If you're good at trigonometry please help meeeeeee

Answer:

3^1 or 3

3^5 * 3^-4 are 3^5-4

so, 3^1!

Hope it helps!

Answer:

3^1

Step-by-step explanation:

Since the bases are the same and we are multiplying we can add the exponents

a^b * a^c = a^(b+c)

3^5 * 3^-4

3^ (5+-4)

3^1

Answer:

10

Step-by-step explanation

Answer:

10

Step-by-step explanation:

So "MATHCOUNTS" has 10 letters.

And "MATH" has 4 letters.

So the probability of you getting the letters "M" "A" "T" "H" is 4/10 or 2/5.

But it has to be in order...

There are 32 ways you can arrange the 4 letters. There is only 1 way you can write "MATH"

So 1/32 probability of 2/5 is 2/160 or 1/80

The probability of getting the word MATH is 1/80

The study of likeliness of an event to happen is probability .

It is given that

Total letters in MATHCOUNTS : 10 letters.

Total chances of getting letter M , A , T , H  is  4

Probability of getting the letters M , A , T , H is 4/10

= 2 /5

The probability of getting the word MATH is 1

And the total number of ways the letters can be arranged is 2⁴

= 32

The probability of getting the word MATH is

= 1 /32 * 2 /5

=1/80

Therefore , The probability of getting the word MATH is 1/80

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Answer:

k=(-1,5)=-5

Step-by-step explanation:

Answer:

ok i got the same question and i think it is and dont qoute me boy i aint said it but i think its B sorry if im wrong

Step-by-step explanation:

C)

Because if you choose some points for example x = 0 and x = 3.14 (≈ pi)

you will see that there's only one match.

Answer:

Option C. y = cos x -2

Step-by-step explanation:

Answer:

248

Step-by-step explanation:

Answer:

x-axis

Step-by-step explanation:

Answer:

It is the x-axis

Step-by-step explanation:

In  a graph, the horizontal part of it is called the x axis.

Here is an definition: horizontal axis of a system of coordinates, points along which have a value of zero for all other coordinates

Answer:

the answer to the question is letter E I believe

Answer:

It is ASA congruence rule as the 2 angles and the included side of the triangle are equal

You need to see if it passes the vertical line test, then graph it to see if it is but is a function tho.

Answer:

A

Step-by-step explanation:

To find the distance between V1 and AQ use the distance formula

[tex]d = \sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]

First find the coordinates of both V1: (-6, 5)    AQ: (5, 5)

Now plug it in and solve for d (11)

Answer:

Step-by-step explanation:

Given two  series A and B;

Series A: 10 + 4 +8/5 + 16/25 + 13/125 + ...

Series B: 1/5 + 3/5 + 9/5 + 27/5 + 81/5 +...

Both series are geometric series since they have the same common ratio. Given the geometric series T₁, T₂, T₃, T₄..., the common ratio r is expressed as [tex]\frac{T_2}{T_1} =\frac{T_3}{T_2} =\frac{T_4}{T_3} = r[/tex].

a) For series A, Given T₁ = 10, T₂ = 4, T₃ = 8/5 and T₄ = 13/125

Its common ratio is expressed as [tex]\frac{4}{10} =\frac{8/5}{4} =\frac{13/125}{8/5} = 2/5[/tex]

Hence the common ratio of series A is 2/5

The sum to infinity of the geometric series will be expressed as [tex]s_\infty = \dfrac{a}{1-r}[/tex]

Note that the sum to infifnity is used since the series is tending to infinity.

a is the first term if the series = 10

r - 2/5

On substituting this values into the formula;

[tex]s_\infty = \dfrac{10}{1-2/5} \\\\s_\infty = \dfrac{10}{3/5} \\\\s_\infty = 10* 5/3\\s_\infty = 50/3[/tex]

Hence the sum of the series is 50/3

b) For the series B;

Series B: 1/5 + 3/5 + 9/5 + 27/5 + 81/5 +...

The common ratio of the series is expressed as shown;

[tex]\frac{3/5}{1/5} =\frac{9/5}{3/5}= \frac{27/5}{9/5 } = r\\ r = (3/5 * 5/1) = 9/5*5/3 = 27/5*5/9 = 3[/tex]

Hence its common ratio is 3.

Sun of the series is expressed similarly as:

[tex]s_\infty = \frac{a}{1-r}\\ s_\infty = \frac{1/5}{1-3}\\\\s_\infty = \frac{1/5}{-2}\\\\[/tex]

[tex]s_\infty = 1/5 * -1/2\\s_\infty = -1/10[/tex]

Hence the sum of series B is -1/10

Answer:

=90

Step-by-step explanation:

because d=32° and b=58°

this is because corresponding  angles are equal

Answer:

Step-by-step explanation:

b+d =90 degree

hope it helps

Answer:

3x³ - 10x² + 14x - 12

Step-by-step explanation:

(3x² - 4x + 6) × (x - 2)

3x³ - 4x² + 6x - 6x² + 8x - 12

3x³ - 10x² + 14x - 12

Thus, the product of 3x² - 4x + 6 and x - 2 in standard form is 3x³ - 10x² + 14x - 12

Answer:

  504 in³

Step-by-step explanation:

The volume of the overall outside dimensions is their product:

  Voverall = (12 in)(8 in)(6 in) = 576 in³

The volume of the "slot" is the product of its dimensions:

  Vslot = (6 in)(6 in)(2 in) = 72 in³

Then the volume of the figure shown is ...

  Vfigure = Voverall -Vslot = 576 in³ -72 in³ = 504 in³

Answer:

504 inches cubed

Step-by-step explanation:

The area missing is 6*6*2=72

The whole area is 576

subtract the two and get 504

since we are talk about volume it is 50 inches cubed

Answer:

3x^2 +x -3

Step-by-step explanation:

f(x)= 3 and g(x) = 3x^2+x-6

f+g (x) =  3+  3x^2+x-6

Combine like terms

          = 3x^2 +x -3

Answer:

  90

Step-by-step explanation:

Let g and b represent the number of girls and boys attending, respectively.

After 15 girls left, the ratio of boys to girls was ...

  b/(g -15) = 2/1

  b = 2g -30 . . . . . multiply by (g-15)

__

After 45 boys left, the ratio of girls to boys was ...

  (g -15)/(b -45) = 5/1

  g -15 = 5b -225 . . . . . . multiply by (b-45)

  g = 5b -210

Using the latter to substitute into the former, we have ...

  b = 2(5b -210) -30

  450 = 9b . . . . . add 450-b

  50 = b . . . . . . 50 boys attended

  g = 5(50) -210 = 40 . . . . . 40 girls attended

The number of students who attended the party was 50 +40 = 90.

_____

Check

After 15 girls left, the ratio of boys to girls was 50/25 = 2/1.

After 45 boys left, the ratio of girls to boys was 25/5 = 5/1.

Answer:

let b = original number of boys

let g = original number of girls

:

Of a group of boys and girls at Central Middle School's after-school party, 15 girls left early to play in a volleyball game.

The ratio of boys to girls then remaining was 2 to 1.

b%2F%28%28g-15%29%29 = 2%2F1

Cross multiply

b = 2(g-15)

b = 2g - 30

:

Later, 45 boys left for a football game. The ratio of girls to boys was then 5 to 1.

%28%28g-15%29%29%2F%28%28b-45%29%29 = 5%2F1

cross multiply

g - 15 = 5(b-45)

g - 15 = 5b - 225

g = 5b - 225 + 15

g = 5b - 210

Replace b with (2g-30)

g = 5(2g-30) - 210

g = 10g - 150 - 210

g = 10g - 360

360 = 10g - g

360 = 9g

g = 360/9

g = 40 girls originally

find b

b = 2(40) - 30

b = 50 boys originally

" How many students attended the party?"

40 + 50 = 90 students

Answer:

2

Step-by-step explanation:

A coefficient is the number placed before the variable. The variable gets multiplied by the coefficient.

The format is not exactly clear with the expression in the question.

Assuming the expression is '8 * 2n', the coefficient would be 2.

'n' is getting multiplied by '2'.

'8' does not have a variable next to it, so it is just a term in the expression.

The product of 8 and 2 is 16. 16 is not in the expression.

If the expression was '8.2n', 8.2 would be the coefficient.

Brainilest Appreciated.

Answer:

x = 1

Step-by-step explanation:

−31−4x=−5−5(1+5x)

First step is to simplify both sides

−31−4x=−5−5(1+5x)

−31+−4x=−5+(−5)(1)+(−5)(5x)

distribute

−31+−4x=−5+−5+−25x

−4x−31=(−25x)+(−5+−5)

and combine like terms

−4x−31=−25x+−10

−4x−31=−25x−10

Then add 25x to both sides

−4x−31+25x=−25x−10+25x

21x−31=−10

Add 31 to both sides

21x−31+31=−10+31

21x=21

And divide by 21!

21x/21 = 21/21

x=1

Answer:

X=1

Step-by-step explanation:

First this is you want to distribute the -5 to the 1 and 5x. Now you should have -31-4x=-5-5-25x. Next thing is to combine your like terms which would be -5 and -5 and you get -10. (-31-4x=-10-25x) Now add 31 to both sides and your new solution is -4x=21-25x. This time you add 25x to both sides and get 21x=21. Final step you divide both sides by 21 and get X=1. :)

Answer:

[tex]d=\sqrt{73}[/tex]

Step-by-step explanation:

[tex]Q(5, -1)[/tex]

[tex]P(-3, 2)[/tex]

Using the distance formula:

[tex]d=\sqrt{(x_{2}-x_{1})^2+(y_2+y_1)^2}[/tex]

[tex]d=\sqrt{(-3-5)^2+(2-(-1))^2}[/tex]

[tex]d=\sqrt{(-8)^2+(3)^2}[/tex]

[tex]d=\sqrt{64+9}[/tex]

[tex]d=\sqrt{64+9}[/tex]

[tex]d=\sqrt{73}[/tex]

[tex]d\approx 8.5[/tex]

Answer:

33

Step-by-step explanation:

We can write an equation:

x+x+1+x+2+x+3=130

x represents the smallest number of the consecutive integers

By the way, an example of consecutive would be 2, 3, 4, 5 or 10, 11, 12, 13

We can combine like terms from our equation:

4x+6=130

4x=124

x=31

The smallest number is 31. The second number would be 31+1=32, which means the third number is 33!

Hope this helps! :) :)

Answer:

[tex]\huge\boxed{3rd\ number = 33}[/tex]

Step-by-step explanation:

Let the consecutive numbers(Coming one after another) be x, x+1, a+2 and x+3

So,

x+x+1+x+2+x+3 = 130

4x + 6 = 130

Subtracting 6 to both sides

4x = 130-6

4x = 124

Dividing both sides by 4

x = 32

So,

1st number = x = 31

2nd Number = x+1 = 31+1 = 32

3rd number = x+2 = 31+2 = 33

4th number = x+3 = 31+3 = 34

Answer:

Of course the answer is 2.

It says 'Double'!

The required scale factor is 2 in a manner to double the volume of the fish tanks. Option A is correct.

The figure is shown of the fish tank, a scale factor to be determined that is applied to the dimensions so the volume becomes twice the former volume.

Volume is defined as the ratio of the mass of an object to its density.

The volume of the fish tank = v
Now new the volume of the new fish tank = 2v
Scale factor = New volume/old volume
                  =  2v/v
                  = 2

Since the scale factor is 2 the dimension of new fish tank should be doubled to get twice the volume of the old fish tank.

The required scale factor is 2 in a manner to double the volume of the fish tanks. Option A is correct.

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Answer:

[tex]4 \sqrt{6}[/tex]

Step-by-step explanation:

The question is not properly presented and has mission options; however, the solution is as follows

Given

[tex]\sqrt{96}[/tex]

Required

Simplify

[tex]\sqrt{96}[/tex]

Start by expanding

[tex]\sqrt{16 * 6}[/tex]

The expression can be split to:

[tex]\sqrt{16} * \sqrt{6}[/tex]

Take positive square root of 16

[tex]4 * \sqrt{6}[/tex]

[tex]4 \sqrt{6}[/tex]

The expression cannot be further simplified

Step-by-step explanation:

Since the original price is $47.96 and bill rate is 7%, $47.96 × 1.07 ≈ $51.32

Answer:

$51.32

The amount of sales tax for the bill if the rate is 7% will be $3.36.

The quantity of anything is stated as though it were a fraction of a hundred.

Vince and 11 of his friends went out for pizza on Saturday night to celebrate Vince’s birthday.

The cost of the pizza and soft drinks before sales tax and tip was $47.96.

Then the amount of sales tax for the bill if the rate is 7% will be

⇒ $47.96 x 0.07

⇒ $3.36

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Answer:

Multiplicative Identity Property,Associative Property of Addition,Commutative Property of Multiplication,Zero Property of Multiplication

Step-by-step explanation:

The required properties for the given expression of the real numbers are multiplication property, associative property,  commutative property, and property of zero multiplication.

Given that,

A number of expressions for the real number are given we have determined the corresponding properties for the arithmetic operation given.

In mathematics, it deals with numbers of operations according to the statements.

Here,
1.
n.1 = n
It is a unit multiplication property.

2.
(4 + b) + 7 = 4 + (b + 7)
it is associative property of real numbers.

3.
m.9 = 9.m
it is commutative property.

4.
0.c = 0
It is a property of zero multiplication.

Thus, the required properties for the given expression of the real numbers are multiplication property, associative property,  commutative property, and property of zero multiplication.

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Answer:

Step-by-step explanation:

To find the side adjacent to the 50° angle we use tan

[tex] \tan( \alpha ) = \frac{opposite}{adjacent} [/tex]

From the question

The opposite is 6m

The adjacent is ?

So we have

[tex] \tan(50) = \frac{6}{?} [/tex]

[tex]? \tan(50) = 6[/tex]

[tex]? = 6 \times \frac{1}{ \tan(50) } [/tex]

But

[tex] \frac{1}{ \tan(x) } = \cot(x) [/tex]

So we have

[tex] \frac{1}{ \tan(50) } = \cot(50) [/tex]

Substitute it into the expression

That's

We have the final answer as

[tex]? = 6 \cot(50) [/tex]

Hope this helps you

=====================================================

Explanation:

We're given an opposite side and an adjacent side. The tangent rule ties these two sides together. "tangent" is nowhere to be found in any of the answer choices, but cotangent is. Recall that

cot = 1/tan

which means

tan = opposite/adjacent

cot = adjacent/opposite

one is the reciprocal of the other

-----------

This means

cot(angle) = adjacent/opposite

cot(50) = x/6

6*cot(50) = x

x = 6*cot(50)

Answer:C and F are correct

Step-by-step explanation:

got it right on edge

Hey there! I'm happy to help!

Sine is a trigonometric ratio. It is the ratio of the opposite side of the angle to the hypotenuse. Since it is a ratio, it does matter how big or small the triangle is as long as the sides remain in proportion. If the opposite side is 4 and the hypotenuse is 5, the sine of x will be the same as it would be if the opposite were 16 and the hypotenuse were 20 because they simplify to the same ratio (4/5).

The sine (or any trigonometric ratio) of any number stays the same even if the triangle is dilated because the proportion between the sides stays the same no matter how big or small. So, they told us the answer at the beginning. The sine of angle x is 4/5.

Have a wonderful day! :D

Answer: 4/5

Step-by-step explanation: Took the test and got it right. I assumed it was the same because angles do not change after being dilated.

Answer:

Perimeter of the shaded region= 22/7cm

Area = 36.48 cm²

Step-by-step explanation:

First of all for the perimeter.

The radius of the arc is 8cm

At an angle of 90°

Perimeter of of the shape is perimeter of the the 2 arc

The both arc are equal so let's determine the perimeter of one first.

Perimeter of the arc= 2πr*(90/360)

Perimeter of the arc= 2*22/7*1/4

Perimeter of the arc= 11/7 cm

Perimeter of the shades region= 2*11/7

Perimeter of the shaded region= 22/7cm

Area of the sector = πr²*(90/360)

Area of the sector= 50.24cm²

Area of non sector= 64-50.24

= 13.76

But non sector is two

Area of non sector= 2*13.76

= 27.52

Area of the shaded region = area of the square -(area of non sector)

= 64-27.52

= 36.48 cm²