Answer:
1.5 hours
Step-by-step explanation:
Translate the following into an algebraic expression: a The number that is 40% more than five more than a number a.
Answer:
x = a + 8
Step-by-step explanation:
x = The number that is 40% more than five more than a number a.
x = 40% more than 5 (plus a)
5 * 0.6 = 3
5+3 = 8
x = a + 8
please solve this fast
Answer:
69
Step-by-step explanation:
Find the measure of c.
Answer:
140°
Step-by-step explanation:
The circle has a central angle of 80. This means that the arc it intercepts is also 80°. Therefore, the rest of the circle not intercepted by the arc is 360-80=280°
Remember that inscribed angles have one-half of the arc-length it intercepts. We can see that Angle C intercepts the entire circle except for the arc intercepted by Angle O. Therefore, the arc intercepted by Angle C is 280°. This means that Angle C is the half of 280, or 140°.
The net of a right rectangular prism is shown below: Find the volume of the prism with the given net (in cubic inches).
Answer:
240 inches cubed
Step-by-step explanation:
Volume equals length times width times height. Imagine the net is folded into its shape. The product of the base, 6 x 10 = 60, and the height, 4, equals 240. Remember that each square accounts for two inches. Hope this helps.
Sue's ice cream has 6 more scoopsthan Tessa's ice cream cone.
Sue's ice cream cone has 9 scoops.
How many scoops are on Tessa's ice cream cone?
Answer:
Tessa has 3 ice-cream scoops
Step-by-step explanation:
A building casts a 33-m shadow when the sun is at an angle of 27° the vertical. How tall is the building to the
nearest meter? How far is it from the top of the building to the tip of the shadow?
Answer:
1. EF = 65m
2. DF = 73m
Step-by-step explanation:
1. EF = height of the building = h = 33 / tan 27 = 65m
2. DF = sqrt (65² + 33²) = 73m
The building is 64.76 meters long and 73 meters far from the top of the building to the tip of the shadow.
From the triangle DEF, we find the value of EF by using tan function.
tan function is a ratio of opposite side and adjacent side.
tan(27)= 33/FE
0.5095 = 33/FE
Apply cross multiplication:
FE=33/0.5095
FE=64.76
Now DF is the hypotenuse, we find it by using pythagoras theorem.
DF²=DE²+EF²
DF²=33²+64.76²
DF²=1089+4193.85
DF²=5282.85
Take square root on both sides:
DF=72.68
In a triangle the the sum of three angles is 180 degrees.
∠D + 27 +90 =180
∠D + 117 =180
Subtract 117 from both sides:
∠D =63 degrees.
Hence, the building is 64.76 meters long and 73 meters far from the top of the building to the tip of the shadow.
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f(x) = [tex]\sqrt{x+7} -\sqrt{x^2+2x-15}[/tex] find the domain
Answer:
x >= -7 ................(1a)
x >= 3 ...............(2a1)
Step-by-step explanation:
f(x) = [tex]\sqrt{x+7}-\sqrt{x^2+2x-15}[/tex] .............(0)
find the domain.
To find the (real) domain, we need to ensure that each term remains a real number.
which means the following conditions must be met
x+7 >= 0 .....................(1)
AND
x^2+2x-15 >= 0 ..........(2)
To satisfy (1), x >= -7 .....................(1a) by transposition of (1)
To satisfy (2), we need first to find the roots of (2)
factor (2)
(x+5)(x-3) >= 0
This implis
(x+5) >= 0 AND (x-3) >= 0.....................(2a)
OR
(x+5) <= 0 AND (x-3) <= 0 ...................(2b)
(2a) is satisfied with x >= 3 ...............(2a1)
(2b) is satisfied with x <= -5 ................(2b1)
Combine the conditions (1a), (2a1), and (2b1),
x >= -7 ................(1a)
AND
(
x >= 3 ...............(2a1)
OR
x <= -5 ................(2b1)
)
which expands to
(1a) and (2a1) OR (1a) and (2b1)
( x >= -7 and x >= 3 ) OR ( x >= -7 and x <= -5 )
Simplifying, we have
x >= 3 OR ( -7 <= x <= -5 )
Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.
PLS PLEASE HELP!!!!!!
Evaluate 18 + 4 ÷ 2 − 8. (5 points) 2 8 12 3
18 + 4 ÷ 2 − 8
Following PEDMAS, divide first:
18 + 2 -8
Now add and subtract to get the final answer:
18+2 = 20
20-8 = 12
The answer is 12
Answer:
12
Step-by-step explanation:
If 120 is divided into 3 parts which are proportional to 1, [tex]\frac{1}{2} [/tex], and [tex]\frac{1}{6}[/tex], what is the middle part?
[tex]k+\frac{k}{2}+\frac{k}{6}=120\\\\6k+3k+k=720\\10k=720\\k=72[/tex]
72,36,12
answer: 36
*PLEASE ANSWER TY* What is the density of a 50-gram pyramid with rectangular base 4 cm x 8 cm and height 10 cm?
Answer:
[tex]\frac{0.47 g}{cm^{3} }[/tex]
Step-by-step explanation:
→ First work out volume of pyramid using the formula [tex]\frac{lwh}{3}[/tex] where 'l' is the length, 'w' is the width and 'h' is the height
[tex]\frac{lwh}{3}[/tex] ⇔ [tex]\frac{4*8*10}{3}[/tex] ⇔ [tex]\frac{320}{3}[/tex] ⇔ 320 ÷ 3 = 106.666666667
→ Volume of pyramid = 106.666666667. Substitute this value into the density formula
Density = Mass ÷ Volume
Density = 50 ÷ 106.666666667
Density = 0.46875 to 1 decimal place is 0.47
Find the distance between (-5,-6) and (-3,-8 WILL GIVEBRANLIEST TO FIRST PERSON WHO AWNSES WITH EXPLANATION
Answer:
d = √8
d ≈ 2.82843
Step-by-step explanation:
Distance Formula: [tex]d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Simply plug in our coordinates into the distance formula:
[tex]d = \sqrt{(-3 + 5)^2+(-8 + 6)^2}[/tex]
[tex]d = \sqrt{(2)^2+(-2)^2}[/tex]
[tex]d = \sqrt{4+4}[/tex]
[tex]d = \sqrt{8}[/tex]
To find the decimal, simply evaluate the square root:
√8 = 2.82843
Answer:
[tex] \boxed{2 \sqrt{2} \: \: units}[/tex]Step-by-step explanation:
Let the points be A and B
A ( - 5 , - 6 ) ⇒ ( x₁ , y₁ )
B ( -3 , - 8 )⇒( x₂ , y₂ )
Now, let's find the distance between these two points:
AB = [tex] \mathsf{ \sqrt{ {(x2 - x1)}^{2} + {(y2 - y1)}^{2} } }[/tex]
Plug the values
⇒[tex] \mathsf{ \sqrt{( - 3 - ( - 5) )^{2} + {( - 8 - ( - 6))}^{2} } }[/tex]
When there is a ( - ) in front of an expression in parentheses, change the sign of each term in the expression
⇒[tex] \mathsf{ \sqrt{ {( - 3 + 5)}^{2} + {( - 8 + 6)}^{2} } }[/tex]
Calculate
⇒[tex] \mathsf{ \sqrt{ {(2)}^{2} + {( - 2)}^{2} } }[/tex]
Evaluate the power
⇒[tex] \mathsf{ \sqrt{4 + 4} }[/tex]
Add the numbers
⇒[tex] \mathsf{\sqrt{8} }[/tex]
Simplify the radical expression
⇒[tex] \mathsf{ \sqrt{2 \times 2 \times 2}} [/tex]
⇒[tex] \mathsf{2 \sqrt{2} }[/tex] units
Hope I helped!
Best regards!
The box plots display the same data set for the number of touchdowns a quarterback threw in 10 seasons of play. Including outlier: A number line goes from 5 to 30. The whiskers range from 5 to 29, and the box ranges from 18 to 26. A line divides the box at 21.5. Excluding outlier: A number line goes from 5 to 30. The whiskers range from 17 to 29, and the box ranges from 19 to 27. A line divides the box at 21. There is an asterisk at 5. Complete the statements describing the effect of the outlier on the measures of variability. The outlier of the data set is . The range of the data set including the outlier is more than the one excluding the outlier. The interquartile range of the data set including the outlier is more than the one excluding the outlier. The outlier had the most effect on the .
Answer:
5
12
0
range
Step-by-step explanation:
i just did it, these are the right answers.
Answer:
5,12,0, and the last answer is range
Step-by-step explanation:
Did it on Edge2021. Hope this helps!
for n prove by
[tex]3 + 3 {}^{2} + 3 {}^{3} ... + 3 {}^{n} = \frac{3(3 {}^{n} - 1) }{2} [/tex]
thank you
Answer:
[tex]3 + 3^2 + 3^3 ...+ 3^n = \frac{3(3^n - 1)}{2}[/tex]
Step-by-step explanation:
Given
[tex]3 + 3^2 + 3^3 ...+ 3^n[/tex]
Required
Show that the sum of the series is [tex]\frac{3(3^{n}-1)}{2}[/tex]
The above shows the sum of a geometric series and this will be calculated as shown below;
[tex]S_n = \frac{a(r^n - 1)}{r - 1}[/tex]
Where
a = First term;
[tex]a = 3[/tex]
r = common ratio
[tex]r = \frac{3^2}{3} = \frac{3^3}{3^2}[/tex]
[tex]r = 3[/tex]
Substitute 3 for r and 3 for a in the formula above;
[tex]S_n = \frac{a(r^n - 1)}{r - 1}[/tex] becomes
[tex]S_n = \frac{3(3^n - 1)}{3 - 1}[/tex]
[tex]S_n = \frac{3(3^n - 1)}{2}[/tex]
Hence;
[tex]3 + 3^2 + 3^3 ...+ 3^n = \frac{3(3^n - 1)}{2}[/tex]
Jen go to the skate park every other day Terry go to skate park every third date Carlos goes to the skate park only on Mondays and Tuesdays today is Monday, June 3 and all the kids are at the skate park on what day would they all be at the skate park again
Answer: Tuesday, July 9 (correct me if I'm wrong)
Step-by-step explanation:
Jen goes every other day, so she goes every odd day.
Terry goes every third day, so Jen and Terry go together every six days.
Six days later is Sunday June 9, then Saturday June 15, then Friday Jun 21, then Thursday June 27, then Wednesday July 3.
Carlos only comes Mondays and Tuesday, so the next six days would be Tuesday July 9.
The following dot plot shows the number of books each student checked out from the library last month. Each dot represents a different student. Which of the following is a typical number of books one student checked out?
Answer:
The answer isn't 1 because most of the students checked out more than 1 bookThe answer isn't 4 because most of the students checked out more than 4 booksThe answer isn't 12 because most of the students checked out fewer than 12 booksThe answer is 7 because most of the students checked out more books than 1, 4, and 12In 7, seven kids checked out 7. [tex]7*7=49[/tex] (Correct answer because 49 is the biggest number here)
In 1, only two kids checked out 1. [tex]1 *2=2[/tex] (Wrong answer because 2 is lower than 49)
In 4, only eight kids checked out 4. [tex]4*8=32[/tex] (Wrong answer because 32 is lower than 49)
In 12, only two kids checked out 12. [tex]12*2=24[/tex] (Wrong answer because 24 is lower than 49)
So 7 is the correct answer because [tex]7*7=49[/tex] is the greatest equation here.
The 0 and 11 number book is the typical book one student checked out.
Given, the dot plot shows the no. of book each student checked out from the library last month.
Since each dot represent a different student, so clearly from the dot plot the 8 number book is checked out by the most of the students because it has most of the dots.
Since the number 0 and 11 has only one dot it represent that only 1 student checked out these books last month.
Hence the 0 and 11 number book is the typical book one student checked out.
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Which function has a constant additive rate of change of –1/4? A coordinate plane with a straight line with a negative slope. The line passes through (negative 2, 2) and (2, 1). A coordinate plane with a curved line passing through (negative 1, 2), (0, negative 1), the minimum (2, negative 2), and (4, negative 1). A two column table with five rows. The first column, x, has the entries, 20, 21, 22, 23. The second column, y, has the entries negative 1, negative 1.5, negative 2, negative 2.5. A two column table with five rows. The first column, x, has the entries, negative 12, negative 11, negative 10, negative 9. The second column, y, has the entries, 7, 11, 14, 17.
Answer:
a) ◇G = ◇H - T◇S wiĺl be negative.
b) It will be a spontaneous reaction.
Explanation:
As ◇H is less than 0 and T◇S is greater than 0 so if we put it in the equation we would get the negative maximum result. And when the energies are with negative sign they are said to be spontaneous.
solve for m. √m-7 = n+3 It is worth like 40 points
Answer:
sqrt of (m-7) = n+3
m = (n+3)^2 + 7 or m= n^2 + 6n + 16
sqrt of (m)-7 = n+3
m = (n+10)^2 or m =n^2 + 20n + 100
Step-by-step explanation:
(2) move the constants to the other side, and square
or (1) square and move constants
then you can solve for m
Answer:
[tex]n^2+6n+16[/tex]
Step-by-step explanation:
I'm going to assume you meant [tex]\sqrt{m-7} = n+3[/tex], not [tex]\sqrt{m} - 7 = n+3[/tex].
[tex](\sqrt{m-7}) ^2 = (n+3)^2\\\\(\sqrt{m-7}^2) = (n+3)^2\\\\(m-7)^{\frac{2}{2} } = (n+3)^2\\\\m - 7 = (n+3)^2\\\\m - 7 = n^2 + 2n\cdot3 + 3^2\\\\m - 7 = n^2 + 6n + 9\\\\m - 7 + 7 = n^2 + 6n + 9 + 7\\\\m = n^2 + 6n + 16[/tex]
Hope this helped!
please help me.... The question no.b and would like to request you all just give me correct answer.
Answer: see proof below
Step-by-step explanation:
You will need the following identities to prove this:
[tex]\tan\ (\alpha-\beta)=\dfrac{\tan \alpha-\tan \beta}{1+\tan \alpha\cdot \tan \beta}[/tex]
[tex]\cos\ 2\alpha=\cos^2 \alpha-\sin^2\alpha[/tex]
LHS → RHS
[tex]\dfrac{2\tan\ (45^o-A)}{1+\tan^2\ (45^o-A)}\\\\\\=\dfrac{2\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)}{1+\bigg(\dfrac{\tan\ 45^o-\tan\ A}{1+\tan\ 45^o\cdot \tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)}{1+\bigg(\dfrac{1-\tan\ A}{1+\tan\ A}\bigg)^2}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{1+\bigg(\dfrac{1-2\tan\A+\tan^2 A}{1+2\tan A+\tan^2A}\bigg)}\\[/tex]
[tex]=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{(1+2\tan A+\tan^2A)+(1-2\tan A+\tan^2 A)}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\dfrac{2+2\tan^2A}{1+2\tan A+\tan^2A}}\\\\\\=\dfrac{2\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{2\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}\\\\\\=\dfrac{\bigg(\dfrac{1-\tan A}{1+\tan A}\bigg)}{\bigg(\dfrac{1+\tan^2A}{(1+\tan A)^2}\bigg)}[/tex]
[tex]=\dfrac{1-\tan A}{1+\tan A}}\times \dfrac{(1+\tan A)^2}{1+\tan^2A}\\\\\\=\dfrac{1-\tan^2 A}{1+\tan^2 A}\\\\\\=\dfrac{1-\dfrac{\sin^2 A}{\cos^2 A}}{1+\dfrac{\sin^2 A}{\cos^2 A}}\\\\\\=\dfrac{\bigg(\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A}\bigg)}{\bigg(\dfrac{\cos^2 A+\sin^2 A}{\cos^2 A}\bigg)}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{\cos^2 A+\sin^2 A}\\\\\\=\dfrac{\cos^2 A-\sin^2 A}{1}\\\\\\=\cos^2 A-\sin^2 A\\\\\\=\cos 2A[/tex]
cos 2A = cos 2A [tex]\checkmark[/tex]
*PLEASE ANSWER* Compare the volume of these two shapes,given their radii and heights are the same .
Answer:
The correct option is;
Left object volume = right object volume
Step-by-step explanation:
The shapes given in the question are two circular cones that have equal base radius and equal height
The formula for the volume, V of a circular cone = 1/3 × Base area × Height
The base area of the two shapes are for the left A = π·r², for the right A = π·r²
The heights are the same, therefore, the volume are;
For the left
[tex]V_{left}[/tex] = 1/3×π·r²×h
For the right
[tex]V_{right}[/tex] = 1/3×π·r²×h
Which shows that
1/3×π·r²×h = 1/3×π·r²×h and [tex]V_{left}[/tex] = [tex]V_{right}[/tex], therefore, the volumes are equal and the correct option is left object volume = right object volume.
Lara is x years old and her two best friends are (x-2) and (x+2). Write an expression for the square of Lara’s age and the product of ages of Lara’s best friends.
Please help with a detailed step by step thanks
Answer: x^2 + (x+2)(x-2)
Step-by-step explanation:
The caret ^ before the 2 indicates that the 2 is an exponent. It means "x squared"
If the keyboard doesn't allow exponents the caret is the thing to use.
The expression for the square of Lara’s age and the product of ages of Lara’s best friends is x² + (x-2)(x+2)
The first thing to do is to calculate the square of Lara's age and this will be:
= x × x = x²
The product of the ages of Lara’s best friends will be (x-2)(x+2).
Therefore, the expression that can be used to calculate the square of Lara’s age and the product of ages of Lara’s best friends is x² + (x-2)(x+2)
Read related link on:
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what is (8*8*8) * (8*8*8*8) in exponential form?
The exponent 7 tells us how many copies of "8" are being multiplied together.
The expression 8*8*8 is equal to 8^3, while 8*8*8*8 = 8^4
Multiplying 8^3 and 8^4 will have us add the exponents to get 8^7. The base stays at 8 the entire time.
The rule is a^b*a^c = a^(b+c) where the base is 'a' the entire time.
Answer:
8^ 7
Step-by-step explanation:
(8*8*8) * (8*8*8*8)
There are 3 8's times 4 8's
8^3 * 8^4
We know that a^b * a^c = a^ (b+c)
8 ^ ( 3+4)
8^ 7
In trapezoid ABCD, AB ∥ CD , m∠A=90°, AD=8 in, DC=9 in, CB=10 in, and ∠B is acute. Find DB.
Answer:
the length of DB is 17 in
Step-by-step explanation:
Consider the sketch attached.
We will draw an imaginary line from point C to met line AB at point E.
A right-angled triangle will now be formed between points CBE.
The dimensions of the right-angled triangle will be:
CB = 10 in
CE= 8 in
EB = unknown
We will now proceed to find out the length of side EB using the Pythagoras' theorem.
[tex]EB =\sqrt{CB^2 -CE^2} \\EB =\sqrt{10^2 -8^2} \\EB = 6 in[/tex]
From the shape, we can find out that another right-angled triangle is made between points DAB.
The dimensions of the triangle are:
DA= 8in
AB = 9 in + 6 in = 15 in
DB = unknown.
We will now proceed to find out the length of side DB using the Pythagoras' theorem.
[tex]DB =\sqrt{AD^2 +AB^2} \\DB =\sqrt{8^2 +15^2} \\DB = 17 in[/tex]
Therefore, the length of DB is 17 in
Name five fractions whose values are between 3/8 and 7/12
Answer:
convert them to decimasls
Step-by-step explanation:
convert thhem to decimals to make it easier
Answer:
1/2 2/4 4/8 6/12 9/18
Step-by-step explanation:
Please help need help asap please
Answer: The two choices with the square root of 2 will have irrational answers
Step-by-step explanation: By definition:
As long As you have normal fractions, you have rational numbers.
Square roots of "perfect squares" 4, 9, 16, 25, etc. can be rational numbers. The square roots of anything else and pi will be irrational.
Can someone please help me please and thanks.
Answer:
The probability of 3 students having blood type A is 1.23 , having blood type B is 0.3 and having blood type AB is 0.12
Step-by-step explanation:
Find the number set which satisfies each of the problems. If 7 is subtracted from the absolute value of the sum of a number and 6, the result is 3.
Answer:
x=4 or x= - 16
Step-by-step explanation:
|x+6|
Now subtract 7 which equals to 3.
|x+6|-7=3
|x+6|=10
Now remove the mode by adding plus minus sign in the front of 10.
x+6=±10
x+6=10 or x+6=-10
x=4 or x=-16
WILL GIVE BRAINLY!!!!!! NEED HELP ASAP!!!!!!!! what is the range of f(x)=3^x+9
Answer:
y > 9
Step-by-step explanation:
The range of a function is the interval of all possible y-values that make the function true.
Here, one way to figure this out is to look at a graph of the function (see attachment).
From the graph, we can see that y-values approach very closely the value 9 and then the line rises beyond 9 forever. Thus, we can conclude that the range for f(x) is y > 9.
~ an aesthetics lover
h(x+1)=x^2-4 evaluate function by substuting x+1
Answer:
h(x + 1) = (x+3)(x-1)
Step-by-step explanation:
Simply plug the value of x+1 into the equation for x.
h(x) = x^2 - 4
h(x + 1) = (x + 1)^2 - 4
h(x + 1) = x^2 + 2x + 1 - 4
h(x + 1) = x^2 + 2x - 3
h(x + 1) = (x+3)(x-1)
Cheers.
Answer:
h(t)= t² - 2t -3
Step-by-step explanation:
h(x+1)= x²-4 is the given function
We can write it x²-4 as:
(x+2)(x-2)= (x+1+1)(x+1 - 3)Substituting x+1 with t. Then function is:
h(t)= (t+1)(t-3)= t² - 2t -3or
h(t)= t² - 2t -3Find x: 50*5x=5000
A) 25
B) 20
C) 50
D) 75
Answer:
[tex]\huge\boxed{B) x = 20}[/tex]
Step-by-step explanation:
50 * 5x = 5000
Dividing both sides by 50
=> 5x = 5000/50
=> 5x = 100
Dividing both sides by 5
=> x = 20
Answer:
the answer is B
Step-by-step explanation:
X: (x)50=20
Question 5
Kate is finding the factors of a large number. Using
a calculator, she has just worked out that 66 is a
factor of this number.
Suddenly, she realises that 22 must be a factor of
the large number as well. Explain why Kate is
correct.
Explanation : If 66 is a factor of this unknown value, then 22 must be as well considering that 22 is a factor off 66. Let's say that this large value is 330. It is a multiple of 66, as 66 [tex]*[/tex] 5 = 330. At the same time 22 [tex]*[/tex] 15 = 330, so 330 is a multiple of 22 as well - or vice versa, 12 is a factor of 330.
We can also tell that 15, 22 fit into 330 through another approach. 22 [tex]*[/tex] 3 = 66, and 66 [tex]*[/tex] 5 = 330, so 5 [tex]*[/tex] 3 = 15 - the same value. This proves that 22 will always be a factor of a value that is the factor of 66.
