Help and explain please !!!

Hi.

Let's call X number of visits.

so members pay for a year : membership 24 and reduce entrance at 3 dollars.

so you member pay : 3X+24

a non member pay entrance fee of 6 for each visit.

so 6X

Question : for how many visit would a membership will be more intresting than standar entrance ?

3X+24 = 6X

3X-6X = -24

-3X=-24

X= -24/-3

X =24/3

X= 8

Under 8 visit a year, it's cheaper non being a member.

at 8 entrance cost is the same for members and non member. After it better to choose membership as

9 entrances for member is : 3x9 +24 = 27+24= 51

non member : 9x6 = 54

And so on for each supplementary visits.

Answer:

1.9

Step-by-step explanation:

You round when the numbers behind the decimal are 5 or greater. This being said, you need to round from the number furthest away from the decimal. In this case it would be 9. 9 is greater than 5 so we round 8 up to 9 and get rid of the number behind it. We are left with 1.9

Answer:

D

Step-by-step explanation:

I took the quiz

Answer:

c on edge

Step-by-step explanation:

Answer:  Choice A

y=2x+3; y=-1/3x+3

==================================================

Explanation:

The left portion of the blue curve is y = 2x+3 but it is only graphed when x < 0 (we could argue that [tex]x \le 0[/tex] but I'll set that aside for the other portion).

The right portion is the line y = -1/3x + 3 and it's only graphed when [tex]x \ge 0[/tex]

So we could have this piecewise function

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x < 0\\-\frac{1}{3}x+3 \ \text{ if } x \ge 0\\\end{cases}[/tex]

Or we could easily swap the "or equal to" portion to move to the first part instead like this

[tex]f(x) = \begin{cases}2x+3 \ \text{ if } x \le 0\\-\frac{1}{3}x+3 \ \text{ if } x > 0\\\end{cases}[/tex]

Either way, we're involving the equations mentioned in choice A

Answer:

Step-by-step explanation:

Let the amount of gas in the tank before filling was x.

We have:

let the amount of gas be x

[tex]\\ \sf\longmapsto x+2\dfrac{4}{7}=4[/tex]

[tex]\\ \sf\longmapsto x+\dfrac{18}{7}=4[/tex]

[tex]\\ \sf\longmapsto x=4-\dfrac{18}{7}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{28-18}{7}[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{10}{7}[/tex]

[tex]\\ \sf\longmapsto x=1\dfrac{3}{7}[/tex]

Answer:

True

Step-by-step explanation:

Any two points are always collinear because you can always connect them with a straight line. Three or more points can be collinear, but they don't have to be. ... Coplanar points: A group of points that lie in the same plane are coplanar. Any two or three points are always coplanar.

Answer:

[tex]we \: know \: that \: commutative \: prop \\ = x + y = y + x \\ then \\ 4xy + 0 = 0 + 4xy \\ thank \: you[/tex]

Answer:

x = - 1, x = - 0.5

Step-by-step explanation:

Given

2x(x + 1.5) = - 1 ← distribute parenthesis on left side

2x² + 3x = - 1 ( add 1 to both sides )

2x² + 3x + 1 = 0 ← in standard form

(2x + 1)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

2x + 1 = 0 ⇒ 2x = - 1 ⇒ x = - 0.5

Answer:

she baked 3 times as many cranberry than blueberry muffins

Step-by-step explanation:

i think that because 9×3=27

the amount of the cranberry muffins are 9

Answer:

it will take 5days to reach a total of 180meters

Step-by-step explanation:

80m+20+20+20+20+20

=180meters

=5days

Answer:

(a+b)³=a³+3a²b+3ab²+b³

Answer:

Step-by-step explanation:

Hello!

(a+b)(a+b)(a+b)

(a+b)(a+b) = a²+2ab + b²

(a²+2ab + b²) (a+b)=

a³ + a²b +  2a²b + 2ab² + ab² + b³ =

a³ + b³ +  2a²b + 2ab² + ab²  + a²b

Answer:

c) 21

Step-by-step explanation:

[tex] \sqrt{169} + \sqrt{64} [/tex]

13+8

answer is 21

Answer:

B

Step-by-step explanation:

x -> x and y -> y+5

-1 -> - 1 and - 3 -> 2, so b is the correct answer.

Answer:

hope it helps

Step-by-step explanation:

Answer:

Step-by-step explanation:

S is the midpoint of QR.

⇒ RS = QS    

QR ⊥ PS

⇒ ∠RSP = ∠QSP = 90°

In ΔPSR & ΔPSQ,

Statement                     Reason

RS ≅ QS                       S is midpoint of QR

∠RSP ≅ ∠QSP              QR ⊥ PS

PS ≅ PS                         Reflexive property

ΔPSR ≅ ΔPSQ               Side Angle Side - S A S Congruent

PR≅  PQ                        CPCTC

Answer:

8 hours 10 minutes

I hope this answers your question

Answer: paul has been away from home for 7 hours and 50 minutes.

Step-by-step explanation:

Answer:

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Step-by-step explanation:

There are mistakes in the statement, correct form is presented below:

[tex]5+\frac{\sqrt{3}}{7} + 2\sqrt{3} = a - b\cdot \sqrt{3}[/tex].

By direct comparison we have the following system of equations:

[tex]a = 5[/tex] (1)

[tex]\frac{\sqrt{3}}{7}+2\sqrt{3} = -b\cdot \sqrt{3}[/tex] (2)

In (2) we solve for [tex]b[/tex]:

[tex]\left(\frac{1}{7}+2 \right)\cdot \sqrt{3} = -b\cdot \sqrt{3}[/tex]

[tex]b = -\frac{15}{7}[/tex]

The values of [tex]a[/tex] and [tex]b[/tex] are [tex]5[/tex] and [tex]-\frac{15}{7}[/tex], respectively.

Answer:

B. 4/5

Step-by-step explanation:

Sin = Opposite/Hypotenuse

Sin∠A = 8/10 = 4/5

Answer:

The cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Step-by-step explanation:

Given that Sayad bought a watch and sold to Dakshes at 10% profit, and Dakshes again sold it to Sahayata for $ 6,050 at 10% profit, to find the cost price of Dakshes and the cost price of Sayad the following calculations must be performed:

6,050 / 1.1 = X

5,500 = X

5,500 / 1.1 = X

5,000 = X

Therefore, the cost price of Dakshes was $ 5,500, while the cost price of Sayad was $ 5,000.

Answer: the answer to your question is 7

Step-by-step explanation:

Answer:

wyatt

Step-by-step explanation:

4:30 mins is 270 seconds

Refer the attached image for the answer

HOPE SO IT HELPS YOU

Step-by-step explanation:

(f*g) (x)=f(x) * g(x)

=(x+3)(2x^2-4)

=2x^3-4x+6x^2-12

Answer:

2nd option

Step-by-step explanation:

Given f(x) then f(x + a) is a horizontal translation of f(x)

• If a > 0 then a shift left of a units

• If a < 0 then a shift right of a units

Here g(x) = (x - 6)²

The base graph has been shifted right 6 units

Answer:

x^2 +2x -6

Step-by-step explanation:

f(x)=2x+1

g(x)=x^2-7,

(f+g)(x) = 2x+1 + x^2 -7

Combine like terms

           = x^2 +2x -6

f (x) = 2x + 1

g (x) = x² - 7

(f+g) (x) = 2x+1 + x² - 7

Adding like terms

⇛ x² + 2x - 6

Answer:

the answer is -299.808 well that's what I think it's

Answer:

-299.808

Step-by-step explanation:

= 10700/100 + 5192/100 - 412

= 107 + 5.192 - 412

= -299.808

Answer:

The answer is 2.)

Step-by-step explanation:

Given initial velocity=135 ft/s

& cliff=76 foot

Given quadratic equation

⇒                      (let h=0 it is given)

⇒  

⇒  

⇒    t=8.96≈9 s (the other root is negative)

Hence, rocket will take 9 s to hit the ground after launched.

Answer:  Choice D

0 = 16t^2 + 135t + 76;  9 s

==============================================

Explanation:

The equation we start with is

[tex]h = -16t^2 + vt + c\\\\[/tex]

where v is the starting or initial velocity, and c is the starting height.

We're told that v = 135 and c = 76

We let h = 0 to indicate when the object hits the ground, aka the height is 0 ft.

That means the equation updates to [tex]0 = -16t^2 + 135t + 76\\\\[/tex]

Based on that alone, the answer is between A or D

-------------------

We'll use the quadratic formula to solve for t

We have

So,

[tex]t = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\t = \frac{-135 \pm \sqrt{135^2 - 4(-16)(76)}}{2(-16)}\\\\t = \frac{-135 \pm \sqrt{23,089}}{-32}\\\\t \approx \frac{-135 \pm 151.9506}{-32}\\\\t \approx \frac{-135 + 151.9506}{-32} \ \text{ or } \ t \approx \frac{-135 - 151.9506}{-32}\\\\t \approx \frac{16.9506}{-32} \ \text{ or } \ t \approx \frac{-286.9506}{-32}\\\\t \approx -0.52971 \ \text{ or } \ t \approx 8.96721\\\\[/tex]

We ignore the negative t value because a negative time duration makes no sense.

The only practical solution here is roughly 8.96721 which rounds to 9.0 or simply 9 when we round to the nearest tenth (one decimal place).

In short, the object will hit the ground at the 9 second mark roughly. Or put another way: the object is in the air for about 9 seconds.

From this, we can see that the final answer is choice D.

Keep in mind that we aren't accounting for any wind resistance. Considering this variable greatly complicates the problem and requires much higher level mathematics. So we just assume that there is no wind at this moment.

Answer:

B

Step-by-step explanation:

here we use trigonometric ratio involving soh,cah,toa