Help anyone can help me do the question,I will mark brainlest.​

Answer: 23, 27,29

Those im absolutely positive about.

Im not sure abt the rest

Step-by-step explanation:

Presumably, ln⁵(x) is the same as (ln(x))⁵ (as opposed to a quintuply-nested logarithm, log(log(log(log(log(x)))))).

Then substituting u = ln(x) and du = dx/x gives

[tex]\displaystyle\int\frac{\mathrm dx}{x\ln^5(x)} = \int\frac{\mathrm du}{u^5} = -\frac1{4u^4}+C = \boxed{-\frac1{4\ln^4(x)}+C}[/tex]

Answer:

6=n

Step-by-step explanation:

Hi there!

We are given this equation:

3(n+4)=5n

And we need to solve it for n

To do that, we need to isolate n on one side

But we need to open up the parentheses on the left side by doing the distributive property

Multiply both n and 4 by 3

3n+12=5n

Now subtract 3n from both sides to remove it from the left side

12=2n

Divide both sides by 2 to change the coefficient on n from 2 to 1

6=n

n is now isolated on one side

Hope this helps!

Answer:

n=6

Step-by-step explanation:

Using the distributive property, we distribute 3 to n and 4. In case if you don't know what that means, it means we multiply 3 to the variables inside the parentheses. So we get (3×n)+(3×4)=5n, and we simplify it so we get 3n+12=5n. Now, we can subtract 3n from both sides and get 12=2n, and divide 2 from both sides and get n=6.

Answer:

Step-by-step explanation:

If Quan had 15 and Kaden had 3 times as much, then Kaden had 15(3) = 45. If he spent 10 then he had 35 left. The amount of money Quan had after his mom gave him some was 4/5 the amount of Kaden's 35 (let x = the amount of money Quan has after his mom gives him some):

[tex]x=\frac{4}{5}(35)[/tex]  35 divides by the 5 in the denominator 7 times, and 7 times 4 is 28. That's how you get your 28 in part a.

For part b., he started with 15 and ended with 28, so his mom gave him 28-15=13. That's how you get the 13.

Answer:

A&D

Step-by-step explanation:

we want to solve the following equation for x:

[tex] \displaystyle ( {2}^{x} - 3) ({2}^{x} - 4) = 0[/tex]

to do so let [tex]2^x[/tex] be u and transform the equation:

[tex] \displaystyle (u - 3) (u - 4) = 0[/tex]

By Zero product property we obtain:

[tex] \displaystyle \begin{cases}u - 3 = 0\\ u - 4= 0 \end{cases}[/tex]

Solve the equation for u which yields:

[tex] \displaystyle \begin{cases}u = 3\\ u = 4 \end{cases}[/tex]

substitute back:

[tex] \displaystyle \begin{cases} {2}^{x} = 3\\ {2}^{x} = 4 \end{cases}[/tex]

take logarithm of Base 2 in both sides of the both equations:

[tex] \displaystyle \begin{cases} \log_{2} {2}^{x} = \log_{2} 3\\ \log_{2} {2}^{x} = \log_{2} 4 \end{cases}[/tex]

hence,

[tex] \displaystyle \begin{cases} x_{1} = \log_{2} 3\\ x_{2} = 2 \end{cases}[/tex]

Answer:

( A ) and ( D )

Step-by-step explanation:

( 2^x -3 ) ( [tex]2^x -4[/tex] ) = 0

[tex]2^x [/tex]- 3 = 0

2^x - 4 = 0

[tex]2^x [/tex]- 3 = 0 , [tex]2^x -4[/tex]

x = [tex]log_2[/tex] (3) , x = 2

The equation has two solutions;

[tex]x_1[/tex] = [tex]log_2[/tex] (3) , [tex]x_2[/tex] = 2.

Answer:

A

Step-by-step explanation:

As two angles are same which means 3rd also is equal which means aaa axiom

Answer:

The formula to determine the area of the circle.

Step-by-step explanation:

↔

Answer: C

Step-by-step explanation:

To find the surface area of a cone, you use the formula [tex]A=\pi r(r+\sqrt{h^2+r^2} )[/tex]. Since we are already given the height and radius, all we have to do is plug in the values and solve.

[tex]A=9\pi (9+\sqrt{41^2+9^2} )[/tex]       [solve inside of square root]

[tex]A=9\pi (9+\sqrt{1762} )[/tex]             [parenthesis]

[tex]A=9\pi (50.976 )[/tex]                   [multiply]

[tex]A=458[/tex]

Therefore, the closest answer is C.

Answer:

ewfwefwfewfwfwe

Step-by-step explanation:

Answer: The correct answer is in the first option.

Step-by-step explanation:

Equation of an Ellipse

[tex]\dfrac{x^{2} }{a^{2} } +\dfrac{y^{2} }{b^{2} } =1\\\\25x^{2} - 150x + 9y^{2} = 0\\\\\text {Let's \: perform \: the \: transformations:}\\\\\dfrac{25x^{2} }{25 \cdot 9} -\dfrac{150x}{25 \cdot 9} +\dfrac{9y^{2} }{25 \cdot 9} =0\\\\\dfrac{x^{2} }{3^{2} } -\dfrac{6x}{3^{2} } +\dfrac{y^{2} }{5^{2} } =0\\\\\dfrac{x^{2} -6x}{3^{2} } +\dfrac{y^{2} }{5^{2} } +\dfrac{3^{2} }{3^{2} } -\dfrac{3^{2} }{3^{2} } =0\\\\\dfrac{x^{2} -6x+3^{2} }{3^{2} } +\dfrac{y^{2} }{5^{2} } =\dfrac{3^{2} }{3^{2} }[/tex]

[tex]\dfrac{(x-3)^{2} }{3^{2} } +\dfrac{y^{2} }{5^{2} } =1[/tex]

Answer:

54piecm^3

Step-by-step explanation:

pie x radius ^2 x h

= v

pie x 9

= 9pie x 6

= 54pie

Given:- 7x + 1 < 4(x - 2)

7x + 1 < 4(x - 2)

7x + 1 < 4x - 8

7x - 4x < -8 -1

3x < -9

x < -9/3

x < -3

Answer:

c

Step-by-step explanation:

Answer:

C. 37 degrees

Step-by-step explanation:

27, 36, 45 is just a larger 3, 4, 5 triangle. The smallest angle is across from the smallest side. With those in mind, we have 37, 53, and 90 degrees as the angles for a 3, 4, 5 triangle. We pair the 27, (the three when we reduce) with the smallest angle, the 37.

I'm sure you can do it with an actual formula, but i can't recall. Cheers

Answer:

32:3/4

33:4/3

34:40

35:48

Step-by-step explanation:

1 . when we collect like terms we only focus on the variables and the power of the variable I f exist so in this question the answer is 8x^2 because both have the same variable and same power or exponent.

2. one term is monomial

two terms is binomial

3. b

4. -9

5. c

Step-by-step explanation:

c. 2x-11 this is the answer

hope this helps you

have a nice day:)

Answer:

5.1 cm

Step-by-step explanation:

(Probable) Question;

Given a circle with center O and radius 2.4 cm. P is a point on the tangent that touches the circle at point Q, such that the length of the tangent from P to Q is 4.5 cm. Find the length of OP

The given parameters are;

The radius of the circle with enter at O, [tex]\overline{OQ}[/tex] = 2.4 cm

The length of the tangent from P to the circle at point Q, [tex]\overline{PQ}[/tex] = 4.5 cm

The length of OP = Required

By Pythagoras's theorem, we have;

[tex]\overline{OP}[/tex]² = [tex]\overline{OQ}[/tex]² + [tex]\overline{PQ}[/tex]²

∴ [tex]\overline{OP}[/tex]² = 2.4² + 4.5² = 26.01

[tex]\overline{OP}[/tex] = √26.01 = 5.1

The length of OP = 5.1 cm

Answer:

4 days

Step-by-step explanation:

The time it would take the group of 40 workers to deliver the work, [tex]t_{estimated}[/tex] = 16 days

The number of workers that retired after 4 days = 10 workers

Therefore, the number of workers remaining = 40 - 10 = 30 workers

The time it would take 1 worker to do the work = The number of work days in the construction = 40 × 16 = 640 work days

The amount of work done in 4 days = 40 × 4 = 160 work days

The amount of work remaining after the elapsed 4 days = (640 - 160) work days = 480 work days

The number of days, n, it would take the remaining 30 workers to do the remaining work, is given as follows;

n = 480 work days/(30 workers) = 16 days

The actual total number of work days it took for the work to be delivered, [tex]t_{actual}[/tex] = 4 days + 16 days = 20 days

The number of days delay the construction will be delivered, [tex]t_{delay}[/tex], is given as follows = [tex]t_{actual}[/tex]

[tex]t_{delay}[/tex] = [tex]t_{actual}[/tex] - [tex]t_{estimated}[/tex]

∴ [tex]t_{delay}[/tex] = 20 days - 16 days = 4 days

The number of days delay the construction will be delivered,  [tex]t_{delay}[/tex] = 4 days

Answer:

1. a) x1 = -8 y x2 = -4

b) x1 = -1/3

2. a) x1 = 0 y x2 = -5

b) x1 = 4 y x2 = -4

3. m debe ser 6. Asi tendriamos (x+3)²=0

4. a) x1 = 4, x2 = -4, x3 = 3 y x3 = -3

b) x1 = 3, x2 = -3 las otras dos raices son complejas.  

Step-by-step explanation:

1. a) [tex]x^{2}+12x+32=0[/tex]

Factorizando:

[tex](x+8)(x+4)=0[/tex]

Entonces: x1 = -8 y x2 = -4

4. a) x1 = 4, x2 = -4, x3 = 3 y x3 = -3

b) [tex]9x^{2}+6x+1=0[/tex]

Factorizando:

[tex](3x+1)(3x+1)=0[/tex]

[tex](3x+1)^{2}=0[/tex]

Entonces: x1 = -1/3

2. a) [tex]2x^{2}+5x=0[/tex]

Aplicando factor comun:

[tex]x(x+5)=0[/tex]

Entonces: x1 = 0 y x2 = -5

b)  [tex]2x^{2}-32=0[/tex]

Despejamos x.

[tex]2x^{2}=32[/tex]

[tex]x^{2}=16[/tex]

Entonces: x1 = 4 y x2 = -4

3. m debe ser 6. Asi tendriamos (x+3)²=0

4. a)  [tex]x^{4}-25x^{2}+144=0[/tex]

Hacemos cambio de variable: [tex]w=x^{2}[/tex]

[tex]w^{2}-25w+144=0[/tex]

Ahara podemos factorizar:

[tex](w-16)(w-9)=0[/tex]  

Usando el cambio de variable nuevamente.

[tex](x^{2}-16)(x^{2}-9)=0[/tex]    

Entonces los valores de x son: x1 = 4, x2 = -4, x3 = 3 y x3 = -3

b)  [tex]x^{4}+9x^{2}-162=0[/tex]

Hacemos cambio de variable: [tex]z=x^{2}[/tex]

[tex]z^{2}+9z-162=0[/tex]

Ahara podemos factorizar:

[tex](z-9)(z+18)=0[/tex]    

Usando el cambio de variable nuevamente.

[tex](x^{2}-9)(x^{2}+18)=0[/tex]            

Entonces los valores de x son: x1 = 3, x2 = -3 las otras dos raices son complejas.  

Espero ye haya servido!

Answer:

-2.50

Step-by-step explanation:

3 is closer to 0then 10

Answer:

-2.53

Step-by-step explanation:

Already rounded to the nearest Hundredth

Answer:

5

Step-by-step explanation:

We cannot repeat an x value for the relation to be a function

Since x=3 ,4, 7 are already used

We must let x=5

Answer:

w ≈ 33.9 in

Step-by-step explanation:

Using Pythagoras' identity in the right triangle

w² + w² = 48²

2w² = 2304 ( divide both sides by 2 )

w² = 1152 ( take the square root of both sides )

w = [tex]\sqrt{1152}[/tex] ≈ 33.9 in ( to the nearest tenth )

Answer:

$6778.36

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Compounded Interest Rate Formula: [tex]\displaystyle A = P(1 + \frac{r}{n})^{nt}[/tex]

Step-by-step explanation:

Step 1: Define

Identify variables

P = 6000

r = 5% = 0.05

n = 1

t = 2.5

Step 2: Find Interest

Answer:

-4

Step-by-step explanation:

2x + 3y = -14

x - y = 3

Multiply the second equation by -2 to eliminate x

2x + 3y = -14

-2x +2 y = -6

-----------------------

    5y = -20

Divide by 5

5y/5 = -20/5

y = -4

Answer:

Step-by-step explanation:

If x = 0.888…, then 10x = 8.888… and

10x - x = 9x = 8   ==>   x = 8/9

Answer:

c. f(-2)= -21

b. g(x)=8

c. h(3)= -19

h(4)= -5

Step-by-step explanation:

Answer:

a = - 6

Step-by-step explanation:

Given

f(x) = 3x + 5 , then

f(a) = 3a + 5 and f(a) = - 13 , then equating the right sides

3a + 5 = - 13 ( subtract 5 from both sides )

3a = - 18 ( divide both sides by 3 )

a = - 6

Answer:

a = -6

Step-by-step explanation:

see, x has been replaced by a.

so f(a) = 3a + 5 . . . . . . . (i)

a displaces x from it's every position in the equation.

and it's given that f(a) = -13

putting f(a) = -13 in equation (i) :-

3a + 5 = -13

3a = -18

[tex] \blue{ \implies}\mathfrak { \red { \underline{ \: a = - 6 } } } [/tex]