Answer:
whats the question that u need help with
there are 12 inches in 1 foot
write an equation to find the number of inches in any number of feet
Answer:
divide the number of inches by 12
Step-by-step explanation:
Jackson at the collectibles fair. He has exactly $8 and will purchase a collectible from a vendor for $5. What percent of his money will Jackson spend on the purchase?
Answer:
62.5%
Step-by-step explanation:
Total money with Jackson = $8
Money spent for buying collectible = $5
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Percentage of any number A with respect to another number B is calculated by multiplying fraction A/B with 100
Numerically A as percentage of b will be expressed as (A/B)100 %
It means that if there are 100 items instead of B item then what will be the value of A.
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Percentage of money spent = (Money spent for buying collectible /Total money with Jackson)
Substituting the total money and money spent for buying collectible
we have
Percentage of money spent = 5/8 * 100 = 0.625*100 = 62.5%
Thus, 62.5% percent of his money will Jackson spend on the purchase of collectible.
The table shows the cost in dollars, y, for renting a pair of snow skis or renting a snowboard for x days. Which function shows the combined cost in dollars, y, for renting two pairs of snow skis and two snowboards for x days? y = 45x + 60 y = 90x + 120 y = 25x + 25 y = 20x + 35
Answer: this is the right answer y = 90x + 120
Step-by-step explanation:
Which is the longest length?
a 1 yd. 20 in.
b 1yd. 1 ft.
С
40 in.
d 3 ft.
Answer:
a-1yd20in
Step-by-step explanation:
a-4ft 8in
b-4ft
c-3ft 4in
d-3ft
Answer:
it's A, one yard and 20 inches
Step-by-step explanation:
If you convert them all to inches, a yard and a 20 inches are equal to 56 inches, so you can rule out the 40 inches answer. a yard and a foot are equal to 48 inches, so we can rule out that also. 3 feet is equal to 36 inches, because we know that a foot is equal to 12 inches. so you are left with A. 1 yard and 20 inches.
Find the interquartile range (IQR) of the data in the box plot below.
Asap ASAP Please PLZ
Answer:
3
Step-by-step explanation:
IQR is the difference between the upper and lower medians so the IQR = 7 - 4 = 3
The interquartile range (IQR) of the data in the given box plot is: 3.
What is the Interquartile Range (IQR) of a Data?In a box plot, the interquartile range (IQR) is the difference between the upper quartile and the lower quartile which are represented as each edge of the rectangular box.
Upper quartile = 7Lower quartile = 4Interquartile range (IQR) = 7 - 4
Interquartile range (IQR) = 3
Learn more about Interquartile range (IQR) on:
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A Bowling ball is rolled down the alley with the constant velocity of 1.6 m/sec at an angle of 85° to the starting line, the position of the person throwing a bowling ball can be represented by the point (0,0). where is the ball after six seconds?
We have been given that a Bowling ball is rolled down the alley with the constant velocity of 1.6 m/sec at an angle of 85° to the starting line, the position of the person throwing a bowling ball can be represented by the point (0,0).
We are asked to find the position of ball after 6 seconds.
We will use horizontal position and vertical position formula to solve our given problem.
Horizontal position is given by formula: [tex]x=v\cdot \text{cos}(\theta)\cdot t[/tex] and vertical position is given by formula: [tex]y=v\cdot \text{sin}(\theta)\cdot t[/tex],where,
v = Velocity,
t = Time,
[tex]\theta[/tex] = Angle to the starting line.
For our given problem [tex]v=1.6[/tex], [tex]t=6[/tex] and [tex]\theta=85^{\circ}[/tex].
[tex]x=1.8\cdot \text{cos}(85^{\circ})\cdot 6[/tex]
[tex]x=10.8 \cdot 0.087155742748[/tex]
[tex]x=0.9412820216784\approx 0.94[/tex]
[tex]y=1.8\cdot \text{sin}(85^{\circ})\cdot 6[/tex]
[tex]y=10.8\cdot 0.996194698092[/tex]
[tex]y=10.7589027\approx 10.76[/tex]
Therefore, the position of ball after 6 seconds would be [tex](0.94,10.76)[/tex].
Answer:
(0.8,9.6)
Step-by-step explanation:
x=1.6*cos85* 6=0.8
y=1.6*sin85 *6=9.6
PLS HELP!!!!!! In a survey of 4530 U.S. adults, 87% said that they would like to donate more to charity. What is the margin of error for the survey? Round to the nearest tenth of a percent
Answer:
Margin of Error = 1.0% to the nearest tenth of a percent.
Step-by-step explanation:
Margin of Error is the width of the confidence interval about the mean.
It is given mathematically as,
Margin of Error = (Critical value) × (standard Error)
Critical value is obtained from the z-tables at the popular confidence level of 95% and z-tables is used because the sample size, 4530, is large enough to approximate the population properties.
Critical value = 1.960
Standard error = σₓ = √[p(1-p)/n]
p = 87% = 0.87
n = sample size = 4530
σₓ = √[0.87×0.13)/4530]
= 0.0049966876
Margin of Error = 1.96 × 0.0049966876 = 0.0097935078 = 0.00979 = 0.979% = 1.0% to the nearest tenth of a percent.
Hope this Helps!!!