Radius=r=R_o/2angular velocity=w=v_omass=m
We know
[tex]\boxed{\sf K.E=\dfrac{1}{2}mv^2}[/tex]
For Rotational motion
[tex]\boxed{\sf v=r\omega}[/tex].
Putting value
[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m(r\omega)^2[/tex]
[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}mr^2\omega^2[/tex]
[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{2}m\left(\dfrac{R_o}{2}\right)^2v_o^2[/tex]
[tex]\\ \qquad\quad\sf{:}\dashrightarrow K.E=\dfrac{1}{4}mv_o^2[/tex]
Two unequal masses m and 2m are attached to a thin bar of negligible mass that rotates about an axis perpendicular to the bar. When m is a distance 2d from the axis and 2m is a distance d from the axis, the moment of inertia of this combination is "I". If the masses are now interchanged, the moment of inertia will be:_______
A) 2/3 I,
B) I ,
C) 3/2 I ,
D) 2 I ,
E) 4 I
Answer:
C) 3/2 I
Explanation:
Initial condition
I = m(2d)² + 2m(d²)
I = 4md² + 2md² = 6md²
swap masses
I' = 2m(2d)² + m(d²)
I' = 8md² + md² = 9md²
I'/I = 9md²/6md² = 3/2
I' = 3/2I
1.Name any two part of a flower?
2.write SI unit and fundamental unit of force, power and volume?
Explanation:
s.i unit of force is kgm/s²
dimensions of force is ML/T²
s.i unit of power kgm²/s³
dimension of power is ML²/T³
s.i unit of volume is m³
the dimension of volume is L³
What is the velocity of an object that moves from 73 m to 62 m in 15 s?
Answer:
Below
Explanation:
You can use this formula to find the velocity of an object
velocity = displacement / change in time
For this problem, we need to find displacement first
To find displacement all you need to do is find the difference between the two distances!
So our displacement here would be
73 - 62 = 11 m
Now that we have displacement we can find velocity
velocity = 11 / 15
= 0.733333....
= 0.73 m/s
Hope this helps! Best of luck <3
The velocity of an object that moves from 73 m to 62 m in 15 s is 0.73 m / s.
What is velocity?When an item is moving, its velocity indicates how quickly its location is changing as seen from a specific point of view and as measured by a specific unit of time.
If a point travels a specific distance along its path in a predetermined amount of time, its average speed throughout that time is equal to the traveled distance divided by the travel time. For instance, a train traveling 100 km in two hours is moving at an average speed of 50 km/h.
Given:
The distance of the object = 73 m to 62 m,
The time taken by the object, t = 15 s,
Calculate the displacement of the object = 73 - 62 = 11 m
Calculate the velocity by the formula given below,
[tex]v = d /t[/tex]
v = 11 / 15
v = 0.73 m / s
Therefore, the velocity of an object that moves from 73 m to 62 m in 15 s is 0.73 m / s.
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If the mass of an object is 5 kg and the velocity is 8 m/s, what is the momentum?
Answer:
40 kg•m/s
Explanation:
momentum (p) = mass (kg) × velocity (m/s)
The resistance of a wire depends on
Select one:
O a. the cross-sectional area of the wire.
b. All of the answers are correct.
O c. the temperature of the wire.
O d. the length of the wire.
Answer:
b
Explanation:
because all are factors that determine the resistivity of a material
explain fundamental quantities in
physics
Answer:
fundamental quanties are mass , time, length, temperature , amount of substance and luminous intensity. All other physical quantity are derived quantity and be made from fundamental quanties.
Explanation:
hope it helps u
Answer:
The other person answered
Explanation:
2. Samuel leaves the end of a 4.0-m-high diving board and strikes the
water 1.3 s later, 3.0 m beyond the end of the board. Considering the
diver as a particle, determine:
(a) His initial velocity,
(b) The maximum height reached;
(c) The velocity Vf
with which he enters the water.
Answer:
a) v = 4.9 m/s at 62° above the horizontal
b) h = 0.94 m above the board or 4.94 m above the water
c) v = 10 m/s at 77° below the horizontal
Explanation:
Assume UP and FOREWARD are positive and the diving board is the origin.
Ignore air resistance.
s = s₀ + v₀t + ½at²
In the vertical
-4 = 0 + vy₀(1.3) + ½(-9.8)(1.3²)
vy₀ = 4.281 m/s
in the horizontal
3.0 = 0 + vx₀(1.3) + ½(0)(1.3²)
vx₀ = 2.307... m/s
v = √(4.281² + 2.307²) = 4.863...
tanθ = 4.281 / 2.307
θ = 61.680...
v² = u² + 2as
s = (v² - u²) / 2a
h = (0² - 4.281²) / 2(-9.8) = 0.9350...
v² = 4.863² + 2(9.8)(4)
v = 10.1019...
cosθ = 2.307/10.1019
θ = 76.798
(a) The initial velocity of Samuel is 4.02 m/s
(b) The maximum height reached by Samuel is 0.55 m
(c) The final velocity when he enters the water is 5.20 m/s
The given parameter:
the height of the board, h = 4 mtime to strike the water, t = 1.3 sthe horizontal distance traveled, x = 3.0 m(a) The initial velocity of Samuel is calculated as;
[tex]h = v_o_y t + \frac{1}{2} gt^2\\\\[/tex]
Assume downward motion to be in negative direction
The vertical component of the velocity is calculated as;
[tex]4 = 1.3\times v_0_y + 0.5\times 9.8\times 1.3^2\\\\4 = 1.3v_{0y} + 8.281\\\\1.3v_{0y} = 4- 8.281\\\\1.3v_{0y} = -4.281\\\\v_{0y} = \frac{-4.281}{1.3} \\\\v_{0y} = -3.293 \ m/s\\\\v_{0y} = 3.293 \ m/s \ \ \ (downwards)[/tex]
The horizontal component of the velocity is calculated as;
Assume forward motion to be in positive direction
[tex]x = v_{0x}t \\\\3 = 1.3v_{0x}\\\\v_{0x} = \frac{3}{1.3} \\\\v_{0x} = 2.308 \ m/s[/tex]
The resultant of initial velocity is calculated as;
[tex]v_0 = \sqrt{v_{0y}^2 + v_{0x}^2} \\\\v_0 = \sqrt{3.293^2 + 2.308^2} \\\\v_0 = \sqrt{16.17} \\\\v_0 = 4.02 \ m/s[/tex]
(b) The maximum height reached by Samuel is calculated as;
[tex]v_f_y^2 = v_0_y^2 + 2gh\\\\at \ maximum \ height \ v_{fy} = 0\\\\0 = v_0_y^2 + 2gh\\\\-2gh = v_0_y^2\\\\h = \frac{v_0_y^2}{-2g} \\\\h = \frac{(3.293)^2}{-2\times 9.8} \\\\h = -0.55 \ m\\\\h = 0.55 \ m \ (downwards)[/tex]
(c) The final velocity when he enters the water;
The height traveled before he hits the water, h = 0.55 m
[tex]v_f^2 = v_{0}^2 + 2gh\\\\v_f^2 = (4.02)^2 + (2\times 9.8\times 0.55)\\\\v_f^2 = 26.94\\\\v_f = \sqrt{26.94} \\\\v_f = 5.20 \ m/s[/tex]
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Encontrar el peso de un elefante cuya masa es de 4500kg. Recordar que la gravedad es de 9.8m/s2
la respuesta es 459.183673 kg s2 / m
Answer:
44,100 N
Explanation:
4500(9.8) = 44,100
hey friends give me the solution to attachment
Answer:
downwards bro now dodododododdodo
Answer:
[tex]vertically \: downward \\ to \: the \: cenre \: of \: earth \\ thank \: you[/tex]
The boiling point of lauric acid is 298.9°C. Its melting point is 43.2°C. At room temperature (~25°C), lauric acid is in which state?
A. solid
B. intermediate between solid and liquid
C. liquid
D. intermediate between liquid and gas
Answer
A. solid
Explanation
We have that At room temperature (~25°C), lauric acid is in a
Solid state
Option A
From the question we are told that
The boiling point of lauric acid is 298.9°C. Its melting point is 43.2°C.
It is important to note that Room temperature is is at 25C
Generally
if lauric acid 298.9°C and melting point is 43.2°C
Therefore at room temperature low than Boiling and melting point lauric acid is
Solid
in conclusion
At room temperature (~25°C), lauric acid is in a Solid state
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two masses m and 2m, approach each along a path at right angles to each other. after collision, they stick together and move off at 2m/s at angle 37° to the original direction of the mass m. what were the initial speeds of the two particles
Explanation:
the answer is in picture
two projectile are thrown at the same intial velocity the angle of the one is theta ,the angle of the oher is 90-theta /can both projectile strict the ground at the distance and time interval of both when they are in arir?
Answer:
Yes, if θ = 45°
Explanation:
Write the following as full (decimal) numbers with standard units metric (SI) units:
(For example, 80.2 kA = 80,200 A)
651.9 mm
71 V
910 mg
30.0 ps
22.5 fm
2.00 gigavolts
Answer:
Explanation:
651.9 mm = 0.6519 m
71 V = 71 V
910 mg = 0.000910 kg
30.0 ps = 0.000 000 000 030 0 s
22.5 fm = 0.000 000 000 000 022 5 m
2.00 gigavolts = 2 000 000 000 V
Question 9 of 10
Which of the following is equal to the area under a velocity-time graph?
A. Velocity
B. Displacement
C. Force
D. Accelertion
SUBMIT
Displacement is equal to the area under a velocity-time graph.
Consider the mass-on-a-spring system as shown in the figure below. The spring has a spring constant of 1.81e+3 N/m, and the block has a mass of 0.988 kg. There is a constant force of kinetic friction between the mass and the floor of 1.79 N. Starting with the spring compressed by 0.172 m from its equilibrium position, how far will the block travel once it leaves the spring? (Assume that block leaves the spring at at the spring's equilibrium position, marked x=0 in the figure.
K1Answer:
s= 6.5cm
Explanation:
Point 1: just right before the block leaves the spring
Point 2: the block has v2=0 (stops moving)
Apply Kinetic-Work Theorem:
K1 + U1 + Wother = K2 + U2
K1=0
U1= 1/2×k×x² (k= 1.81e+3 N/m and x= -0.172 m)
Wother = F×s= 1.79×s
K2=0
U2=0
=> s= 6.5cm
This is my attempt to solve. Let me know if this isn't right
29. Convert 2.922 x 10-14 to a standard number.
Since the exponent is negative, move the decimal point to the left (backward).
0.000 000 000 000 029 22
Yellow light passes through a diffraction grating. it's first order maximum occurs at an angle of 21.2. What is the slit separation d?
Answer:
19.284
or
9.33
Explanation:
Answer:
1.66
Explanation:
Found answer on chegg. Works for acellus
A ball is rotating on a circle of radius 0.500m at a constant ratr of 200 rev/min.Find the speed and acceleration of the ball.
Answer:
Solution
verified
Verified by Toppr
The radius of the tire is r=0.500m. The speed of the stone on its outer edge is
v
t
=
T
2πr
=
(60.0s/200rev)
2π(0.500m)
=10.5m/s
and its acceleration is
a=
R
v
2
=
0.500m
(10.5m/s)
2
=219m/s
2
inward.
Explanation:
A human hair is approximately 50 pm in diameter. Express this diameter in meters.
A human hair is approximately 50 μm = 5 × 10⁻⁵ m in diameter
what change occurs to the gravitational force of attraction between two bodies when the distance between them is made half 1 by 2 by keeping masses constant
Explanation:
Since the gravitational force is inversely proportional to the square of distance, changing the distance to half the original results in 4 times the original force
the value of mass of a body is everywhere
Explanation:
The value of mass of a body is not same everywhere.
Because it depends on gravity and the gravity isn't same at every places.
Answer:
Mass is the quantity of matter contained in a body, while weight is the force by which the body is pulled to the earth's center. Mass is an intrinsic property of a body, as it remains the same everywhere in the universe. Weight is variable due to change in the magnitude of the gravitational force applied by the earth.
By how many times will the kinetic energy of a body increase if its speed is tripled? Show by calculation.
Answer:
9 times more kinetic energy
Explanation:
KE₀ = ½mv²
KE₁ = ½m(3v)² = 9(½mv²) = 9KE₀
two car moving in the same direction have speed of 100km/h-1 and 130km/h.what is the resultant of velocity .shoe carnival in the same direction having speed of 100 km per hour - 1 and 130 km per hour to kilometre-per-hour - 1
Answer:
jjjjjjhshahshhddhdhh
what are the newtons law and their formulas
Answer:
Newton's second law of motion states that the acceleration ( a) experienced by an object is directly proportional to the net force ( Fnet) experienced by the object and inversely proportional to the mass of the object. In equation form, it could be said that a = Fnet/m. The net force is the vector sum of all the individual force values.
Explanation:
A car accelerates from rest at a rate of 8.1 m/s2. How much time does it take the car to travel a distance of 65 meters?
Answer:
ोोञककतकषगकषषमषघ
Explanation:
zzjjjfkgkzgkggkkkammmmmmatAllzy##pglCsg
Diamond has a density of 3.26 g/cm3
. What
is the mass of a diamond that has a volume of
0.214 cm3
?
Answer in units of g
Explanation:
Hey there!
According to the question;
Density of diamond (d) = 3.26g/cm³
And Volume (v) = 0.214 cm³
Mass(m) = ?
From the definition of density;
d = m/v
Or, 3.26 g/cm³ = m/(0.214 cm³)
or, 3.26 g/cm³ * 0.214 cm³ = m
Therefore, mass of the diamond is 0.69764 g.
Hope it helps!
How much time does a train take to travel1800 km if it's velocity is 90km/hr
Explanation:
Time= Distance÷Velocity
Time= 1800÷90
Time= 20 hr
20×60= 1200 min
A small piece of aluminum (atomic number 13) contains 10^15 atoms (The atomic number is the number of protons; it determines the (positive) electric charge of the nucleus and, thus, the number of electrons in a neutral atom.) If the piece of aluminum has a net positive charge of 3.0 uc what fraction of the electrons that the aluminum had when it was neutral would have had to be lost?
Answer:
3 micro coulombs = 3 * 10E-6 coulombs charge of aluminum
13 * 10E15 * 1.6 * 10E-19 = 2.08 E-3 Coulombs - charge of atoms in Al
3 * 10E-6 / 2.08 * E-3 = 1.44 * E-3 = .00144 = .144 %
.00144 of the original electrons would have to be lost
A boy with a mass of 45 kg runs towards a stationary trolley with a total mass of 30 kg. The boy then jumps on the trolley and the trolley starts to move.
a) Explain why the trolley starts to
move after the boy jumps on it.
b) Calculate the magnitude of the
velocity of the trolley after the boy jumps on it.
anyone here cold helps me to solve and explain the answer... thanks in advance
Answer:
The trolley moves because a force of exertion is pushed onto it when the boy launches himself onto it. It also moves in a direction, so velocity is applied to it.
The velocity goes from stand-still to something. Also, to find velocity, I think acceleration and time are 2 constants that are needed to find velocity, which is not present in the question.
Sorry if this is not the answer you wanted.. I just gave a basic guess as to what I think the answer is. I just started to learn physics.
Explanation:
differentiate between air pressure and liquid pressure in table .
Air pressure or atmospheric pressure is the pressure as the force exerted by the collisions of particles in the air.
The key difference between air pressure and liquid pressure is that air pressure allows the gaseous state of matter to be compressible, whereas liquid pressure makes a liquid incompressible
Answer:
Air pressureAtmospheric pressure, also known as barometric pressure, is the pressure within the atmosphere of Earth. The standard atmosphere is a unit of pressure defined as 101,325 Pa, which is equivalent to 760 mm Hg, 29.9212 inches Hg, or 14.696 psi.
Liquid pressureLiquid pressure is the increase in pressure at increasing depths in a liquid. This pressure increases because the liquid at lower depths has to support all of the water above it. We calculate liquid pressure using the equation liquid pressure = mass x acceleration due to g density x depth in fluid.