The given augmented matrix is equivalent to a system of linear equations with 1 equation and 3 variables. The system is underdetermined and the solution to the system is [tex](x, y, z)[/tex]= (0, 0, 0).
The given augmented matrix is in row-reduced form and is equivalent to a system of linear equations. The matrix has 3 columns and 1 row, so there is 1 equation and 3 variables in the corresponding system of linear equations. Since there is only one equation, the system is underdetermined and has infinitely many solutions.
The solution to the system can be stated as: (x, y, z) = (0, 0, 0). The solution is a point where all the variables are equal to zero. Since the matrix is in row-reduced form, this is the only solution to the system. If the augmented matrix was not in row-reduced form, then the solution would be stated as a parameter, such as (x, y, z) = (0, 0, t), where t is a parameter.
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Answer:
1 equation, 3 variablesunderdetermined(x, y, z) = (1 -s +t, 4s, 4t)Step-by-step explanation:
For the given augmented matrix, you want to know the number of equations and variables it represents, whether the system is under- or over-determined, and the solution, using parameters as required.
[tex]\left[\begin{array}{ccc|c}1&\dfrac{1}{4}&-\dfrac{1}{4}&1\\\vphantom{\dfrac{T}{q}}0&0&0&0\end{array}\right][/tex]
Augmented matrixEach column of the augmented matrix is the coefficient of the variable in a linear equation represented by the row. The first row of the matrix represents the equation ...
[tex]1x +\dfrac{1}{4}y-\dfrac{1}{4}z=1[/tex]
The second row of the matrix represents the tautology ...
0x +0y +0z = 0
It contributes no information about the relationships between the variables.
The matrix represents 1 equation in 3 variables.
SolutionFor there to be a unique solution to a linear system, there must be as many consistent and independent equations as there are variables. Here, there are fewer equations than variables. This system is underdetermined.
The solution to an underdetermined system can be written in terms of parameters of free choice. We will need as many parameters as there are missing equations: 2.
Here, the coefficients of y and z suggest we choose parameters that let us represent those values as multiples of 4.
Parameters: s, t
Let y = 4s, z = 4t. Then the equation becomes ...
x +1/4(4s) -1/4(4t) = 1
x +s -t = 1
x = 1 +t -s
Now, the solution can be written as ...
(x, y, z) = (1 +t -s, 4s, 4t)
What is the y-intercept of y = 2/3 x + 2? Responses A (3, 2)(3, 2) B (2, 3)(2, 3) C (-3, 0)(-3, 0) D (0, 2)
Answer:
Y intercept is (0,2) Answer D.
Step-by-step explanation:
I included a graph for equation y=2/3 x + 2.
compute the determinants in exercises 9-14 by cofactor expansions. at each step, choose a row or column that involves the least amount of computation. [\begin{array}{ccc}6&3&2&4&0\\9&0&-4&1&0\\8&-5&6&7&1\\3&0&0&0&0\\4&2&3&2&0\end{array}\right]
Answer:
Step-by-step explanation:
Marisa bought a car for $9,632. She paid $2,000 down. She will pay the remainder
in 24 monthly payments. How much will she pay each month?
Explain your answer.
Answer: $318/mo
Step-by-step explanation:
First, we get the remainder, which is the difference between $9, 632 and $2,000. That gives us $7, 632.
Then, since we know she will pay in 24 months, we assume she pays the same amount each month and divide $7, 632 by 24 = $318/mo
Given the function y = 4x + 3 do the following. Find its average rate of change: from x = 2 to x = 5
Answer: 4 is the average rate of change
Step-by-step explanation:
The equation to find the average rate of change is:
[tex]\frac{f(x_{2})-f(x_{1} ) }{x_{2}-x_{1} }[/tex]So f(2)= 11 and f(5)=23 then you plug these numbers in:
[tex]\frac{23-11}{5-2}[/tex] = [tex]\frac{12}{3}[/tex] = 4
Question 8 (4 points)
For a meat raffle, 100 tickets were sold.
The following were prizes:
number of winners
1
4
15
prize
grand prize - $1000 cash
$250 meat package
$50 meat package
What is the probability of winning the grand prize? 1/20
What is the expected value for someone buying a single ticket for $10.00 ? $
Hi pls help me! Correct my answers if they’re wrong and I need help with 5-9! Thank you :D
Answer:
Proofs attached to answer
Step-by-step explanation:
Proofs attached to answer
the heights of adult men can be approximated as normal with a mean of 70 and standard eviation of 3 what is the probality man is shorter than
Question: The heights of adult men can be approximated as normal, with a mean of 70 and a standard deviation of 3, the probability that a man is shorter than 65 inches is approximately 0.0475 or 4.75%.
Let X be the height of an adult man, which follows a normal distribution with mean μ = 70 and standard deviation σ = 3. Then, we need to find the probability that a man is shorter than some height, say x₀. We can write this probability as P(X < x₀).To find P(X < x₀), we need to standardize the random variable X by subtracting the mean and dividing by the standard deviation. This yields a new random variable Z with a standard normal distribution. Mathematically, we can write this transformation as:Z = (X - μ) / σwhere Z is the standard normal variable.
Now, we can find P(X < x₀) as:P(X < x₀) = P((X - μ) / σ < (x₀ - μ) / σ) = P(Z < (x₀ - μ) / σ)Here, we use the fact that the probability of a standard normal variable being less than some value z is denoted as P(Z < z), which is available in standard normal tables.
Therefore, to find the probability that a man is shorter than some height x₀, we need to standardize the height x₀ using the mean μ = 70 and the standard deviation σ = 3, and then look up the corresponding probability from the standard normal table.In other words, the probability that a man is shorter than x₀ can be expressed as:P(X < x₀) = P(Z < (x₀ - 70) / 3)We can now use standard normal tables or software to find the probability P(Z < z) for any value z.
For example, if x₀ = 65 (i.e., we want to find the probability that a man is shorter than 65 inches), then we have:z = (65 - 70) / 3 = -1.67Using a standard normal table, we can find that P(Z < -1.67) = 0.0475. Therefore, the probability that a man is shorter than 65 inches is approximately 0.0475 or 4.75%. Thus, P(X < 65) = 0.0475 or 4.75%. Therefore, the probability that a man is shorter than 65 inches is approximately 0.0475 or 4.75%.
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Fractions MUST SHOW WORKING!!
Total seats in plane: 186
108+64+14
5/7 of 14 is: 10
14÷7= 2
2x5= 10
5/16 of 64 is: 20
64÷16=4
5×4= 20
5/9 of 108 is: 60
108÷9= 12
12x5= 60
60+20+10=90
90/186 of seats are being used
simplified: 15/31
No
A number exceeds 20% of itself by 40. find the number.
WITH STEPS
Answer:
50
Step-by-step explanation:
Let the number = x.
20% of the number is 20% of x = 0.2x.
Since the number exceeds 20% of itself by 40, then teh number minus 20% of itself is 40.
x - 0.2x = 40
0.8x = 40
x = 40/0.8
x = 50
an amusement park charges a $ entrance fee. it then charges an additional $ per ride. which of the following equations could bum so use to properly calculate the dollar cost, , of entering the park and enjoying rides?
The equation you would use to properly calculate the dollar cost of entering the park and enjoying rides is Total Cost = Entrance Fee + (Number of Rides x Ride Fee).
In this case, Total Cost is the cost of entering the park and enjoying rides, Entrance Fee is the fee for entering the park, Number of Rides is the number of rides you will be taking, and Ride Fee is the fee charged for each ride.
Thus, plugging in the given values, the equation becomes Total Cost = Entrance Fee + (Number of Rides x Ride Fee).
Therefore, if the Entrance Fee is $ and each ride costs an additional $ , the Total Cost of entering the park and enjoying rides is $ .
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solve( 3x^ 2)+2y +4=0
Answer:
Step-by-step explanation:
You can’t solve this equation as none of the numbers have the same coefficient to solve. If you wanted to solve for x and y, you will need two equations as there are two unknown variables in the equation and the only way to solve for x and y is to use simultaneous method which includes two equations.
There are 170 deer on a reservation. The deer population is increasing at a rate of 30% per year
A function [tex]P(t) = 170.(1.30)^t[/tex] that gives the deer population P(t) on the reservation t years from now
We were told there were 170 stags on reservation. The number of deer is increasing at a rate of 30% per year.
We could see the deer population grow exponentially since each year there will be 30% more than last year.
Since we know that an exponential growth function is in form:
[tex]f(x) = a*(1+r)^x[/tex]
where a= initial value, r= growth rate in decimal form.
It is given that a= 170 and r= 30%.
Let us convert our given growth rate in decimal form.
[tex]30 percent = \frac{30}{100} = 0.30[/tex]
Upon substituting our given values in exponential function form we will get,
[tex]P(t) = 170.(1+0.30)^t[/tex]
⇒ [tex]P(t)= 170.(1.30)^t[/tex]
Therefore, the function [tex]P(t) = 170.(1.30)^t[/tex] will give the deer population P(t) on the reservation t years from now.
Complete Question:
There are 170 deer on a reservation. The deer population is increasing at a rate of 30% per year. Write a function that gives the deer population P(t) on the reservation t years from now.
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A sample of automobiles traversing a certain stretch of highway is selected. Each automobile travels at a roughly constant rate of speed, though speed does vary from auto to auto. Let x = speed and y = time needed to traverse this segment of highway. Would the sample correlation coefficient be closest to 0.9,0.3,-3,or -0.9? Explain.
The right answer is -0.9, but I do not know the reason.
The sample correlation coefficient would be closest to -0.9.
Here's why:
Correlation Coefficient: The correlation coefficient is a statistical measure of the degree of correlation (linear relationship) between two variables. Pearson’s correlation coefficient is the most widely used correlation coefficient to assess the correlation between variables.
Pearson’s correlation coefficient (r) ranges from -1 to 1. A value of -1 denotes a perfect negative correlation, 1 denotes a perfect positive correlation, and 0 denotes no correlation. There is a negative correlation between speed and time. As the speed of the car increases, the time needed to traverse the segment decreases. So, the sample correlation coefficient would be negative.
Since the sample size is large enough, the sample correlation coefficient should be close to the population correlation coefficient. The population correlation coefficient between speed and time should be close to -1, which implies that the sample correlation coefficient should be close to -1.
Therefore, the sample correlation coefficient would be closest to -0.9.
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in a school of hundred students, 40 are in the hockey team and 70 are in the football team.
Each student is in at least one team. Find the number of students who are in both teams.
Answer: There are 10 students who are in both the hockey and football teams.
Step-by-step explanation: We can use the principle of inclusion-exclusion to find the number of students who are in both the hockey and football teams.
The total number of students in both teams is the sum of the number of students in the hockey team and the number of students in the football team, minus the number of students who are in both teams (to avoid double-counting):
Total = Hockey + Football - Both
Substituting the given values, we get:
100 = 40 + 70 - Both
Simplifying, we get:
Both = 40 + 70 - 100
Both = 10
Therefore, there are 10 students who are in both the hockey and football teams.
Tiago sells sunflower oil in large tins and extra-large tins.
The large tin and the extra-large tin are mathematically similar.
The volume of the extra-large tin is 75% more than the volume of the large tin. Both tins are cylinders.
The radius of the large tin is 20 cm.
Calculate the radius of the extra-large tin.
Answer:
24 cm (to nearest cm)
Step-by-step explanation:
XLV = extra large tin volume (cm³)
LV = large tin volume (cm³)
XLR = extre large tin radius (cm)
LR = large tin radius (cm) = 20
XLV = 1.75 × LV
Since the tins are geometrically similar cylinders, we can infer that the volumes and radii of the 2 tins are related;
We know the relationship between the volume of the two tins, i.e. the XL tin is 75% greater in volume than the L tin;
This means the volumetric scale factor or multiplier is ×1.75;
Subsequently, we know:
XLV = 1.75 × LV
Similarly, there is a relationship between the radii of the tins;
The relationship is, however, slightly different;
[tex]XLR = (\sqrt[3]{1.75}) \times LR[/tex]
We need to take the cube root of the volumetric scale factor, reason being, the radius is a linear dimension unlike volume;
Easy way to figure this is radius is in cm, volume is in cm³;
So:
XLR = 1.205... × LR
XLR = 1.205... × 20
XLR = 24.101... --> 24 cm (to nearest cm)
● Thornton
1 centimeter =
50 kilometers
Peter's mother is a pilot. She often makes deliveries
near their community. Peter and his mother flew from
Charlton to Thornton to make a mail delivery. Then they
continued on to Avon and Ashton and returned to Charltc
How many kilometers did Peter and his mother
travel in all?
The answer is 250 kilometers. Peter and his mother traveled a total distance of 250 kilometers on their mail delivery.
What is distance?Distance is a numerical measurement of how far apart two objects or points are. It is a scalar quantity, meaning that it is only expressed as a magnitude, or numerical value, without any direction.
1 centimeter is equal to 0.01 kilometers, so 50 kilometers would be equal to 5,000 centimeters. The total distance between the four cities is 5,000 centimeters, which is equal to 50 kilometers.
Charltc to Thornton is 1,000 centimeters, Thornton to Avon is 1,500 centimeters, Avon to Ashton is 1,000 centimeters, and Ashton to Charltc is 1,500 centimeters. This gives us a total of 5,000 centimeters, or 50 kilometers.
This can be calculated by multiplying the total distance between the four cities (50 kilometers) by the number of times they traveled the route (5 times, since they flew from Charltc to Thornton, then to Avon, then to Ashton, and then back to Charltc). This gives us 250 kilometers, which is the answer to the question.
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Peter and his mother traveled a total distance of 250 kilometers on their mail delivery. The answer is 250 kilometers.
What is distance?Distance is a numerical measurement of how far apart two objects or points are. It is a scalar quantity, meaning that it is only expressed as a magnitude, or numerical value, without any direction.
1 centimeter = 0.01 kilometers,
so 50 kilometers = 5,000 centimeters.
Charlton to Thornton= 1,000 centimeters,
Thornton to Avon= 1,500 centimeters,
Avon to Ashton= 1,000 centimeters,
and Ashton to Charlton= 1,500 centimeters.
Total distance= 1,000+1,500+1,000+1,500
= 5,000 centimeters, or 50 kilometers.
The total distance between the four cities is 5,000 centimeters, which is equal to 50 kilometers.
This can be calculated by multiplying the total distance between the four cities (50 kilometers) by the number of times they traveled the route (5 times.
=50*5
=250
Since they flew from Charlton to Thornton, then to Avon, then to Ashton, and then back to Charlton.
250 kilometers is the answer to the question.
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Question:
Peter's mother is a pilot. She often makes deliveries near their community. Peter and his mother flew from Charlton to Thornton to make a mail delivery. Then they continued on to Avon and Ashton and returned to Charlton. How many kilometers did Peter and his mother travel in all?
I need help pls help me find the area:
Answer:
Step-by-step explanation:
348.55
Anita borrowed ₹6000 from a bank at 15% interest rate per annum. Find the interest and
amount to be paid at the end of 3 years.
Answer: The interest and amount to be paid at the end of 3 years is Rs.8700
Step-by-step explanation:
let P ,R, T be the Principle amount , Rate of interest and Time
Given that ,P= 6000rs
R= 15%
T=3 years
Interest= PRT÷ 100=6000rs×15r×3t÷100
=2700rs
value to be paid after 3 years = 6000rs+2700rs= 8700rs
Idil drove 12 miles in 1/5an hour. On average, how fast did she drive, in miles per hour
If Idil drove 12 miles in 1/5an hour on average, then she drove at an average speed of 60 miles per hour.
To calculate the average speed of Idil's car in miles per hour, we need to divide the distance she drove (12 miles) by the time it took her to drive that distance (1/5 hour):
Average speed = distance ÷ time
Average speed = 12 miles ÷ (1/5) hour
To divide by a fraction, we can multiply by its reciprocal, so:
Average speed = 12 miles × 5/1 hour
Average speed = 60 miles per hour
Therefore, Idil drove at an average speed of 60 miles per hour.
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if the gross weight of a bag of rice is 25.8 Kg and the net weight is 25 Kg, then...
a. The tare of the rice is _ grams
b. the tare percentage of the rice is _ %
(a) the tare οf the rice is 800 grams. and (b) the tare percentage οf the rice is 3.10%.
What is Percentage?A rate, number, οr amοunt in each hundred
a. The tare οf the rice is the weight οf the packaging οr cοntainer used tο hοld the rice. It can be calculated by subtracting the net weight οf the rice frοm the grοss weight οf the bag:
Tare weight = Grοss weight - Net weight
Tare weight = 25.8 Kg - 25 Kg
Tare weight = 0.8 Kg
Tο cοnvert this tο grams, we can multiply by 1000:
Tare weight = 0.8 Kg × 1000
Tare weight = 800 grams
Therefοre, the tare οf the rice is 800 grams.
b. The tare percentage οf the rice is the percentage οf the grοss weight that is accοunted fοr by the tare weight. It can be calculated using the fοrmula:
Tare percentage = (Tare weight / Grοss weight) × 100%
Substituting the values we fοund earlier, we get:
Tare percentage = (800 g / 25.8 Kg) × 100%
Tare percentage = 3.10%
Therefοre, the tare percentage οf the rice is 3.10%.
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लगाउनुहोस् । The capacity of a closed cylindrical tank of height 2 m. is 3080 liters. Find the base area of the tank.
11.87 m² metal sheet would be needed to make the base area of tank.
Volume of the cylinderVolume of cylinder, determines how much material it can carry, is determined by the cylinder's volume. A cylinder is a three-dimensional structure having two parallel, identical bases that are congruent.
It is given that capacity of a closed cylindrical vessel of height 2 m is 3080 liters
Let us assume that Radius of cylinder = r
Then Volume of cylinder = π ×r² ×h
= 2π ×r²× m³
1 m³ = 1000 liters
= 2000 π r² liters
Volume of tank = Capacity
2000 π r² = 3080
=> 2000 × (22/7) × r² = 3080
=> r² = 49/100
=> r = 7/10 m
=> r = 0.7 m
Base Area of tank = TSA = 2πrh + 2πr²
= 2×(22/7)(0.7)×2 + 2×(22/7)×(0.7)²
= 3.0772 +8.792
= 111.87 m²
Hence, 11.87 m² metal sheet would be needed to make it.
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Red hair (autosomal recessive) is found in approximately 4% of the people in Norway. if we assume that the Norwegian population is in Hardy-Weinberg equilibrium with respect to hair color: A) what are the frequencies of the red hair (r) and non-red hair (R) alleles? B) what is the frequency of heterozygotes? C) what is the proportion of matings that CAN NOT have a child with red hair?
The answer is: A) r=0.04; R=0.96 B) 8% C) 92.16%.
The Hardy-Weinberg equilibrium is a method for determining the frequency of certain genetic traits in a population. The following are the frequencies of the red hair (r) and non-red hair (R) alleles in the Norwegian population, according to the question: A) The total frequency of alleles is 1. If red hair (r) is found in approximately 4% of the people in Norway, then the frequency of the R allele must be 0.96 or 96%. R = 0.96 r = 0.04 B) The frequency of hetero zygotes in a population can be determined by multiplying the frequency of the R allele by the frequency of the r allele and then multiplying that number by 2.
Heterogeneous genotype = 2pq Here, p represents the frequency of the R allele, and q represents the frequency of the r allele. p = R = 0.96 q = r = 0.04 Therefore, 2pq = 2(0.96 x 0.04) = 0.077, or approximately 8%. C) In order for a child to have red hair, both parents must carry the r allele. If both parents are homozygous for the R allele, there is no chance that their child will have red hair. This means that the proportion of matings that cannot result in a child with red hair is (0.96 x 0.96) = 0.9216 or 92.16%.
Therefore, the answer is: A) r=0.04; R=0.96 B) 8% C) 92.16%.
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Find the unknown lengths in these similar triangles. (Round off to two decimal places.)
The value of the unknown lengths in these similar triangles is FH is 6.67 units and EG is 27 units.
What is triangle?A triangle is a polygon with three sides and three angles. It is a two-dimensional shape that is commonly studied in mathematics, geometry, and other fields. The sum of the angles in a triangle is always 180 degrees, and the lengths of the sides can vary. Triangles can be classified based on the lengths of their sides and the measures of their angles. Common types of triangles include equilateral, isosceles, scalene, acute, right, and obtuse triangles. Triangles have many important properties and are used in various applications, including construction, engineering, and physics.
Here,
1. Let x be the length of FH. We have:
AB/EF = BD/FH
12/8 = 10/x
Cross-multiplying, we get:
12x = 80
x = 80/12
x ≈ 6.67
Therefore, FH ≈ 6.67.
2. Let y be the length of EG. We have:
AC/BD = FH/EG
15/9 = 5/y
Cross-multiplying, we get:
5y = 135
y = 135/5
y ≈ 27
Therefore, EG ≈ 27.
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A love expert carried out a study to quantify the effect of love songs on emotion. To do so, he used 30 volunteers. He random
Publishers
assigned the 30 volunteers to listen to either a love song or classical music. Then he asked them to draw a heart on a piece of paper. He measured the size of the heart drawn from bottom to top, in inches, for each person. The results are displayed in the stem and leaf plots.
The analysis of the data to obtain the confidence interval of the difference in the means indicates;
99% confidence interval for [tex]\bar x[/tex]₁ - [tex]\bar x[/tex]₂
The correct options are;
Name of Procedure
Two sample interval for [tex]\bar{x}[/tex]₁ - [tex]\bar{x}[/tex]₂Random
The volunteers are randomly selectedWe have a random sample of 15 subjects who listen to love songsWe have a random sample of 15 subjects who listen to classical music10%
The 10% condition is metNormal/Large Sample
The stemplot of the classical music sample data shows no strong skewness or outliersThe stemplot of the love song music sample data shows no strong skewness or outliers99% CI = (-0.302, 2.301)
Conclude;
We are 99% confident that the interval give in the previous step captures -0.301 to 2.301 = the true difference in mean heart height for all subject like these who listen to love songs versus classical music.
What is a confidence interval?A confidence interval is a range of value that is likely to contain the true value of a population parameter with a certain degree of confidence.
The two-sample t-test can be used to construct the 99% confidence interval as follows;
([tex]\bar x[/tex]₂ - [tex]\bar x[/tex]₁) ± t(α/2, df) × √(s₁²/n₁ + s₂²/n₂)
Where;
[tex]\bar x[/tex]₂ and [tex]\bar x[/tex]₁ = The sample means of the love song and classical music groups
s₁, and s₂ = The sample standard deviations
n₁ and n₂ = The sample sizes
df = The degrees of freedom
t(α/2, df) = The value from the t-distribution table with a significance level of 0.01 and df = n₁ + n₂ - 2
The data indicates;
n₁ = n₂ = 15
[tex]\bar x[/tex]₁ = 5.07, s₁ = 1.63
[tex]\bar x[/tex]₂ = 4.07, s₂ = 1.13
Therefore, we get;
([tex]\bar x[/tex]₂ - [tex]\bar x[/tex]₁) ± t(α/2, df) × √(s₁²/n₁ + s₂²/n₂)
= (5.07 - 4.07) ± t(0.005, 28) × √(1.62²/15 + 1.13²/15)
= 1 ± 2.763 × 0.469
= 1 ± 1.301
The 99% confidence interval for the difference in the true mean heart for subjects who listen to a love song versus classical music is; (-0.301, 2.301).
The correct statement is; 99% confidence interval for [tex]\bar x[/tex]₁ - [tex]\bar x[/tex]₂
The correct statements, placed in the box are;
Name of Procedure;
Two sample interval for [tex]\bar x[/tex]₁ - [tex]\bar x[/tex]₂
Random
The volunteers are randomly selected
The random condition is met
We have a random sample of 15 subjects who listen to a love song
We have a random sample of 15 subjects who listen to classical music
10%
The 10% condition is met
15 < 10% of all subjects like these who listen to love songs
15 < 10% of all subjects like these who listen to classical music
Normal/Large Sample
The Normal/Large condition is met
The stemplot of the classical music sample data shows no strong skewness or outliers
The stemplot of the love song music sample data shows no strong skewness or outliers
Therefore;
99% CI = (-0.301, 2.301)
Conclude;
We are 99% confident that the interval given in the previous step captures -0.301 to 2.301 = the true difference in mean heart height for all subject like these who listen to love songs versus classical music.
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biconditional of that of two angles are supplementary,then the sum of their measures is 180
Answer:
just a Condit
Step-by-step explanation:
hfjgygdhydv htfhdfjyfdg hyfjkg
Answer:
If two angles are supplementary, then the sum of their measures is 180°.
Given a square with area a, you can use the formula P = 4a² to find the
perimeter P of the square. Find the perimeter of a square that has an area of 64 m².
The perimeter of the square is 256 m.
What ia area?Area is a measure of the amount of two-dimensional space enclosed by a closed figure or shape. It is usually measured in square units, such as square meters, square feet, or square centimeters.
What is a Square?A square is a regular quadrilateral with four equal sides and four right angles. It is a special case of a rectangle and a rhombus, and its properties are a combination of both.
In the given question,
We can start by using the formula for the area of a square, which is:
a = s²
where a is the area and s is the length of one side of the square.
If the area of the square is 64 m², then we have:
64 = s²
Solving for s, we get:
s = √64 = 8 m
Now, we can use the formula for the perimeter of a square in terms of its area:
P = 4a²
Substituting a = 64, we get:
P = 4(64) = 256 m
Therefore, the perimeter of the square is 256 m.
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ab +3a² - 7a+ab+a² simplify this algebraic expression
Simplifying the algebraic expression ab + 3a² - 7a + ab + a² = a(4a + 2b - 7)
What is an algebraic expression?An algebraic expression is a mathematical expression in which letters are used to represent the variables.
Since we have the algebraic expression ab + 3a² - 7a + ab + a², and we want to simplify it. We proceed as follows
ab + 3a² - 7a + ab + a²
First, we collect the like terms together
ab + 3a² - 7a + ab + a² = 3a² + a²- 7a + ab + ab
Adding the similar terms together, we have
= 3a² + a²- 7a + ab + ab
= 4a²- 7a + 2ab
= 4a²- 7a + 2ab
Factorizing out a, we have that
= a(4a - 7 + 2b)
= a(4a + 2b - 7)
So, ab + 3a² - 7a + ab + a² = a(4a + 2b - 7)
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I need to show my work please help
Answer:
x=15
Step-by-step explanation:
use the side splitter theorem
(x-6)/x = 3/5 (cross-multiply)
3x=5(x-6) distributive property
3x=5x-30
2x = 30
x = 15
In order to test a claim that more than 40% of all calls to the emergency 911 phone number are actually not for emergency situations, 40 recordings of 911 calls are selected at random from those received in the past year, and 22 calls are classified as non-emergency. What are the p-value and conclusions for this test?A. P-value = 0.0264. There is strong evidence to show that no more than 40% of 911 calls are actually not emergency, at significance level a-0.05.B. P-value = 0.0264. There is strong evidence to show that more than 40% of 911 calls are actually not emergency, at significance level a 0.05.C. P-value = 0.0528. There is no strong evidence to show that more than 40% of 911 calls are actually not emergency, at significance level a 0.05.D. P-value = 0.0528. There is strong evidence to show that more than 40% of 911 calls are actually not emergency, at significance level a=0.05.
Answer:
0.005
Step-by-step explanation:
I NEED HELP ON THIS ASAP!!!
The system of inequalities to represent the constraints of the situation are x ≤ 260, y ≤ 320, and x + y ≤ 360.
What is system of inequalities?A group of two or more linear inequalities are grouped together and graphed on a coordinate plane to discover the solution that concurrently solves all of the inequalities. Each inequality forms a half-plane on the coordinate plane, and the location where all the half-planes overlap is where the system is solved. Each point inside the feasible area meets all of the system's inequalities. This region is known as the feasible region. To identify the optimum solution given a set of constraints, systems of linear inequalities are frequently utilised in optimization issues.
Let us suppose the number of boards of Mahagony sold = x.
Let us suppose the number of black walnut boards sold = y.
According to the given problem the equation can be set as follows:
x ≤ 260 (the company has 260 boards of mahogany available)
y ≤ 320 (the company has 320 boards of black walnut available)
x + y ≤ 360 (the company expects to sell at most 360 boards of wood)
Hence, the system of inequalities to represent the constraints of the situation are x ≤ 260, y ≤ 320, and x + y ≤ 360.
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