Jackson at the collectibles fair. He has exactly $8 and will purchase a collectible from a vendor for $5. What percent of his money will Jackson spend on the purchase?

Answers

Answer 1

Answer:

62.5%

Step-by-step explanation:

Total money with Jackson = $8

Money spent for buying collectible  = $5

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Percentage of any number A with respect to another number B is calculated by multiplying fraction A/B with 100

Numerically A as percentage of b will be expressed as (A/B)100 %

It means that if there are 100 items instead of B item then what will be the value of A.

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Percentage of money spent = (Money spent for buying collectible /Total money with Jackson)

Substituting the total money and money spent for buying collectible

we have

Percentage of money spent  = 5/8 * 100 = 0.625*100 = 62.5%

Thus, 62.5% percent of his money will Jackson spend on the purchase of collectible.


Related Questions

The table shows the cost in dollars, y, for renting a pair of snow skis or renting a snowboard for x days. Which function shows the combined cost in dollars, y, for renting two pairs of snow skis and two snowboards for x days? y = 45x + 60 y = 90x + 120 y = 25x + 25 y = 20x + 35

Answers

Answer: this is the right answer y = 90x + 120

Step-by-step explanation:

there are 12 inches in 1 foot
write an equation to find the number of inches in any number of feet

Answers

Answer:

divide the number of inches by 12

Step-by-step explanation:

1/12=x/12 then you would cross multiply it

A Bowling ball is rolled down the alley with the constant velocity of 1.6 m/sec at an angle of 85° to the starting line, the position of the person throwing a bowling ball can be represented by the point (0,0). where is the ball after six seconds?

Answers

We have been given that a Bowling ball is rolled down the alley with the constant velocity of 1.6 m/sec at an angle of 85° to the starting line, the position of the person throwing a bowling ball can be represented by the point (0,0).

We are asked to find the position of ball after 6 seconds.

We will use horizontal position and vertical position formula to solve our given problem.

Horizontal position is given by formula: [tex]x=v\cdot \text{cos}(\theta)\cdot t[/tex] and vertical position is given by formula: [tex]y=v\cdot \text{sin}(\theta)\cdot t[/tex],where,

v = Velocity,

t = Time,

[tex]\theta[/tex] = Angle to the starting line.

For our given problem [tex]v=1.6[/tex], [tex]t=6[/tex] and [tex]\theta=85^{\circ}[/tex].

[tex]x=1.8\cdot \text{cos}(85^{\circ})\cdot 6[/tex]

[tex]x=10.8 \cdot 0.087155742748[/tex]

[tex]x=0.9412820216784\approx 0.94[/tex]

[tex]y=1.8\cdot \text{sin}(85^{\circ})\cdot 6[/tex]

[tex]y=10.8\cdot 0.996194698092[/tex]

[tex]y=10.7589027\approx 10.76[/tex]

Therefore, the position of ball after 6 seconds would be [tex](0.94,10.76)[/tex].

Answer:

(0.8,9.6)

Step-by-step explanation:

x=1.6*cos85* 6=0.8

y=1.6*sin85 *6=9.6

Find the interquartile range (IQR) of the data in the box plot below.

Asap ASAP Please PLZ

Answers

Answer:

3

Step-by-step explanation:

IQR is the difference between the upper and lower medians so the IQR = 7 - 4 = 3

The interquartile range (IQR) of the data in the given box plot is: 3.

What is the Interquartile Range (IQR) of a Data?

In a box plot, the interquartile range (IQR) is the difference between the upper quartile and the lower quartile which are represented as each edge of the rectangular box.

Upper quartile = 7Lower quartile = 4

Interquartile range (IQR) = 7 - 4

Interquartile range (IQR) = 3

Learn more about Interquartile range (IQR) on:

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