If 2^x=3^y=12^z then prove it 2/x = 1/z -1/y.​

GIVEN -> Triangles r similar

so sides r in ratio

[tex] \frac{2.4}{3} = \frac{2.8}{x} \\ 0.8 = \frac{2.8}{x} \\ x = \frac{2.8}{0.8} \\ x = \frac{28}{8} \\ x = 3.5 \: \: ans[/tex]

Answer:

3.5

Step-by-step explanation:

We can write a ratio to solve

2.4      2.8

----- = --------

3         x

Using cross products

2.4x = 3(2.8)

2.4x =8.4

Divide each side by 2.4

2.4x /2.4 = 8.4/2.4

x = 3.5

Answer: the radius is perpendicular to the chord.

If a radius of a circle bisects a chord which is not diameter, then the radius is perpendicular to the chord.

Answered by Gauthmath must click thanks and mark brainliest

The radius is perpendicular to the chord.

If the radius of the circle is perpendicular to the chord of the circle, the radius bisects the chord. The two strings are congruent only if they are equidistant from the center of the circle.

No, not all strings in a circle are diameters because the diameter passes through the center of the circle. Therefore, all the diameters of a circle are also strings, not all the strings of a circle.

Learn more about chord at

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#SPJ2

Answer:

51 miles

Step-by-step explanation:

Boat with 7 gallons of gas = 21 miles

Boat with 1 gallon of gas = 21/7 = 3 miles

Boat with 17 gallons of gas = 17 x 3 = 51 miles

Answer:

51 miles

Step-by-step explanation:

1 gallon = 3 miles

17 gallons = ? miles

17 * 3 = 51 miles

[tex]\sf\huge\underline\color{pink}{༄Answer:}[/tex]

[tex]\tt3 \frac{1}{3} = \frac{x}{6} \\ = \tt \frac{10}{3} = \frac{x}{6} \\ = \tt \frac{x}{6} = \frac{10}{3} \\ = \tt6 \frac{x}{6} = 6( \frac{10}{3} ) \\ = \tt\large\boxed{\tt{\color{pink}{x = 20}}}[/tex]

[tex]\color{pink}{==========================}[/tex]

#CarryOnLearning

Answer:

the average number of cars waiting in line L[tex]q[/tex] is 0.45

Step-by-step explanation:

Given the data in the question;

Cars arrive at an automatic car wash system every 10 minutes on average.

Car arrival rate λ = 1 per 10 min = [ 1/10 × 60 ]per hrs = 6 cars per hour

Washing time for each is 6 minutes per car

Car service rate μ = 6min per car = [ 1/6 × 60 ] per hrs = 10 cars per hour

so

P = λ/μ = 6 / 10 = 0.6

Using the length of queue in M/D/1 system since there is only one service bay;

L[tex]q[/tex] = [tex]\frac{1}{2}[/tex][ P² / ( 1 - P ) ]

so we substitute

L[tex]q[/tex] = [tex]\frac{1}{2}[/tex][ (0.6)² / ( 1 - 0.6 ) ]

L[tex]q[/tex] = [tex]\frac{1}{2}[/tex][ 0.36 / 0.4 ]

L[tex]q[/tex] = [tex]\frac{1}{2}[/tex][ 0.9 ]

L[tex]q[/tex] = 0.45

Therefore, the average number of cars waiting in line L[tex]q[/tex] is 0.45

Answer:

Whole number —> X

Twice the square of the number —> 2X²

X + 2X² = 10

2X²+X –10 =0

(2x + 5) ( x–2) =0

2x +5=0 —> 2x= – 5 —> x= – 5/2 = —> x= - 2.5 (rejected)

x–2=0 —> x= 2

So Ans ; X= 2 ( the number )

I hope I helped you^_^

Answer:

125000000

Step-by-step explanation:

1.25 x 10^8

Move the decimal 8 places to the right

1.25

We can move it two places

125

We need to add 6 more zeros

125000000

Answer: 125,000,000

Step-by-step explanation:

Given:

The given values are:

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

[tex]r^2=0.9435996398[/tex]

[tex]r=0.9713905701[/tex]

To find:

The exponential regression equation for the given values (Rounded to three decimal places).

Solution:

The general form of exponential regression equation is:

[tex]y=a\cdot b^x[/tex]          ...(i)

Where, a is the initial value and b is the growth/decay factor.

We have,

[tex]a=0.2094539899[/tex]

[tex]b=2.507467975[/tex]

Round these numbers to three decimal places.

[tex]a\approx 0.209[/tex]

[tex]b\approx 2.507[/tex]

Substitute [tex]a=0.209, b=2.507[/tex] in (i) to find the exponential regression equation.

[tex]\hat{y}=0.209\cdot 2.507^x[/tex]

Therefore, the correct option is C.

Answer: I'm not Einstein sorry

Step-by-step explanation:

Have to be smart as Einstein.................Which I'm not

Answer:

12/55

Step-by-step explanation:

Probability is the ratio of the number of possible outcomes to the number of total outcomes.

Given that the bag contains 8 red balls and 3 white balls, the probability of picking a red ball

p(r) = 8/(8+3) = 8/11

Probability of picking a white ball

= 3/11

when a red ball is picked first, the total number of balls reduces to 10 hence the probability that the second ball is white, given that the first ball is red

=8/11 * 3/10

= 24/110

= 12/55

Answer: 0.38

Step-by-step explanation:

Since the variable x is represented by a standard normal distribution, the probability of x > 0.3 will be calculated thus:

P(x > 0.3)

Then, we will use a standard normal table

P(z > 0.3)

= 1 - p(z < 0.3)

= 1 - 0.62

= 0.38

Therefore, p(x > 0.3) = 0.38

The probability of x > 0.3 is 0.38.

Answer:

All of area is πr²

Step-by-step explanation:

and we should write the area kind of radian. So if all area is π*(12)²= 144π - this for 360°- and 240° is 96π

but we must add area of the triangle which has two same side and has 6 high so it's area is 6*12√3/2 = 36✓3

our answer is 96π+ 36✓3

Answer:

Hello,

5 s

Step-by-step explanation:

[tex]h(t)=-16t^2+48t+160\\=-16(t^2-3t-10)\\=-16(t^2-5t+2t-10)\\=-16(t(t-5)+2(t-5))\\=-16(t-5)(t+2)\\\\h(t)=0 \Longleftrightarrow\ t=-2\ or\ t=5\\\\Only\ t=5\ is \ a\ answer.(time\ must\ be\ positive)[/tex]

Answer:

1 + 7n

Step-by-step explanation:

7-(3n+6)+10n​

7 - 3n - 6 + 10 n

1 - 7n

Answered by Gauthmath

Answer:

20+(x+1) = 5x

x=21/4

x= 5.25

The entrance ticket per person can be calculated using algebraic equation. We have create the algebraic expression as per the question.

The entrance ticket per person is Rs. 5.25.

Given:

Total boys are 5

4 boys has 5 rupee each so total rupee are [tex]=5\times 4=20[/tex].

Let the entrance ticket per boy is [tex]x[/tex].

One boy had 1 rupee more than entrance ticket [tex](x+1)[/tex].

Write the algebraic expression to calculate the entrance ticket per person.

[tex]5x=20+(x+1)\\5x=20+x+1\\5x-x=20+1\\4x=21\\x=5.25[/tex]

Thus, the entrance ticket per person is Rs. 5.25.

Learn more about algebraic expression here:

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Answer:

The answer is A

Step-by-step explanation:

The answer needs to be in slope-intercept form or y=mx+b because the amount of carpet being cleaned every minute is a constant decrease of 9 square feet.

So our b value (or how much carpet cleaned at 0 minutes) is 220

And our m value (or slope or how much carpet is being cleaned every minute) is 9

So if we plug the variables with the tangible numbers we get A(t) = -9x+220 or A(t) = 220-9x.

provided by gauth math

Answer:

see below

Step-by-step explanation:

Part A

The slope is found by

m = ( y2-y1)/(x2-x1)

    = ( 1200-1500)/(4-0)

    = -300/4

    =-75

Part B

point slope  y-y1 = m(x-x1)  where m is the slope and (x1,y1) is a point on the line

y-1200 = -75(x-4)

slope intercept  y = mx+b  where m is the slope and b is the y intercept

y = -75x + 1500

standard form  Ax+By =C

75x + y = 1500

Part C

Change y to g(x) in the slope intercept form

g(x) = -75x + 1500

Part D

Let x = 5

g(5) = -75(5) + 1500

      =-375+1500

      =1125

Answer:

The situation that represents this situation is:

[tex]t = \frac{60}{n}[/tex]

Step-by-step explanation:

The amount of time t needed to assemble the set is inversely  proportional to the number people n working.

This means that:

[tex]t = \frac{k}{n}[/tex]

In which k is the constant of proportionality.

Twelve people can assemble the set in 5 hours.

This means that for [tex]n = 12, t = 5[/tex]. We use this to find k.

[tex]t = \frac{k}{n}[/tex]

[tex]5 = \frac{k}{12}[/tex]

[tex]k = 12*5 = 60[/tex]

Write an equation to represent the situation.

[tex]t = \frac{60}{n}[/tex]

The 3rd one

Step-by-step explanation:

Reason being that it has no factors, meaning it cannot be simplified any further, but quadratic method can be used to attain factors.

hope it makes sense :)

Answer:

c=80

Step-by-step explanation:

Based on my reading the critical damping occurs when the discriminant of the quadratic characteristic equation is 0.

So let's see that characteristic equation:

20⁢r^2+c⁢r+80⁢=0

The discriminant can be found by calculating b^2-4aC of ar^2+br+C=0.

a=20

b=c

C=80

c^2-4(20)(80)

We want this to be 0.

c^2-4(20)(80)=0

Simplify:

c^2-6400=0

Add 6400 on both sides:

c^2=6400

Take square root of both sides:

c=80 or c=-80

Based on further reading damping equations in form

a⁢y′⁢′+b⁢y′+C⁢y=0

should have positive coefficients with b also having the possibility of being zero.

Answer:

It's a negative.

Step-by-step explanation:

The value of a positive number is still a positive number.

Answer:

slope= 3/1

y-intercept (0,2)

y= 3/1 b + 2

9514 1404 393

Answer:

Step-by-step explanation:

Reflection over the x-axis changes the sign of the y-coordinate. Reflection over the y-axis changes the sign of the x-coordinate. We can summarize the transformations as ...

  preimage point ⇒ reflection over x ⇒ reflection over y

A(−8,−2) ⇒ A'(-8, 2) ⇒ A"(8, 2)

B(−4,−3) ⇒ B'(-4, 3) ⇒ B"(4, 3)

C(−2,−8) ⇒ C'(-2, 8) ⇒ C"(2, 8)

D(−10,−6) ⇒ D'(-10, 6) ⇒ D"(10, 6)

Answer:

base-2 base-10

110011 = 51

110100 = 52

110101 = 53

110110 = 54

21 more rows

9514 1404 393

Answer:

Step-by-step explanation:

If n represents the number, we have ...

  10(-270 +n) = -20 . . . an equation for n

__

The solution can be found as ...

  -270 +n = -2 . . . . . divide by 10

  n = 268 . . . . . . . add 270

The number is 268.

Answer:

x=1.7099

Step-by-step explanation:

2x³=10

x³=10/2

x³=5

x=∛5

x=1.7099

Step-by-step explanation:

7 times a certain number :

Let the unknown number be x

[tex]7 \times x[/tex]

is less four times that same number -2 is 58 :

7x - 4x -2 = 58

Collect like terms

7x-4x = 58+2

3x = 60

3x/3 = 60/3

x = 20

Let the number be x

ATQ

[tex]\\ \sf\longmapsto 7x-4x-2=58[/tex]

[tex]\\ \sf\longmapsto 3x-2=58[/tex]

[tex]\\ \sf\longmapsto 3x=58+2[/tex]

[tex]\\ \sf\longmapsto 3x=60[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{60}{3}[/tex]

[tex]\\ \sf\longmapsto x=20[/tex]

Answer:

See pic below.

Answer: C. 380°

Step-by-step explanation: