KINDLYY FASTT A uniform metre rule of mass 100 g is pivoted at the 60 cm mark. At what point on the meter rule should a mass of 50 g be suspended for it to balance horizontally?
Answers
Answer:
80 cm.
Explanation:
Since the metre rule is 1 m i.e 100 cm it means that the mass of the metre can be obtained at the 50 cm mark.
But the metre is pivoted at the 60 cm.
Please refer to the attached photo for details.
In the attached photo, y is the distance between the mark (that will balance the metre rule when a 50 g mass is hunged) and the pivot.
Thus, we can obtain the value of y as follow:
Anticlock wise moment = Clock wise moment
Anticlock wise moment = 100 × 10
Clock wise moment = y × 50
Anticlock wise moment = Clock wise moment
100 × 10 = y × 50
Divide both side by 50
y = (100 × 10) /50
y = 20 cm
Now, to obtain the mark, B that will balance the metre, we simply add 20 cm to 60 cm ie
B = 60 + 20
B = 80 cm
Related Questions
The model of the atom has changed as scientists have gathered new evidence. Four models of the atom are shown below, but one important model is missing. An image at left with overlapping red and blue balls in the center with a circular fuzzy green cloud outside them. An image at center left with a purple ball in the center surrounded by overlapping concentric black ovals, each with a small green ball on each of the 6 ovals. An image at center right with a large black cross in a purple circle with a black line around the purple, with 10 small green balls dispersed within the purple circle. An image at right with a purple center outlined in black with two concentric black circles around the center, the inner circle having 2 small green balls on it and the outer circle having 8 small green balls on it. Which atomic model is missing from this set? Bohr’s model Dalton’s model Rutherford’s model Thomson’s model
Answers
Answer:
Thomson’s model
Explanation:
Thompson regarded the atom largely as a sphere of positively charged matter in which negative charges were embedded.
This came to be known as the plum pudding model of the atom because it resembles a pudding studded with currants.
This was an early model of the atom and did not survive further experimental scrutiny of the structure of the atom.
Answer:
Thompsons model
Explanation:
i got it right on the quiz
9. An object of weight 80kg on earth is taken to a
planet where the acceleration due to the gravity is one-
third of its value on earth. The weight of the object on
the planet is
Answers
Answer:
266. 4
Explanation:
acceleration due to vravity on earth is 10m/s.
One third of it is (1/3)*10
=3.333m/s.
Weight is mass × acceleration
weight= 80kg÷ 3.333m/s
W= 266.4 Newton.
Dennis throws a volleyball up in the air. It reaches its maximum height 1.1\, \text s1.1s1, point, 1, start text, s, end text later. We can ignore air resistance. What was the volleyball's velocity at the moment it was tossed into the air?
Answers
Answer:
If max height = 1.1 meters, then initial velocity is 3.28 m/s
If max height is 1.1 feet, then the initial velocity is 5.93 ft/s
Explanation:
Recall the formulas for vertical motion under the acceleration of gravity;
for the vertical velocity of the object we have
[tex]v=v_0-g \,t[/tex]
for the object's vertical displacement we have
[tex]y-y_0=v_0\,t - \frac{g}{2} \,t^2[/tex]
If the maximum height reached by the object is given in meters, we use the value for g in [tex]m/s^2[/tex] which is: [tex]9.8\,\,m/s^2[/tex]
If the maximum height of the object is given in feet, we use the value for g in [tex]ft/s^2[/tex] which is : [tex]32\,\,ft/s^2[/tex]
Now, when the ball reaches its maximum height, the ball's velocity is zero, so that allows us to solve for the time (t) the process of reaching the max height takes:
[tex]v=v_0-g \,t\\0=v_0-g \,t\\g\,\,t=v_0\\t=\frac{v_0}{g}[/tex]
and now we use this to express the maximum height in the second equation we typed:
[tex]y-y_0=v_0\,t - \frac{g}{2} \,t^2\\max\,height=v_0\,(\frac{v_0}{g}) - \frac{g}{2} \,(\frac{v_0}{g})^2\\max\,height= \frac{v_0^2}{2\,g}[/tex]
Then if the max height is 1.1 meters, we use the following formula to solve for [tex]v_0[/tex]:
[tex]1.1= \frac{v_0^2}{2\,9.8}\\(9.8)\,(1.1)=v_0^2\\v_0=10.78\\v_0=\sqrt{10.78} \\v_0=3.28\,\,m/s[/tex]
If the max height is 1.1 feet, we use the following formula to solve for [tex]v_0[/tex]:
[tex]1.1= \frac{v_0^2}{2\,32}\\(32)\,(1.1)=v_0^2\\v_0=35.2\\v_0=\sqrt{35.2} \\v_0=5.93\,\,ft/s[/tex]
Answer:
11
Explanation:
for khan academy, this is the answer
Answer answer answer it it it
Answers
Answer:
(B) Parachutes
Explanation:
Air resistance works to slow down trains and airplanes, so it isn't desirable. Air resistance also causes pendulums to slow and stop.
Parachutes need air resistance to slow a person's fall. So air resistance is desirable here.
Answer:
B i answered it it it
Explanation:
The probe used in a medical ultrasound examination emits sound waves in air that have a wavelength of 0.12 mm. What is the wavelength of the sound waves in the patient?a) 0.54 mm b) 0.12 mm c) 0.26 mm d) 0.027 mm
Answers
Answer:
0.54mm
Explanation:
Given the following :
Wavelength (λ) of Soundwave in air = 0.12mm
Velocity of sound wave (v) = 340m/s
Calculate the frequency (f) :
v = fλ
Wavelength to metres
1000mm = 1 m
0.12mm = (0.12/1000)m
= 0.00012m
v = fλ
340 = F * 0.00012
f = 340 / 0.00012
f = 2833333.3 Hz
Wavelength of Soundwave in the patient:
Velocity of sound wave through body tissue = 1540m/s
Therefore,
Using v = fλ
λ = v / f
λ = 1540 / 2833333.3
λ = 0.0005435m
λ = (0.0005435 * 1000)mm
λ = 0.5435mm = 0.54mm
The distance between neighbouring, identical wave components, such as adjacent compressions, determines a sound's wavelength. The number of waves passing a spot in a given amount of time is known as the frequency, which is the same as the source's frequency.
What wavelength of the sound waves in the patient?Wavelength (λ) of Soundwave in air = 0.12 mm
Velocity of sound wave (v) = 340m/s
Calculate the frequency (f) :
v = fλ
Wavelength to metres
1000 mm = 1 m
0.12 mm = (0.12/1000)m
= 0.00012 m
v = fλ
340 = F × 0.00012
f = 340 / 0.00012
f = 2833333.3 Hz
Wavelength of Soundwave in the patient:
Sound waves travel through body tissue at a speed of 1540 m/s.
Therefore, Using v = fλ
λ = v / f
λ = 1540 / 2833333.3
λ = 0.0005435m
λ = (0.0005435 × 1000)mm
λ = 0.5435mm = 0.54 mm
Learn more about wavelength here:
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A ship sets out to sail to a point 123 km due north. An unexpected storm blows the ship to a point 112 km due east of its starting point. (a) How far and (b) in what direction (as an angle from due east, where north of east is a positive angle) must it now sail to reach its original destination
Answers
Answer:
Explanation:
We shall represent the point of destination and point of new starting point in vector form .
i and j will represent east and north .
point of destination = 123 j
starting point = 112 i
distance between the two
D = 123 j - 112 i
magnitude of D = √ ( 123² + 112² )
= 166.35 km
Direction of D
Tanθ = - 123 / 112
= - 1.09
θ = 132.54 degree from east in positive angle .
20 pts. What type of forces do not change the motion of an object? Acceleration forces Balanced forces Inertia forces Unbalanced forces
Answers
Answer:
Balanced forces
Explanation:
Answer:
its balance force
Explanation:
An iron ball at 40°C is dropped in a mug containing water at 40°C.
The heat will
(a) flow from iron ball to water.
(b)
not flow from iron ball to water or from water to iron ball
(c)
flow from water to iron ball
(d) increase the temperature of both
10. A wooden spoon is dipped in a cup of ice cream. Its other end
(a) becomes cold by the process of conduction.
(b) becomes cold by the process of convection
(c) becomes cold by the process of radiation.
(d) does not become cold.
Answers
Answer:
1. option a
2. option d
Explanation:
HOPE IT HELPS YOU
You are hiking in a canyon and you notice an echo. You decide to let out a yell and notice it took 2 seconds before you heard the echo of your yell. How far away is the canyon wall that reflected your yell
Answers
Answer:
d = 343 m
Explanation:
Given that,
You notice that an echo took 2 seconds before you heard the echo of your yell.
We need to find that how far away is the canyon wall that reflected your yell. It means we need to find the distance.
The distance covered by an object is given by :
d = v × t
v is speed of sound in air, v = 343 m/s
The sound took 1 s to reach the wall and 1 s back to you.
It means that,
d = 343 × 1
d = 343 m
So, canyon will reflect your yell at a distance of 343 m
Air contains 78.08% nitrogen, 20.095% oxygen, and 0.93% argon. a sample of air occupies 8 l at 273 k and applies a pressure of 2.45 atm to its container. the sample of air is heated to 550 k, at which time it takes up 11.8 l. what is the partial pressure of nitrogen after the air has been heated
Answers
Answer:
the partial pressure of nitrogen after the air has been heated is 2.61atm
Explanation:
Using combined gas law which is the combination of Boyle's Law and Charles' Law, and it gives The relationship between pressure, volume, and absolute temperature
PV/T= K
P1₁V₁/T₁=P₂V2₂/T₂
P₂=final pressure= ?
P₁= initial pressure=2.45 atm
.T₁= initial temperature= 273k
T₂= final temperature= 550 K,
We can make P₂ subject of the formula then we have
P₂=P₁V₁T₂/T₁T₂
=( 2.45×8×550)/(273×11.8)
P2=3.35atm
Now we can calculate the partial pressure of N₂
N₂= 3.35×(78.08/10)
=2.61atm
Therefore, the partial pressure of nitrogen after the air has been heated is 2.61atm
Velocity is a description of an object’s _____.
Answers
Answer:
speed
Explanation:
Will mark as BRAINLIEST.... Plz answer the 44. Ques
Answers
Answer:
T= 2.66 seconds
Explanation:
Convert 80 km to m, which would be 0.08 m
[tex]t = d \div s[/tex]
[tex]t = 0.08 km\div 108kmph[/tex]
[tex]t = 0.00074074074 \: h[/tex]
[tex]1 \: hour = 3600 \: sec[/tex]
[tex] \frac{1}{3600} \times \frac{0.00074}{x} [/tex]
[tex]0.00074074074h \times 3600s = 2.66s[/tex]
A force of 20N changes the position of a body. If mass of the body is 2kg, find the acceleration produced in the body.2. A ball of mass 500g is thrown upwards with a velocity of 15m/s. Calculate its momentum at the highest point.
Answers
Explanation:
Hello there!!!
You just need to use simple formula for force and momentum,
F= m.a
and momentum (p)= m.v
where m= mass
v= velocity.
a= acceleration .
And the solutions are in pictures.
Hope it helps..
A body with an initial velocity of 10m/s has an acceleration of 8m/s^2. Determine graphically the velocity after 5 seconds, & the distance travelled in that time. Verify your answer using the equations of motion.
Answers
Answer:
From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table
Please find attached the graph
Explanation:
The initial velocity of the body = m/s
The acceleration of the body = 8 m/s²
The velocity after 5 seconds can be determined graphically and by calculation as follows;
Graphically, we have the data points which can be found by the straight line relation v = u + a×t,
Where ,
a = The slope = 8 m/s²
u = 10 m/s = The y-intercept
Which gives;
v = 10 + 8 × t
The following data can be calculated for various time t;
Time, t Velocity , v
0, 10
1, 18
2, 26
3, 34
4, 42
5, 50
6, 58
From the graph, at t = 5 seconds, the velocity = 50 m/s as shown also in the above table
Please find attached the graph
By calculation, we have;
v = u + a×t
Where;
v = The final velocity
u = The initial velocity = 10 m/s
a = The acceleration = 8 m/s²
t = The time = 5 seconds
v = 10 + 5× 8 = 50 m/s.
The length and breadth of rectangular sheet of metal are 4.234m, 1.005,
and 2.01cm respectively.
Give the area and volume of sheet to correct significant figures..
Answers
Answer:
The area of the sheet of metal = 4.255 m²
The volume of the sheet of metal = 0.08553 m³
Explanation:
The area of a rectangle is given by the following relation;
Area, A = Length × Breadth
Therefore, the area of the rectangular sheet of metal, A[tex]_m[/tex], is given as follows;
A[tex]_m[/tex] = 4.234 m × 1.005 m = 4.255 m²
The area of the sheet of metal = 4.255 m²
The volume of the metal sheet id given by the relation, volume V[tex]_m[/tex]= area × Thickness
The thickness of the sheet of metal = 2.01 cm = 0.0201 m
Therefore,
V[tex]_m[/tex] = 4.255 m × 0.0201 m = 0.08553 m³
The volume of the sheet of metal = 0.08553 m³.
Answer:
Are yarr mei bhi Indian hu.....
Explanation:
Tumse milkar accha laga
Pls help promise to mark as brainlist
Answers
Answer:
The answers to your questions are given below
Explanation:
A. Definition of momentum.
Momentum of an object can be defined as the product of the mass of the object and its velocity. Mathematically, it expreessed as:
Momentum = mass x Velocity
From the above equation, we can derive the SI unit of momentum as follow:
Mass is measured in Kilogram (Kg)
Velocity is measured in meter per second (ms¯¹).
Momentum = mass x Velocity
Momentum = Kg x ms¯¹
Momentum = Kg•ms¯¹
Therefore, the SI unit of momentum is Kg•ms¯¹.
Bi. Determination of the force of the body from O to A.
Mass (m) = 5 kg
Velocity (v) = 40 ms¯¹
Time (t) = 2 secs.
Force (F) =?
Next, we shall determine the acceleration of the body.
Acceleration (a) = Velocity (v) /Time (t)
a = v /t
Velocity (v) = 40 ms¯¹
Time (t) = 2 secs.
Acceleration (a) =.?
a = v/t
a = 40/2
a = 20 ms¯²
Now, we can obtain the force as follow:
Mass (m) = 5 kg
Acceleration (a) = 20 ms¯²
Force (F) =?
Force (F) = mass (m) x Acceleration (a)
F = ma
F = 5 x 20
F = 100 N
Therefore, the force of the body from O to A is 100 N.
Bii. Determination of the force of the body from B to C.
Mass (m) = 5 kg
Velocity (v) = 40 ms¯¹
Time (t) = 10 – 6 = 4 secs.
Force (F) =?
Next, we shall determine the acceleration of the body.
Acceleration (a) = Velocity (v) /Time (t)
a = v /t
Velocity (v) = 40 ms¯¹
Time (t) = 4 secs.
Acceleration (a) =.?
a = v/t
a = 40/4
a = 10 ms¯²
Now, we can obtain the force as follow:
Mass (m) = 5 kg
Acceleration (a) = 10 ms¯²
Force (F) =?
Force (F) = mass (m) x Acceleration (a)
F = ma
F = 5 x 10
F = 50 N
Therefore, the force of the body from B to C is 50 N.
An emf of 22.0 mV is induced in a 519-turn coil when the current is changing at the rate of 10.0 A/s. What is the magnetic flux through each turn of the coil at an instant when the current is 3.70 A?
Answers
Answer:
[tex]\phi=1.56\times 10^{-5}\ Wb[/tex]
Explanation:
Given that,
Emf, V = 22 mV
Number of turns in the coil us 519
Rate of change of current is 10 A/s.
We need to find the magnetic flux through each turn of the coil at an instant when the current is 3.70 A.
Let's find the inductance first. So,
[tex]L=\dfrac{\epsilon}{(dI/dt)}\\\\L=\dfrac{0.022}{10}\\\\L=0.0022\ H[/tex]
We have,
[tex]L=\dfrac{N\phi}{I}[/tex], [tex]\phi[/tex] is magnetic flux
[tex]\phi=\dfrac{LI}{N}\\\\\phi=\dfrac{0.0022\times3.7}{519}\\\\\phi=1.56\times 10^{-5}\ Wb[/tex]
So, the magnetic flux is [tex]1.56\times 10^{-5}\ Wb[/tex].
A 970-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked, and the two cars skid forward 2.9 m before stopping. The police officer, estimating the coefficient of kinetic friction between tires and road to be 0.80, calculates the speed of the sports car at impact.
Answers
Answer:
22.73 m/s or 81.72 kph
Explanation
We can find the combined mass of both cars as
970 kg + 2300 kg = 3270 kg.
Then the normal force of the cars can be calculated as
F(n)= mg
Where g is acceleration due to gravity 9.8m/s^2
3270 kg ×9.8 = 32046 kg*m/s^2.
coefficient of kinetic friction between tires and road to be 0.80 × F(n)
Then the frictional force can be calculated as
= (32046kg*m/s^2 × 0.80 )
= 25636.8 kg*m/s^2
We can now calculate the work done that was used stopping the cars as
Frictional force × distance
(25636.8 kg*m/s^2 ) × 2.9m= 74346.72kg*m^2/s^2
From kinetic energy formula, the combined velocity of the car can be determined
E=0.5 M V²
√(2E/M) = V
√(2*74346.72kg*m^2/s^2 / 3270 kg) = V
V= √ (45.472)
V=6.743293m/s
the momentum of both cars can be determined as
6.743293m/s * 3270 kg
= 22050.57kg*m/s
Now the final momentum of both cars must be equal to the the momentum of
the sports car just prior to the collision. Therefore, the speed of the sports car at impact.
=(22050.57 kg*m/s) / 970 kg = 22.73 m/s
We can convert that to km/h.
22.73 m/s * 3600 s/h / 1000 m/km = 81.72 kph
Which of the following illustrates an increase in potential energy? Group of answer choices a wind-up toy winding down a person climbs a set of stairs an apple dropping from a tree a firecracker explodes
Answers
Answer:
A person climbs a set of stairs
Explanation:
Potential energy is said to be possessed by an object due to its position. As the height from the ground level increase, the potential energy increases. It is calculated by the below formula as :
P = mgh
Out of the given options, the option that illustrates an increase in potential energy is option (b) i.e. a person climbs a set of stairs. As he steps one stair, its position from ground increases. It means its potential energy increases.
Match the following:
Tailored software
. Utility software
Operating system
Software
Packaged software
Set of programs
Library management system
Scan viruses
Microsoft Office
used to coordinate the hardw
the computer
Answers
Answer:
1) Tailored software Library management system
2) Utility software Scan viruses
3) Operating system Used to coordinate the hardware of the computer
4) Packaged software set of programs Microsoft office
Explanation:
1) A tailored software, also known as a custom software, is one that is designed and tailor-made only for a particular organisation
2) A utility software is a computer maintenance and analysis software used to enable proper functioning of the computer by performing restorative and maintenance tasks
3) Operating system software
The operating system software controls the operation of the computer hardware within the system and enables the operation of other programs in the computer
4) Packaged software are a collection of programs that are oriented to perform interrelated tasks that a focused to a particular area, such as Microsoft Office.
with solutions please give with solution
if u give me with solution I will mark in brainlist
Answers
Answer:
Magnitude of Force : 0.8 N
Explanation:
We know that the velocity of this particle changes from 15ms⁻¹, or in other words 15m / s, to the respective velocity 25m / s over the course of 2.5 seconds. Given this information we can determine the acceleration of the particle,
a = v₁ - v₂ / t = 25 - 15 / 2.5 = 10 / 2.5 = 4m / s²
Knowing the acceleration we can calculate the magnitude of the force using the formula f = ma - Newton's second law of motion,
f = m [tex]*[/tex] a = 200g [tex]*[/tex] 4m / s² = 800 g [tex]*[/tex] m / s²
Remember however that Newtons are in the standard units kg [tex]*[/tex] m / s². Therefore we have to convert 800 g to kg to receive our solution,
800 g = 800 / 1000 kg = 0.8 kg,
Magnitude of Force = 0.8 N ; Solution = Option B
A series combination of 12 Ω and 3 Ω is connected in parallel with another series combination of 6 Ω and 3 Ω. If a potential difference of 4 V is applied across it find the i) current is drawn from the battery ii) current through 12 Ω resistor (iii)potential difference across 6 Ω resistor?
Answers
Answer:
a) 0.73A
b) 0.23A
c) 2.76V
Explanation:
We need to first resolve the two resistors in series. The resistors in series are
12 Ω and 3 Ω AND 6 Ω and 3 Ω
For 12 Ω and 3 Ω in series, total effective resistance = 12 Ω + 3 Ω = 15 Ω
For 6 Ω and 3 Ω in series, total effective resistance = 6 Ω + 3 Ω = 9 Ω
Since the equivalent series resistors i.e 15Ω ND 9Ω are connected in parallel, the total effective resistance Rt will be expressed as;
1/Rt = 1/15+1/9
1/Rt = (3+5)/45
1/Rt = 8/45
Rt = 45/8 Ω
a) If a potential difference of 4 V is applied across it, the total current I in the circuit can be derives using the ohms law.
According to the law E = IRt
Given E = 4V, Rt = 45/8
I = E/Rt
I = 4/(45/8)
I = 4 * 8/45
I = 32/45
I = 0.73A
Hence, the current drawn from the battery is 0.73A
b) Before we can calculate the current in the 12Ω resistor, we need to calculate the current in the equivalent resistance of 15Ω(sum of 12Ω and 3Ω)
Current in the 15Ω resistor = Voltage across the 15Ω resistor/Resistance
Current in the 15Ω resistor = 4/15
Current in the 15Ω resistor = 0.27A
Since the same current flows in a series connected resistors, hence the correct in the 12ohms resistor is also 0.27A.
c) Before we can calculate the pd across the 6ohms resistor, we need to know the voltage across the effective resistance of 9ohms(6ohms+3ohms). The pd across the 9ohm resistance will be the same as the source voltage i.e 4Volts.
We will need to share this 4volts between the 6ohms and the 3ohms using ohms law.
According to the law, V = IR
For the 6ohms resistor, voltage across it will be;
V = (0.73-0.27)×6
V= 0.46×6
V = 2.76Volts.
Hence the voltage across the 6ohms resistor is 2.76V.
A 30-µF capacitor is charged to an unknown potential V and then connected across an initially uncharged 10-uF capacitor. If the final potential difference across the .10-µF capacitor is 20 V, determine V
Answers
Answer:
V = 26.6 volts
Explanation:
Let Initial Potential Difference be V.
Charge (Q) accumulated in 30 mF Capacitor =
Q = C * V
Q= 30 * V
Now, Common Potential after connecting to uncharged 10mF capacitor in parallel = 20 Volt
Total Charge =Total Capacity * Common Potential
30 * V = ( 30 + 10) * 20
V = 26.6 volts
The unknown potential across the 30-µF capacitor is 6.67 V.
The given parameters;
initial capacitance of the capacitor, C = 30 µFunknown potential in the 30 µF capacitor = V₁potential difference in 10 µF capacitor = 20 VSince the potential difference between the two capacitors are different, the two capacitors are in series connection.
In series circuit arrangement, the quantity of charge flowing in each capacitor is the same.
[tex]Q_{30\ \mu F} = Q_{10 \ \mu F}[/tex]
[tex]Q_{10 \ \mu F} = CV = 10\times 10^{-6} \times 20 = 0.0002 \ C[/tex]
The potential difference are different and the total potential is given as;
[tex]V_{T} = V_1 + V_2\\\\V_1 = \frac{Q}{C_1} \\\\V_2 = \frac{Q}{C_2} \\\\V_1+V_2 = \frac{Q}{C_1} + \frac{Q}{C_2}\\\\V_1 + V_2 = Q(\frac{1}{C_1} + \frac{1}{C_2} )\\\\V_1 + 20 = Q(\frac{1}{C_1} + \frac{1}{C_2} )\\\\V_1+ 20 = \frac{Q(C_2+ C_1)}{C_1 C_2} \\\\V_1 = \frac{Q(C_2+ C_1)}{C_1 C_2} - 20[/tex]
[tex]V_1 = \frac{0.0002(10\times 10^{-6}\ + \ 30\times 10^{-6})}{(30\times 10^{-6}) (10\times 10^{-6})} - 20\\\\V_1 = \frac{8\times 10^{-9}}{3\times 10^{-10}} - 20\\\\V_1 = 26.67 - 20\\\\V_1 = 6.67 \ V[/tex]
Thus, the unknown potential across the 30-µF capacitor is 6.67 V.
Learn more here:https://brainly.com/question/23899758
Sound waves move the fastest through which medium?
Answers
Answer:
Sound travels fastest through solids.
Explanation:
This is because molecules in a solid medium are much closer together than those in a liquid or gas, allowing sound waves to travel more quickly through it. In fact, sound waves travel over 17 times faster through steel than through air.
Sound waves move the fastest through the solid. The speed of the sound wave in the liquid and gas is low,
What is sound wave?A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.
Solids transmit sound the fastest. Because the molecules in a solid medium are much closer together than in a liquid or gas, sound waves can move through it much faster.
Hence, sound waves move the fastest through the solid.
To learn more about the sound wave, refer to the link;
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famous comparative and superlative form
Answers
Answer:
comparative----more famous, superlative----- most famous
[tex]\huge{\fbox{\red{Answer:}}}[/tex]
Word Given :Famous
___________________✍
Comparative Form : more famous
Superlative Form : most famous
Hope you understand❣
A 30-cm long string, with one end clamped and the other free to move transversely, is vibrating in its second harmonic. The wavelength of the constituent traveling waves is:
Answers
Answer:
[tex]\lambda[/tex] = 40 cm
Explanation:
given data
string length = 30 cm
solution
we take here equation of length that is
L = [tex]n \times \frac{1}{4} \lambda[/tex] ...............1
so
total length will be here
[tex]L = \frac{\lambda}{2} + \frac{\lambda}{4}\\[/tex]
[tex]L = \frac{3 \lambda }{4}[/tex]
so [tex]\lambda[/tex] will be
[tex]\lambda = \frac{4L}{3}\\\lambda = \frac{4\times 30}{3}[/tex]
[tex]\lambda[/tex] = 40 cm
If an object floats, the volume of the displaced water is equal to the volume of the whole object. True or false?
Answers
Answer:
True
Explanation:
This is in fact what the Archimedes principle states, and what he used in the famous anecdote about finding if the crown of the King was really made of gold.
is work the same as power justify the statement
Answers
Answer: No
Explanation: Simply Power’s Si base unit is kgm^2s^-3 but work done‘s Si base unit is kgm^2s^-2.
So this itself proves that they arent the same!
Explain.
4. State the limitations of our senses to obtain accurate in
formation concerning
our environment.
Answers
Answer:
The limits of our senses are
Limits of Sight
Our vision field of view is 120° sideways and 135° vertically
Angular visual resolution is about an 1/60 of one degree
The presence of blind spots in the eyes
Limits of sound
The hearing range is within 20 - 20,000 Hz and our threshold hearing above 0 to 5 decibel of sound
Limits of taste
We have very limited sense of taste which is partly dependent on our sense of smell with little objectivity in distinguishing tastes
Sense of smell
The establishing of the effectiveness of human sense of smell is gauged on numerous parameters with certain tests being inconsistent, as such, it is difficult to clearly establish the effectiveness of the human sense of smell
In comparison with the sense of smell of other living things such as dogs, the human sense organ is comparatively low
Explanation:
please help ASAP.
these are examination questions ..
no nonsense answers .
i will mark as brainliest if you got it correct .
Answers
Answer:
1st question c part
2nd question c part
