 30 m/s in 5 seconds. Find the car’s average acceleration. (Prefered if using KWEPA method!)
The car’s average acceleration is 6 meter/second^2.
What is acceleration?Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).
Given that: the car can accelerate from rest to 30 m/s in 5 seconds.
Hence, average acceleration of the car = change in speed/time interval
= ( final speed - initial speed)/time interval
= ( 30 m/s - 0 m/s) / 5 second
= (30/5) meter/second^2
= 6 meter/second^2.
Hence, the average acceleration of the car is 6 meter/second^2.
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what is the relathion shop between perriod and frequency
Frequency is inversely proportional to the time period. That is, f = 1/T.
What is frequency?This refers to the number of waves that passes a fixed place in a given amount of time. Frequency is measured in hertz, this is equal to one event per second.
What is period, T ?
This refers to the time needed for one complete cycle of vibration to pass a given point. A period is measured in seconds.
Note: AS the frequency of a wave increases, the period of the wave decreases. Frequency and Period are in reciprocal relationships.
Mathematically :
f = 1/T
T =Total time,Period
f = Frequency
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an automobile traveling at 80.0 km/h has tires of 75.0 cm diameter. what is the angular speed of the tires about their axles? if the car is brought to a stop uniformly in 300.0 complete turns of the tires (without skidding), what is the magnitude of the angular acceleration of the wheels? how far does the car move while braking
Initial velocity=- 80km/h, the diameter of the tyre= 75cm, and revolution= 300. initial angular velocity wi= v/r (80) (5/18)/75/200= 59.26 rad/sec. so, angular acceleration is 0.93 rad/sec2.
What was the tire's angular acceleration?We must first determine the tires' angular acceleration. Let's transform the provided translational velocity to rotational velocity to do this. Thus, the tires' angular acceleration is 2.42 rad/s2 rad/s2.
How can you figure out angular velocity?The angular velocity (w), a vector quantity in a uniform circular motion, is determined by dividing the angular displacement (), also a vector quantity, by the change in time (t). Speed is equal to |w|R and is calculated by dividing the arc length traveled (S) by the change in time (t).
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A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2. What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
A satellite weighing 5,400 kg is launched into orbit 30,000 km above sea level. The mass of Earth is 6.0 × 1024 kg and its radius is 6,400 km. The gravitational constant is 6.673 × 10–11 N•m2/kg2 . What is the gravitational force of Earth on the satellite in scientific notation with two decimals.
–1.6 × 103 N
–1.63 × 103 N
–2.4 × 103 N
–5.27 × 104 N
The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N
How do I determine the gravitational force?The gravitaional force between two objects can be obtained by using the following formula:
F = GM₁M₂ / r²
Where
F is the gravitaional force G is the gravitational constant M₁ and M₂ are the masses of the objects r is the distance apartThe following data were obtained from he question:
Mass of satellite (M₁) = 5400 = 5.4×10³ KgHeight (h) = 30000 km = 30000 × 1000 = 30000000 mMass of Earth (M₂) = 6.0×10²⁴ KgRadius of Earth (R) = 6400 km = 6400 × 1000 = 6400000 mDistance apart (r) = R + h = 6400000 + 30000000 = 36400000 mGravitational constant (G) = 6.673×10¯¹¹ Nm²/Kg²Gravitational force (F) =?The gravitaional force can be obtained as shown below:
F = GM₁M₂ / r²
F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²
F = 1.63×10³ N
Thus, the gravitational force is 1.63×10³ N
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the sun has a mass of 2.0 x 1030 kg and radiates energy at the rate of 3.9 x 1026 w. (a) at what rate does the sun transfer its mass to other forms of energy? (b) what fraction of its original mass has the sun lost in this way since it began to burn hydrogen, about 4.5 x 109 y ago?
The rate at which sun transfers its mass to other forms of energy is 4.3* 10⁹ kg/s.
The fraction of its original mass has the sun lost in this way since it began to burn hydrogen, about 4.5 x 109 y ago is 3.1 * 10⁻⁴.
Given that,
Mass of the sun = 2* 10³⁰ kg
Radiation power P = 3.9* 10²⁶ W
The rate of changing mass is P = E/t = (m*c²)/t
Re-arranging the terms, we have,
m/t = P/c² = (3.9* 10²⁶)/(3* 10⁸)² = 4.3* 10⁹ kg/s
Fraction of original mass lost is Δm = m/t * t = (4.3* 10⁹)* (4.5* 10⁹)
⇒ 6.15 * 10²⁶ kg
Fraction of mass lost = Δm/(m + Δm) = (6.15 * 10²⁶)/(2* 10³⁰ + 6.15 * 10²⁶)
⇒ 3.1 * 10⁻⁴
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according to the uncertainty principle, the more we know about a particle's momentum, the less we know about its group of answer choices location or position. mass kinetic energy. speed. none of these
The correct answer is option a. According to the uncertainty principle, the more we know about a particle's momentum, the less we know about its location or position.
The uncertainty principle is a fundamental principle in quantum mechanics that states that it is impossible to simultaneously know both the exact position and momentum of a particle. This is because any attempt to measure the position of a particle with high accuracy will inevitably disturb its momentum and vice versa.
The uncertainty principle is a consequence of the wave-particle duality of quantum mechanics, which states that all particles exhibit both wave-like and particle-like behavior. When we measure the position or momentum of a particle, we are essentially measuring the wave-like properties of the particle, which are inherently uncertain. This uncertainty is inherent in the nature of the universe and cannot be overcome, no matter how advanced our measurement technologies become.
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