Answer:
The correct answer is "encode some of the proteins needed for aerobic respiration and photosynthesis, respectively, as well as ribosomal and transfer RNA".
Explanation:
Most organisms have a mitochondrial or a chloroplast genome in addition to the main genomic sequence located in the cell nucleus. The genes that are located in these organelles' genome include the genes that are used directly in the mitochondrion or chloroplast , including: proteins needed for aerobic respiration and photosynthesis (for instance genes involved in oxidative phosphorylation), respectively, as well as ribosomal and transfer RNA, which serve to the translation of proteins.
In the image, the arrow Is pointing to a celestial object. Which attribute disqualifies the object from being a planet?
A. It appears to have no moons.
B. It is spherical in shape.
C. Its neighborhood is not clear.
D. It has horizontal bands on its surface.
The correct answer is C. Its neighborhood is not clear.
Explanation:
One of the key features of a planet is that it clears its neighborhood; this means the planet gravitational force is strong enough that there are no other celestial bodies on its orbit or next to it except by its moons or satellites. This does not occur in the image presented because there are smaller celestial bodies near to the main or bigger celestial body. This likely occurs if the celestial body is not big enough to clear its neighborhood, and therefore it is not a planet.
In which of these stages is mitosis most important? A tiger cub is born. A tiger cub learns to walk. A tiger cub begins to grow. A tiger cub play-fights.
Answer:
A tiger cub begins to grow
Explanation:
because that's when they change the most
Answer:
A tiger club play fights
Explanation:
One main part of mitosis is the replacement of cells, so when the tiger gets hurt fighting, mitosis kicks in to replace the cells.
In most organisms, the end product of glycolysis is pyruvate. Pyruvate still contains a substantial amount of energy, which can be further extracted. Whether the organisms are operating under aerobic or anaerobic conditions determines the metabolic pathway that pyruvate undergoes to produce more ATP. In this tutorial, you will identify the end products of these metabolic pathways.
Answer:
Pyruvate helps in the production of ATP.
Explanation:
The molecule of pyruvate converted into acetyl CoA. Then each molecule which is produced during glycolysis loses electron and carbondioxide releases. After the breakdown of pyruvate, the electrons loses by pyruvate are transferred to NAD+ in order to produce NADH, which will be used by the cell to produce energy molecule such as ATP. So we can say that pyruvate plays a vital role in the formation of ATP molecule.
Design a controlled experiment to test the effect of water temperature on goldfish. be sure to include your hypothesis, independent variable, dependent variable as well as experimental group and control group.
Answer:
In this experiment, indepedent variable will be temperature and dependent variable will be the respiratory rate of goldfish. Temperature affects the respiratory rate of goldfish, as it's respiratory rate decreases with decrease in temperature of water, the experiment is as follows:
Take two glass containers filled with water A and B and put one goldfish in each container.Measure the temperature of the water using a thermometer.Count mouth movement of both the fishes in certain time.Now put some ice in container B that will decrease the temperature of water and measure the temperature again.Now count the mouth movement of both the fishes for the same time it was counted earlier.The result will be that respiratory rate of goldfish decreases with the decrease in temperature in container B in comparison to container A goldfish.
An experiment meant to determine the cause of an effect, the effect is the independent variable, while the cause is the dependent variable
A controlled experiment to test the effect of water temperature on goldfish is designed as follows:
The experimental group are: The gold fish in a glass Jar X filled with fresh water and with the lid left open (the treatment of temperature reduction is applied to the experimental group)
The control group are: A second gold fish (selected at random) of the same size, in another glass jar Y filled to the same level with fresh water collected from the same source of the first gold fish
Independent variable: The independent variable is the temperature of the water which will be varied by placing ice cube gradually into the glass jar B
Dependent variable: The number times the gold fish gulp air by rising to the surface, and or the number of time goldfish opens its mouth, which indicates that the goldfish is breathing
The hypothesis: The breath rate of goldfish decreases with decrease in temperature because the goldfish metabolic rate decreases and the water holds more dissolved air and therefore oxygen at a reduced temperature
The Experiment Design:
The experiment is conducted by measuring the initial temperature and breathing rate of both fishes
The temperature of the fresh water in jar X is decreased gradually by adding ice cubes and recording the temperature and breathing rate of the goldfish
A similar experiment from an online source (Maryland School improvement website) the following results where obtained
[tex]\begin{array}{|c|cc|} \underline {Breathing \ rate}&&\underline {Water \ Temperature } \\&&\\ (Dependent \ Variable)&&(Independent \ Variable)\ \\&&\\103&&78.8 ^{\circ}F\\78&&68^{\circ}F\\55&&57.2^{\circ}F\\28&&46.4^{\circ}F\\4&&35.6^{\circ}F\end{array}\right][/tex]
From the experiment, it can be seen that the in the experimental group dependent variable, which is the breathing rate of the goldfish reduces as the temperature which is the dependent variable is reduced
Learn more about experimental variables here:
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ABO blood type is examined in a Taiwanese population, and allele frequencies are determined. In the population,
f (IA) = 0.30,
f(IB) = 0.15, and
f (i) = 0.55.
What are the frequencies of the various genotypes and various phenotypes in this population? Assume Hardy-Weinberg equilibrium.
Answer and Explanation:
Due to technical problems, you will find the answer and explanation in the attached file.
why are g protein important for drug discovery?
Answer:
G protein - coupled receptors(GPCRs)n belong to a large family of signaling proteins that mediate cellular reponses to most hormones ,metabolites,cytokines and neuotransmitters and therefore serve as fritful targets for DRUGS DISCOVERYS.
Explanation: histamine(HRH1),serotonin dopamine,opiod and adrenergic receptors.
I HOPE IT'S HELPS YOU TO UNDERSTAND
Centrioles have pulled the chromosomes all the way to the spindle poles, the process of cleavage furrowing appears to be about to begin. What kind of a cell is this?
Answer:
An animal cell in the telophase
Explanation:
Telophase is one of the stages of cell division in animal cell .
In the animal cell during telophase, Centrioles have pulled the chromosomes all the way to the spindle poles, the process of cleavage furrowing appears to be about to begin because the nuclear membrane and nucleoli reform, cytokinesis is almost coming to completion and the chromosomes eventually uncoil to chromatin. Usually cytokinesis occurs during telophase.
What are some of the main characteristics of skeletal muscle cells that make them distinct from the other two types of muscle cells Why are these characteristics important for understanding the function of skeletal muscle?
Answer:
They are voluntary , require force and fast.
Explanation:
Main characteristics of skeletal muscle cells are given below:
1) these muscles are voluntary which means it can be controlled by the human.
2) skeletal muscles requires force for its movement.
3) movement of skeletal muscle is fast.
Due to its structure, skeletal muscle provide support to the body and the body is able to move from one place to another. It also provide protection to the delicate organs of the body. It is also used as a storage of minerals and fats.
____________ a regulatory protein that may bind DNA to inhibit transcription. ____________ a DNA sequence that binds a regulatory protein. ____________a DNA sequence that binds RNA polymerase and regulates transcription. ____________a compound that interacts with another protein or compound to form an active repressor ____________a compound that induces or activates transcription, such as lactose.a. Repressorb. Operator c. Promoterd. Corepressore. Inducer
Answer:
A repressor is a regulatory protein that may bind DNA to inhibit transcription. An operator is a DNA sequence that binds a regulatory protein. A promoter is a DNA sequence that binds RNA polymerase and regulates transcription. A corepressor is a compound that interacts with another protein or compound to form an active repressor. An inducer is a compound that induces or activates transcription, such as lactose.
Explanation:
Repressor proteins bind to DNA and RNA to suppress target gene expression. A DNA repressor blocks transcription by inhibiting the attachment of RNA polymerase to the promoter sequence, while an RNA repressor bind to the mRNA to block translation of the protein. An operator is a DNA sequence required for the attachment of transcription factors. The genes that are transcribed by the binding of a transcription factor to an operator sequence are collectively referred to as an operon. Operons are generally found in prokaryotes but they also can be found in some eukaryotes including Caenorhabditis elegans and Drosophila melanogaster. An inducer is a molecule that activates gene transcription either by binding to repressors/corepressors (thereby inactivating their functions) or by binding activators. For example, the allolactose act as an inducer of the lac operon.
What growth information leads to your answer? The colonies are able to grow on minimal medium containing no additional supplements. The colonies are able to grow on complete medium.
Answer:
A growth medium or culture medium is a solid, liquid or semi-solid designed to support the growth of a population of microorganisms or cells via the process of cell proliferation,[1] or small plants like the moss Physcomitrella patens.[2] Different types of media are used for growing different types of cells.[3]
The two major types of growth media are those used for cell culture, which use specific cell types derived from plants or animals, and microbiological culture, which are used for growing microorganisms, such as bacteria or fungi. The most common growth media for microorganisms are nutrient broths and agar plates; specialized media are sometimes required for microorganism and cell culture growth.[1] Some organisms, termed fastidious organisms, require specialized environments due to complex nutritional requirements. Viruses, for example, are obligate intracellular parasites and require a growth medium containing living cells.
A research team discovered that a novel hormone X stimulates an enzyme that hydrolyzes proteins in the small intestine. However, when hormone X was added to a test-tube mixture containing the enzyme and proteins, no breakdown occurred.
Required:
a. Why is this the case?
b. Name ONE signal transduction pathway that hormone X is using to transfuse its signal. (write all the steps and intermediates)
Answer:
a. It is a hormone that acts upstream in the signaling pathway (i.e., acting as a ligand by binding to cell receptors)
b. Dopamine-mediated pathways
Explanation:
It is well known that many cellular transduction pathways are activated via binding of signaling molecules (ligands) to receptors capable of triggering signaling cascades into the cell. For example, dopamine is a signaling hormone (neurotransmitter) involved in diverse brain processes (i.e., motor control, emotional response, etc). It is a neurotransmitter that binds to dopamine receptors and then stimulates the enzyme adenylate cyclase in a process that subsequently activates the production of the second messenger cyclic adenosine monophosphate (cAMP). Finally, cAMP acts as an intracellular signal transductor that play roles in many biological processes by transferring into the cell the effects of dopamine.
Why are so many of the same genes found in almost all living organisms
Answer:
Molecular homology occurs when different species inherit similar molecules, such as nucleic acids or proteins, from an evolutionary common ancestor. In many cases, especially for essential housekeeping genes involved in protein synthesis or DNA replication, genes are homologous across most, if not all, living organisms. Hope this helps!
Explanation:
The main function of a cell membrane is to allow substances to enter and leave the cell. Which is a correct description of transport through a cell membrane
Answer:
The question is incomplete, below is the completed question:
The main function of a cell membrane is to allow substances to enter and leave the cell. Which is a correct description of transport through a cell membrane ?
a. Diffusion, or passive transport, occurs when molecules diffuse from a lower concentration to a higher concentration.
b. Facilitated transport occurs when proteins that extend through the cell membrane provide a channel through which certain substances can diffuse more rapidly than by passive diffusion.
c. The lipid bilayer opens up and allows the ions or molecules to enter the cell, then closes.
d. Active transport occurs when molecules diffuse from a higher concentration to a lower concentration.
Answer:
b. Facilitated transport occurs when proteins that extend through the cell membrane provide a channel through which certain substances can diffuse more rapidly than by passive diffusion.
Explanation:
Transport through cell membranes can be broadly classified as active transport or passive transport.
Active transport requires energy in the form of ATP for the transportation of substances across the cell membrane.
Option b correctly describes facilitated diffusion, which is a passive-mediated diffusion process, where channels in the cell membrane mainly composed of proteins called transmembrane integral proteins, allow for the movement of certain molecules (mostly polar/hydrophilic) molecules that will not otherwise be transported through simple diffusion because of the hydrophobic nature of the cell membrane.
The other options are wrong because:
a. diffusion or simple transport involves the movement of substances from regions of higher to a lower concentration not lower to higher as suggested here.
c. The lipid bi-layer does not allow ions or hydrophilic molecules because it is hydrophobic in nature, and it is not a channel, so it does not open and closes
d. In active transport, transfer of molecules is from regions of lower to higher concentration and not higher to lower concentration as suggested here.
Is the talc renewable?
Answer:
no.its nonrenewable.
talc is nonrenewable.
thanks.
What percentage of the nation’s demand for electricity could be produced in the future by wind energy?
Answer:
5-10%
hope this is helpful
The diagram represents a food pyramid. The concentration of the pesticide DDT in individual
organisms at level D is higher than the concentration in individuals at level A because DDT is
A. produced by organisms at level C ingested by
those in level D
B. passed through levels A, B, and C to organisms
at level D.
C. excreted by organisms at level A as a toxic
waste.
D. synthesized by organisms at level D.
Answer:
The answer is "Choice b".
Explanation:
In the given question diagram is missing. so first, we define the diagram after that we explain why the above given choice is correct.
In the attached file the food pyramid can be a divide into the level, in which the D pesticides use the "dichloro-diphenyl-trichloroethane ", which concentration is higher than its entities from the level of A because DDT is transferred with species at level D by levels A, B, and C, that's why the choice "b" is correct.
A student did an experiment with two identical fish tanks, Tank 1 and Tank 2. About 20 ml water purifier was added to Tank 1 and 10 ml
water punfier was added to tank 2. Tank 1 was heated to 88° F and Tank 2 was left at room temperature. The water purity of each tank was
tested every day in particles per liter. The purity was recorded over a period of 5 weeks in the table shown below.
Week Water Purity of Tank 1 Water Purity of Tank 2
12.6
12.6
13.7
13.9
14.3
14.4
15.7
15.8
17.6
17.6
Based on the table, which of these conclusions is correct?
a
Fish need 10 mL of water purifier to survive.
b
More purifier is needed to keep heated water clean.
с
Water purifier can help a fish survive longer.
d
Water purifier keeps fish tanks clearer for longer.
pleasee helppp !!
Answer:
a . Fish need 10 ml of water purifier to survive.
Explanation:
Fish need 10 ml of water purifier to survive because the data of 10 ml and 20 ml purifier is the same so it is recommended to use 10 ml purifier. First the data was same but by recording next week data, it shows slightly increase in the value of tank 2 while in the last week, both has the same value so we can concluded that by using 10 ml purifier is enough for the fish to survive.
Answer:
Its B/More purifier is needed to keep heated water clean.
Explanation:
g dGDP is made from ________ by the ribonucleotide reductase. This enzyme is inactive when ______ is bound to its master regulatory pocket.
Answer:
1. GTP dephosphorylation
2. hydrolyzed or removed
Explanation:
GDP, (Guanosine diphosphate) is a biological term, that is made of composition including pyrophosphate group, a pentose sugar ribose, and the nucleobase guanine and it is made from GTP ( Guanosine triphosphate ) dephosphorylation by the ribonucleotide reductase. This enzyme is inactive when hydrolyzed or removed, and then eventually bound to its master regulatory pocket.
What are the
traditional
circulatory
endpoints of
resuscitation
in shock?
Explanation:
traditional circulatory endpoints of resuscitation in shock include hypertension,tachycardia,decreased mentation and urine output
Which of the following properties is the temperature at which a liquid turns to gas? (3 points)
оа
Magnetism
Ob
Thermal conductivity
ос
Melting point
Boiling point
Od
thermal conductivity
Answer:
Boiling point
Explanation:
I did the test
What complications might arise from genetic screens targeting an organ that differentiates late in development?
Answer:
No sign of testicular development in boys and breast development in girls.
Explanation:
Complications like no sign of testicular development in boys and breast development in girls occurs if an organ develop very late. There are many causes of this type of complications such as long term illness, eating improper food and disorder of sexual development. Sometime these complications also occurs due to genetically. These complications should be treated well with medication and use of nutritious food. These medicines increases the performance of sex hormones in order to initiate puberty.
RNA polymerase is an enzyme that copies (1 point)
o DNA into DNA.
O RNA into mRNA
O mRNA into tRNA.
DNA into RNA
Answer:Copies DNA into RNA
Explanation:
PLEASE ANSWER QUICK!The Greek roots of the word prokaryote mean “before nucleus.” Describe the way that DNA is organized in prokaryotic cells without the help of a nucleus. How does this approach differ from the way that eukaryotic cells organizes their DNA
Answer:
Prokaryotic cells' DNA are located in the cytoplasm of the cell rather than in the nucleus, like in eukaryotic cells. DNA aids in protein synthesis and determines functions of the cell in cells, regardless of being within the membrane of a nucleus or not.
-----
I hope this helps a little.
The word prokaryote in Greek means before kernel (nucleus). Unlike the eukaryotic cells, the nuclear material is located in the cytoplasm of the cell in a nucleoid.
What are the characteristics of prokaryotic cells?The prokaryotic cells are the primitive karyons that are defined by the lack of the true nucleus and organelles. Unlike the eukaryotes, the organelles lack the membrane that covers them but has a tough cell wall.
The prokaryotes include archaea and bacteria which are unicellular and microscopic organisms that are simple and have their genetic material organized into nucleoids in the center of the cell. They have the ability to live in harsh conditions.
Therefore, the eukaryotes and prokaryotes differ in the arrangement of the genetic material.
Learn more about prokaryotes, here:
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Characteristics of Living Things
7. The basic unit of organization of living things is a(n)
A. atom B. organism
C. cell
D. organ
8. Storing energy obtained from food is an example of
A. evolution B. homeostasis
C. response
D. growth
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9. The passing of genes from one generation to another is
A homeostasis
B. response
C. growth D. heredity
10. The main function of reproduction is to
A. have enough male and female to reproduce
B. overpopulate
D. to be able to replace themselves.
C. grow
11. The milkweed plant feeding the caterpillar is an example of
A. interdependency.
C. preparing to die after a long life.
B. reproduction
D. heredity
12. Adaptation is very important to species because it allows them to
A. grow and become successful
C. Die
B. produce offspring better equipped to survive.
D. produce many offspring.
Answer:
bbbc
Explanation:
all of these were to long so
assuming hardy weinberg equilibrium what is the probability that sarah who is phenotypically normal with no family history and tom
Answer:
The probability of having a disorder is 50 %.
Explanation:
The offspring has that genetic disorder if the Sarah who is phenotypically normal with no family history and tom has a genetic disorder so there is 50 percent chance that the children of Sarah and tom has that genetic disorder. if the disorder linked with Y chromosome of male so this disorder is present in the sons but if the disorder linked with X chromosome of male so this disorder is present in the daughters.
b) How will you describe any three (3) major components of the environment to a named
class puyil?
Answer:
Hydrosphere, atmosphere and biosphere are the three major components of the environment.
Explanation:
Hydrosphere, atmosphere and biosphere are the three major components of the environment. hydrosphere refers to water bodies such as ocean, sea, ponds and lakes etc that is present in our environment. atmosphere refers to the gaseous layer which is present above the earth surface. in this layer oxygen, nitrogen and carbondioxide etc are present. biosphere refers to all living organisms such as human, animals, plants and microbes etc which are present on earth surface..
Studies of the relative efficacy or nonefficacy of a drug based on specific genotypes would be considered part of the field of
Answer:
Personalized genomic medicine
Explanation:
Personalized genomic medicine is a field that uses genomics data to develop personalized technologies and therapies for clinical care. All people share a sequence homology level higher than 99%; however a very small fraction of the genome (lesser than 1%) contains genetic polymorphisms among individuals, and this variation is associated with the likelihood of suffering diseases, either by increasing or by reducing disease susceptibility. Personalized genomic medicine first identifies genetic variations and then develops new strategies and personalized drugs to treat genetic disorders.
On April 26, 1986, Reactor 4 at the Chernobyl Nuclear Power Station in Ukraine exploded, releasing radioactive isotopes into the air. The majority of the isotopes that were released and spreading thousands of miles were of the element iodine. As a class, discuss what endocrine glands would be most affected and how it would become apparent in the nearby population.
Answer:
In the given case, the thyroid gland will be affected the most due to the exposure of the element iodine. For the synthesis of thyroid gland hormone, T3 and T4 iodine is required. As the exposure of the radioactive iodine element is taking place, therefore, it will result in the deterioration of the thyroid gland. Radioactive iodine is generally used in the treatment of hyperthyroidism.
However, in normal individuals, the exposure of the radioactive iodine element results in a decrease in the level of thyroid hormones below the normal level due to the destruction of the thyroid cells. The symptoms seen can be neck tenderness, swollen salivary gland, and loss in body weight.
The thyroid gland will be mostly affected in this case. The element Iodine is
the major precursor which is involved in the formation of two hormones.
Thyroid hormonesTriiodothyronine (T3)Thyroxine (T4).When an individual is exposed to radioactive iodine , it alters the production
of the hormones which leads to series of effects such as:
Decreased metabolismLow body weightGoitre etc.Read more about Thyroid hormones here https://brainly.com/question/2469666
What makes up the backbone of a DNA molecule? nucleic acids RNA molecules sugars and phosphates ribose and deoxyribose
Answer:
sugars and phosphates
Explanation:
gradpoint
n your lab you are studying the genome of venomous rattlesnakes to find the gene which codes for their venom glands. You have two rattlesnakes, one rattlesnake has a mutation but can still produce venom. You compare his DNA to a normal rattlesnake. What type of mutation has occurred? Normal: AATCGCTACGCACGTCAG Mutated: TATCGCTACGCACGTCAG
Answer:
There are no options but the kind of mutation that occurred by carefully observing both sequences is:
POINT SUBSTITUTION MUTATION
Explanation:
Mutation is any change, whether small or big, in the nucleotide sequence of a gene (DNA). Mutation occurs from time to time in an organism either by a mistake during DNA replication or induced by a mutagen (mutation-causing substance). Mutation can be of different types depending on the effect on the mutant.
In this case of comparing the DNA sequence two rattle snakes, the sequences of the two snakes are:
Normal: AATCGCTACGCACGTCAG
Mutated: TATCGCTACGCACGTCAG
By carefully observing the two DNA sequences, one would realize that the only difference in the two sequences is the first nucleotide base. That is, in the normal sequence, th first base is Adenine (A) while in the mutated sequence, the first base is Thymine (T).
This type of mutation that involves only one nucleotide base is called POINT MUTATION. It can also be noticed that base "A" was changed "T". Hence, this is a type of SUBSTITUTION MUTATION because a single base was replaced by another in the sequence.
