calculate the number of moles equivalent to 20.0 gram of calcium phosphate ​
please help

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☃️ Chemical formulae ➝ [tex]\sf{Ca_3(PO_4)_2}[/tex]

For solving this question, We need to know how to find moles of solution or any substance if a certain weight is given.

[tex] \boxed{ \sf{No. \: of \: moles = \frac{Given \: weight}{Molecular \: weight} }}[/tex]

Atomic weight of elements:

❍ Molecular weight of [tex]\sf{Ca_3(PO_4)_2}[/tex]

= 3 × 40 + 2 × 31 + 8 × 16

= 120 + 62 + 128

= 310 g/mol

❍ Given weight: 20 g

Then, no. of moles,

⇛ No. of moles = 20 g / 310 g mol‐¹

⇛ No. of moles = 0.0645 moles

⚘ No. of moles of Calcium phospate in the given weight = 0.0645 moles.

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Answer:

Explanation:

To find the number of moles in calcium phosphate we use the formula

[tex]n \: = \frac{m}{M} [/tex]

where

n is the number of moles

M is the molar mass

m is the mass of the substance

To find the number of moles we must first find the molar mass

Chemical formula for calcium phosphate is

Ca3( PO4)2

Ca = 40 , P = 31 , O = 16

So the Molar mass of calcium phosphate is

M( Ca3( PO4)2 ) = (20×3) + 2( 31 + (16×4)

= 60 + 2( 31 + 64)

= 60 + 2(95)

= 60 + 190

Molar mass of calcium phosphate =

250g/mol

Mass = 20 g

So we have

[tex]n = \frac{20g}{250g/mol} [/tex]

We have the final answer as

Hope this helps you