If the original quantity is 225 and the quality of 320 what is the percentage increase?

Answers

Answer 1

Step-by-step explanation:

The change fro 225 to 320 is 95

95 is what percentage of 225?

95/225 x 100% = 42.2% increase


Related Questions

Find the circumference and the area of a circle with radius 7 yards use the value 3.14 for pi 

Answers

Answer:

circumference=43.96 yd

Area=153.86 yd^2

Step-by-step explanation:

c=2pi r

c=2x3.14x7

c=43.96 yd


area=pi r^2

Area=3.14x7^2

Area=153.86 yd^2

you decide to record the hair colors of people leaving a lecture at your school. what is the probability that the next person who leaves the lecture will have gray hair? express your answer as a simplified fraction or a decimal rounded to four decimal places. counting people blonde red brown black gray 50 40 39 33 43

Answers

The probability is a fraction of 43/205 which is approximately 0.2098.

What is the probability that the next person who leaves the lecture will have grey hair?

To calculate the probability of the next person who leaves the lecture having gray hair, we need to know the total number of people who left the lecture, as well as the number of people who have gray hair.

From the given data, we can see that there were a total of 50+40+39+33+43 = 205 people who left the lecture. We also know that there were 43 people who had gray hair.

Therefore, the probability of the next person who leaves the lecture having gray hair is:

P(gray hair) = (number of people with gray hair) / (total number of people who left the lecture)

P(gray hair) = 43/205

P(gray hair) ≈ 0.2098

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1. The line segment AB has endpoints A(-5, 3) and B(-1,-5). Find the point that partitions the line segment in
a ratio of 1:3

Answers

Answer:

To find the point that partitions the line segment AB in a ratio of 1:3, we can use the following formula:

P = (3B + 1A) / 4

where P is the point that partitions the line segment in a ratio of 1:3, A and B are the endpoints of the line segment, and the coefficients 3 and 1 represent the ratio of the segment we are dividing.

Substituting the values, we get:

P = (3*(-1, -5) + 1*(-5, 3)) / 4

P = (-3, -7)

Therefore, the point that partitions the line segment AB in a ratio of 1:3 is (-3, -7).

Step-by-step explanation:

1 point) Consider the linear system -3-21→ a. Find the eigenvalues and eigenvectors for the coefficient matrix. 0 and 42 b. Find the real-valued solution to the initial value problem yj 5y1 +3y2, y2(0) = 15. = Use t as the independent variable in your answers. y (t) = y(t) =

Answers

(a) The eigenvalues of the coefficient matrix is  [-1,3]  and for λ=42, we get the eigenvector [1,5].

Itcan be found by solving the characteristic equation |A-λI|=0, where A is the coefficient matrix and λ is the eigenvalue. Solving for λ, we get λ=0 and λ=42.

o find the eigenvectors, we substitute each eigenvalue into the equation (A-λI)x=0 and solve for x. For λ=0, we get the eigenvector [-1,3]. For λ=42, we get the eigenvector [1,5].

(b) The solution is y(t) = c1e^(0t)[-1,3] + c2e^(42t)[1,5].

To find the real-valued solution to the initial value problem, we can use the eigenvectors and eigenvalues to diagonalize the coefficient matrix. We have A = PDP^-1, where P is the matrix whose columns are the eigenvectors and D is the diagonal matrix with the eigenvalues on the diagonal.

Using the initial condition y2(0) = 15, we can solve for the constants c1 and c2.

The solution is y(t) = c1e^(0t)[-1,3] + c2e^(42t)[1,5]. Solving for c1 and c2 using the initial condition, we get

y(t) = [-15e^(42t) + 3e^(0t), 15e^(42t) + 5e^(0t)].

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A cat gave birth to 333 kittens who each had a different mass between 147147147 and 159\,\text{g}159g159, start text, g, end text. Then, the cat gave birth to a 4^{\text{th}}4 th 4, start superscript, start text, t, h, end text, end superscript kitten with a mass of 57\,\text{g}57g57, start text, g, end text.

Answers

The answer to the question is 334 kittens.

Given that a cat gave birth to 333 kittens who each had a different mass between 147 g and 159 g. Then the cat gave birth to a 4th kitten with a mass of 57 g.

First of all, we will find out the range of the mass of kittens. The range is given as follows;Range = Maximum Value - Minimum Value Range = 159 g - 147 g Range = 12 g

Now, the cat gave birth to a 4th kitten with a mass of 57 g, we can say that the minimum value of kitten's mass is 57 g.So, the maximum value of kitten's mass can be calculated as follows;Maximum Value = 57 g + Range Maximum Value = 57 g + 12 g Maximum Value = 69 g Now, we can say that all kittens with a mass of 69 g or less would be born because the minimum value of kitten's mass is 57 g and the range of mass is 12 g.

Therefore, the answer to the question is 334 kittens.

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suppose the minimum volume of a clown is 60,000 cm3 and the volume of my car is 3 million cm3. 55 is______ the maximum number of clowns that can fit in my car.
a. An upper bound on
b. Not a bound
c. A lower bound on
d. exactly

Answers

When the minimum volume of a clown is 60,000 cm³ and the volume of a car is 3 million cm³, 55 is an upper bound on the maximum number of clowns that can fit in a car. The correct answer is Option A.

What are bounds?

Bounds are the maximum and minimum limits that are permitted, within which something can or must be performed. Bounds are used to refer to an acceptable range of values that provide safe operation or performance. In mathematics, a set of bounds can define the limits of the amount of things or objects.

The minimum volume of a clown is 60,000 cm³, so to fit 55 clowns in a car we need:

55 clowns × 60,000 cm³/clown = 3,300,000 cm³

This is lower than the volume of the car. Therefore, 55 is an upper bound on the maximum number of clowns that can fit in the car.

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Triangle ABC is given where A=42°, a=3, and b=8. How many distinct triangles can be made with the given measurements? Explain your answer.
A. 0
B. 1
C. 2
D. 3

Answers

Answer: it is b

Step-by-step explanation:

it is b bec if you do that by 10x9 90=a a x x =1 90/s

Answer:

C

Step-by-step explanation:

To determine the number of distinct triangles that can be made with the given measurements, we can use the Law of Sines, which states:

a/sin(A) = b/sin(B) = c/sin(C)

where a, b, c are the lengths of the sides opposite to the angles A, B, and C, respectively.

Using this formula, we can solve for sin(B) as follows:

sin(B) = b*sin(A)/a

sin(B) = 8*sin(42°)/3

sin(B) ≈ 0.896

Since sin(B) is a positive value, we know that there are two possible angles B that satisfy this equation: one acute angle and one obtuse angle. To find the acute angle B, we take the inverse sine of sin(B):

B = sin^(-1)(0.896)

B ≈ 63.8°

To find the obtuse angle, we subtract the acute angle from 180°:

B' = 180° - 63.8°

B' ≈ 116.2°

Now, we can use the fact that the sum of the angles in a triangle is 180° to find the possible values for angle C. For the acute triangle, we have:

C = 180° - A - B

C = 180° - 42° - 63.8°

C ≈ 74.2°

For the obtuse triangle, we have:

C' = 180° - A - B'

C' = 180° - 42° - 116.2°

C' ≈ 21.8°

Therefore, we have found two distinct triangles that can be made with the given measurements: one acute triangle with angles A = 42°, B ≈ 63.8°, and C ≈ 74.2°, and one obtuse triangle with angles A = 42°, B' ≈ 116.2°, and C' ≈ 21.8°. Thus, the answer is C. 2.

which of the contexts below could be modeled by a linear function? the amount of a certain medication in a person's bloodstream decreases by 1/3 every week. a town's population shrinks at a rate of 2.2% every year. a certain population of 4 aggressive zombies quintuples every hour. snow was falling at a rate of 2 inches per hour.

Answers

The context that could be modeled by a linear function is "snow was falling at a rate of 2 inches per hour."

What is function?

In mathematics, a function is a relation between a set of inputs and a set of possible outputs with the property that each input is related to exactly one output. In other words, a function takes an input and produces a corresponding output. It is often represented as a mathematical equation or a graph. Functions are used to model real-world phenomena and are an important tool in many areas of mathematics, science, and engineering.

Here,

A linear function describes a constant rate of change, and in this context, the rate of snowfall is constant at 2 inches per hour. The other contexts involve exponential or percentage change, which cannot be modeled by a linear function.

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A system of equations is graphed on the coordinate plane.
A student concludes that the solution of the system is (-0.5, 1.5).
Is this correct? Justify your response.

Answers

The correctness of the student's solution, we need to have the equations of the system.

A system of equations is graphed on the coordinate plane. A student concludes that the solution of the system is (-0.5, 1.5). Is this correct? Justify your response.To conclude that a system of equations has a solution in the coordinate plane, a set of ordered pairs (x, y) should satisfy both equations in the system of equations. That is, the system of equations should have a point (x, y) that is a solution of both equations.Only by testing the solution in the given system of equations can we know if the student's conclusion is correct. If the solution is satisfied by the system of equations, then the answer is true. Otherwise, it is false. However, since no system of equations is provided in the question, we cannot test the student's solution.To justify the correctness of the student's solution, we need to have the equations of the system.

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Estimating the within-group variance. Refer to the previous exercise. Here are the cell standard deviations and sample sizes for cooking enjoyment: Find the pooled estimate of the standard deviation for these data. Use the rule for examining standard deviations in ANOVA from Chapter 12 (page 560) to determine if it is reasonable to use a pooled standard deviation for the analysis of these data.

Answers

In the following question, among the given options, the statement is said to be, The pooled estimate of the standard deviation for the data given is √(54.14^2/10 + 24.26^2/10) = 22.74.

According to the rule for examining standard deviations in ANOVA from Chapter 12 (page 560), the within-group standard deviation should be no more than twice the size of the between-group standard deviation. In this case, the between-group standard deviation is 44.85 and the within-group standard deviation (22.74) is less than twice the size of the between-group standard deviation, so it is reasonable to use a pooled standard deviation for the analysis of these data.

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Write
a real-world situation that can be
represented by 15 + c = 17.50. Tell what
the variable represents. Then solve the
equation and describe what your answer
represents for the problem situation. Can you also please try to make it something a little original I need help with this ASAP pls.

Answers

Answer:

The given expression is

[tex]15 + c = 17.50[/tex]

We can use this expression to model the cost for a service.

Let's say that your gardener charges an initial amount of $15, and an additional per hour. If the gardener worked only for one hour, and the total cost charged was $17.50, how much was the additional cost?

So, the given expression models this real life situation, we can answer the problem by just solving the equation for [tex]c[/tex]

[tex]15 + c = 17.50[/tex]

[tex]c=17.50-15[/tex]

[tex]c=2.50[/tex]

Answer: Well C equals 2.5. You could use...

You have 3 sticks. one stick is 15 inches long and the other is 17.50. You want to get a small stick to add to the first one so that the first and last stick is equal to the 2nd stick.  C is the third stick.  15+C = 17.50. What is the length of C?

Step-by-step explanation:

EASY

Move all terms not containing C to the right side of the equation. C = 2.5

let tan0= 3/4 and 0 be in Q3
Choose all answers that are correct

Answers

Answer:

Correct choices

[tex]\csc (\theta) = - \dfrac{5}{3} \quad \quad \text{2nd option}\\\\\cot(\theta) = \dfrac{4}{3} \quad \quad \text{3rd option}\\\\\cos(\theta) = -\dfrac{4}{5} \quad \quad \text{4th option}\\\\[/tex]

Step-by-step explanation:

[tex]\text{If \;$ \tan\theta = \dfrac{3}{4} $}} \\\\\text{then }\\\theta = \tan^{-1} \left(\dfrac{3}{4}\right)\\\\= 36.87^\circ \text{ in Q1}\\[/tex]

But since tan θ is periodic it will also be 3/4 in Q3 which is 180° + 36.87 = 216.87°

sin θ  is negative in Q3  with sin(216.87) = - 3/5
so  this choice is incorrect
csc (θ) = 1/(sin θ) = -5/3 so correct
cot (θ) = 1/tan (θ) = 4/3 so correct
cos(θ) =cos(216.87) = -4/5 so correct
sec(θ) = 1/cos(θ) = -5/4 so this choice is incorrect

HW4 Distance on the Coordinate Plane
Find the perimeter of the trapezoid.
456
P
B
G
10
Units

Answers

The required perimeter of the trapezoid is22 units.

How to find the perimeter of trapezoid?

The given vertices of the trapezoid are (1,3), (4,7), (9,7), and (9,3). To find the perimeter of the trapezoid, we need to add up the lengths of all four sides.

We can use the distance formula to find the length of each side of the trapezoid:

[tex]{Side 1: }&(1,3) \text{ to } (4,7) \&d = \sqrt{(4 - 1)^2 + (7 - 3)^2} = \sqrt{9 + 16} = 5 \\\text{Side 2: }&(4,7) \text{ to } (9,7) \&d = \sqrt{(9 - 4)^2 + (7 - 7)^2} = \sqrt{25} = 5 \\\text{Side 3: }&(9,7) \text{ to } (9,3) \&d = \sqrt{(9 - 9)^2 + (3 - 7)^2} = \sqrt{16} = 4 \\\text{Side 4: }&(9,3) \text{ to } (1,3) \&d = \sqrt{(1 - 9)^2 + (3 - 3)^2} = \sqrt{64} = 8\end{align*}[/tex]

Therefore, the perimeter of the trapezoid is:

[tex]$\begin{align*}P &= \text{Side 1} + \text{Side 2} + \text{Side 3} + \text{Side 4} \&= 5 + 5 + 4 + 8 \&= 22\end{align*}[/tex]

Thus, the perimeter of the trapezoid is22 units.

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which of the following is equivalent to 3/8? -0.6, square root of 100, 2/5, -2/3, 0.35217534 ...

Answers

The option in the question that is equivalent to 3/8 is 2/5.

How to calculate the equivalent of 3/8

We can simplify 3/8 and 2/5 so that they have a common denominator:

3/8 = 3*(5/5)/(85/5) = 15/40

2/5 = 2(8/8)/(5*8/8) = 16/40

Since 15/40 and 16/40 have the same denominator, we can compare their numerators to see which is larger:

15/40 < 16/40

Since 16/40 is larger, we can conclude that 2/5 is greater than 3/8.

Therefore, the option that is equivalent to 3/8 is 2/5.

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give three examples of contracts you are currently a part of or have been a part of in the past. identify whether they are unilateral or bilateral; express or implied; executed or executory.

Answers

The three examples of contracts are:

Employment ContractRental AgreementPurchase Agreement

Contracts are legal agreements between two or more parties that involve the exchange of goods, services, or money. They can be classified as unilateral or bilateral, express or implied, executed or executory.

Here are three examples of contracts that a person can be a part of:

Employment Contract: An employment contract is a bilateral, express contract between an employer and an employee. It defines the terms and conditions of employment, including salary, benefits, and job responsibilities. An employment contract is executed when both parties have agreed to the terms of the agreement and have signed the contract.Rental Agreement: A rental agreement is a unilateral or bilateral, express or implied, executory contract between a landlord and a tenant. It outlines the terms of the lease, such as the duration of the tenancy, rent, security deposit, and maintenance responsibilities. A rental agreement can be either oral or written. It is considered executed when the tenant moves in and starts paying rent.Purchase Agreement: A purchase agreement is a bilateral, express contract between a buyer and a seller. It outlines the terms of the sale, including the price, payment terms, delivery method, and warranty. A purchase agreement is executed when the buyer pays the agreed-upon amount and the seller delivers the product or service.

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Gary's backpack weighs 1.2 pounds. His math textbook weighs 3.75 pounds, and his science textbook weighs 2.85 pounds. How much will his backpack weigh with the math and science textbooks in it?

Answers

Answer:

To find out how much Gary's backpack will weigh with the math and science textbooks in it, we need to add the weight of the textbooks to the weight of the backpack:

Total weight = backpack weight + math textbook weight + science textbook weight

Total weight = 1.2 + 3.75 + 2.85

Total weight = 7.8 pounds

Therefore, Gary's backpack will weigh 7.8 pounds with the math and science textbooks in it.

Answer: His backpack will weigh 7.8 pounds

Step-by-step explanation:

Gary's backpack already weights 1.2 pounds without the science and math textbook, now we add the weights of both the math and science textbook.

1.2 + 3.75 = 4.95

4.95 is the weight with only his math textbook in his bag

now we add the science textbooks weight to 4.95

4.95 + 2.85 = 7.8

7.8 is the weight of his backpack with both his science and math textbook in his bag

Daniel is paid an hourly rate of $9. 00 plus six percent commission on direct phone sales. Last week he worked 48 hours and received $72. 00 in commissions. What was his pay for the week?

Answers

Daniel's pay for the week was $504.00, which includes his hourly pay and his commission on direct phone sales.

To calculate Daniel's pay for the week, we need to find his total earnings, which include his hourly wage and his commission on direct phone sales.

First, let's calculate his commission on direct phone sales. We know that he received $72.00 in commissions, and we also know that his commission is six percent of his sales. So, we can use the formula:

Commission = Sales x Commission Rate

To find his sales, we can rearrange the formula to:

Sales = Commission / Commission Rate

Plugging in the given values, we get:

Sales = $72.00 / 0.06 = $1200.00

So, Daniel's direct phone sales for the week were $1200.00.

Now, let's calculate his hourly pay. He worked for 48 hours at a rate of $9.00 per hour, so his hourly earnings were:

Hourly Pay = Hours Worked x Hourly Rate

Hourly Pay = 48 x $9.00 = $432.00

Finally, we can add his commission and his hourly pay to find his total earnings for the week:

Total Pay = Hourly Pay + Commission

Total Pay = $432.00 + $72.00

Total Pay = $504.00

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In April, the party and occasions department had an opening inventory at 57,000 at retail. The sell thru percentage rate for April was 28 %, and the closing stock was 49. 0. What were the net sales in the department during the month of April

Answers

The net sales in the department during the month of april is $15960.

Sell-thru perecentage rate = Units sold / Units recieved

In our case:

Net sales = (Sell-thru rate)*(opening inventory)

Net sales = (0.28)*($57000)

= $15960

Net sales refer to the total amount of revenue generated by a company from its primary business operations, minus any returns, allowances, and discounts. This figure reflects the actual revenue earned by a company after accounting for any deductions and is a critical metric for evaluating the financial performance of a business.

Net sales are reported on a company's income statement and are a key component of the top line, which also includes other sources of revenue, such as interest income or gains from the sale of assets. Understanding a company's net sales is essential for assessing its growth potential, profitability, and overall financial health. Investors, creditors, and other stakeholders use net sales as a metric to evaluate a company's ability to generate revenue from its core operations, as well as its ability to compete effectively in its industry.

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For triangles ABC and DEF, ∠A ≅ ∠D and B ≅ ∠E. Based on this information, which statement is a reasonable conclusion?
a. ∠C ≅ ∠D because they are corresponding angles of congruent triangles.
b. CA ≅ FD because they are corresponding parts of congruent triangles.
c. ∠C ≅ ∠F because they are corresponding angles of similar triangles.
d. AB ≅ DE because they are corresponding parts of similar triangles.

Answers

the triangles are similar, corresponding parts of the triangles are equal in measure. Thus, it is reasonable to conclude that [tex]AB ≅ DE.[/tex]

It is reasonable to conclude that [tex]AB ≅ DE[/tex]because triangles ABC and DEF are similar.

This means that corresponding parts of the two triangles are equal in measure. Specifically, ∠A and ∠D are equal in measure, as are ∠B and ∠E.

Therefore, the corresponding sides AB and DE are equal in measure.

A way to show that the two triangles are similar is by using the AA Similarity Postulate.

This postulate states that if two angles of one triangle are equal in measure to two angles of a second triangle, then the two triangles are similar. In this case, [tex]∠A ≅ ∠D and B ≅ ∠E[/tex], which means the two triangles are similar.

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Select the correct answer.
Solve:

|x − 3| − 10 = -5

A.
x = -2 or x = 8
B.
x = -8 or x = 2
C.
x = 2 or x = 8
D.
x = 8 or x = 18

Answers

Answer:

A. x = -2 or x = 8

Good luck!!

Step-by-step explanation:

(x - 3) - 10 = -5

x - 3 = - 5 + 10

x - 3 = 5

x = 5 + 3

x = 8

Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 15 people took the trip. She was able to purchase coach tickets for ​$220 and first class tickets for ​$910. She used her total budget for airfare for the​ trip, which was ​$8130. How many first class tickets did she​ buy? How many coach tickets did she​ buy?

Answers

Let's use x to represent the number of coach tickets that Sarah purchased, and y to represent the number of first class tickets. Since a total of 15 people took the trip, we know that:

x + y + 1 = 15

where the extra 1 represents Sarah.

We also know that Sarah used her entire budget of $8130 for airfare, so we can write an equation for the cost of the tickets:

220x + 910y = 8130

Now we have a system of two equations with two variables. We can solve for x and y using substitution or elimination.

Using substitution, we can solve for x in terms of y from the first equation:

x + y + 1 = 15 => x = 14 - y

Substituting this expression for x into the second equation, we get:

220(14 - y) + 910y = 8130

3080 - 220y + 910y = 8130

690y = 5050

y = 7.319 (rounded to three decimal places)

Since we cannot purchase a fractional number of tickets, we need to round y to the nearest whole number. Since y represents the number of first class tickets, Sarah must have purchased either 7 or 8 first class tickets.

If she purchased 7 first class tickets, then the number of coach tickets would be:

x = 14 - y = 14 - 7 = 7

This would result in a total cost of:

220(7) + 910(7) = 6440

But since Sarah's budget was $8130, she must have purchased more first class tickets than this.

If she purchased 8 first class tickets, then the number of coach tickets would be:

x = 14 - y = 14 - 8 = 6

This would result in a total cost of:

220(6) + 910(8) = 7280

This is less than Sarah's budget of $8130, so it is a possible solution.

Therefore, Sarah purchased 8 first class tickets and 6 coach tickets.

Simplify 4 triangles to 16 squares

Answers

The expression 4 triangles to 16 squares when simplified is 1 triangle to 4 squares

How to simplify the expression

Given that

4 triangles to 16 squares

When expressed as ratio, we have

Triangle : Square = 4 : 16

To simplify the ratio Triangle : Square = 4 : 16, we can divide both the numerator and denominator by their greatest common factor, which is 4.

So, we have

Triangle : Square = 4 : 16

Divide both sides by 4:

Triangle/4 : Square/4 = 1 : 4

So the simplified ratio is 1 : 4, which means for every one triangle, there are four squares.

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How to do matrix multiplication in MIPS?

Answers

To perform matrix multiplication in MIPS, we can use nested loops to iterate over the rows and columns of the matrices.

The outer loop iterates over the rows of the first matrix, while the inner loop iterates over the columns of the second matrix. We then perform the dot product of the corresponding row and column, which involves multiplying the elements and summing the products.

To perform multiplication efficiently, we can use MIPS registers to store intermediate values and avoid accessing memory unnecessarily. We can also use assembly instructions like "lw" and "sw" to load and store values from memory, and "add" and "mul" to perform arithmetic operations.

In summary, matrix multiplication in MIPS involves nested loops, efficient use of registers and assembly instructions, and arithmetic operations.

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This is the Challenge:

There is a race consisting of 10 individual races in a row. You are able to bet on the racecars for a chance to multiply your money. The potential payout and chances of winning per racer are listed below.

Blue

- 30% Chance of winning

- 2x Payout on winning bids

Red

- 25% Chance of winning

- 2.5x Payout on winning bids

Purple

- 18% Chance of winning

- 3x Payout on winning bids

Yellow

- 10% Chance of winning

- 5x Payout on winning bids

Black

- 8% Chance of winning

- 7x Payout on winning bids

Green

- 5% Chance of winning

- 10x Payout on winning bids

Orange

- 3% Chance of winning

- 15x Payout on winning bids

Pink

- 1% Chance of winning

- 50x Payout on winning bids

At the end of the race, bets placed on the top 3 winning racecars will be paid back to the player depending on the sheep's placement

1st Place: 100% Bet Payout

2nd Place: 40% Bet Payout

3rd Place: 10% Bet Payout

All other bets placed on non top 3 place racecar will be lost

You can safely assume that if one is likely to win but doesn't win then they are statistically most likely to come second and so on

During the 10 rounds, what is the most efficient bets to increase your money?

Answers

Calculating the expected value of payout using the probabilities given, we can bet on blue for all 10 races, bet on red for all 10 races and bet on purple for all 10 races

What is the most efficient bets to increase the return?

To determine the most efficient bets to increase your money during the 10 rounds, we need to consider the probability and potential payout for each racecar. We can start by calculating the expected value of each racecar's payout:

Blue: 0.3 x 2 = 0.6

Red: 0.25 x 2.5 = 0.625

Purple: 0.18 x 3 = 0.54

Yellow: 0.1 x 5 = 0.5

Black: 0.08 x 7 = 0.56

Green: 0.05 x 10 = 0.5

Orange: 0.03 x 15 = 0.45

Pink: 0.01 x 50 = 0.5

Based on the expected value of payout, the most efficient bets would be on the racecars with the highest expected value. However, we also need to consider the probability of each racecar winning or placing in the top 3.

To maximize our chances of winning, we should bet on the racecars with the highest probability of winning or placing in the top 3, even if their expected payout is not the highest.

Assuming that if one racecar is likely to win but doesn't win, they are statistically most likely to come second, and so on, we can rank the racecars in terms of their probability of winning or placing in the top 3:

1. Blue - 30% chance of winning

2. Red - 25% chance of winning

3. Purple - 18% chance of winning

4. Black - 8% chance of winning

5. Yellow - 10% chance of winning

6. Green - 5% chance of winning

7. Orange - 3% chance of winning

8. Pink - 1% chance of winning

Based on this ranking, the most efficient bets would be as follows:

1. Bet on Blue for all 10 races. The expected payout is not the highest, but the probability of winning is the highest at 30%.

2. Bet on Red for all 10 races. The probability of winning is the second-highest at 25%.

3. Bet on Purple for all 10 races. The probability of winning is the third-highest at 18%.

Betting on these three racecars will give you the highest chance of winning or placing in the top 3, and therefore, the most efficient bets to increase your money. However, keep in mind that gambling always carries risks, and there is no guarantee of winning.

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The following is a list of prices for zero-coupon bonds of various maturities. a. Calculate the yield to maturity for a bond with a maturity of (i) one year; (ii) two years; (iii) three years; (iv) four years. Assume annual coupon payments. (Do not round intermediate calculations. Round your answers to 2 decimal places.) YTM Maturity (Years) 1 Price of Bond $ 945.90 $ 911.47 % 2 % 3 $ 835.62 % % 4 $ 770.89 b. Calculate the forward rate for (i) the second year; (ii) the third year; (iii) the fourth year. Assume annual coupon payments. (Do not round intermediate calculations. Round your answers to 2 decimal places.) Maturity (years) 1 2 3 4 Price of Bond $ 945.90 911.47 835.62 770.89 Forward Rate Maturity (Years) 2 3 $ % Price of Bond 911.47 835.62 770.89 $ $ 4 % The following is a list of prices for zero-coupon bonds of various maturities. a. Calculate the yield to maturity for a bond with a maturity of (i) one year; (ii) two years; (iii) three years; (iv) four years. Assume annual coupon payments. (Do not round intermediate calculations. Round your answers to 2 decimal places.) Answer is complete and correct. Maturity (Years) YTM 1 $ 5.72 % $ Price of Bond 945.90 911.47 835.62 770.89 2 3 4.74 6.17 >>> % % % 4 S 6.72 b. Calculate the forward rate for (i) the second year; (ii) the third year; (iii) the fourth year. Assume annual coupon payments. (Do not round intermediate calculations. Round your answers to 2 decimal places.) Maturity (years) 1 2. 3 4 Price of Bond $ 945.90 911.47 835.62 770.89 Answer is complete but not entirely correct. Price of Bond Forward Rate Maturity (Years) 2 $ 911.47 3.79 % 3.60 X % 3 $ 835.62 4 770.89 2.89 x %

Answers

For the fourth-year forward rate: The forward rate is equaI to [(770.89/835.62)(1/(4-3)] - 1 = 0.0289 or 2.89% .

What is equation ?  

An equation in mathematics is a cIaim that two mathematicaI expressions are equivaIent. The Ieft-hand side (LHS) and the right-hand side (RHS), which are separated by the equaI sign ("="), make up an equation. Equations are a common tooI for probIem-soIving and determining the vaIue of an unknowabIe variabIe since they are used to describe mathematicaI reIationships.

given

I For a bond having a one-year maturity:

[tex]YTM = [(1000/945.90)^{(1/1)}] - 1 = 0.0572 or 5.72%[/tex]

(ii) For a bond having a two-year maturity:

[tex]YTM = [(1000/911.47)^{(1/2)}] - 1 = 0.0474 or 4.74%[/tex]

(iii) For a bond having a three-year maturity:

[tex]YTM = [(1000/835.62)^{(1/3)}] - 1 = 0.0617 or 6.17%[/tex]

(iv) For a bond with a four-year maturity:

[tex]YTM = [(1000/770.89)^{(1/4)}] - 1 = 0.0672 or 6.72%[/tex]

We can use the foIIowing formuIa to determine the forward rates:

Forward rate is equaI to [((Bond Price 1/Bond Price 2)(1/(n2-n1))]]. - 1

where n₂-n₁ is the time period between the maturities, Price of Bond 1 is the price of the bond with maturity n₁, and Price of Bond 2 is the price of the bond with maturity n₂.

We may determine the forward rates using the bonds' current prices by foIIowing these steps:

I For the second-year forward rate:

((911.47/945.90)(1/(2-1))) is the forward rate. - 1 = 0.0379 or 3.79%

(ii) For the third-year forward rate:

The forward rate is equaI to [((835.62/911.47)(1/(3-2))] - 1 = 0.0360 or 3.60%

For the fourth-year forward rate: The forward rate is equaI to [(770.89/835.62)(1/(4-3)] - 1 = 0.0289 or 2.89% .

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Square ABCD is similar to square EFGH. The ratio of AB:EF is 1:4. The area of square EFGH is 14,400ft ft squared by 2. What is AB?

Answers

The Length of AB in square ABCD is 30 feet.

Since the squares ABCD and EFGH are similar, their corresponding sides are proportional, so we can set up the following relation:

AB/EF = 1/4

We can also use the fact that the ratio of the areas of two similar figures is equal to the square of the ratio of their corresponding sides. Therefore,

AB²/EF² = (Area of square ABCD)/(Area of square EFGH)

Substituting the given values:

AB²/EF² = (Area of square ABCD)/(14400)

Since the areas of squares are proportional to the square of their sides, we can write,

Area of square ABCD/Area of square EFGH = (AB/EF)²

Substituting this into the above equation and solving for AB, we get,

AB²/EF² = (AB/EF)²

AB² = (AB/EF)² * EF²

AB² = (1/4)² * 14400

AB² = 900

AB = 30 feet

Therefore, the length of the side AB of square ABCD is 30 feet.

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You put $200 at the end of each month in an investment plan that pays an APR of 4. 5%. How much will you have after 18 years? Compare this amount to the total deposits made over the time period.

a.

$66,370. 35; $43,200

c.

$66,380. 12; $43,000

b.

$66,295. 23; $43,000

d.

$66,373. 60; $43,200

Answers

As per the given APR, the sum of amount after 18 years is $66,373. 60, and the total deposits made over the time period is  $43,200. (option d).

To calculate this, we can use the formula for future value of an annuity:

FV = PMT x (((1 + r)⁻¹) / r)

where FV is the future value, PMT is the monthly payment, r is the monthly interest rate (which is calculated by dividing the APR by 12), and n is the number of payments (which is 18 x 12 = 216 in this case).

Plugging in the numbers, we get:

FV = $200 x (((1 + 0.045/12)²¹⁶ - 1) / (0.045/12)) = $66,373.60

Therefore, you would have approximately $66,373.60 in your investment plan after 18 years.

Now let's compare this amount to the total deposits made over the time period. In this case, the total deposits would be:

$200 x 12 x 18 = $43,200

Hence the correct option is (d).

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Please helppp answer A through E. 100 pts plus first person to answer brainliest

Answers

Refer to pic...........

The cat population in catonsville has been recorded since 2010. The population. p. can be represented by the equation p = 1600(2)t where is time in years since the begging of 2010. What was that cat population 2007

A. 4000
B. 200
C. 800
D. 100​

Answers

The cat population in Catonsville in 2007 was 200. The answer is option B.

What is population?

Population refers to the total number of people, animals, or objects in a particular group or area. It is the entire group or collection of individuals, things, or events that we are interested in studying or describing.

According to question:

We can use the given equation to find the cat population at any given time in years since the beginning of 2010. However, to find the population in 2007, we need to make a conversion from years since the beginning of 2010 to years since the beginning of 2007.

From the beginning of 2007 to the beginning of 2010, there are 3 years, so if we subtract 3 from the number of years since the beginning of 2010, we will get the number of years since the beginning of 2007. Therefore, we need to substitute t = -3 into the given equation and solve for p:

[tex]p = 1600(2)^t\\p = 1600(2)^(-3)\\p = 1600(1/8)\\p = 200[/tex]

Therefore, the cat population in Catonsville in 2007 was 200. The answer is option B.

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I need help! Refer to functions n and p. Find the function and write the domain in interval notation.

Answers

Answer:

To find the function of n(p(x)), we substitute p(x) for x in the function n(x):

n(p(x)) = p(x) + 4

n(p(x)) = x^2 + 6x + 4

The domain of p(x) is all real numbers. Therefore, we need to find the domain of n(p(x))

To find the domain of n(p(x)), we need to consider the domain of p(x) that makes n(p(x)) a real number. Since the coefficient of the x^2 term is positive, the graph of the function p(x) is a parabola that opens upwards, which means that it has a minimum value. The minimum value of p(x) occurs at x = -3, where p(-3) = 9 - 18 = -9

Therefore, the range of p(x) is [ -9, ∞ ). To ensure that n(p(x)) is a real number, we need to have p(x) ≥ -4. Therefore, the domain of n(p(x)) is [ -3 - 2√5, -3 + 2√5 ] or ( -∞, -3 - 2√5 ] ∪ [ -3 + 2√5, ∞)

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