Hello,
[tex]\displaystyle \int {-\dfrac{2}{3} \sqrt{(2-5x)^3}} \, dx \\\\\displaystyle=-\dfrac{2}{3}*\dfrac{-1}{5} \int {-5*(2-5x)^{\frac{3}{2} }} \, dx \\\\\displaystyle=\dfrac{4}{3}*(2-5x)^{\frac{5}{2} }+C[/tex]
using trig to solve for missing angle
The length of a spring varies directly with the mass of an object that is attached to it. When a 30-gram object is attached, the spring stretches 9 centimeters. Which equation relates the mass of the object, m, and the length of the spring, s?
A s= 3/ 10m
B s= 10/3m
C m=3/10s
D m=1/30s
Answer:
Step-by-step explanation:
I'm assuming that the length of the spring is s and the mass of the object is m. If that be the case, the direct variation equation, which a line btw, is
s = km where k is the constant of proportionality. We have to solve for k, the slope of the line, in order to determine the model for this situation.
9 = k(30) so
[tex]k=\frac{9}{30}=\frac{3}{10}[/tex] Now that we know, the slope of the line, we can rewrite the equation with the slope in place:
[tex]s=\frac{3}{10}m[/tex], choice A.
solve this simultaneous linear equation=X+y=4and2x-y=5
From eq(1)
[tex]\\ \sf\longmapsto x+y=4[/tex]
[tex]\\ \sf\longmapsto x=4-y\dots(3)[/tex]
Put values in eq(2)[tex]\\ \sf\longmapsto 2x-y=5[/tex]
[tex]\\ \sf\longmapsto 2(4-y)-y=5[/tex]
[tex]\\ \sf\longmapsto 8-2y-y=5[/tex]
[tex]\\ \sf\longmapsto 8-3y=5[/tex]
[tex]\\ \sf\longmapsto 8-5=3y[/tex]
[tex]\\ \sf\longmapsto 3y=3[/tex]
[tex]\\ \sf\longmapsto y=\dfrac{3}{3}[/tex]
[tex]\\ \sf\longmapsto y=1[/tex]
Put value in eq(3)
[tex]\\ \sf\longmapsto x=4-y[/tex]
[tex]\\ \sf\longmapsto x=4-1[/tex]
[tex]\\ \sf\longmapsto x=3[/tex]
plz answer quick!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answer:
[tex]144\pi[/tex]cm
multiple 24 pi with 6 on a scientific calculator.
Answer:
4pi
Step-by-step explanation:
that is the procedure above
answer
answer
asap
pls
Answer:
true
Step-by-step explanation:
Answer:
true
Step-by-step explanation:
An integer can be written as a fraction by giving it a denominator of one
can you help me to do this
Answer:
keep the pic clearly
Step-by-step explanation:
keep the pic clearly
A factory produces wrenches. The factory wants all of its
wrenches to weigh the same, but will accept a certain level of er-
ror. The inequality below describes the error they are willing to
accept, in pounds:
Answer:
b
Step-by-step explanation:
HELP FAST Which solution shown bellow contains an error
Answer:
B
Step-by-step explanation:
39 3,822 Whats the answer
Answer:
The answer is 98
Step-by-step explanation:
Can I get branly plz and hope this help
c) The GCF and LCM of two numbers are 2 and 70 respectively. If one of the numbers is 10, find the other number? [3m] solution: of too numbers
Their LCM is
70
hope it helps you.
Answer:
Their L.C.M IS
70....
IT IS YOUR ANSWER
how do we know a given number in the radical is whether rational or irrational
number is described as rational if it can be written as a fraction (one integer divided by another integer). A number is irrational if it cannot be written as a fraction. The decimal form of an irrational number does not terminate or recur.
0.008 x 2.5 in standard form is (A) 2 x 10-² (B) 2 x 10 (C) 2 x 10-¹ (D) 2 x 10²
Answer:
(D) 2 x 10²
Step-by-step explanation:
Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the 10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.
Hope it is helpful.....Answer:
2 × 10 ^2
Step-by-step explanation:
(d) option is correct
square root of 3x^4 times square root of 5x^2 times square root of 10.
Multiply and remove all perfect squares from inside the square roots. Assume x is positive.
Answer:
[tex]5x^3\sqrt{6}[/tex]
Step-by-step explanation:
We need to simplify
[tex]\sqrt{3x^4}\times\sqrt{5x^2}\times\sqrt{10}[/tex]
Right away we can take out the perfect squares. Remember a perfect square is the result of multiplying any value by itself.
[tex]= x^2\sqrt{3}\times x\sqrt{5}\times\sqrt{10} \\= x^3\sqrt{3\times 5 \times 10}\\= x^3\sqrt{3 \times 5 \times 5 \times 2 }\\= 5x^3\sqrt{6}[/tex]
The square root of 3x⁴ times square root of 5x² times square root of 10, the product of all the term is, 5x³ [tex]\sqrt{6}[/tex]
What is square root?In mathematics, square roots is a concept in which, if we multiply square roots of any number by itself then it will give us an original number.
if 'a' is square root of 'b' then it will represent as, a = √b.
Given that,
three terms,
[tex]\sqrt3{x^{4} }[/tex]
[tex]\sqrt{5x^{2} }[/tex]
[tex]\sqrt{10}[/tex]
by multiplying all the three terms,
⇒ [tex]\sqrt3{x^{4} }[/tex] × [tex]\sqrt{5x^{2} }[/tex] × [tex]\sqrt10} }[/tex]
⇒ √(3x⁴×5x²10)
⇒ √ 150x⁶
⇒ 5x³ [tex]\sqrt{6}[/tex]
Hence, the product is 5x³ [tex]\sqrt{6}[/tex]
To know more about square root check:
https://brainly.com/question/29286039
#SPJ2
Find the missing value.
Hint: Use the number line to find the missing value.
-(-7)=5
{ #
-15
→
15
-10
-5
0
5
10
Answer:
= -2
Step-by-step explanation:
-2 -(-7)
= 5
I hope this Helps!Is it the answer option D?
Answer:
D
Step-by-step explanation:
graph it
A candy jar contains several small pieces of candy:
• 5 miniature peanut butter cups
• 7 dark chocolate candy bars
• 8 gummy worms
Roger randomly selected one piece of candy from the jar.
Problem
Read aloude What is the probability in decimal form that the candy Roger selected was NOT a gummy worm?
Answer:
12/20 = 60%
Step-by-step explanation:
The probability that the candy Roger selected was NOT a gummy worm;
P(Not a gummy worm) = 0.6
We are told the quantity of candies in the jar is as follows;
Miniature peanut butter cups = 5
Dark Chocolate bars = 7
Gummy worms = 8
Total number of candy bars = 5 + 7 + 8
Total number of candy bars = 20
Probability is found as; number of possible outcomes/number of events.
P(randomly selected is a gummy worm) = 8/20
P(randomly selected is a gummy worm) = 0.4
Thus, probability that it was not a gummy worm = 1 - 0.4Probability that it was not a gummy worm = 0.6
Read more at; https://brainly.com/question/13160116
factorise (x+1)^2 + 4(x+1)
Answer:
(x + 1)(x + 5)
Step-by-step explanation:
Given
(x + 1)² + 4(x + 1) ← factor out (x + 1) from each term
= (x + 1)(x + 1 + 4)
= (x + 1)x + 5)
Find the height of the triangle
Answer:
The height is 12 cm
Step-by-step explanation:
Hi there!
We are given a triangle with the 3 sides marked as 15, 20, and 25 and we want to find the height of it (marked as x in the problem).
This problem can seem a bit difficult, but let's see if the triangle is a right triangle first off.
One way to figure out if it is a right triangle is to apply the converse of the Pythagorean theorem.
Let's label the sides, where a is the shortest side, b is the second shortest side, and c is the longest side:
a=15
b=20
c=25
Now square a and b, then add the result together. If it's the same as c squared, then the triangle is a right triangle
15²+20²=25²
225+400=625
625=625
So we can safely say that the triangle is a right triangle
This makes the problem way easier, as there are 2 ways to find the area of a right triangle:
The first way is to multiply the legs (the sides that make up the right angle) together, then divide the result by 2
The other way is to multiply the height and the hypotenuse (the side OPPOSITE to the right angle) together, and then divide the result by 2
First, we need to figure out which sides are the legs, and which side is the hypotenuse
By the triangle inequality theorem, the hypotenuse of a right triangle is the longest side, which means that the 25 cm side is the hypotenuse, and that leaves 15 cm and the 20 cm sides as the legs
So let's find the area of the triangle using the legs
A=[tex]\frac{15*20}{2}[/tex]=[tex]\frac{300}{2}[/tex]=150
So the area of the triangle is 150 cm²
However, as mentioned above, we can also find the area of the triangle by multiplying the hypotenuse by the base, then dividing the result by 2
Which means that the area is also:
A=[tex]\frac{25x}{2}[/tex] cm²
As these both equal the area of the triangle, we can set them equal to each other. This is possible via a property known as transitivity (if a=b and b=c, then a=c)
[tex]\frac{25x}{2}=150[/tex]
Multiply both sides by 2
25x=300
Divide both sides by 25
x=12 cm
So the height of the triangle is 12 cm
Hope this helps!
PLEASE I REALLY CAN'T THINK OF ANYTHING ELSE
list 2 differences between y = sin x and y = cos x
Answer:
- sin(x) is the ratio of the opposite leg to the hypotenuse in a right triangle, while cos(x) is the ratio of the adjacent leg to the hypotenuse in a right triangle.
-The graph of y = sin(x) at x = 0 starts at the origin, and then increases, while the graph of y = cos(x) starts at a max, and then decreases.
Here's a 3rd: sin(x) is the cofunction of cos(x), which means that sin(x) = cos(90-x). This also shows that they are different.
Solve for t in terms of q, r, and s.
r = sqt
t=
Answer:
t=r/(sq)
Step-by-step explanation:
r=sqt
=> r/(sq)=t
Answer:
T= r/(sq)
Step-by-step explanation:
r= sqt
=r/(sq) =t
In the paper airplane shown, ABCD = EFGH, M
Answer:
it should be 90 I could be wrong
Is it ok if you help me solve this?
Answer:
For it to be parallel the answer is B (3)
Answer:
B) 3
Explanation:
If two lines are parallel that means that their equations have the same value of slope.
Circles in the Coordinate Plane
Acellus
Complete the equation of this circle:
A
1
Answer: [tex](x-3)^2 + (y-2)^2 = 16[/tex]
Explanation:
The center of this circle is point A(3,2). These coordinates are the (h,k) values.
The radius is r = 4
Plug those three items into the template [tex](x-h)^2 + (y-k)^2 = r^2[/tex] to arrive at the final answer shown above.
Write the Roman numeral CLXXIX in standard form.
179 is the answer
hope it helps
Answer:
179 = CLXXIX = 100 + 50 + 10 + 10 + 10 − 1
Step-by-step explanation:
Numbers close to CLXXIX
Below are the numbers CLXXVI through CLXXXII, which are close to CLXXIX. The right column shows how each roman numeral adds up to the total.
176 = CLXXVI = 100 + 50 + 10 + 10 + 5 + 1
177 = CLXXVII = 100 + 50 + 10 + 10 + 5 + 1 + 1
178 = CLXXVIII = 100 + 50 + 10 + 10 + 5 + 1 + 1 + 1
179 = CLXXIX = 100 + 50 + 10 + 10 + 10 − 1
180 = CLXXX = 100 + 50 + 10 + 10 + 10
181 = CLXXXI = 100 + 50 + 10 + 10 + 10 + 1
182 = CLXXXII = 100 + 50 + 10 + 10 + 10 + 1 + 1
Symbol Value
I 1
V 5
X 10
L 50
C 100
D 500
M 1000
I hope this helps.
32% of 300 is what number?
Answer: 96
Step-by-step explanation:
This equation helps
X / 100 = is / of
32/100 = X / 300 (cross multiplication)
32 times 300, divided by 100
= 96
Answer:
96
Step-by-step explanation:
every percent is out of hundred so (32 * 300)/100 = 96
Evaluate the line integral 2 + x2y ds where c is the upper half of the circle x2 + y2 = 1.
Parameterize C by
r(t) = 〈x(t), y(t)〉 = 〈cos(t), sin(t)〉
with 0 ≤ t ≤ π. Then the line integral is
[tex]\displaystyle \int_C (2+x^2y)\,\mathrm ds = \int_0^\pi (2+\cos^2(t)\sin(t))\left\|\mathbf r'(t)\right\|\,\mathrm dt \\\\ = \int_0^\pi (2+\cos^2(t)\sin(t)) \,\mathrm dt = \boxed{\frac23+2\pi}[/tex]
4 1
+
15
(Type a simplified fraction.)
5
Answer:
7/15
Step-by-step explanation:
hope the picture helps
Find the length of y. Assume the triangles are similar.\
A. 3.6
B. 3.2
C. 3.9
D. 3.4
6,3:y=4,2:2,4
y=3,6
Chọn a
solve for x. you must show all of your work to receive credit.
Answer:
x = 6
Step-by-step explanation:
The tangent- tangent angle WVU is half the difference of the measure of the intercepted arcs. , that is
5x + 17 = [tex]\frac{1}{2}[/tex] (37x + 5 - (23x - 5) )
5x + 17 = [tex]\frac{1}{2}[/tex] (37x + 5 - 23x + 5)
5x + 17 = [tex]\frac{1}{2}[/tex] (14x + 10) ← multiply both sides by 2 to clear the fraction )
10x + 34 = 14x + 10 ( subtract 14x from both sides )
- 4x + 34 = 10 ( subtract 34 from both sides )
- 4x = - 24 ( divide both sides by - 4 )
x = 6
Will Mark Brainlest Help Please Please
Answer:
a=2
b=-3
c=2
d=0
Step-by-step explanation:
3a+b=3......1
3c-d=6.......2
a-b=5....... 3
a+b+d=2d-1
a+b=2d-d-1
a+b=d-1......4
taking equation 1 and 3 we get,
3a+b =3....... 1
a-b=5
a=5+b
substitute the value of a in equation 1 we get,
3*(5+b)+b=3
15+3b+b=3
4b=3-15
4b=-12
b=-12/4
b=-3
now putting the value of b in equation 3 we get,
a-b=5
a+3=5
a=5-3
a=2
substitute the value of a and b in equation 4 we get,
a+b=d-1
2-3=d-1
-1=d-1
d=-1+1
d=0
substitute the value of d in equation 2 we get,
3c-d=6
3c-0=6
3c=6
c=6/3
c=2
[tex]\\ \sf\longmapsto \left[{3a+b\atop a-b}\:\:\:{3c-d\atop a+b+d}\right]=\left[{3\atop 5}\:\:\;{6\atop 2d-1}\right][/tex]
Now constructing equations
[tex]\\ \sf\longmapsto 3a+b=3\dots(1)[/tex]
[tex]\\ \sf\longmapsto a-b=5\dots(2)[/tex]
[tex]\\ \sf\longmapsto 3c-d=6\dots(3)[/tex]
[tex]\\ \sf\longmapsto a+b+d=2d-1\dots(4)[/tex]
Adding eq(1) and (2)
[tex]\\ \sf\longmapsto 4a=8[/tex]
[tex]\\ \sf\longmapsto a=\dfrac{8}{4}[/tex]
[tex]\\ \bf\longmapsto a=2[/tex]
Put the value in eq(2)
[tex]\\ \sf\longmapsto a-b=5[/tex]
[tex]\\ \sf\longmapsto b=a-5[/tex]
[tex]\\ \sf\longmapsto b=2-5[/tex]
[tex]\\ \bf\longmapsto b=-3[/tex]
put the values in eq(4)
[tex]\\ \sf\longmapsto a+b+d=2d-1[/tex]
[tex]\\ \sf\longmapsto 2+(-3)+d=2d-1[/tex]
[tex]\\ \sf\longmapsto d-1=2d-1[/tex]
[tex]\\ \sf\longmapsto d-2d=-1+1[/tex]
[tex]\\ \sf\longmapsto -d=0[/tex]
[tex]\\ \bf\longmapsto d=0[/tex]
Put the value in eq(3)
[tex]\\ \sf\longmapsto 3c-d=6[/tex]
[tex]\\ \sf\longmapsto 3c-0=6[/tex]
[tex]\\ \sf\longmapsto 3c=6+0[/tex]
[tex]\\ \sf\longmapsto 3c=6[/tex]
[tex]\\ \sf\longmapsto c=\dfrac{6}{3}[/tex]
[tex]\\ \sf\longmapsto c=2[/tex]
