How many grams of H2 can be produced from the reaction of 11.50 g of sodium with an excess of water? The equation for the reaction is 2 Na + 2 H2O -> 2 NaOH + H2 Ans: 0.504 2 g H2 I would like to know how to solve this problem, the teacher gave me the answer but I am unsure how to solve it thanks!

Answers

Answer 1

Answer:

[tex]m_{H_2}=0.504gH_2[/tex]

Explanation:

Hello,

In this case, since the reaction is:

[tex]2 Na + 2 H_2O \rightarrow 2 NaOH + H_2[/tex]

We notice that since there is an excess of water, we can directly compute the yielded grams of hydrogen by using the following stoichiometric procedure, considering the 2:1 molar ratio between sodium and hydrogen (notice the 2 before the sodium and the 1 before the hydrogen at the chemical reaction) and that gaseous hydrogen has a molar mass of 2 g/mol:

[tex]m_{H_2}=11.50gNa*\frac{1molNa}{22.98gNa} *\frac{1molH_2}{2.02molNa} *\frac{2gH_2}{1molH_2} \\\\m_{H_2}=0.504gH_2[/tex]

Best regards.

Answer 2

Answer:

0.503g of H₂ are produced

Explanation:

Based on the chemical reaction:

2 Na + 2 H₂O → 2 NaOH + H₂

2 moles of Na react with 2 moles of water to produce 2 moles of NaOH and 1 mole of H₂

11.50g of Na -limiting reactant, molar mass 22.99g/mol- are:

11.50g× (1mol / 22.99g) = 0.500 moles of Na.

As 2 moles of Na produce 1 mole of H₂:

0.500 moles of Na × (1 mole H₂ / 2 moles Na) = 0.250 moles of H₂

As molar mass of H₂ is 2.01g/mol:

0.250 moles of H₂ × (2.01g / 1mol) = 0.503g of H₂ are produced


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Answers

Answer:

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Explanation:

From the question given above, it is evident that 222 86Rn is emitting alpha particle since the daughter nuclei produced has a mass number lesser than 4 when compared to parent element.

Therefore, the miss value in the equation is 84.

Please see attachment for further details

Based on the calculations, the missing value that will balance the equation is: A. 84.

What is an alpha decay?

An alpha decay is a type of nuclear reaction in which the atomic nucleus of a radioactive element emits an alpha particle (helium atom), thereby, producing chemical elements with a different atomic nucleus.

In this exercise, we are given the following nuclear equation with an alpha decay:

²²²R₈₆   -----> ²¹⁸Poₓ + ⁴He₂

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What is the general word equation for salt formation by neutralization?
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b. Acid + metal
c. Base + nonmetal
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Answers

Answer:d. Acid+base

Explanation:

Because, The general word equation for salt formation by neutralization is acid + base = salt + water.

Answer:

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Explanation:

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Explanation:

Answer:

El bromuro de litio es un compuesto químico de litio y bromo. Su carácter higroscópico extremo hace que LiBr sea útil como desecante en ciertos sistemas de aire acondicionado.

Explanation:

The map shows the main streams and the the rivers near City A and City B, as well as the nearby factories and farmland, The arrows in
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Select One:

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It will pollute the air for the City B

It will pollute the water source of city B

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Answers

Answer:

c

Explanation:

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Discribe how an internal combustion engine works. What is drawback to the type of power?

Answers

Answer:

An internal combustion engine is a heat engine in which the combustion of a fuel occurs with an oxidizer in a combustion chamber. The force of combustion is converted into mechanical energy through the use of levers and gears. The by products of combustion include energy, water vapor, carbon dioxide (CO2), nitric oxide (NO), nitrogen dioxide (NO2), and carbon monoxide (CO). The two primary drawbacks to the internal combustion engine are the primary energy source is non-renewable (fossil fuels) and the by products can have damaging effects on the environment.

Explanation:

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0.75mL

30 mL

3 mL

15 mL

Answers

Answer:

15 mL

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

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Answer:

b

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in a titration 20.0 mL of 0.150 M NaOH(aq) Solution exactly neutralize is 24.0 mL of an HCl solution what is the concentration of the HCl solution

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Answer:

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Explanation:

i took a test and got it right choosing this answer hopes this help

A chemistry student mixes 25 milliliters of 3.0 M hydrochloric acid (HCl) with excess sodium hydroxide. The chemicals react according to this chemical equation:

HCl + NaOH → NaCl + H2O.

If the volume of the resulting solution is 68 milliliters, what is the concentration of sodium chloride?

Answers

Answer:

1.1 mol/liter

Explanation:

You would use the M1V1 = M2V2 equation to solve this.

We know M1 is 3.0 M, V1 is 25 milliliters, and V2 is 68 milliliters. We need to find M2.

To find M2, first plug in what you know.

(3.0 M)(25 mL) = M2(68 mL)

Then, divide everything by 68 mL to get M2 by itself

Your answer should be a quite large decimal but I rounded it to 1.1 mol/liter.

Answer:

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Explanation:

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Answers

Explanation:

Utiliza mayúsculas para el primer carácter en el elemento y minúsculas para el segundo carácter. Ejemplos: Fe, Au, Co, Br, C, O, N, F.

Puedes utilizar los paréntesis () o los corchetes [].

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Answer:

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Which has more total Heat Energy/
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B.) A thermos of HOT coffee
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Answers

Answer:

The thermos should have more heat energy because of the greater mass.

Sulfuric acid (H2SO4) has a molar mass of 98.1 g/mol. How many oxygen atoms are found in 75.0 g of H2SO4? A. 1.15 × 10^23 B. 1.84 × 10^24 C. 4.61 × 10^23 D. 7.87 × 10^23

Answers

Answer:

B

Explanation:

first find the no. Of moles of H2SO4

=  75/98.1

= 0.7645

Next step

In on mole of H2SO4 the no.of oxygen atom is 4.

1 H2SO4 : 4 O

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next multiply avogadros constant

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Mass present in 1 gram of mole substance is called molar mass. Molar mass is calculated by: dividing the mass of the compound in grams by the number of moles present in the substances.

The correct answer is:

option B. 1.84 × 10²⁴

Given,

The mass of sulfuric acid =75.0 g

The molar mass of sulfuric acid = 98.1 g/mol

1.The moles of sulfuric acid can be calculated by

M = m ÷ n

where M is molar mass, m is mass and n moles.

moles of sulfuric acid = mass ÷ molar mass

= 75 g ÷ 98.1 g/mol  

=0.7645 moles

Hence moles of sulfuric acid present is 0.7645 moles.

2. 1 mole of sulfuric acid = 4 oxygen atoms.

Then, 0.7645 moles of sulfuric will contain: 0.7645 × 4 = 3.0581 atoms of oxygen

3. Oxygen atoms present in 75.0 g of H₂SO₄ will be calculated by multiplying it with Avogadro's constant:

= 3.0581 x 6.022× 10²³

= 1.84x10²⁴

Therefore, 1.84 × 10²⁴ oxygen atoms will be found in 75.0 g of H₂SO₄.

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Explanation:

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Answer:

An amplifying device that indicates the presence of ionizing particles  

GEIGER COUNTERS

A device that permits determination of alpha and beta radiation emitted from a substance  

BOTH

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A sample of air has a volume of 140.0 mL at 67C. To w
hat temperature must the gas
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Answers

Answer:

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Answer:

rapid shaking of the earth, caused by the breaking and shifting of underground rock. Earthquakes can cause buildings to collapse and cause heavy items to fall, resulting in injuries and property damage.

Explanation:

Answer:

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Explanation:

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Answers

Answers:

in the wild of over 100 years,...

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C. equal to, elements, products

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I took a quiz and it said this was right

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Answer:

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Explanation:step-by-step

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How many moles of NaCl are contained in 100.0ml of a 0.20m solution

Answers

M= 0.20 M
V= 100.0 ml = 0.100 L
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:. n = MV

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Consider the intermediate chemical reactions.



2 equations. First: upper C a (s) plus upper C upper O subscript 2 (g) plus one half upper O subscript 2 (g) right arrow upper C a upper C upper O subscript 3 (s). Delta H 1 equals negative 812.8 kilojoules. Second: 2 upper C a (s) plus upper O subscript 2 (g) right arrow 2 upper C a upper O (s). Delta H 2 equals negative 1, 269 kilojoules.



The final overall chemical equation is Upper Ca upper O (s) plus upper C upper O subscript 2 (g) right arrow upper C a upper C upper O subscript 3 (s).. When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation

Answers

When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

Let's consider the following intermediate chemical reactions.

Reaction 1: Ca(s) + CO₂(g) + ½O₂(g) → CaCO₃(s)    ΔH₁ = -812.8 kJ

Reaction 2: 2 Ca(s) + O₂(g) → 2 CaO(s)                  ΔH₂ = -1269 kJ

We want to calculate the enthalpy of the following overall chemical equation.

CaO(s) + CO₂(g) → CaCO₃(s) ΔH = ?

We can apply Hess' law.

What is Hess' law?

Hess' law states that regardless of the multiple stages or steps of a reaction, the total enthalpy change for the reaction is the sum of all changes.

To apply Hess' law in this case we have to:

Conserve equation 1 as is.Reverse equation 2 and multiply it by 1/2, thus changing the sign of its enthalpy and multiplying it by 1/2.Add both equations and their enthalpies.

Ca(s) + CO₂(g) + ½ O₂(g) → CaCO₃(s)    ΔH = -812.8 kJ

+

CaO(s) → Ca(s) + ½ O₂(g)                       ΔH = 634.5 kJ

--------------------------------------------------------------------------------------

CaO(s) + CO₂(g) → CaCO₃(s)                  ΔH = -178.3 kJ

When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

The complete question is as follows.

Consider the intermediate chemical reactions.

Ca (s) + CO₂ (g) + ½O₂ (g) → CaCO₃ (s) ΔH₁ = -812.8 kJ

2Ca (s) + O₂ (g) → 2CaO (s) ΔH₂ = -1269 kJ

The final overall chemical equation is

CaO (s) + CO₂ (g) → CaCO₃ (s) ΔH = ?

When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation

is halved and has its sign changed. is halved. has its sign changed. is unchanged.

Learn more about Hess' law here: https://brainly.com/question/11628413

Answer:

Consider the following intermediate reactions.

                              CH₄(g)+2O₂(g)⇒CO₂(g)+2H₂O(g)           ΔH₁ = -802 kJ

                              2H₂O(g)⇒2H₂O(I)                                     ΔH₁ = - 88 kJ

The overall chemical reaction is as follows.

                              CH₄(g)+2O₂(g)⇒CO₂(g)+2H₂O(I)             ΔH₂ = -890 kJ

What is the correct enthalpy diagram using the Hess law for this system?

✔️ A←

❌ B

❌ C

❌ D

Please help

What causes a wave to have a higher amplitude?

Answers

Answer:

More energy

Explanation:

Wave amplitude is determined by the energy of the disturbance that causes the wave. A wave caused by a disturbance with more energy has greater amplitude.

Answer:

energy of the disturbance

Explanation:

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The moon's period of rotation and revolution are equal

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