Identify two Pythagorean triples using the known triple 9, 40 , 41. *
Your answer

Answers

Answer 1

Step-by-step explanation:

[tex] {a}^{2} + {b}^{2} = {c}^{2} \\ {9}^{2} + {40}^{2} = {41}^{2} \\ 81 + 1600 = 1681 \\ 1681 = 1681[/tex]


Related Questions

Andre hit 46 balls at practice. He hit no fewer than 20 less than double the number of hits Jason had. Which inequality represents the situation if j represents the number of hits Jason had?
46 minus 20 less-than 2 j
2 j minus 20 less-than-or-equal-to 46
46 minus 20 less-than-or-equal-to 2 j
2 j minus 20 greater-than-or-equal-to 46

Answers

Answer:

  2j -20 ≤ 46

Step-by-step explanation:

"20 less than double the number Jason [hit]" can be represented by 2j-20.

We are told that 46 is no fewer than this value, so it is greater than or equal to this value:

  46 ≥ 2j -20

  2j -20 ≤ 46 . . . . . swapping sides to match answer choices

Answer:

2j -20 ≤ 46

Step-by-step explanation:

7.6 cm
3.7 cm
Find the area of the parallelogram.

Answers

Answer:

7cm²

Step-by-step explanation:

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