Engineering College

Mr. Ray deposited $200,000 in the Old and Third National Bank. If the bank pays 8% interest, how much will he have in the account at the end of 10 years?

Answers

Answer 1

Answer:

2,160,000

Explanation:

8/100 × 200000/1 = 8/1 × 2000/1

2000 × 8 = 16,000 = interest

200,000 + 16,000 = 216,000

216,000 × 10 = 2,160,000 = amount in bank account

Related Questions

Question 4. Select the statement that best describes the PM wave. a. Carrier phase angle changes represent the PM modulated signal, however, unlike FM and AM modulated carriers, it is not always easy to see these phase changes in the plot. b. The FM signal accurately represents the message. c. Although PM and FM techniques are classified as angular modulation techniques, they cannot be used interchangeably (i.e., modulated with FM and demodulated with PM, and visa versa). d. All statements are correct.

Answers

Answer:

c. Although PM and FM techniques are classified as angular modulation techniques, they cannot be used interchangeably i.e., modulated with FM and demodulated with PM, and vice versa.

Explanation:

Phase modulation is modulation pattern for conditioning communication signals for transmission. PM signals appears to change frequency with message wave. Both PM and FM are angular modulation techniques. The message in PM wave is captured in phase changes.

A crane is set up for steel erection at the site of a 5 story office building where each story is 15 feet tall. The new building will be 50 feet wide and 75 feet long and the crane is located 5 feet off the southwesterly corner of the building. Assuming that you need a 10 foot boom clearance over the last piece of steel.

Required:
Compute the minimum boom length

Answers

Answer:

127.58 ft

Explanation:

We need first to calculate the length from corner to corner of the story, L.

Since the length of each floor is 75 ft and its width 50 ft, and since each floor is a rectangle with diagonal, L, using Pythagoras' theorem, we have

L² = (75 ft)² + (50 ft)²

= 5625 ft² + 2500 ft²

L² = 8125 ft²

L = √(8125 ft²)

L = 90.14 ft

Since the crane is 5 ft off the southwesterly corner of the building, the working radius, R = L + 5 ft = 90.14 ft + 5 ft = 95.14 ft.(since the diagonal length of the floor plus the distance of the crane from the south westerly corner add to give the working radius)

The boom tip height, H = height of building h + clearance of boom, h'

h = height of each story, h" × number of stories, n

Since h" = 15 ft and n = 5

h = 15 ft × 5 = 75 ft

Also, h' = 10 ft

So, H = h + h'

H = 75 ft + 10 ft

H = 85 ft

So, the minimum boom length, L' = √(H² + R²)

substituting the values of the variables into the equation, we have

L' = √(H² + R²)

L' = √((85 ft)² + (95.14 ft)²)

L' = √(7225 ft² + 9051.6196 ft²)

L' = √(16276.6196 ft²)

L' = 127.58 ft

in c the square root of a number N can be approximated by repeated calculation using the formula NG = 0.5(LG + N/LG) where NG stands for next guess and LG stands for last guess. Write a function that calculates the square root of a number using this method. The initial guess will be the starting value of LG. The program will com- pute a value for NG using the formula given. The difference between NG and LG is checked to see whether these two guesses are almost identical. If they are, NG is accepted as the square root; otherwise, the next guess (NG) becomes the last guess (LG) and the process is repeated (another value is computed for NG, the difference is checked, and so on). The loop should be repeated until the difference is less than 0. 005. Use an initial guess of 1. 0. Write a driver function and test your square root function for the numbers 4, 120. 5, 88, 36.01, 10,000, and 0. 25
PLEASE İN C PROGRAMMİNG

Answers

Answer:

Following are the program to the given question:

#include <stdio.h>//header file

double square_root(double N, double initialGuess)//defining a method square_root that takes two variable in parameters

{

double NG, LG = initialGuess,diff;//defining double variable

while(1)//use loop to calculate square root value

{

NG = 0.5 * (LG + N / LG);//using given formula

diff = NG - LG;//calculating difference

if(diff < 0)//use if to check difference is less than 0

diff = -diff;//decreaing difference

if(diff < 0.005)//use if that check difference is less than 0.005

break;//using break keyword

else//defining else block

{

LG = NG;//holding value

}

return NG;//return value

}

int main()//defining main method

{

double ans, n,initialguess = 1.0;//defining double variable

n = 4;//use n to hold value

ans = square_root(n, initialguess);//calculating the square root value and print its value