The advantages that can be associated to
drawings and symbols over written descriptions in engineering design and prototyping process are;
Communicate design ideas as well as technical information to engineers.
Symbols and drawings can be universal which means it is easy to interpret any where by professionals.
An engineering drawing serves as complex dimensional object and symbol use by engineer to communicate.Drawings and symbols makes it easier to communicate design ideas and technical information to engineers and and how the process will go.Therefore, drawings and symbols is universal to all engineer unlike written one.
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Do the coil resistances have any effect on the plots?
Consider a 25-mm-diameter and 15-m-long smooth tube that is maintained at a constant surface temperature. Fluids enter the tube at 50°C with a mass flow rate of 0.01 kg/s. Determine the tube surface temperatures necessary to heat water, engine oil, and liquid mercury to the desired outlet temperature of 150°C
Answer: ⚠this is not my answer it from hamzaahmeds⚠
Water: h = 35.53 W/m².k
Engine oil: h = 18.84 W/m².k
Mercury: h = 1.19 W/m².k
Explanation:
Assuming the steady state, one-dimensional heat flow, it is clear that the added to the fluid by tube heat will be equal to the heat transfer through convection outside the tube.
Therefore,
mCΔT = hAΔT
mC = hA
h = mC/A
where,
h = convection coefficient
m = mass flow rate = 0.01 kg/s
C = specific heat capacity of fluid
A = surface area of tube = 2πrL = 2π(0.0125 m)(15 m) = 1.178 m²
FOR WATER:
C = 4186 J/Kg.k
Therefore,
h = (0.01 kg/s)(4186 J/Kg.k)/(1.178 m²)
h = 35.53 W/m².k
FOR ENGINE OIL:
C = 2220 J/Kg.k
Therefore,
h = (0.01 kg/s)(2220 J/Kg.k)/(1.178 m²)
h = 18.84 W/m².k
FOR LIQUID MERCURY:
C = 140 J/Kg.k
Therefore,
h = (0.01 kg/s)(140 J/Kg.k)/(1.178 m²)
h = 1.19 W/m².k
effects of salinity water on alfalfa
how long did it take you to answer all of these questions
Answer:
not sure
Explanation:
not sure
true/False
1.
Around 50 percent of all sales of farm commodities are from dairy
products.
Answer:true
Explanation:
It is true that around 50 percent of all sales of farm commodities are from dairy products.
What are dairy products?Dairy products or milk products, also known as lacticinia, are milk-based foods.
Cows, water buffalo, nanny goats, and ewes are the most common dairy animals. Dairy products include common grocery store foods such as yogurt, cheese, and butter in the Western world.
Milk, yogurt, cheese, lactose-free milk, and fortified soy milk and yogurt are all part of the Dairy Group. The Dairy Group excludes milk-based foods with low calcium and a high fat content. Cream cheese, sour cream, cream, and butter are all examples of this.
Dairy products account for roughly half of all farm commodity sales.
Thus, the given statement is true.
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why people act like that
Answer:
i dob't know
Explanation:
Describe three differences between liquids and gases in fluid power systems.
Answer:
Liquids have less force of attraction between molecules than solids and more than gases; gases have a very weak force of attraction between the molecules which is the least amongst the three states of matter.
Explanation:
An Infrastructure as a Service (IaaS) provider shares its computing resources between a number of different clients, each of whom has a separate dedicated instance to host their own operating systems and applications.
Which Cloud computing concept is illustrated here?
Answer:
Elasticity
Explanation:
Cloud computing comprises of three (3) service models and these are;
1. Platform as a Service (PaaS).
2. Software as a Service (SaaS).
3. Infrastructure as a Service (IaaS).
How to calculate total photon flux incident on the photodiode
Answer:
Use this PDF file it should help you calculate total photon flux incident on the photodiode.
Explanation:
It's a file on lecture notes that help people learn about engineering and maybe in the lecture notes it might have information about how to calculate total photon flux incident on the photodiode
why the power factor is Low in no load test in induction motor ?
The reason for low power factor in no load test in induction motor is high rotor reactance at lower loading since the rotor reactance value gets decreased with increased loading on induction motor
Usually at no load, the Cosine of the phase angle between the stator current(I1) and the stator applied voltage(V1) is the power factor of an induction motor.
In conclusion, the reason for low power factor in no load test in induction motor is high rotor reactance at lower loading since the rotor reactance value gets decreased with increased loading on induction motor
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why different types of
engines used gas turbine give reasons
Answer:
Four types of gas turbine engines are used to propel and power aircraft. They are the turbojet, turbofan, turboprop, and turboshaft.
Answer:
A gas turbine, also called a combustion turbine, is a type of continuous and internal combustion engine. The main elements common to all gas turbine engines are: ... Gas turbines are used to
Explanation:
The first three terms of a geometric series are 15,7.5 and 3.75. find the representation of the n th term of tge sequence
Answer:
30 1/2
Explanation:
To find the quotient of 8 divided by 1/3, multiply 8 by?
i need it asap but its should be 1 2 3 or 4 to answer
DONT GIVE ME LINKS ITS STUIPID JUST SAY A B C OR D
Answer: 8.33333333 or 6.1989778
Explanation:
How much work, in Newtons, is required to lift a 20.4-kg (45lb) plate from the ground to a stand that is 1.50 meters up?
ASAP PLS
Answer:
Explanation:
Work, U, is equal to the force times the distance:
U = F · r
Force needed to lift the weight, is equal to the weight: F = W = m · g
so:
U = m · g · r
= 20.4kg · 9.81 [tex]\frac{N}{kg}[/tex] · 1.50m
= 35.316 [tex]\frac{N}{m}[/tex]
= 35.316 W
what is the relationship between the voltages of the output and adjust pins of LM1117 when in normal operation
Based on the engineering analysis, the relationship between the voltages of the output and adjust pins of LM1117 when in normal operation is "the LM1117 adjustable version establishes a 1.25V reference voltage, (VREF) between the output and the adjust terminal."
The LM1117 generally has a 1.2V at 800mA of load current.
The LM1117 is known to be a progression of low dropout linear voltage regulators. It is adjustable and be assigned between the output voltage of 1.25 to 13.8 V using just two external resistors.
Hence, in this case, it is concluded that the correct answer is "the LM1117 adjustable version establishes a 1.25V reference voltage, (VREF), between the output and the adjust terminal.
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