how many quarts make 5 gallons

Answers

Answer 1

Answer:

4 quarts

Hope it helps!

Step-by-step explanation:

Answer 2

Answer: 5 gallons= 20 quarts

              1 gallon = 4 quarts


Related Questions

What decimal number does point A on the number line below represent? A vertical number line is shown from negative 2.00 to 0 to positive 2.00.There are tick marks to show increments of 1 over 4. Only the whole numbers are labeled. Point A is plotted at the third tick mark below negative 1.00. 0.25 −0.25 1.75 −1.75

Answers

Answer: 0.25

Step-by-step explanation:

To find :  decimal number represented by  point A on the given number line.

Given:  Vertical number line is shown from negative 2.00 to 0 to positive 2.00.There are tick marks to show increments of 1 over 4.

Point A is plotted at the third tick .

That means, Point A is marked at 1 over 4.

1 over 4 = [tex]\dfrac{1}{4}=0.25[/tex]    [divide 1 by 4]

Hence, the point A  represents 0.25 on the given number line.

Answer:

Step-by-step explanation:

Where is the picture

15 points! :( help asap!:(
(-1,-5)
(0,-3)
(4,5)
(9,15)

Answers

Answer:

(0,-3)

Step-by-step explanation:

You can plug in x and y into the equations to see if it works.

(-1,5)

2(-1)-(-5)=-2+5=3 Yes

(-1)+2(-5)=-1-10=-11 No

So (-1,5) Does NOT work.

(0,3)

2(0)-(-3)=0+3=3 Yes

(0)+2(-3)=0-6=-6 Yes

So (0,-3) DOES work.

The volume of a sphere whose diameter is 18 centimeters is π cubic centimeters. If its diameter were reduced by half, its volume would be of its original volume.

Answers

Answer:

3053.5517 cm^3 ; 1/8

Step-by-step explanation:

Given the following :

Volume (V) of sphere = (4/3)πr^3 where r = radius

Diameter of sphere = 18 ; radius(r) = diameter / 2 = 18/2 = 9cm

V = (4/3) × π × 9^3

V = 1.3333 × π × 729

V = 3053.5517 cm^3

When diameter(d) is reduced to half

d = d/2

Volume (V1) of sphere with diameter 'd' =

V1 = (4/3)π(d/2)^3

Volume (V2) of sphere with diameter 'd' reduced to half, d = d/2, d/2 * 1/2 = d/4

V2 = (4/3)π(d/4)^3

V1 / V2 = [(4/3)π(d/2)^3] / [(4/3)π(d/4)^3]

V1 / V2 = (d/2)^3 / (d/4)^3

V1 / V2 = [d^3 / 2^3] / [d^3 / 4^3]

V1 / V2 = 8 / 64

V1 / V2 = 1 / 8

Answer:

first blank is 972

second blank is 1/8

yup

Step-by-step explanation:

A dress shop bought material for £4.65 a metre and sold it for £6.90 a metre. How much
profit would be made on a roll of 30 metres?​

Answers

Answer:

  £67.50

Step-by-step explanation:

On each metre of material, the shop makes a profit of ...

  £6.90 -4.65 = £2.25

So, for 30 metres, the profit will total ...

  30 × £2.25 = £67.50

A profit of £67.50 would be made on a 30-metre roll of material.

I need 51-55 Thanks You :D no

Answers

Answer:

Below

Step-by-step explanation:

All figures are squares. The area of a square is the side times itself

Let A be the area of the big square and A' the area of the small one in all the 5 exercices

51)

● (a) = A - A'

A = c^2 and A' = d^2

● (a) = c^2 - d^2

We can express this expression as a product.

● (b) = (c-d) (c+d)

■■■■■■■■■■■■■■■■■■■■■■■■■■

52)

● (a) = A-A'

A = (2x)^2 = 4x^2 and A'= y^2

● (a) = 4x^2 - y^2

● (b) = (2x-y) ( 2x+y)

■■■■■■■■■■■■■■■■■■■■■■■■■■

53)

● (a) = A-A'

A = x^2 and A' = y^2

● (a) = x^2-y^2

● (b) = (x+y) (x-y)

■■■■■■■■■■■■■■■■■■■■■■■■■■

54)

● (a) = A-A'

A = (5a)^2 = 25a^2 and A' =(2b)^2= 4b^2

● (a) = 25a^2 - 4b^2

● (a) = (5a-2b) (5a+2b)

■■■■■■■■■■■■■■■■■■■■■■■■■■

55)

● (a) = A - 4A'

A = (3x)^2 = 9x^2 and A'= (2y)^2 = 4y^2

● (a) = 9x^2 - 4 × 4y^2

● (a) = 9x^2 - 16y^2

● (a) = (3x - 4y) (3x + 4y)

Find the value of x so that the function has the given value.


j(x)=−4/5x+7; j(x)=−5

x=



Answers

Answer:

x = 3

Step-by-step explanation:

j(x) = 4/5(-5) + 7

= -4 + 7

= 3

Answer:

15

Step-by-step explanation: -4/5 x has to be -12 because -12+7 equals 5. Since we want to figure out x, we have to flip -4/5 x to 4/5x which would change the -12 to 12. What is a fourth of 12? It is three. 12+3 equals 15. This is the first right answer on all of the internet for this question!

What is the smallest positive integer $n$ such that $\frac{n}{n+101}$ is equal to a terminating decimal?

Answers

Answer:

n = 24

Step-by-step explanation:

Given the fraction:

[tex]$\frac{n}{n+101}$[/tex]

To find:

Smallest positive integer [tex]$n$[/tex] such that the fraction is equal to a terminating decimal.

Solution:

The rule that a fraction is equal to a terminating decimal states that, the denominator must contain factors of only 2 and 5.

i.e. Denominator must look like [tex]2^m\times 5^n[/tex], only then the fraction will be equal to a terminating decimal.

Now, let us have a look at the denominator, [tex]n+101[/tex]

Let us use hit and trial method to find the value of [tex]n[/tex] as positive integer.

n = 1, denominator becomes 102 = [tex]2 \times 3 \times 17[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 4, denominator becomes 105 = [tex]5 \times 3 \times 7[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 9, denominator becomes 110 = [tex]2 \times 5 \times 11[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 14, denominator becomes 115 = [tex]5 \times 23[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 19, denominator becomes 120 = [tex]5 \times 3 \times 2^3[/tex] not of the form [tex]2^m\times 5^n[/tex].

n = 24, denominator becomes 125 = [tex]2^0 \times 5 ^3[/tex] It is of the form [tex]2^m\times 5^n[/tex].

So, the answer is n = 24

please help!!!! Use the graph to complete the statement. O is the origin. Ry−axis ο Ry=x: (-1,2)
A. (1, -2) B. (-1, -2) C. (2, -1) D. (-2, -1)

Answers

Answer:  D. (-2, -1)

Step-by-step explanation:

Here we do two reflections to the point (-1, 2).

First, we do a reflection over the line x = y.  Remember that a reflection over a line keeps constant the distance between our point and the given line, so we have that for a pint (x, y), the reflection over the line y = x is:

Ry=x (x, y) = (y, x)

so for our point, we have:

Ry=x (-1, 2) = (2, -1)

Now we do a reflection over the y-axis, again, a reflection over a line keeps constant the distance between our point and the given line, so if we have a point (x,y) and we do a reflection over the y-axis, our new point will be:

Ry-axis (x,y) = (-x, y)

Then in our case:

Ry-axis (2, -1) = (-2, -1)

The correct option is D.

Can someone help pls it’s a multiple choice question

Answers

Answer: A & E

Explanation:

What is the answer that = n?

Answers

Answer:

n = 5

Step-by-step explanation:

To start off, we know that whenever the bases are the same, their exponents are equal to each other. Therefore, since both of the numbers bases are the same (both are z), we know that they will be equal.

The n can be distributed to the [tex]z^2[/tex] so that it now reads to be:

[tex]z^2^n = z^{10}[/tex]

Exponents are equal, so:

2n=10

Divide the 2 on both sides:

n=5

Answer:

n =5

Step-by-step explanation:

z^2^n

We know that a^b^c = a^ (b*c)

z^(2n)

This is equal to z^10

Since the bases are the same, the exponents are the same

2n = 10

Divide by 2

2n/2 = 10/2

n = 5

A wave has a time period of 0.2 s Calculate the frequency of the wave.

Answers

Answer:

[tex]\huge\boxed{f = 5\ Hz}[/tex]

Step-by-step explanation:

Given:

Time period = T = 0.2 sec

Required:

Frequency = f = ?

Formula:

f = 1/T

Solution:

f = 1/0.2

f = 5 Hertz

Answer:

[tex] \boxed{\sf Frequency \ (f) \ of \ the \ wave = 5 \ Hz} [/tex]

Given:

Time Period (T) = 0.2 s

To Find:

Frequency (f) of the wave

Step-by-step explanation:

[tex] \sf Frequency (f) = \frac{1}{Time Period (T)} [/tex]

[tex] \sf f = \frac{1}{0.2} [/tex]

[tex] \sf f = \frac{1}{0.2} \times \frac{10}{10} [/tex]

[tex] \sf f = \frac{10}{2} [/tex]

[tex] \sf f = \frac{ \cancel{2} \times 5}{ \cancel{2}} [/tex]

[tex] \sf f = 5 \: Hz[/tex]

How do the number line graphs of the solutions sets of Negative 23 greater-than x and x greater-than-or-equal-to negative 23 differ?

Answers

Answer:

For "Negative 23 greater-than x" , highlight the left half of the number line starting at -23 and use a parenthesis ) on -23.

For "x greater-than-or-equal-to negative 23", highlight the right half of the number line starting at -23, and use a square bracket [ on -23.

Step-by-step explanation:

Start by locating the number -23 on the number line. Please see attached image to accompany the explanation.

In the first case:  "Negative 23 greater-than x" , which is expressed mathematically as:

[tex]-23 >x[/tex]

notice that "x" has to be strictly smaller than the number -23, therefore those sought x values must reside to the left of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself shouldn't be considered as part of the set, that symbol is by convention a parenthesis ).

In the second case: "x greater-than-or-equal-to negative 23", which is expressed mathematically as:

[tex]x\geq -23[/tex]

notice that "x" has to be greater than or equal to the number -23, therefore those sought x values must reside to the right of the number -23, so we have to highlight that half of the number line. Apart from that, we need to include a symbol on top of the number -23, that indicates that -23 itself should be considered as part of the set, that symbol is by convention a square bracket [.

Answer:

the answer is A

Step-by-step explanation:

If (x + 2) is a factor of x3 – 19x – p, find the value of p. Help please​

Answers

If [tex]x-a[/tex] is a factor of a polynomial [tex]P(x)[/tex] then, [tex]a[/tex] is its root.

So [tex]-2[/tex] is a root of [tex]x^3-19x-p[/tex]

[tex](-2)^3-19\cdot(-2)-p=0\\-8+38-p=0\\p=30[/tex]

Briefly describe this graph of a Femis wheel.


Answers

Answer: This is a periodic relation.

Step-by-step explanation:

This is a periodic relation, that can be modeled with a sinusoidal relation, that relates the height as a function of time.

Then we can write this as h(t) = A*sin(C*t + F) + B

Where A is the amplitude, C is a constant that depends on the period, F is a phase shift, and B is the midpoint of the function.

2*A is the distance between the maximum height and the minimum height.

B is the middle height of the Femis Wheel.

If BH = 108, find DE.

Answers

Answer:

BH= 108 --> 1st until 6th space

so, 108/6 = 18 for each space

DE...?

DE only use 1 space so the answers is 18 unit

I hope this helps^_^

how to find y in this equation 11=12-14y

Answers

11 = 12 - 14y
(Subtract 12 from both sides)
-1 = -14y
(Divide both sides by -14)
1/14 = y

Given that the trinomial x^2+ 11x + 28 has a factor of x +4, what is the other factor?

Answers

Answer:

the other factor is (x+7)

Step-by-step explanation:

Given x^2+11x+28

factor into

x^2+7x + 4x + 28

=x(x+7) + 4(x+7)

= (x+4)(x+7)

Answer: the other factor is (x+7)

Please someone help me im desperate

Find Tan0 , csc0, and cos0 where 0 is the angle shown in the figure. Give EXACT values, not decimal approximations.

Answers

Answer:

1. Tan θ = √11/5

2. Cosec θ = 6√11 /11

3. Cos θ = 5/6

Step-by-step explanation:

Let the side opposite to angle θ be y.

The value of y can be obtained by using the pythagoras theory as follow:

b² = 6² – 5²

b² = 36 – 25

b² = 11

Take the square root of both side.

b = √11

1. Determination of Tan θ

Tan θ =?

Opposite = √11

Adjacent = 5

Tan θ = Opposite /Adjacent

Tan θ = √11/5

2. Determination of Cosec θ.

We'll begin by calculating the Sine θ. This is illustrated below:

Sine θ =?

Opposite = √11

Hypothenus = 6

Sine θ = Opposite /Hypothenus

Sine θ = √11/6

Now, we shall determine Cosec θ as follow:

Cosec θ = 1/Sine θ

Sine θ = √11/6

Cosec θ = 1 ÷ √11/6

Cosec θ = 1 × 6/√11

Cosec θ = 6/√11

Rationalise the denominator

Cosec θ = 6/√11 × √11/√11

Cosec θ = 6√11 /11

3. Determination of Cos θ.

Cos θ =?

Adjacent = 5

Hypothenus = 6

Cos θ = Adjacent / Hypothenus

Cos θ = 5/6

We want to factor the following expression:
(x+4)^2 -4y^5 (x+4) + 4y10
We can factor the expression as (U – V)2 where U and V are either constant integers or single-variable
expressions.
1) What are U and V?

Answers

Answer:

U = x + 4 and V = 2y^5.

Step-by-step explanation:

Square root of (x + 4)^2 = x + 4

Square root of 4y^10 = 2y^5

U = x + 4 and V = 2y^5.

(U - V)^2 = U^2 - 2UV + V^2

= (x + 1)^2 - 2 (2y^5 (x + 1) + 4y^10

= (x + 1)^2 - 4y^5 (x + 4) + 4y^10

Answer:

U = x + 4 and V = 2y^5.

Step-by-step explanation:

Hiiii can you help me ?

Answers

Answer:

  842, 743, 394, 305, 836

Step-by-step explanation:

We arbitrarily chose the ones digit to start with as 2. (It must be 5 or less.) The other two digits are chosen by a random number generator, as shown in the attached.

The 5 three-digit numbers we chose are ...

  842, 743, 394, 305, 836

Answer:

The only criteria the question gives are that there must be 5 numbers, and the numbers must have 3 digits. The ones digit in the numbers should go up by 1.

So, we can have 111, 112, 113, 114, and 115.

Hope this helps!

Question 5 of 10
Which type of unemployment is characterized by a worker looking for a job
when there is no reason that he or she should not find one?
A. Structural unemployment
B. Seasonal unemployment
C. Frictional unemployment
D. Periodic unemployment

Answers

I think the answer has to be C. Frictional unemployment

Can somebody please tell me if it’s right? i’ll mark u the brainliest

Answers

Answer:

Yes, you are correct.

Step-by-step explanation:

You are substituting the measure of angle x as the measure of angle a since they are congruent to each other.

solve the equation 3), x=???? Please help me!!!

Answers

Answer:

  x = {π/4, 7π/6, 5π/4, 11π/6} +2kπ . . . for any integer k

Step-by-step explanation:

  [tex]\dfrac{\sin^3{x}}{1+\cos{x}}+\dfrac{\cos^3{x}}{1+\sin{x}}=\cos{2x}+2\cos{x}-1\\\\\dfrac{\sin{x}(1-\cos^2{x})}{1+\cos{x}}+\dfrac{\cos{x}(1-\sin^2{x})}{1+\sin{x}}=\cos^2{x}-\sin^2{x}+2\cos{x}-1\\\\\sin{x}(1-\cos{x})+\cos{x}(1-\sin{x})=\cos^2{x}-\sin^2{x}+2\cos{x}-1\\\\\sin{x}+\cos{x}-2\sin{x}\cos{x}=2\cos{x}-2\sin^2{x}\qquad\text{use $1=s^2+c^2$}\\\\\sin{x}+2\sin^2{x}-\cos{x}-2\sin{x}\cos{x}=0\\\\\sin{x}(1+2\sin{x})-\cos{x}(1+2\sin{x})=0\\\\(\sin{x}-\cos{x})(1+2\sin{x})=0[/tex]

This will have solutions where the factors are zero.

sin(x) -cos(x) = 0

Dividing by cos(x), we have ...

  tan(x) -1 = 0

  x = arctan(1) = π/4, 5π/4

1 +2sin(x) = 0

  sin(x) = -1/2

  x = arcsin(-1/2) = 7π/6, 11π/6

The four solutions in the interval [0, 2π] are x = {π/4, 7π/6, 5π/4, 11π/6}. Solutions repeat every 2π radians.

_____

Additional comment

We have made use of the factoring of the difference of squares:

  (1 -a^2) = (1 -a)(1 +a)

and we have made use of the cosine double angle identity:

  cos(2x) = cos(x)^2 -sin(x)^2

The "Pythagorean" identity for sine and cosine was used several times:

  1 = sin(x)^2 +cos(x)^2

Find the range of f(x) = –x + 4 for the domain {–3, –2, –1, 1}.

Answers

Answer:

[tex]\boxed{ \{7, 6, 5, 3 \} }[/tex]

Step-by-step explanation:

The domain is all possible values for x.

The range is all possible values for f(x) or y.

The domain given is {-3, -2, -1, 1}.

Plug x as {-3, -2, -1, 1} and find the f(x) or y values.

[tex]f(-3)=-(-3)+4=7\\f(-2)=-(-2)+4=6\\f(-1)=-(-1)+4=5\\f(1)=-(1)+4=3[/tex]

The range is {7, 6, 5, 3}, when the domain is {-3, -2, -1, 1}.

Shea made 11 of her first 17 free-throw attempts. What is the minimum number of her next 20 free-throw attempts that she must make for her overall success rate to be at least $80\%$? Express your answer to the nearest whole number.

Answers

Answer:

19 throws.

Step-by-step explanation:

For her success rate to be 80% in 37 throws she must make  0.8 * 37

= 29.6 throw - that is 30 to nearest throw.

So for the next 20 throws she must make  30 - 11 = 19 throws.

7 is subtracted from the quotient of 48 divided by the sum of 5 and differences of 11 and 8​

Answers

Write it out as an equation:

(48 /(5+(11-8))) -7

Simplify:

(48/(5+3))-7

(48/8)-7

6-7 = -1

The answer is -1

A geometric sequence has a common ratio of 22 and the 12th12th term is −12,288.−12,288.

What is the explicit rule that describes this sequence?

Answers

Answer:

Tₙ = -3(2)ⁿ

Step-by-step explanation:

The explicit rule for determining the nth term of a geometric sequence is expressed as Tₙ = arⁿ⁻¹ where;

a is the first term of the geometric sequence

r is the common ratio

n is the number of terms

If a geometric sequence has a common ratio of 2 and the 12th term is −12,288, then;

T₁₂ = ar¹²⁻¹

T₁₂ = ar¹¹

Given T₁₂ = -12,288 and r = 2, we can calculate the first term a

-12,288 = a2¹¹

a = -12,288/2¹¹

a =  -12,288/2048

a = -6

Since the explicit rule for determining the nth term of a geometric sequence is expressed as Tₙ = arⁿ⁻¹, then for the sequence given, the explicit rule will be;

Tₙ = -6(2)ⁿ⁻¹

Tₙ = -6 * 2ⁿ * 2⁻¹

Tₙ = -6 * 2ⁿ * 1/2

Tₙ = -3(2)ⁿ

Hence the explicit rule that describes this sequence is Tₙ = -3(2)ⁿ

Solve the equation. 0.15 = y-0.45

Answers

Answer:

0.6

Step-by-step explanation:

0.6-0.45=0.15

The value of y from the given equation is 0.60.

What is an equation?

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The given equation is 0.15=y-0.45.

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

Here, 0.15=y-0.45

y=0.15+0.45

y=0.60

Therefore, the value of y is 0.60.

To learn more about an equation visit:

https://brainly.com/question/14686792.

#SPJ2

Tim owns a clothing store where he designs pairs of shorts, s, and T-shirts, t.
He sells the shorts for $12 and the T-shirts for $8 each. Tim can work 18
hours a day, at most. It takes him 30 minutes to design a T-shirt and 45
minutes to design a pair of shorts. He must design at least 12 items each
day, but he cannot design more than 30 items in one day. Which set of
inequalities below represents this scenario?
A. s 2 12 + $ ss 30 + tiss 24-0.66t, s2; 0; t2 0
B. s> 12-tss 30 - t Ss 24 -0.66t, s 2 0; t> 0
O c. s? 12-ts? 30-tss 24 -0.66t, s 2 0;t20
D. S 2 12-tss 30-ts 24 -0.66t, s 20; t 0​

Answers

Answer:

The correct option is;

B. s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t

Step-by-step explanation:

The given parameters are;

The number of T-shirts, t, and shorts, s, Tim must design a day = 12

The maximum number of T-shirts and shorts Tim can design a day = 30

The maximum number of hours Tim can work = 18 hours

Therefore, we have;

The number of shorts Tim designs in a day is ≥ The minimum number of T-shirts and shorts Tim must design a day less the number of T-shirts Tim designs

Which gives;

s ≥ 12 - t

Also the number of shorts Tim designs in a day is ≤ The maximum number of T-shirts, and shorts, Tim can design a day less the number of T-shirts Tim designs

Which gives;

s ≤ 30 - t

The number of 45 minute period for the design of shorts in 18 hours = 18×60/45 = 24

The fraction of 36 minutes in 45 minutes = 36/45 = 0.667

Therefore we have;

The number of shorts Tim designs in a day is ≤ The number of 45 minute periods in 18 hours less the number of 36 minutes periods used to design T-shirts

Which gives;

s ≤ 24 - 0.66·t

The correct option is s ≥ 12 - t, s ≤ 30 - t, s ≤ 24 - 0.66·t.

Answer:

B. s> 12-tss 30 - t Ss 24 -0.66t, s 2 0; t> 0

Step-by-step explanation:

Hope this helps!!

a/4 + 4 = 6 please helppppp!

Answers

━━━━━━━☆☆━━━━━━━

▹ Answer

a = 8

▹ Step-by-Step Explanation

a/4 + 4 = 6

Multiply both sides:

a + 16 = 24

Subtract 16 from both sides:

16 - 16 = a

24 - 16 = 8

a = 8

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Answer:

a = 8

Step-by-step explanation:

a/4 + 4 = 6

Subtract 4 from each side

a/4 + 4-4 = 6-4

a/4 = 2

Multiply each side  by 4

a/4 * 4 = 2*4

a = 8

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Mike wants to galvanize iron to protect it from rusting. Which metal should he use?AplatinumB.aluminumC.copperD.zincE.tungsten About how many feet are in 3.6 kilometers? 1 m = 39.37 in A company is considering purchasing a machine that costs $280,000 and is estimated to have no salvage value at the end of its 8-year useful life. If the machine is purchased, annual revenues are expected to be $100,000 and annual operating expenses exclusive of depreciation expense are expected to be $38,000. The straight-line method of depreciation would be used. If the machine is purchased, the annual rate of return expected on this machine is:__________. A 42-year-old realtor comes to your clinic, complaining of "growths" in her vulvar area. She is currently undergoing a divorce and is convinced she has a sexually transmitted disease. She denies any vaginal discharge or pain with urination. She has had no fever, malaise, or night sweats. On examination you see a woman who is anxious but appears otherwise healthy. Her blood pressure, pulse, and temperature are unremarkable. On visualization of the perineum you see two 2- to 3-mm, round, yellow nodules on the left labia. On palpation they are nontender and quite firm. What diagnosis best fits this description of her examination? If this is the only water being used in your house, how fast is the water moving through your house's water supply line, which has a diameter of 0.021 m (about 3/4 of an inch)? Quantitative Problem 1: Assume today is December 31, 2017. Barrington Industries expects that its 2018 after-tax operating income [EBIT(1 T)] will be $450 million and its 2018 depreciation expense will be $65 million. Barrington's 2018 gross capital expenditures are expected to be $110 million and the change in its net operating working capital for 2017 will be $30 million. The firm's free cash flow is expected to grow at a constant rate of 4.5% annually. Assume that its free cash flow occurs at the end of each year. The firm's weighted average cost of capital is 9%; the market value of the company's debt is $3 billion; and the company has 180 million shares of common stock outstanding. The firm has no preferred stock on its balance sheet and has no plans to use it for future capital budgeting projects. Using the free cash flow valuation model, what should be the company's stock price today (December 31, 2017)? Do not round intermediate calculations. Round your answer to the nearest cent. $ per share 6. If x + 2 is the only factor of the polynomial P(x),then P(2) is: Options: A. Cannot be determined B. Not Zero C. R(2) D. Zero In the pictured cell, the side containing zinc is the Choose... and the side containing copper is the Choose... . The purpose of the N a 2 S O 4 NaX2SOX4 is to Write a letter to the campus head of your university and divert the attention towards the unhygienic food being sold in canteen. Michael is using a number line to evaluate the expression 8 3. A number line going from negative 12 to positive 12. A point is at negative 8. After locating 8 on the number line, which step could Michael complete to evaluate the expression? Divide. Write the quotient in lowest terms. 3 3/4 5/7 As you finish listening to your favorite compact disc (CD), the CD in the player slows down to a stop. Assume that the CD spins down with a constant angular acceleration. If the CD rotates clockwise (let's take clockwise rotation as positive) at 500 rpm (revolutions per minute) while the last song is playing, and then spins down to zero angular speed in 2.60 s with constant angular acceleration, the angular acceleration of the CD, as it spins to a stop at -20.1 rad/s 2. How many revolutions does the CD make as it spins to a stop? Mildreds salary has increased from 24,600 to 25,338. By what percentage has her salary increase? (3) In a group of 60 seldiers have enough food for20 days - How many soldiers should leave the groupso that the food is enough for 100 days ? Find it. How do weathering and deposition differ? Weathering breaks down rocks; deposition leaves them in new places. Weathering has to do with air; deposition has to do with plants. Weathering occurs only in summer; deposition occurs year-round. Weathering can be chemical or physical; deposition is only chemical According to the author, the McCarthy era was one marked with fear and lack of dissent. People who worked for the federal government were forced to prove they were loyal, which was extremely difficult to do. As a result, many people lost their jobs and their livelihoods. The McCarthy era lasted throughout the 1950s and didn't begin to wane until the 1960s.A. TrueB. False What is called "I eat rice" in nepali? Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth.3.659.413 Technician A says that nonemission-related codes that make the malfunction indicator lamp (MIL) illuminate are called "Type A" codes. Technician B says that emission-related codes that illuminate the MIL after the first fault are called "Type A" codes. Who is correct? A. Neither Technician A nor B B. Both Technicians A and B C. Technician B D. Technician A really urgent...i need the working also ...pls help me