How many cm3 in a L?

Answers

Answer 1
There’s 1000 cubic cm (cm^3) in a litre

Related Questions

¿Como pasar 254 meses a minutos?
Por favor ayudaaa!!
Le doy corona a la respuesta

Answers

Answer:

Ver las respuestas abajo.

Explanation:

Este problema se puede resolver conociendo la relacion entre horas y minutos, sabemos que:

1 hora [h] → 60 minutos [min]

De esta manera:

2 [min] = 2/60 = 0.033 [h]

15 [min] = 15/60 = 0.25 [h]

30 [min] = 30/60 = 0.5 [h]

10 [min] = 10/60 = 0.166 [h]

6 [min] = 6/60 = 0.1 [h]

20 [min] = 20/60 = 0.33 [h]

5 [min] = 5/60 = 0.0833 [h]

Color of the CuCl2 hydrate before heating:

Answers

hydrated cucl2 have blue-green colour

best way to separate a solid from a liquid what separation technique is needed​

Answers

Filtration is a method for separating an insoluble solid from a liquid.

Answer:

Filtiration technique

Explanation:

Convert 500.45 g to kg (do not use Scientific Notation)

Answers

Answer:

To convert grams to kilograms, you divide the number of grams you have by 1000. So, 800 g = 800/1000 = 0.8 kg.

Explanation:

3 point different between reactant and product​

Answers

Answer:

reactants

The substance(s) to the left of the arrow in a chemical equation are called reactants. A reactant is a substance that is present at the start of a chemical reaction

Explanation:

product_The substance(s) to the right of the arrow are called products . A product is a substance that is present at the end of a chemical reaction. In the equation above, the zinc and sulfur are the reactants that chemically combine to form the zinc sulfide product.

There is a standard way of writing chemical equations. The reactants are all written on the left-hand side of the equation, with the products on the right-hand side. An arrow points from the reactants to the products to indicate the direction of the reaction:

reactants → products

Reactants

1. The substances used as starting materials and which react with one another are reactants.

2. Example: In this reaction Mg and O2 are reactants.

Products

1. The substances which are formed as a result of reaction are products.

2. Example: In this reaction MgO is a product.

The levels of carbon dioxide in the atmosphere a. began decreasing when the burning of fossil fuels increased. b. are estimated to be higher than at any time in the past 420,000 years. c. are high but not higher than the highest estimated levels in the last 420,000 years. d. peaked around 1950 and have begun slowly decreasing since then.

Answers

The levels of carbon dioxide in the atmosphere are estimated to be higher than at any time in the past 420,000 years. That is option B

Carbon dioxide is a very harmful compound which is easily released into the atmosphere through burning of fossil fuels and other carbon compounds in plenty of air.

The released carbon dioxide rises to the upper atmosphere and blocks the radiation of solar energy back into the space. This precipitates a global temperature increase called the greenhouse effect.

According to Intergovernmental Panel on Climate Change (IPCC) in a current research discovered that CO2 concentration in the earth’s atmosphere is higher than at any point during the last 650,000 years. They where able to study this through the study of higher levels of CO2 concentration which coincide with higher temperatures.

Therefore the correct option is B which states that the levels of carbon dioxde in the atmosphere are estimated to be higher than at any time in the past 420,000 years.

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why metals are not often used to
make clothes

Answers

Answer:

They would be to heavy and you would be really stiff

Explanation:

Imagine walking in a suit made of iron or tin

You would feel like the Tin Man

You would be stiff

Metals are hard and heavy

I have no idea how to do this and need help

Answers

Answer:

60.55%

Explanation:

nO3=155/48

nO2 used: 3/2nO3=4.84375

percent yield: 4.84375/8=60.55%

Suppose 'A' is a liquid aromatic compound with molecular weight 78 and burns with sooty flame. a.Give the name of the compound 'A' b.write the molecular structure of 'A' C. What is the product when 'A' is treated with ? i.conc.HNO3 with conc.H2SO4 as catalyst ii.Halogen (cl2)in presence of sunlight and mention the use of the product obtained​

Answers

Aromatic compounds are compounds that contain carbon-carbon multiple bonds.

The question did not mention that a heteroatom is present in the compound so we can assume that there is none of such. In that case, the compound contains only hydrogen and carbon.

So,

(CH)n = 78

where n is the number of each atom present.

(12 +1)n = 78

n = 78/13

n = 6

The molecular formula of the compound is C6H6

When C6H6 is treated with .conc.HNO3/conc.H2SO4 the compound shown in image 1 is formed. The reaction occurs at the C-C multiple bond.

When C6H6 is reacted with chlorine in the presence of sunlight, hexachlorobenzene (shown in image 2 attached) is formed.

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Which soil would most likely be found in the Arctic?

Answers

It would be Permafrost

Answer:

The answer is B

Explanation:

Gelisols

What is the volume occupied by 2.34 grams of CO2 gas at STP?​

Answers

Answer:

The volume occupied by 2.34 grams of CO2 gas at STP   is 1.18  L

Grease is applied to the moving part of machine.

Answers

Answer:

Explanation:

The moving part won't move on its own there's a force but the force isn't enough for something like a bike chain it need grease to move smoothly or else it will just be super stuck or slow.

Answer:

because grease produce more fiction which helps moving part of machine not get jamm while working

write the balanced chemical equation for the following word equation. sodium+sulphate Acidsodium sulphate +hydrogen​

Answers

Answer:

2NaOH+ H2SO4 → Na2SO4 + 2H2O

I HOPE ITS RIGHT IF NOT THEN SORRY

HAVE A GREAT DAY :)

Answer:

Sodium+sulphate=Na2SO4

Acidsodium sulphate + hydrogen=Na2SO4+H2O

Calculate the weight of CuO formed when 200g of Copper carbonate is heated.(Atomic weight of Copper-64,Carbon-12,Oxygen-16)

Answers

Answer:

129 g of CuO

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CuCO₃ —> CuO + CO₂

Next, we shall determine the mass of CuCO₃ that decomposed and the mass of CuO produced from the balanced equation. This can be obtained as follow:

Molar mass of CuCO₃ = 64 + 12 + (16×3)

= 64 + 13 + 48

= 124 g/mol

Mass of CuCO₃ from the balanced equation = 1 × 124 = 124 g

Molar mass of CuO = 64 + 16

= 80 g/mol

Mass of CuO from the balanced equation = 1 × 80 = 80 g

SUMMARY:

From the balanced equation above,

124 g of CuCO₃ decomposed to produce 80 g of CuO.

Finally, we shall determine the mass of CuO produced by the decomposition of 200 g of CuCO₃. This can be obtained as follow:

From the balanced equation above,

124 g of CuCO₃ decomposed to produce 80 g of CuO.

Therefore, 200 g of CuCO₃ will decompose to produce

= (200 × 80)/124 = 129 g of CuO.

Thus, 129 g of CuO was obtained from the reaction.

Sarah measures out 151 grams of SO2. How many moles is this? Express your answer to three significant figures.

Answers

Answer:

[tex]\boxed {\boxed {\sf 2.36 \ mol \ SO_2}}[/tex]

Explanation:

We are asked to convert grams to moles. We will use the molar mass and dimensional analysis to perform this conversion.

1. Molar Mass

The molar mass is the mass of 1 mole of a substance. These values are found on the Periodic Table because they are equivalent to the atomic masses, but the units are grams per mole instead.

We are given a mass of sulfur dioxide (SO₂). Look up the molar masses of the individual elements.

Sulfur (S): 32.07 g/mol Oxygen (O): 15.999 g/mol

Notice that the formula of the compound contains a subscript. The subscript after O means there are 2 moles of oxygen in 1 mole of sulfur dioxide. We must multiply oxygen's molar mass before adding sulfur's.

O₂: 15.999 * 2 = 31.998 g/mol SO₂= 32.07 + 31.998 = 64.068 g/mol

2. Convert Grams to Moles

Now we will use dimensional analysis to convert grams to moles. From the molar mass, we know there are 64.068 grams of sulfur dioxide per mole, so we can set up a ratio.

[tex]\frac {64.068 \ g \ SO_2} {1 \ mol \ SO_2}[/tex]

We are converting 151 grams to moles, so we multiply by this value.

[tex]151 \ g \ SO_2 *\frac {64.068 \ g \ SO_2} {1 \ mol \ SO_2}[/tex]

Flip the ratio so the units of grams of sulfur dioxide cancel.

[tex]151 \ g \ SO_2 *\frac {1 \ mol \ SO_2}{64.068 \ g \ SO_2}[/tex]

[tex]151 *\frac {1 \ mol \ SO_2}{64.068 }[/tex]

[tex]\frac {151}{64.068 } \ mol \ SO_2[/tex]

[tex]2.356870825 \ mol \ SO_2[/tex]

3. Round

The original measurement of grams (151) has 3 significant figures, so our answer must have the same. For the number we calculated, that is the hundredth place. The 6 in the thousandth place tells us to round the 5 in the hundredth up to a 6.

[tex]2.36 \ mol \ SO_2[/tex]

151 grams of sulfur dioxide is approximately 2.36 moles of sulfur dioxide.

calculate the molecular formula of H2O​

Answers

i believe it is just H2O. one molecule of water consists of one oxygen atom covalently bonded to two hydrogen atoms.

a. For a chemistry lab final exam, a high school chemistry student was given a 1-mole sample of CaCl2 and a 1-mole sample of MgCl2 but was not told which sample was which. He was to identify the powders.

He looked up the enthalpies of formation for both of the chemicals and calculated the ΔHreaction for dissolving each powder: CaCl2 (s) Ca 2+ (aq) + 2Cl – (aq), and MgCl2 (s) Mg 2 (aq) + 2Cl – (aq). He then put each powder in a coffee-cup calorimeter and added water.

When sample A dissolved, the temperature increased by 0.74°C. When sample B dissolved, the temperature increased by 0.39°C. Which chemical was A, and which was B? Use the table of enthalpies of formation to help you. Explain your reasoning.

Answers

Ca^2+ ion  is smaller than Mg^2+ ion hence it has a greater heat of formation or lattice energy.

When a crystal lattice is formed, the energy that is released if the component ions of the compound are brought together from infinity is called the lattice energy. It is the energy released when a crystal lattice is formed from its component ions.

The question lets us know that the heat released by the compounds depends on the energy released upon formation of the compound. Hence, the higher the energy released upon formation, the higher the magnitude of heat released upon dissolution of the compound.

Recall that lattice energy depends on the size of the ions. Thus, the smaller the ions, the higher the lattice energy.

Ca^2+ is smaller than Mg^2+ hence more energy is given off when CaCl2  is formed than when MgCl2  is formed.

As stated above, the greater the lattice energy, the greater the heat released when the lattice dissolves and the higher the rise in temperature.

Putting all these together, Sample A must be CaCl2 while sample B must be MgCl2.

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Complete and write net ionic equation:
NH3 + HCI->

Answers

Answer:

IONIC EQUATION OF NH3 AND HCL IS NH4CL


500kg, 42m, 675g, and 10m/s are all examples of what typed of data?b

Answers

500kg, 42m, 675g, and 10m/s are all examples of a: continuous data.

A numerical data can be defined as a data set that is expressed in numbers only or a data set consisting of numbers rather than words. A numerical data is also known as a quantitative data.

Generally, numerical data are classified into two (2) main categories and these are;

Discrete data: a discrete data is a data set in which the number of possible values are either finite or countable. Some examples are; the value of a fair die, number of pen in a box, number of eggs in a crate, etc.Continuous data: a continuous data is a data set that has infinitely many possible values and as such those values cannot be counted, which simply means they are uncountable. Any data (quantity) such as mass, height, volume, weight, density, velocity, length, pressure, temperature, speed, distance, time are generally classified as continuous data.

In conclusion, mass (500 kg), height (42m), mass (675g), and speed (10m/s) are all examples of a: continuous data.

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list three factors that affect the rate of a chemical reaction

Answers

Answer:  1)  temperature, 2) add a catalyst, and 3) concentrations

Explanation:  A rise in temperature adds kinetic energy to the reactants, leading to more frequent, and energetic collisions, which will often accelerate the reaqction.  A catalyst is an agent that helps the reaction move forward more quickly by offering a substrate that aids in orienting the reactants for more efficient reaction.  A higher concentration increases the chances of collisons that result in products.

Usually scientists do not specialize and study one aspect of the
natural world, but will focus on many aspects to understand
why and how things happen.
TRUE
FALSE

Answers

If This is a true or false question then this is true.

A 1.732 g sample of iron is heated in air. It oxidizes to form a product with a mass of 2.205 g.
What is the empirical formula of the product?

Answers

Answer:

A 1.732 g sample of iron is heated in air. It oxidizes to form a product with a mass of 2.205 g. What is the empirical formula of the product? FeO 4. Caffeine is made of 49.48% carbon, 5.19% hydrogen, 28.85% nitrogen, and 16.48% oxygen by mass.

Explanation:

The empirical formula of the product formed by the reaction of iron and oxygen is FeO.

Let's consider the following generic chemical equation:

Fe + O₂ ⇄ FexOy

According to the law of conservation of mass, the sum of the masses of the reactants is equal to the sum of the masses of the products. The mass of O₂ that reacted, and remains in the oxide is:

[tex]mFe + mO_2 = mFexOy\\mO_2 = mFexOy - mFe = 2.205 g - 1.732 g = 0.473 g[/tex]

The oxide has 1.732 g of Fe and 0.473 g of oxygen and a total mass of 2.205 g. To determine the empirical formula, we need to calculate the percent composition.

[tex]\%Fe = \frac{mFe}{mFexOy} \times 100 \% = \frac{1.732 g}{2.205 g} \times 100 \% = 78.55\%[/tex]

[tex]\%O = \frac{mO}{mFexOy} \times 100 \% = \frac{0.473 g}{2.205 g} \times 100 \% = 21.45\%[/tex]

Now, we will divide each percentage by the atomic mass of the element.

[tex]Fe: 78.55/55.85 = 1.406\\O: 21.45/16.00 = 1.340[/tex]

Finally, we divide both numbers by the smallest one.

[tex]Fe: 1.406/1.340 \approx 1 \\O: 1.340/1.340 = 1[/tex]

The empirical formula of the product is FeO.

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What is the balanced form of the chemical equation shown below?
C2H5OH() + O2(9)
H2O() + CO2(9)
A. C2H5OH() + 302(9) — 3H20() + 2002(9)
B. 2C2H5OH() + O2(g) – 5H20(1) + CO2(g)
C. C2H20(1) + 202(9)
-
H20(1) + 2C02(9)
D. C2H5OH() + O2(g) → H20(1) + CO2(g)

Answers

Answer:

C2H5OH +3O2 = 2Co2+ 3H2O

Explanation:

The balanced chemical equation is C2H5OH + 302 → 3H20 + 2CO2.

What is balanced chemical equation?

A balanced chemical equation is one in which the count of atoms in all of the molecules is equivalent on both sides of the equation. The balancing of a particular chemical equation is governed by the Law of Conservation of Mass.

Balancing chemical equation is shown as below:

It can be seen that the count of carbon atom in left side 2 on the other hand the count of carbon in right side only one. By multiply with 2 in right side of the reaction , equation will be balanced.

Therefore, the balanced chemical equation is C2H5OH + 302 → 3H20 + 2CO2.

To know more about balanced chemical equation .

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Question 14 (Essay Worth 10 points) (03.05 MC) Use complete sentences to differentiate between acids and bases on the basis of touch. Give an example of each type.​

Answers

Answer:

Acid is a molecule capable of donating hydrogen ion and they form aqueous solutions with a sour taste while base is a substance that accepts proton from proton donor and in aqueous solution, they have an astringent or bitter taste. Moreover, a good example for base is sodium hydrogen carbonate as baking soda or baking powder and for acid, the most common example is the acetic acid or vinegar.

Answer:

Well, for starters, bases mostly consist of soaps and cleaning products, acids consist of vinegar,lemon,and stuff like that. Most acids on the basis of touch can burn your skin or be very sour, unlike bases which are more soapy and have a cleaner touch.A good example of an acid is vinegar, which can be used for cleaning but can also be used for making foods, on the other hand. A good example of a base is dish soap. It is used for cleaning.

Explanation:

i just did the exam and got a 100

what is the name of this organic molecule

Answers

Answer:

C2H4 Ethylene

Explanation:

Hope it helps! :)

10. As electrons move through the electron-transport chain,
they lose energy, which is used to form
A. NAD.
B. ADP
C. ATP.
D. GBP

Answers

Answer:

NAD

Explanation:

mark me brainlist please

Answer:

They lose energy which is used to form ATP

as the balloon rises what happens to the external pressure

Answers

Answer:

As the ballon rises higher the atmospheric pressure will drop if the ballon is made of an elastic material,it will stretch to allow the gas inside it to expand

How does a balanced chemical equation represent the conservation of
matter in a chemical reaction?
1. There are more atoms in the reactants than in the products.
2. The type of matter in the products is different from the type of matter in
the reactants.
3. The number of atoms of each element in the reactants equals the number
of atoms of each element in the products.
4. There are fewer atoms in the reactants than in the products

Answers

Answer:

The correct answer would be 3. The number of atoms of each element in the reactants equals the number of atoms of each element in the products.

Explanation:

The law of conservation of matter states that energy cannot be created or destroyed, only transfered. Thus, option 3 is correct.

The solubility of solids______ when the temperature is increased.

A. increases
B. decreases
C. does not change

Answers

The answer is increases

What temperature scale is used in the ideal gas equation

Answers

Answer:

kelvin scale?

Explanation:

i`m not 100% on this one

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