Hunger and thirst are examples of external stimulus true or false
false External stimulus. The external stimulus includes touch and pain, vision, smell, taste, sound, and balance (equilibrium)
A 9.0V battery is connected across a 2.2kilo ohms and 6.8kilo omhs resistors connected in series. what is the potential differences across 2.2kilo ohms resistor.
Answer:
[tex]V_{2.2} =2.2V[/tex]
Fast and loose: that's a classic voltage divider. the drop from the i-th resistor is [tex]R_i \over {\sum R}[/tex] of the drop across the whole series. In our situation, it's [tex]2.2\cdot 10^3 \over {2.2\cdot10^3 + 6.8\cdot 10^3[/tex] of 9 V. By plugging numbers in a calculator, it's 22/90 of 9V, or 2.2V
With Ohm's Law
The series is equivalent of a single resistor of Resistance [tex]2.2\cdot 10^3+6.8\cdot 10^3 \Omega = 9.0 k\Omega[/tex]. By Ohm's first Law ([tex]V=Ri[/tex]) the current flowing through the resistor is [tex]9V = 9*10^3\Omega i \rightarrow i=1mA[/tex]. At this point, the drop across the first resistor is, again by Ohm's law[tex]V = 2.2 \cdot 10^3 \Omega \cdot 1\cdot 10^{-3} A = 2.2V[/tex]
¿Cuál es el parámetro que indica la cantidad de energía liberada en un movimiento sísmico?
Answer:
Explanation:
en un movimiento sísmico?
this is about the magnet fields. thanks in advance.
Explain what matter is
Answer:
it doesnt matter
Explanation:
matter is what makes up everything around us; anything takin up space
Explanation:
matter can be defined as anything at all that has weight and occupies space
What is the Scientific name for Ectoparasites?
Ectoparasites are a taxonomically diverse group of organisms that infest the skin of human beings and other animals. Ectoparasitic arthropods and nematodes are similar in that an individual organism can produce skin lesions that are large enough to see with the unaided eye. Ectoparasitic infestations are often intensely itchy, causing considerable annoyance and discomfort. These conditions are often focally hyperendemic in impoverished communities, with a particularly high prevalence in vulnerable families, households, and neighborhoods.
Pediculosis (infestation by head and body lice) and scabies are found to some degree in all human populations, but myiasis (fly larva infestation), tungiasis (sand flea disease), and cutaneous larva migrans occur mainly in tropical and subtropical environments. Except for body lice, the organisms discussed in this article are not vectors of pathogenic microorganisms. In other words, most ectoparasites do not carry disease-causing agents; they are, instead, the direct cause of disease. Mortality is low, but the cumulative morbidity from the direct discomfort, secondary bacterial infections, and sequelae of those infestations and infections is considerable.
Despite the abundant presence of ectoparasitic infestations across human populations, biomedical science lacks firm evidence-based practices to reliably control these organisms. In addition, head lice and scabies are developing resistance to some chemical compounds employed to treat infested individuals, prevent spread, and control outbreaks.
Please mark me brainliest.
How far did Michael Phelps swim, if he swam at a speed of 10m/s in 30 seconds?
Answer: his total speed would be 3 seconds
Explanation: because if you mulimply 10 x 3 you get 30 meaning that your answer would be 3
The sandbox of the previous exercises had 10kg of sand. It was initially at 15°C and the specific heat of this sand is 830 j/(kg°C). What will be the final temperature of the sand? (-8100J=|0kg)
Answer:
Sorry I need points [tex] \boxed{}[/tex]
could someone answer this
The given kinematic equations of motion are derived from Newton's Laws
of Motion.
A) The ball's speed the instant it left the soccer player's foot is approximately 11.074 m/s.B) The time it took the ball to rise to its maximum height is approximately 1.129 seconds.
Reasons:
The direction the ball is kicked = Upwards in the air
Maximum height to which the ball rises = 6.25 m
A) The speed of the ball the instant it left the soccer player's foot
Solution:
The equation to use is; v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)
[tex]a_y[/tex] = The acceleration due to gravity ≈ -9.81 m/s²
At the maximum height, y - y₀ = 6.25 m
The velocity at the maximum height, v = 0
v₀ = The speed of the ball the instant it left the soccer player's foot
Which gives;
v² = v₀² + 2·[tex]a_y[/tex]·(y - y₀)
0 = v₀² - 2 × 9.81 × (6.25) = v₀² - 122.625
v₀² = 122.625
v₀ = √(122.625) ≈ 11.074
The ball's speed the instant it left the soccer player's foot, v₀ ≈ 11.074 m/s.
B) Required:
The time it takes the soccer ball to rise to the maximum height.
Solution:
The equation of motion required is v = v₀ + [tex]a_y[/tex]·t
At the maximum height, v = 0
v₀ ≈ 11.074 m/s
v = v₀ + [tex]a_y[/tex]·t
Which gives;
0 = 11.074 - 9.81 × t
[tex]t \approx \dfrac{11.074}{9.81} \approx 1.129[/tex]
The time it took the ball to rise to its maximum height, t ≈ 1.129 seconds
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Who is most likely to be offered a higher auto loan rate based on their credit-
to-debt ratio?
A. Juan has $10,000 in credit and owes $6,000.
B. Chester has $5,000 in credit and owes $750
C. Jalissa has $5000 in credit and owes $500.
credjtar
D. Nancy has $10,000 in credit and owes $2,000.
SUBMIT
HELP ME PLEASE
Answer:
A - Juan
Explanation:
I took the test!
Two Force 16N and 4N acts at rights angle each other calculate the resultant force
When a capacitor is charged, the electric field E, and hence the electric flux Φ, between the plates changes. This change in flux induces a magnetic field, according to Ampère's law as extended by Maxwell: ∮B⃗ ⋅dl⃗ =μ0(I+ϵ0dΦdt). You will calculate this magnetic field in the space between capacitor plates, where the electric flux changes but the conduction current I is zero. A parallel-plate capacitor of capacitance C with circular plates is charged by a constant current I. The radius a of the plates is much larger than the distance d between them, so fringing effects are negligible. Calculate B(r), the magnitude of the magnetic field inside the capacitor as a function of distance from the axis joining the center points of the circular plates. Express your answer in terms of μ0 and given quantities. B(r) =
The magnitude of the magnetic field B(r) inside the capacitor as a function of distance from the axis is [tex]\mathbf{B(r) =\dfrac{\mu_o I r}{2 \pi a^2} }[/tex]
A charged capacitor usually cause changes between the plates of electric field E and the electric flux Φ
As seen in Ampere's law which is extended by Maxwell:
[tex]\mathbf{\oint B^{\to} .dl^{\to} = \mu_o \Big( I+\dfrac{d \phi }{dt} \Big)}[/tex]
To meet the equilibrium equation of electric charge, Maxwell modified Ampere's law by incorporating the displacement current through into electric current component.
∴
The displacement current can be expressed by the relation;
[tex]\mathbf{I = \varepsilon_o \dfrac{dE}{dt} }[/tex]
From the given information, the displacement current density through area A can now be expressed as:
[tex]\mathbf{I = \varepsilon_o A \dfrac{dE}{dt} }[/tex]
Replacing the value of displacement current density into Maxwell modified Ampere Law, we have:
[tex]\mathbf{\oint B .dl= \mu_o I_{enclosed} }[/tex]
[tex]\mathbf{B \times (2 \pi r) = \mu_o I\Big (\dfrac{\pi r^2}{\pi a^2} \Big) }[/tex]
[tex]\mathbf{B(r) =\dfrac{\mu_o I r}{2 \pi a^2} }[/tex]
Learn more about magnetic field here:
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1. A truck is traveling at a speed of 12 km/s is going to school. It took 10 seconds to get to school. What was the distance?
Answer:
120km
Explanation:
To get speed you divide distance by time.
Consider the following arrangement with a frictionless/massless pulley. Determine the force F required to move block A if the coefficient of static friction between block A and the floor is 0.35 and the coefficient of static friction between block A and block B is 0.25
Answer: The free - body diagrams for blocks A and B. frictionless surface by a constant horizontal force F = 100 N. Find the tension in the cord between the 5 kg and 10 kg blocks. The string that attaches it to the block of mass M2 passes over a frictionless pulley of negligible mass. The coefficient of kinetic friction Hk between M.
Explanation: Hope this helped :)
Please can someone solve this for me i will really appreciate it
Answer:
• Average current = 25,000 Amperes
• Time = 0.80 seconds
a)
[tex]{ \rm{quantity \: of \: charge = current \times time}} \\ { \rm{q = 25000 \times 0.80}} \\ { \boxed{ \mathfrak{answer : \: { \rm{quantity \: of \: charge = 20000 \: coulombs}} }}}[/tex]
b)
[tex]{ \rm{number \: of \: electrons = \frac{current}{charge \: quantity} }} \\ \\ { \rm{n = \frac{25000}{20000} }} \\ \\ { \boxed{ \mathfrak{ \: answer : \: { \rm{n = 1.25 \: }}}}}[/tex]
[tex]{ \underline{ \mathfrak{ \green{Good \: grace}} \: \:⚜ \: \: { \blue{ \mathfrak{Good \: God}}}}}[/tex]
what is the formula of parallelogram method to work out the sum of two vectors
Answer:
The sum of vectors P and Q is given by the vector R, the resultant sum vector using the parallelogram law of vector addition. If the resultant vector R makes an angle ϕ with the vector P, then the formulas for its magnitude and direction are: |R| = √(P2 + Q2 + 2PQ cos θ) β = tan-1[(Q sin θ)/(P + Q cos θ)]
What distance does a police car travel if it is going 3.0 m/s for 20 seconds
Answer:
60 meters
Explanation:
If you are going 3 meters in a second, and you are traveling for 20 seconds, you have to multiply
3meters/second*20seconds
cross out the seconds and you have
3 meters*20
60 meters
If the force exerted by the intern is doubled and the dis- tance is halved, does the work done by the intern increase, decrease, or remain the same?
If the force exerted by the intern is doubled and the distance is halved, the work done by the intern remains the same. Work done is the force applied to move a body through a distance.
Answer: Remains the same.
A person travels from C to D. One third of the time travels at v1 = 42km/h, the rest of the time travels at v2 = 36km/h. Find his average speed as he travels from C to D.
Answer:39km/h
Explanation:we know V=(u+v)/2. Here is u=42 and v=36
solve by formulae method and completing the square method. 4x²-29x+7=0
Answer:
(4x - 1) (x - 7)
Explanation:
4x^2 - 29x + 7 = 0
(4*-7=-28) and: (1*- 1 = -1)
-28 - 1 = -29 and - 1 times -7 = 7
You need low pressure to walk on
snow and ice. True or faulse
Answer:
True
Explanation:
Answer: false please give brainliest
Explanation: Reducing air pressure will not give you more traction and your tires could become seriously underinflated, affecting steering.
why is all motion relative
Explanation:
All motions are relative to some frame of reference. Saying that a body is at rest, which means that it is not in motion, merely means that it is being described with respect to a frame of reference that is moving together with the body
Answer:
Motion is always described in relation to a reference point.
Explanation:
For example, if a car is driving at the speed of 30 miles per hour and you are standing by the road, to you, the car appears to be moving 30 miles per hour down the road. However, if you were in a car also driving at 30 miles per hour next to the truck, the same truck wouldn't appear to move.
What is displacement
Answer:
the moving of something from its place or position
or
he occupation by a submerged body or part of a body of a volume which would otherwise be occupied by a fluid
There are 2 different definitions.
1. The moving of something from its place or position.
2. The occupation by a submerged body or part of a body of a volume which would otherwise be occupied by a fluid.
Please help...
Describe energy transformations in your own words.
why is the answer A and not C?
please help!
Answer:
because it gives a complete thought
Un bloque de cobre cuya masa es 250 gramos , absorbe calor y su temperatura se eleva de 20 ˚C a 150 `C. ¿Cuál es la cantidad de calor absorbida por el bloque de cobre?. Expresar el resultado en unidades caloríficas y en unidades mecánicas.
Dada la información de la pregunta, el calor absorbido por el cobre es de 12513 J o 2990 calorías.
El calor ganado se obtiene de la relación;
H = mcdt
Dónde;
H = calor absorbido
m = masa
c = capacidad calorífica del cobre
Δt = cambio de temperatura
La capacidad calorífica del cobre es de 385 J / kg / ° C
Entonces;
m = 250 gramos o 0,25 kg
Δt = 150 ° C - 20 ˚C = 130 ˚C
H = 0,25 kg * 385 J / kg / ° C * 130 ˚C
H = 12513 J o 2990 calorías
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See screen shot...momentum in collision
Please find attached photographs for your answer.
Hope it helps.
Do comment if you have any query.
Question:
A second set of data was obtained using thicker pieces of putty. Both sets of results are shown in graph 2. What is the relationship between the resistance and the thickness of the conducting putty?
The resistance of the thin wire is greater than the resistance of the thick wire because the thin wire has fewer electrons to carry the current. Therefore, for thinner pieces of conducting putty we have the larger resistance and for the thicker pieces of conducting putty we have the lower resistance.
Why is it important to try to use as many renewable resources as possible?
Answer:
It is important to use renewal resources because we use so many non- renewable resources that we may lose the ability to make a lot of things like gasoline or power for our cities.
Select the correct answer.
Planet A Planet B
Distance from Sun 0.72 AU 9.54 AU
Planet composition rocky mantle, iron core hydrogen, helium
Gases in atmosphere very dense atmosphere that is 96.5% poisonous carbon dioxide and 3.5% nitrogen mostly hydrogen and helium
Number of moons 0 62
Rings no rings visible rings
Which planet is planet A?
A.
Mars
B.
Saturn
C.
Uranus
D.
Venus
Answer:
D, Venus
Explanation:
Using the facts
Do I add squared or not?
Answer: add it
Explanation:
