help me with this please pleaseee!

Answer:(

fx).(gx)=D. -40x^3+25x^2+45

Step-by-step explanation:

Answer:

BC^2=10^2+30^2

Step-by-step explanation:

Using pythagorean theorem

[tex]\\ \sf\longmapsto BC^2=10^2+30^2[/tex]

[tex]\\ \sf\longmapsto BC^2=100+300[/tex]

[tex]\\ \sf\longmapsto BC^2=400[/tex]

[tex]\\ \sf\longmapsto BC=\sqrt{400}[/tex]

[tex]\\ \sf\longmapsto BC=20[/tex]

Answer:

The price that maximizes the revenue is $165

Step-by-step explanation:

We can model the price as a function of sold units as a linear relationship.

Remember that a linear relationship is something like:

y = a*x + b

where a is the slope and b is the y-intercept.

We know that if the line passes through the points (x₁, y₁) and (x₂, y₂), then the slope can be written as:

a = (y₂ - y₁)/(x₂ - x₁)

For this line, we have the point (40, $110)

which means that to sell 40 units, the price must be $110

And we know that if the price increases by $11, then he will sell 2 units less.

Then we also have the point (38, $121)

So we know that our line passes through the points (40, $110) and  (38, $121)

Then the slope of the line is:

a = ($121 - $110)/(38 - 40) = $11/-2 = -$5.5

Then the equation of the line is:

p(x) = -$5.5*x + b

to find the value of b, we can use the point (40, $110)

This means that when x = 40, the price is $110

then:

p(40) = $110 = -$5.5*40 + b

            $110 = -$220 + b

       $110 + $220 = b

        $330 = b

Then the price equation is:

p(x) = -$5.5*x + $330

Now we want to find the maximum revenue.

The revenue for selling x items, each at the price p(x), is:

revenue = x*p(x)

replacing the p(x) by the equation we get:

revenue = x*(-$5.5*x + $330)

revenue = -$5.5*x^2 + $330*x

Now we want to find the x-value for the maximum revenue.

You can see that the revenue equation is a quadratic equation with a negative leading coefficient. This means that the maximum is at the vertex.

And remember that for a quadratic equation like:

y = a*x^2 + b*x + c

the x-value of the vertex is:

x = -b/2a

Then for our equation:

revenue = -$5.5*x^2 + $330*x

the x-vale of the vertex will be:

x = -$330/(2*-$5.5) = 30

x = 30

This means that the revenue is maximized when we sell 30 units.

And the price is p(x) evaluated in x = 30

p(30) = -$5.5*30 + $330 = $165

The price that maximizes the revenue is $165

9514 1404 393

Answer:

  1.56×10^10 cL

Step-by-step explanation:

There are 1000 liters in a cubic meter, so 10^5 centiliters in a cubic meter. The 1.56×10^5 cubic meters will then have ...

  (1.56×10^5 m^3)×(10^5 cL/m^3) = 1.56×10^10 cL

_____

That's 15,600,000,000 cL.

"Centi-" is a prefix meaning 1/100.

Answer: SORRY NEED AN ACCOUNT ON - 10

Step-by-step explanation:

To resolve the proposed issue, an explanation is needed in which the subject is addressed

Answer:

10+26+4=40

in total there is 40 animals

because there is in total for 40 animals then that mean 40 animals is 100%

now we see that there are 26 horses we only need to divid ( but remember you have to divid the percent and the number of animals together)

40 ÷ 20 = 2.    2 x 13 = 26

100% ÷ 20 = 5%.  5% x 13 = 65%

the answer for this question:

the percentage of animals that are horses is 65%

Answer:

Step-by-step explanation:

Answer:

sir she hey Jen Jen Jenn receive surge

Answer:

Hello,

Step-by-step explanation:

z=0.7734

p(z<?)=0.75 ==> ?=0.7734

The equation of the reflected function across the y-axis is g(x) = -4x - 8.

A statement, principle, or policy that creates the link between two variables is known as a function. Functions are found all across mathematics and are required for the creation of complex relationships.

The function f(x) = 4x - 8 is reflected across the y-axis.

The function g(x) will be given by putting the negative x in place of x. Then the reflected function is obtained.

g(x) = -4x - 8

Then the equation of the reflected function across the y-axis is g(x) = -4x - 8.

The graph of the reflected graph is given below.

More about the function link is given below.

https://brainly.com/question/5245372

#SPJ2

3000 people participated in the survey, of which 2790 like some type of drink.

Since in a survey of some people, 73% like to drink tea, 85% like to drink coffee and 65% like to drink tea as well as coffee, if 210 people like neither tea nor coffee, to find the total number of people taken part in the survey and show how many of them like at least one of the given drink, the following calculations must be performed:

-First, it must be determined how many people do not prefer any of the drinks, in percentages, subtracting the 65% who like both from the percentages of each particular drink, and adding these results.

-Therefore, the 210 people who do not like any drink are 7 percent of the total survey. Therefore, to determine the total number of people who participated, the following cross multiplication must be carried out.

3000 - 210 = 2790

Therefore, 3000 people participated in the survey, of which 2790 like some type of drink.

Learn more about cross multiplication in https://brainly.com/question/24327293.

Answer:

D.

Step-by-step explanation:

2=-2，3=-3

2²=-2²，3²=3²

Answer:

D 1

Step-by-step explanation:

i^12

We know i^4 = 1

Rewriting

i^4^3

1^3

1

Answer:

part 1- D. 1

part 2- Square root of -144 =12i

Step-by-step explanation:

Got them correct

9514 1404 393

Answer:

  67.0 square units

Step-by-step explanation:

The formula for the area is ...

  Area = 1/2ab·sin(C)

  Area = (1/2)(14)(28)sin(20°) ≈ 67.036 . . . . square units

The area of the triangle is about 67.0 square units.

Answer:

b) Y =5.73X +4.36

C)  =5.73225*(21)X +4.359

    124.73625

D) 163.728 = 5.73X +4.36  

     X = (163.728 - 4.36)/5.73

     X = 27.81291449

  Year would be 2027

Step-by-step explanation:

x1 y1  x2 y2

4 27.288  16 96.075

(Y2-Y1) (96.075)-(27.288)=   68.787  ΔY 68.787

(X2-X1) (16)-(4)=    12  ΔX 12

slope= 5 41/56    

B= 4 14/39    

Y =5.73X +4.36      

Answer:

B. 1 + ln 2 - ln x

General Formulas and Concepts:

Algebra II

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle ln(\frac{2e}{x})[/tex]

Step 2: Simplify

Answer:

48,000,000

Step-by-step explanation:

47,709,982

Look at the millions place and then see if the number after that is a greater number than 4. If it isn't, round down but if it is, round up

Answer:

[tex]C(x) = \left[\begin{array}{ccc}4x &0 \le x \le 2& \\4 +2x &2 < x \le 6& \\16 &6<x\le 8& \end{array}\right[/tex]

Step-by-step explanation:

Given

See attachment for question

Required

The piece-wise function

From the attachment, we have:

(1) $4/hr for first 2 hours

This is represented as:

[tex]C(x) = 4x[/tex]

The domain is: [tex]0 \le x \le 2[/tex]

(2) $2/hr for next 4 hours

Here, we have:

[tex]Rate = 2[/tex]

The total cost in the first 2 hours is:

[tex]C(x) = 4x[/tex]

[tex]C(2) = 4*2 = 8[/tex]

So, this function is represented as:

[tex]C(x) = C(2) + Rate * (Time - 2)[/tex] ----- 2 represents the first 2 hours

So, we have:

[tex]C(x) = C(2) + Rate * (Time - 2)[/tex]

[tex]C(x) =8 + 2(x - 2)[/tex]

Open brackets

[tex]C(x) =8 + 2x - 4[/tex]

Collect like terms

[tex]C(x) =8 - 4+ 2x[/tex]

[tex]C(x) =4+ 2x[/tex]

The domain is:

[tex]2 < x \le 2 + 4[/tex]

[tex]2 <x \le 6[/tex]

(3) 0 charges for the last 2 hours

The maximum charge from (2) is:

[tex]C(x) =4+ 2x[/tex]

[tex]C(6) = 4 + 2*6[/tex]

[tex]C(6) = 4 + 12[/tex]

[tex]C(6) = 16[/tex]

Since there will be no additional charges, then:

[tex]C(x) = 16[/tex]

And the domain is:

[tex]6 < x \le 8[/tex] --- 8 represents the limit

So, we have:

[tex]C(x) = \left[\begin{array}{ccc}4x &0 \le x \le 2& \\4 +2x &2 < x \le 6& \\16 &6<x\le 8& \end{array}\right[/tex]

Answer:

SEE BELOW

Step-by-step explanation:

1. sample size - 1,251

2 .statistic - 53.6%

3. parameter - 86%

hope this helps :)

Answer:

W=7 and L=11

Step-by-step explanation:

We have two unknowns so we must create two equations.

First the problem states that  length of a rectangle is 10 yd less than three times the width so: L= 3w-10

Next we are given the area so: L X W = 77

Then solve for the variable algebraically. It is just a system of equations.

3W^2 - 10W - 77 = 0

(3W + 11)(W - 7) = 0

W = -11/3 and/or W=7

Discard the negative solution as the width of the rectangle cannot be less then 0.

So W=7

Plug that into the first equation.

3(7)-10= 11 so L=11

Answer:

b. The solution is a non empty set.

Step-by-step explanation:

There are no common elements.

9514 1404 393

Answer:

Step-by-step explanation:

Let x represent the quantity of 80% solution. Then the quantity of 55% solution is (130-x) and the total amount of antifreeze in the mix is ...

  0.55(130 -x) +0.80(x) = 0.70(130)

  0.25x +71.5 = 91 . . . simplify

  0.25x = 19.5 . . . . . . subtract 71.5

  x = 78 . . . . . . . . . . . divide by 0.25; amount of 80%

  130-78 = 52 . . . . amount of 55%

52 gallons of the 55% brand, and 78 gallons of the 80% brand must be used.

Answer:

The answer is "0.07404893".

Step-by-step explanation:

Applying the binomial distribution:

[tex]n = 22\\\\p= 82\%=0.82\\\\q = 1-0.82 = 0.18\\\\[/tex]

Calculating the probability for not enough seats:

[tex]=P(X>20)\\\\= P(21) + P(22)\\\\[/tex]

[tex]= \binom{22}{21} (0.82)^{21}(0.18)^1+ \binom{22}{22} (0.82)^{22}(0.18)[/tex]

[tex]=0 .06134598+ 0.01270295\\\\=0.07404893[/tex]

Answer:

1.5

Step-by-step explanation:

Let the first term be a and the common ratio be r

ATQ, ar=50 and ar^3=112.5, divide these two. r^2=2.25, r=1.5

Jane is given a $100 gift to start and saves $35 a month from her allowance.

   After 1 month, Jane has saved

   After 2 months, Jane has saved

   After three months, Jane has saved

   and so on

In general, after x months Jane has saved

This means that it makes sense to represent the relationship between the amount saved and the number of months with one constant rate (in this case the constant rate is 35). It makes sense because the amount of money increases by $35 each month. Since the amount of increase is constant, we get constant rate. Also the initial amount is known ($100), so there is a possibility to write the equation of linear function representing this situation.

Step-by-step explanation:

First, find the inverse of f,

[tex]y=e^x[/tex]

[tex]x=e^y[/tex]

Now take the natural logarithm on both sides,

[tex]\ln x=\ln e^y\implies f^{-1}(x)=\boxed{\ln(x)}[/tex]

Second, find the inverse of g,

[tex]y=5x\implies g^{-1}(x)=\boxed{\frac{x}{5}}[/tex]

Now take their composition,

[tex](g\circ f)(x)=g(f(x))=\frac{\ln(x)}{5}[/tex]

Let [tex]y=\frac{\ln(x)}{5}[/tex], now again find the inverse,

[tex]x=\frac{\ln(y)}{5}[/tex]

[tex]5x=\ln y[/tex]

exponentiate both sides to base e,

[tex]e^{5x}=e^{\ln y}\implies (g\circ f)^{-1}(x)=\boxed{e^{5x}}[/tex]

Hope this helps :)

Answer:

The answer is a.

Answer:

The numbers are 18 and 25

Step-by-step explanation:

Given

[tex]\bar x_1 = 14[/tex]     [tex]n_1 = 17[/tex]

[tex]\bar x_2 = 13[/tex]     [tex]n_2 = 15[/tex]

[tex]a - b = 7[/tex] --- the difference of the 2 numbers

Required

Find a and b

We have:

[tex]\bar x = \frac{\sum x}{n}[/tex] -- mean formula

So, we have:

[tex]\bar x_1 = \frac{\sum x_1}{n_1}[/tex]

[tex]14 = \frac{\sum x_1}{17}[/tex]

Cross multiply

[tex]\sum x_1 = 14 * 17[/tex]

[tex]\sum x_1 = 238[/tex]

When the two numbers are removed, we have:

[tex]\bar x_2 = \frac{\sum x_2}{n_2}[/tex]

[tex]13 = \frac{\sum x_2}{15}[/tex]

Cross multiply

[tex]\sum x_2 = 13 * 15[/tex]

[tex]\sum x_2 = 195[/tex]

The two numbers that were removed are:

[tex]a + b = \sum x_1 - \sum x_2[/tex]

[tex]a + b = 238 - 195[/tex]

[tex]a + b = 43[/tex]

Make a the subject

[tex]a= 43 - b[/tex]

We have:

[tex]a - b = 7[/tex]

Substitute [tex]a= 43 - b[/tex]

[tex]43 - b - b = 7[/tex]

[tex]43 - 2b = 7[/tex]

Collect like terms

[tex]2b = 43 - 7[/tex]

[tex]2b = 36[/tex]

Divide by 2

[tex]b = 18[/tex]

Substitute [tex]b = 18[/tex] in [tex]a= 43 - b[/tex]

[tex]a = 43 - 18[/tex]

[tex]a = 25[/tex]

Base case (n = 1):

• left side = 1×2² = 4

• right side = 1×(1 + 1)×(3×1² + 11×1 + 10)/12 = 4

Induction hypothesis: Assume equality holds for n = k, so that

1×2² + 2×3² + 3×4² + … + k × (k + 1)² = k × (k + 1) × (3k ² + 11k + 10)/12

Induction step (n = k + 1):

1×2² + 2×3² + 3×4² + … + k × (k + 1)² + (k + 1) × (k + 2)²

= k × (k + 1) × (3k ² + 11k + 10)/12 + (k + 1) × (k + 2)²

= (k + 1)/12 × (k × (3k ² + 11k + 10) + 12 × (k + 2)²)

= (k + 1)/12 × ((3k ³ + 11k ² + 10k) + 12 × (k ² + 4k + 4))

= (k + 1)/12 × (3k ³ + 23k ² + 58k + 48)

= (k + 1)/12 × (3k ³ + 23k ² + 58k + 48)

On the right side, we want to end up with

(k + 1) × (k + 2) × (3 (k + 1) ² + 11 (k + 1) + 10)/12

which suggests that k + 2 should be factor of the cubic. Indeed, we have

3k ³ + 23k ² + 58k + 48 = (k + 2) (3k ² + 17k + 24)

and we can rewrite the remaining quadratic as

3k ² + 17k + 24 = 3 (k + 1)² + 11 (k + 1) + 10

so we would arrive at the desired conclusion.

To see how the above rewriting is possible, we want to find coefficients a, b, and c such that

3k ² + 17k + 24 = a (k + 1)² + b (k + 1) + c

Expand the right side and collect like powers of k :

3k ² + 17k + 24 = ak ² + (2a + b) k + a + b + c

==>   a = 3   and   2a + b = 17   and   a + b + c = 24

==>   a = 3, b = 11, c = 10

Answer:40, 80 and 62

Step-by-step explanation:

182-22= 160

160/4 = 40 so,

Shortest side is 40

Longest is 80

Third side is 62

Answer:

Mark Brainliest please

The answer is 1

Step-by-step explanation:

(1 — x^ m-n) ^-1 + (1- x ^n-m)^ -1

1/[1-x^(m-n)] + 1/[1-x^(n-m)]

1/[1-x^m × x^(-n)] + 1/[1-x^n × x^(-m)]

x^n/(x^n - x^m) + x^m/(x^m - x^n)

x^n/(x^n - x^m) - x^m/(x^n - x^m)

Now taking the LCM here, we get

(x^n - x^m)/(x^n - x^m)