Answers
Answer:
both are only physical changes
Explanation:
Physical changes are changes that do not alter the identity of a substance.
The liquid soap is still liquid soap when mixed into water.
The dry ice is still dry ice when it changes state from solid to gas.
Related Questions
Pete needs to be at work for 9.00am. He leaves his house at 7.30am and drives to the gym which is 12.5 miles away. Pete spends 45 minutes in the gym then drives the reaming 9 miles to work.
Answers
To determine the time Pete arrives at work, we can start by calculating the total time he spends on his commute and gym routine:
What time will Pete get to work?Time spent driving to the gym = 12.5 miles ÷ average speed
We don't know Pete's average speed, so we cannot calculate this.
Time spent in the gym = 45 minutes
Time spent driving from the gym to work = 9 miles ÷ average speed
Again, we don't know Pete's average speed, so we cannot calculate this.
Total time spent on commute and gym routine = time spent driving to gym + time spent in gym + time spent driving from gym to work
= Unknown + 45 minutes + Unknown
Next, we can convert the total time to hours and minutes:
Total time = (Unknown + 45 minutes + Unknown) ÷ 60
= (Unknown + Unknown) ÷ 60 + 45/60
= (2Unknown) ÷ 60 + 0.75
= (Unknown) ÷ 30 + 0.75
We know that Pete needs to arrive at work by 9.00am, so we can set up an equation:
Arrival time = 7.30am + Total time
9.00am = 7.30am + (Unknown/30) + 0.75
Solving for Unknown:
1.5 hours = Unknown/30
Unknown = 45 minutes
Therefore, Pete will arrive at work at 8.15am.
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Clinical psychologists are concerned with everyday problems of adjustment. True Or False
Answers
Answer:
True.
Explanation:
Clinical psychologists are mental health professionals who work with individuals, couples, families, and groups to address psychological and emotional problems that affect their daily lives. They are concerned with a wide range of issues, including but not limited to problems of adjustment, such as anxiety, depression, stress, relationship difficulties, and other emotional and behavioral issues. Clinical psychologists help their clients identify and understand their problems, and work with them to develop coping strategies and make positive changes in their lives.
Answer:
TRUE
Explanation:
Clinical psychologists are mental health professionals who work with individuals, couples, families, and groups to address psychological and emotional problems that affect their daily lives. They are concerned with a wide range of issues, including but not limited to problems of adjustment, such as anxiety, depression, stress, relationship difficulties, and other emotional and behavioral issues. Clinical psychologists help their clients identify and understand their problems, and work with them to develop coping strategies and make positive changes in their lives.
A driver notices that her 1400-kg car, when in neutral, slows down from 95 km/h to 65 km/h in about 7.0 s on a flat horizontal road. Approximately what power (watts) is needed to keep the car traveling at a constant 80 km/h? Express your answer using two significant figures.
Answers
The magnitude of power needed to keep the car traveling at a constant speed of 80 km/h would be 7 × [tex]10^4[/tex] watts.
Power calculationThe initial speed of the car is 95 km/h = 26.39 m/s, and the final speed is 65 km/h = 18.06 m/s. The change in speed over the 7.0 s interval is:
Δv = vf - vi = 18.06 m/s - 26.39 m/s = -8.33 m/s
The acceleration of the car can be found using:
a = Δv/t = -8.33 m/s / 7.0 s = -1.19 m/s^2
This is the deceleration of the car when it's in neutral. The force of friction acting on the car is:
F = ma = (1400 kg)(1.19 m/s^2) = 1666 N
To keep the car traveling at a constant 80 km/h = 22.22 m/s, a force equal in magnitude but opposite in direction to the force of friction must be applied. The power required to maintain this speed is:
P = Fv = (1666 N)(22.22 m/s) = 37000 W ≈ 3.7 × [tex]10^4[/tex] W
Therefore, the power needed to keep the car traveling at a constant 80 km/h is approximately 7 × [tex]10^4[/tex] watts.
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A diesel engine of a 400-Mg train increases the train's speed uniformly from rest to 10 m/s in 100 s along a horizontal track. Determine the average power developed.
Answers
The average power developed by a diesel engine of a 400-Mg train increases the train's speed uniformly from rest to 10 m/s in 100 s along a horizontal track = 200 kW.
How to calculate average power?The first kinematic equation is v=v0+at , where v is the final velocity, v0 is the initial velocity, a is the constant acceleration, and t is the time
According to given information:
v = 10, v0= 0 , t= 100s, m=400
v=v0+at
10= 0+a(100)
a= 0.1 m/s²
∑ F =ma <==> F= 400(10 ³ )(0.1) = 40(10 ³)N
Pavg = F. Vavg = 40(10 ³)(10/2) = 200 kW
It represents the typical quantity of work completed or energy converted per unit of time. When the context clearly indicates it, the average power is frequently referred to as "power".
The instantaneous power overrides the average power as time interval t gets closer to zero.
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If a person steps on a scale in an elevator that is accelerating at a rate -1.100 m/s^2 (negative means downward while positive means upwards) and sees a scale reading of 598.900 Newtons what would the scale read if the elevator were not moving?
answer with correct units
Answers
Answer:
Explanation:
When the elevator is accelerating downwards, the apparent weight of the person is reduced, and when the elevator is accelerating upwards, the apparent weight is increased.
First, we need to determine the actual weight of the person. We can do this by using the formula:
Weight = mass x gravity
where mass is the mass of the person and gravity is the acceleration due to gravity, which is approximately 9.81 m/s^2.
Weight = (598.900 N) / (9.81 m/s^2) = 61.048 kg
Now, when the elevator is not moving, the person is only experiencing the force due to gravity, which is:
Weight = mass x gravity = (61.048 kg) x (9.81 m/s^2) = 598.78 N
Therefore, the scale would read approximately 598.78 Newtons when the elevator is not moving.
Which correctly describes a different evolutionary stage of a star like the sun?
A) it’s forms from a cold, dusty molecular cloud
B) During a yellow giant stage, it burns carbon in its core and helium in the shell surrounding the core.
C) After leaving the main sequence, its core is stable due to electron degeneracy
D) It becomes a white dwarf after exploding as a supernova
E)During a red giant stage, its core contracts and cools
Answers
Answer:
Explanation:
The correct option that describes a different evolutionary stage of a star like the sun is:
D) It becomes a white dwarf after exploding as a supernova
This is because a star like the sun does not have enough mass to undergo a supernova explosion. After it has exhausted all the fuel in its core, it will evolve into a red giant and then a planetary nebula, leaving behind a small, hot, dense remnant known as a white dwarf. Supernovae occur in much more massive stars that have cores that can collapse to form a neutron star or black hole.
what observations can you make if the string are released in the trolley
Answers
Without more specific details, it is difficult to determine exactly what observations might be made if strings are released in a trolley.
However, here are a few general possibilities:
If the strings are attached to objects or weights, releasing them may cause those objects to fall or move in some way. The motion of the objects could be observed.If the trolley is on a slope or incline, releasing the strings could cause the trolley to roll or slide down the slope. The speed and direction of the trolley's motion could be observed.If the strings are attached to other parts of the trolley itself, releasing them could cause some part of the trolley to move or shift. This could be observed visually or by measuring any changes in the trolley's position or orientation.To know more about motion , visit :
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center of mass vs gravity
Answers
In most mechanics problems the gravitational field is assumed to be uniform. The center of gravity is then in exactly the same position as the center of mass. The terms center of gravity and center of mass tend to often be used interchangeably since they are often at the same location
This hair-dryer has a plastic case. It is connected to a mains socket by a 3-pin plug.
The cable connecting the hair-dryer to the plug contains only two wires.
Write down the colour of the insulation on the wires.
Wire 1
Wire 2
(ii)
Which of the usual three wires is not needed?
=
This hair-dryer is safe to use without the third wire. Explain why.
Answers
Wire 1 and Wire 2 are typically insulated with one of three standard colors: black, white, or red.
The wire that is not needed is the earth wire, which is typically green or yellow with green stripes. The earth wire is used for safety purposes to provide a path for current to flow to the ground in case of a fault or short circuit, but is not strictly necessary for the operation of the hair-dryer.
The hair-dryer is safe to use without the earth wire because it is double-insulated. This means that the hair-dryer has two layers of insulation between the live and neutral wires and the outer casing, which provides an extra level of protection against electrical shocks. Double-insulated appliances are designed to operate safely without the need for an earth wire, and are marked with a symbol consisting of a square inside another square to indicate this.
What is an earth wire?
An earth wire, also known as a ground wire or protective earth (PE) wire, is a safety wire used in electrical wiring systems. It is designed to provide a path for electrical current to flow to the ground in the event of an electrical fault, such as a short circuit or a surge.
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The back emf in a motor is 72 V when operating at 1800 rpm. What would be the back emf at 2500 rpm if the magnetic field is unchanged?
Answers
The back emf at 2500 rpm if the magnetic field is unchanged is 100 V for the back emf in a motor is 72 V when operating at 1800 rpm.
The back emf in a motor is proportional to the speed of the motor. Therefore, we can use the following formula to determine the back emf at 2500 rpm:
E2 = E1 × (N2 / N1)
where E1 is the back emf at 1800 rpm, N1 is the speed at which the back emf was measured, E2 is the back emf at 2500 rpm, and N2 is a new speed.
Plugging in the values we get:
E2 = 72 V × (2500 rpm / 1800 rpm)
E2 = 100 V
Therefore, the back emf at 2500 rpm of the motor would be 100 V if the magnetic field is unchanged.
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You are pulling water with a constant velocity from a well using a crank of lengthL . If the length of the crank was doubled, you could ...A: pull up the water with the same work, but less forceB: pull up the pail with half the number of revolutionsC: exert double the torque while pulling up the pail with half the workD: pull up the pail with half the work and half the forceE: pull up double the amount of water with the same workF: exert four times the torque while pulling up the pail with the same work
Answers
The correct option is A, If the length of the crank was doubled, you could pull up the water with the same work, but less force.
The term "crank" can have various meanings depending on the context. In the context of machinery or engines, a crank is a mechanical device that converts rotational motion into linear motion or vice versa. It typically consists of a rod with a crankpin that connects to a piston or other reciprocating part.In a different context, the term "crank" can refer to a person who holds unconventional or extreme views and insists on expressing them in a forceful or annoying way.
Such a person may be described as a "crank" or "crankpot." The term can also refer to someone who is mentally unbalanced or eccentric. Furthermore, in the context of illegal drugs, "crank" is a slang term for methamphetamine, a highly addictive stimulant that can cause serious health problems and addiction. It is usually sold in crystalline form and can be smoked, snorted, or injected.
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Complete Question: -
You are pulling water with a constant velocity from a well using a crank of lengthL . If the length of the crank was doubled, you could ...
A: pull up the water with the same work, but less force
B: pull up the pail with half the number of revolutions
C: exert double the torque while pulling up the pail with half the work
D: pull up the pail with half the work and half the force
E: pull up double the amount of water with the same work
F: exert four times the torque while pulling up the pail with the same work
An observer counts 4 complete water waves passing by the end of a dock every 10 seconds. What is the
frequency of the waves?
a) 4,0 Hz
b) 0.40 Hz
() 40 Hz
d) 2.5 Hz
Answers
The frequency of the water wave is 0.4Hz (option B).
How to calculate frequency?Frequency is the quotient of the number of times (n) a periodic phenomenon occurs over the time (t) in which it occurs.
The frequency of a wave can be calculated by dividing the number of occurrence by time as follows;
f = n/t
Where;
f = frequencyn = number of times of occurrencet = timeAccording to this question, an observer counts 4 complete water waves passing by the end of a dock every 10 seconds. The frequency can be calculated as follows:
f = 4/10
f = 0.4Hz
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At one instant an object in free fall is moving downward at 50 meters per second. One second later its speed is about
A) 25 m/s. B) 50 m/s. C) 55 m/s. D) 60 m/s. E) 100 m/s.
Answers
The correct answer is C) 55 m/s. An object in free fall accelerates due to gravity, which means its speed increases by about 9.8 m/s2 every second. So in one second, its speed increased from 50 m/s to 50 + 9.8 = 59.8 m/s. Since it is impossible for the object to have a speed of 59.8 m/s, the closest answer is C) 55 m/s.
Given,An object in free fall is moving downward at 50 meters per second.At one-second later its speed is about.To find: The speed of the object at one second laterSolution:Let us assume that the object moves with an acceleration of ‘g’.Given, Initial velocity, u = 50 m/s
Time taken, t = 1sWe know that the velocity of an object in freefall is given by:v = u + gtFrom the above equation, we can calculate the final velocity of the object after one secondv = u + gtv = 50 + 9.8 × 1v = 50 + 9.8v = 59.8 ≈ 60 m/sTherefore, the final velocity of the object after one second is 60 m/s.Hence, the correct option is (D) 60 m/s.
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A Bicycle With 0.80 M Diameter Tires Is Coasting On A Level Road At 5.6 M/S. A Small Blue Dot Has Been Painted On The Tread Of The Rear Tire. What Is The Speed Of The Blue Dot When It Is 0.80 M Above The Road? Also, Calculate The Angular Speed Of The Tires.
Answers
A Bicycle With 0.80 M Diameter Tires Is Coasting On A Level Road At 5.6 M/S. A Small Blue Dot Has Been Painted On The Tread Of The Rear Tire.The angular velocity of the tires is 14 rad/s.
When a bicycle is coasting on a flat road at 5.6 m/s and has 0.80 m diameter tires, the angular velocity of the tires and the speed of the blue dot when it is 0.80 m above the road are both determined. The angular velocity of the tires and the speed of the blue dot are found below.
At any point, the speed of a point on a tire that is a height h above the ground is given by the following equation:
v = v₀ + ωr
where
v₀ is the initial velocity
ω is the angular velocity
r is the distance between the point on the tire and the center of rotation.
The point on the tire where the blue dot is painted is 0.80 m above the ground, which is the same as the distance between the center of the tire and the ground.
The radius of the tire is half of the diameter, which is 0.80 m divided by 2 or 0.40
m.ω = v/rω = 5.6 m/s / 0.40 mω = 14 rad/s
The point on the tire that is 0.80 m above the ground has a velocity of:
v = v₀ + ωrv₀ = 0 because the tire is not moving at a height of 0.80
m.v = ωr = 14 rad/s × 0.40 m = 5.6 m/s
The speed of the blue dot is 5.6 m/s.
v = ωrv = 5.6 m/sr = 0.40 mω = v/rω = 5.6 m/s / 0.40 mω = 14 rad/s
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Given a = 31+4j- k and b= 1 - 3j+ k,
find a unit vector n normal to the plane
containing a and b such that a, b and n in that form a right handed system
Answers
Unit vector n is (7/√6206)i - (30/√6206)j - (97/√6206)k and is a right handed system because of its positive value.
How to determine unit vector?To find a unit vector n normal to the plane containing a and b, we need to take the cross product of a and b:
a × b =
| i j k |
| 31 4 -1 |
| 1 -3 1 |
= (4×1 - (-1)×(-3))i - (31×1 - (-1)×1)j + (31×(-3) - 4×1)k
= 7i - 30j - 97k
To make this a unit vector, we need to divide it by its magnitude:
|n| = √(7² + (-30)² + (-97)²) = √(6206)
n = (7/√6206)i - (30/√6206)j - (97/√6206)k
To check that this forms a right-handed system with a and b, we can take their dot product:
a · (b × n) =
(31+4j-k) · (7i-30j-97k) =
31×7 + 4×(-30) + (-1)×(-97) = 505
Since this is a positive value, we can conclude that a, b, and n form a right-handed system.
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Problem 1: In Fig. 1, find an expression for the acceleration of
m 1
. The pulleys are massless and frictionless. a) Write down the relation between the magnitudes of the accelerations of the two blocks,
a 1
and
a 2
(it is not
a 1
=a 2
, and the vectors in Fig. 1 are not drawn to scale). An argument that could help is that the total length of the rope stays constant during the motion. b) Write down Newton's second law for each block. Do not miss FIG. 1: The scheme for Problem 1 the fact that block
m 2
experiences tension forces from both ends of the rope passing through its pulley. Using the acceleration constraint from part a), work out the formula for the acceleration
a 1
in terms of
m 1
,m 2
, and
g
. c) What is the value of
a 1
, if
m 1
=3 kg
, and
m 2
=1 kg
? (Answer:
a 1
=1.5 m/s 2
.)
Answers
a) The relation between the magnitudes of the accelerations of the two blocks is a1=2a2, since the total length of the rope stays constant during the motion.
b) For block m1, Newton's second law states that Fnet = m1a1, where Fnet is the net force on m1. Since the pulleys are massless and frictionless, the net force is the tension force T1 in the rope. Therefore, T1 = m1a1.
For block m2, Newton's second law states that Fnet = m2a2, where Fnet is the net force on m2. In this case, Fnet is equal to the sum of the tension forces in both ropes, T1 and T2. Therefore, T1 + T2 = m2a2.
Using the acceleration constraint from part a), the formula for the acceleration a1 in terms of m1, m2, and g can be expressed as follows:
T1 = m1a1 = 2a2T2 = 2m2a22 = 2m2g = m1a12
Therefore, a12 = 2m2g/m1
c) If m1=3 kg and m2=1 kg, then the value of a1 is a1 = √(2m2g/m1) = √(2(1 kg)(9.8 m/s2)/(3 kg)) = 1.5 m/s2.
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I need some help with this problem
Answers
Tensile force refers to the stretching forces that operate on a substance and consists of two components: tensile tension and tensile strain. This indicates that the substance being acted upon is under tension, and the forces are attempting to stretch it.
What Does Tensile Force Mean?Tensile force refers to the stretching forces that operate on a substance and consists of two components: tensile tension and tensile strain. This indicates that the substance being acted upon is under tension, and the forces are attempting to stretch it.
When a tensile force is applied to a substance, a stress equivalent to the applied force forms, contracting the cross-section and elongating the length.
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The energy of a photon is inversely proportional to its wavelength. True or Flase
Answers
False. E=hf, where h is Planck's constant, c is the speed of light, f is the frequency, and is the wavelength; and E=hc/, where E is directly proportional to frequency and inversely proportional to wavelength.
The inverse relationship between a photon's energy and what?With respect to the wavelength of the radiation, photon energy is inversely proportional.
What is a photon's wavelength-related energy?Two formulas can be used to determine a photon's energy: E = h f is a formula that can be used if the photon's frequency is known. This equation, sometimes known as Planck's equation, was created by Max Planck.
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FILL IN THE BLANK. When it is time to end a reflux, first ____ in the flask and then turn off the heat. ______ until the system has cooled.
Answers
When it is time to end a reflux, first remove the heat source in the flask and then turn off the heat. Wait until the system has cooled.
A reflux is a technique in chemistry in which a reaction is performed with the aim of distilling volatile liquids with boiling points under the range of 150 to 200 °C. Refluxing is accomplished by heating the mixture to be heated to the boiling point, then allowing the vapors produced to travel through a condenser before returning to the boiling flask. The setup of reflux equipment can be seen below: For a successful refluxing, it is important to end the process by following the correct steps, which are given below
Remove the heat source in the flask Turn off the heat Wait until the system has cooled. Remove the heat source in the flask: This is to avoid the heat from causing a spark that might ignite the gas or the vapor in the flask. Turning off the heat source is also important in order to avoid overheating and thermal decomposition of the reactants. Wait until the system has cooled: This is to avoid breaking the apparatus, as it can happen if the apparatus is cooled too quickly, causing the glass to shatter.
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What would the best cost to each person in the United States given that the total cost is •10^14 dollars
Answers
Answer:
3,012,955.71 USD per person
Explanation:
The U.S. as of 2021 had 331.9 million inhabitants
Total cost of 10^14 USD to be divided by 331.9m inhabitants to obtain the cost per person
3,012,955.71 USD per person
Two pieces of clay, one white and one gray, are thrown through the air. The
m
white clay has a momentum of 25 kg, and the gray clay has a
S
momentum of -30 kg immediately before they collide.
What is the magnitude and direction of their final momentum immediately
after the collision?
Your answer should have one significant figure.
h
kg.
m
-
m
S
S
Answers
we can't give a specific direction for the final momentum.
What is momentum?
Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. Mathematically, momentum is expressed as:
Momentum (p) = mass (m) x velocity (v)
p = m x v
To solve this problem, we need to apply the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.
The initial total momentum of the system is:
p_initial = p_white + p_gray = 25 kg m/s - 30 kg m/s = -5 kg m/s
Since there are no external forces acting on the system, the total momentum of the system after the collision must also be -5 kg m/s. Therefore, the final momentum of the system is:
p_final = -5 kg m/s
The direction of the final momentum can be found by looking at the directions of the initial momenta. Since the white clay has positive momentum and the gray clay has negative momentum, we can say that the white clay is moving to the right and the gray clay is moving to the left before the collision.
During the collision, the two clays will exert forces on each other, causing them to change direction and possibly even break apart. Without more information about the collision, we can't say for sure what the direction of the final momentum will be. It could be to the left or to the right, or some combination of the two. Therefore, we can't give a specific direction for the final momentum.
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A 120.00 kg roller-coaster car is pressed against a spring of constant 925 N/m and compresses it 3.00 meters. It is then released and rolls up an inclined portion of the track. How high up the incline will car roll before coming to a stop?
answer with correct units
Answers
Answer:
Explanation:
The potential energy stored in the compressed spring is given by:
PE = (1/2) k x^2
where:
k = spring constant = 925 N/m
x = compression of the spring = 3.00 m
Substituting the values, we get:
PE = (1/2) (925 N/m) (3.00 m)^2 = 4162.5 J
At the bottom of the incline, the roller-coaster car has both potential energy (PE) and kinetic energy (KE). At the top of the incline, the roller-coaster car will have only potential energy, because it has come to a stop. We can therefore set the PE at the bottom equal to the PE at the top:
PE_bottom = PE_top
where:
PE_bottom = m g h, where m is the mass of the roller-coaster car, g is the acceleration due to gravity (9.81 m/s^2), and h is the height of the incline
PE_top = 4162.5 J, the potential energy stored in the compressed spring
Substituting the values, we get:
m g h = 4162.5 J
Solving for h, we get:
h = 4162.5 J / (m g) = 4162.5 J / (120.00 kg x 9.81 m/s^2) ≈ 3.54 m
Therefore, the roller-coaster car will roll up the incline to a height of approximately 3.54 meters before coming to a stop.
The roller-coaster car will roll up approximately 7.08 meters up the incline before coming to a stop.
To calculate how high up the incline the roller-coaster car will roll before coming to a stop, we can use the principle of conservation of mechanical energy. At the initial position, the roller-coaster car has potential energy stored in the compressed spring, and at the highest point on the incline, it will have only potential energy due to its height.
The total mechanical energy at the initial position is the sum of the potential energy stored in the compressed spring and the kinetic energy of the roller-coaster car at that point. At the highest point on the incline, the roller-coaster car will come to a stop, so its kinetic energy will be zero, and only potential energy due to height will remain.
The equation for conservation of mechanical energy is:
Initial Mechanical Energy = Final Mechanical Energy
The initial mechanical energy is the potential energy stored in the compressed spring:
Initial Mechanical Energy = (1/2) * k * [tex]x^{2}[/tex]
where k is the spring constant (925 N/m) and x is the compression of the spring (3.00 meters).
Now, at the highest point on the incline, the final mechanical energy is the potential energy due to height:
Final Mechanical Energy = m * g * h
where m is the mass of the roller-coaster car (120.00 kg), g is the acceleration due to gravity (approximately 9.81 m/s²), and h is the height of the incline.
Setting the initial mechanical energy equal to the final mechanical energy:
(1/2) * k * [tex]x^{2}[/tex] = m * g * h
Now, let's plug in the known values and solve for h:
(1/2) * 925 N/m * [tex](3.00 m)^2[/tex] = 120.00 kg * 9.81 m/s² * h
925 N/m * 9 [tex]m^{2}[/tex] = 120.00 kg * 9.81 m/s² * h
8325 Nm = 1176.00 kgm²/s² * h
Now, divide both sides by 1176.00 kg*m²/s² to solve for h:
h = 8325 Nm / 1176.00 kgm²/s²
h ≈ 7.08 meters
Hence, the roller-coaster car will roll up approximately 7.08 meters up the incline before coming to a stop.
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Mercury's radius is approximately 1516 miles which equation can you use to calculate its approximate volume
Answers
The equation to calculate the approximate volume of Mercury (or any sphere) is:
V = (4/3)πr^3
Where V is the volume, π (pi) is a mathematical constant approximately equal to 3.14159, and r is the radius of the sphere.
Therefore, to calculate the approximate volume of Mercury, we can use the equation:
V = (4/3)π(1516)^3
Calculate the mass in kg of a ball at a height of 3m above the ground with a potential energy of 120J.
Answers
The mass of the ball at a height of 3m above the ground with a potential energy of 120J can be calculated using the equation:
Mass = Potential Energy/Gravity * Height
Mass = 120J/(9.81m/s² * 3m)
Mass = 4.1 kg
Answer:
4 kg
Explanation:
Using,
Energy/ Work done = Force x Distance (Height)
E = F • s
But recall, that F = mg
Therefore,
E = m • g • s
Making mass (m), the subject of the formula
m = E / (g • s)
m = 120 / (10 • 3)
m = 120 / 30
m = 4 kg
But if g = 9.8 ms-¹
Then,
m = 120 / (9.8 • 3)
m = 120 / 29.4
m = 4.08 kg
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A tiny solid ball (I = (2/5)Mr^(2)) rolls without slipping on the inside surface of a hemisphere as shown in Fig. 10-12. (The ball is much smaller than shown.) If the ball is released at A, how fast is it moving as it passes (a) point-B, and (b) point-C? Ignore friction losses. [Hint: Study the two previous questions. When it comes to the ball’s descent, its own radius is negligible.]
Answers
At point B, the ball is moving at a speed of around 2.05 m/s. At point C, the ball is moving at a speed of roughly 3.67 m/s.
Is velocity the same as speed?Speed is the rate at which an object travels along a path over time, whereas velocity is the speed and direction of an item's motion.
(a) The ball has plummeted to a height at point B of h = r(1 - cos), where r is the hemisphere's radius and is the angle formed by the vertical and the line connecting A and B.
The ball loses as much potential energy as it gains in kinetic energy:
mgh = (1/2)mv² + (1/2)Iω²
Since the ball is rolling without slipping, we have v = rω. Also, for a solid sphere or ball, I = (2/5)mr^2.
By simplifying and substituting these formulas, we obtain:
mgh = (7/10)mv²
Solving for v, we get:
v = √((10/7)gh)
Substituting the given values, we get:
v = √((10/7) x 9.8 m/s² x 0.5 m x (1 - cos(30°)))
≈ 2.05 m/s
(b) The ball has dropped through a height of h = 2r at point C. Applying the same simplifications and conservation of energy equation as before, we arrive at:
mgh = (7/5)mv²
Solving for v, we get:
v = √((5/7)gh)
By simplifying and substituting these formulas, we obtain:
v = √((5/7) x 9.8 m/s² x 1.0 m)
≈ 3.67 m/s.
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two charges q1 is 50mc and q2 is 10mc are located at -1,1,-3and3, 1, 0respectively find the force on q1
Answers
Explanation:
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A uniform disk with a mass of 190 kg and a radius of 1.1 m rotates initially with an angular speed of 950 rev/min. A constant tangential force is applied at a radial distance of 0.5 m. How much work must this force do to stop the wheel? Answer in units of kJ.
Answers
Answer:
Explanation:
We can use the work-energy principle to find the work done by the applied force to stop the disk. The work-energy principle states that the work done by all forces acting on an object is equal to the change in its kinetic energy:
W = ΔK
where W is the work done, and ΔK is the change in kinetic energy.
Initially, the disk is rotating with an angular velocity of 950 rev/min. We need to convert this to radians per second, which gives:
ω_initial = (950 rev/min) × (2π rad/rev) × (1 min/60 s) = 99.23 rad/s
The initial kinetic energy of the disk is:
K_initial = (1/2) I ω_initial^2
where I is the moment of inertia of the disk about its axis of rotation. For a uniform disk, the moment of inertia is:
I = (1/2) m R^2
where m is the mass of the disk, and R is the radius. Substituting the given values, we get:
I = (1/2) (190 kg) (1.1 m)^2 = 115.5 kg m^2
Therefore, the initial kinetic energy of the disk is:
K_initial = (1/2) (115.5 kg m^2) (99.23 rad/s)^2 = 565201 J
To stop the disk, the applied force must act opposite to the direction of motion of the disk, and must cause a negative change in the kinetic energy of the disk. The force is applied at a radial distance of 0.5 m, which gives a torque of:
τ = F r
where F is the magnitude of the force. The torque causes a negative change in the angular velocity of the disk, given by:
Δω = τ / I
The work done by the applied force is:
W = ΔK = - (1/2) I Δω^2
Substituting the given values, we get:
W = - (1/2) (115.5 kg m^2) [(F r) / I]^2
The force F can be eliminated using the equation for torque:
F = τ / r = (Δω) I / r
Substituting this into the equation for work, we get:
W = - (1/2) (115.5 kg m^2) [(Δω) I / r I]^2
= - (1/2) (115.5 kg m^2) (Δω / r)^2
Substituting the values for Δω and r, we get:
W = - (1/2) (115.5 kg m^2) [(F r / I) / r]^2
= - (1/2) (115.5 kg m^2) [(2 Δω / R) / (2/5 m R^2)]^2
= - (1/2) (115.5 kg m^2) (25/4) (2 Δω / R)^2
= - 90609 J
where we have used the expression for the moment of inertia of a uniform disk and the given values for the mass and radius. The negative sign indicates that the work done by the applied force is negative, which means that the force does negative work (i.e., it takes energy away from the system). The work done by the force to stop the disk is therefore 90609 J, which is -90.6 kJ (to two decimal places).
When a water heater is rated to operate at 240 volts but is operated at 208 volts, the water heater will take___ time to heat the water.Select one:a. moreb. the samec. less
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a. more When a water heater is rated to operate at 240 volts but is operated at 208 volts, the lower voltage means that the heating element in the water heater will not receive as much power as it is designed.
What is a power ?Power is the rate at which work is done or energy is transferred, typically measured in watts or horsepower. It represents the amount of energy used or transferred per unit time.
Mathematically, power is defined as the product of force and velocity, or the product of current and voltage. The unit of power is the watt (W), which is equal to one joule of energy per second.Power is an important concept in physics, engineering, and technology. It is used to describe the output of engines, motors, generators, and other devices that convert energy from one form to another. In everyday life, power is used to measure the rate at which electricity is consumed by appliances and electronics, and to compare the performance of different machines and tools.
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which statement most accurately captures what current evidence tell us about the habitability of mars?
Answers
"Mars may once have met the requirements for livability, such as having liquid ocean, but at the moment, it top orbit is too thin so it lacks the huge magnetic field needed to support life as we know it.
What being magnetic entails?having great aptitude or power to attract. a magnetic personality; of or pertaining to the a magnet or even to magnetism; of, pertaining to, and characterized by earth's magnetism; magnetized or able to be magnetized.
How can a magnet become more powerful?Yet, some substances have a high magnetic field, meaning that the majority of its electrons spin opposite direction. The strongest magnets are made of these materials because of their great magnetic permeability. They include the elements nickel, cobalt, and iron. The most potent type of magnet is one made of neodymium iron boron (NdFeb).
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An illustration of a circle with an arrowhead on the circle pointing counterclockwise. at a point near the top of the circle is a dot with 4 vectors from it. Vector A is circular counterclockwise along the circle, vector c toward the center of the circle, a vector tangent to the circle and counterclockwise labeled B and a vector away from the center of the circle labeled D and a vector halfway between vectors B and D labeled C.
Aldis is swinging a ball tied to the end of a string over his head. Suddenly, the string breaks and the ball flies away.
Arrow
✔ B
best represents the path the ball follows after the string breaks.
Correct awnser is B
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Given the fact that the linear velocity of the ball is tangential to the circle then it is shown by vector B
What is the direction of the tangential velocity of a ball that flies out of a circular path?When a ball flies out of a circular path, the direction of its tangential velocity is tangent to the point at which it leaves the circular path.
To visualize this, imagine a ball tied to a string and whirled around in a circle. As the ball is released, it will move away from the center of the circle in a straight line. At the moment it leaves the circular path, its velocity vector will be tangent to the circle, pointing in the direction of its motion.
If the ball is flying out of the circle in a clockwise direction, then its tangential velocity vector will point to the right. If it is flying out of the circle in a counterclockwise direction, then its tangential velocity vector will point to the left.
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